I am making a task sheet for my students and I have written the following code:
=IF(J35-K35>5,"Task 1",IF(J35-K35>3,"Task 2",IF(J35-K35>2,"Task 3", IF(J35-K35>0,"Task 4",IF(K35-J35<1,"Task 5",IF(K35-J35<3,"task 6",IF(K35-J35>3,"Task 7")))))))
The cell K35 contains "Total hours worked" and
The cell J35 contains "Total hours required".
Their format is in [h]:mm
The problem I am facing here is that it is showing me output for only 2 conditions - for the one which is greater than 0 (Task 4) and the other which is less than 1 (task 5). None of the other conditions are getting executed. I need a way in which I can compare hours with numbers.
How can I solve this problem?
If the cells contain times, the calculation J35-K35 will return a number between 0 and 1 for a positive value, between -1 and 0 for a negative value. The formula will use the underlying values, not what they will look like if formatted as time.
The value of one hour, formatted as general is 0.041666667. You can either use that and its multiples in your formula or multiply the result of the subtraction by 24 to arrive at numbers where the part before the decimal point is the number of hours, so your formula could be
=IF((J35-K35)*24>5,"Task 1",IF((J35-K35)*24>3,"Task 2",IF((J35-K35)*24>2,"Task 3", IF((J35-K35)*24>0,"Task 4",IF((K35-J35)*24<1,"Task 5",IF((K35-J35)*24<3,"task 6",IF((K35-J35)*24>3,"Task 7")))))))
Related
I have a list of date and time, say 3/5/2018 15:00:00
I want a formula to calculate the time remaining until tonight 00:00
for this example, it should be 09:00:00
this is an image of the resulting table I wanted
what i tried: =TEXT(TIME(24,0,0)-A20, "hh:mm") the result is #Value!
The general algorithm for this, in any programming language or environment is simple:
Get the date component from the date-time value.
Increment the day value.
Subtract the date-time value from the date value in step 2
This works because the value from step 2 is still a date-time value, but the time-of-day component is now zero which represents that day's morning-midnight (i.e. 00:00 in the 24-hour clock).
In Excel, date, time, and date-time values are all represented by decimal numbers where the integer component represents a day-count after some epoch and fractional component represents the time-of-day.
This means step 1 is done by simply doing INT( date-time-value ).
And step 2 is done by simply adding +1 to that value.
And step 3 is simple subtraction, but be sure to set the cell's display format to "Time" and not Date or Date-Time.
Cell B2 should have this formula:
=( INT( A2 ) + 1 ) - A2
Then drag-fill that for the column to get the values for the other rows.
That's it.
So, did this, do note that my answer is in decimals... You can sort to hours, minutes and seconds...
=24-(HOUR(B4)+MINUTE(B4)/60+SECOND(B4)/3600)
This should do:
=24-TEXT(A20,"hh:mm")
Considering midnight is either 0 or 24, depending on where you come from, as we are moving towards it we consider as "24" and when we are moving from it, "0". So I subtract the current time/date in a format that excludes the date from "24" and there you have remaining time to midnight.
Do not forget to format the cell to "time", otherwise the results will be wrong.
Case 1
I have a set of data which i need to determine if the cell is in Business Hours or Not.
8 - 18 (08:00 - 18:00) Business Hours (BH)
outside the timeframe is Non Business Hours (NBH)
Given Cell value for example is = "7" (which is NBH)
here is the formula i created =if(AND(C2>=8,C2<=18 ),"BH","NBH")
Case 2
I have a set of data for days in a week, i need to determine if the cell is in Weekdays or Weekends.
I have this formula = =if(OR(I2="Saturday", I2="Sunday"), "NBH", "BH")
note : i used the same variable name NBH - Weekends , BH - Weekdays
What I really need to do is to combine those two cases into 1 formula.
I need to output these scenarios correctly, listing below :
Time is 08:00, date is Saturday/Sunday = Combined formula of case 1 and 2 should output "NBH"
Time is 07:00, date is Monday-Friday = Combined formula of case 1 and 2 should output "NBH"
Time is 12:00, date is Monday-Friday = Combined formula of case 1 and 2 should output "BH"
Formulas can be seen in column BH/NBH WEEKDAYS and BH/NBH Weekends, you can browse attached file thanks much!
Click to access the file
If you want to calculate it directly on the initital values:
=IF(OR(H2="Saturday", H2="Sunday", B2>18, B2<8), "NBH", "BH")
p.s. Alternatively you can combine the already calculated columns, if you intend to keep these columns:
=IF(AND((E2="BH"), (D2="BH")), "BH", "NBH")
I have a rather big (long) table and need to do something quite simple but I'm currently with a sort of blackout...
Imagine that you have:
Date 1 Value 1 Date 2 Value 2 Date 3 Value 3 Date of MAX
... ... ... ... ... ... ????
I want to deploy in ???? a formula that will result in the date at which the maximal value (between Value 1...3) was registered. For instance:
Date 1 Value 1 Date 2 Value 2 Date 3 Value 3 Date of MAX
20160501 10 20160722 47 20161002 9 20160722
meaning, the Date of MAX is of Date 2 because that was the date at which the MAX was measured.
Thanks in advance.
You could do a more general solution using offset:-
=MAX(N(OFFSET(D2,0,COLUMN(A:D)*3)))
to find the largest value - put this in (say) R2.
Then find a match for it and pick out the corresponding date:-
=OFFSET(C2,0,MATCH(R2,N(OFFSET(D2,0,COLUMN(A:D)*3)),0)*3)
assuming the dates and values are every third column.
These are array formulae and must be entered with CtrlShiftEnter
If the last value really was in P21 you would have to give a row offset as well as a column offset.
OK, I found a dirty but simple solution (don't know why I didn't think of it at first):
=IF(G2>=MAX(G2,J2,M2,P21),F2,IF(J2>=MAX(G2,J2,M2,P21),I2,IF(M2>=MAX(G2,J2,M2,P21),L2,O2)))
where the pairs (4 of them) are at FG, IJ, LM, OP. Not elegant but does the job.
Hoping someone can help,
I work for a fire department and i am trying to determine the number of times all our rigs on the road at emergencies at the same time. I have all the data from date, times, etc... So what i am looking for is an excel summation total that would display the sum of overlapping times that were greater than 3. So kinda as follows:
Rig Date Start Time End Time
1 1/1/2015 0703 0759
2 1/1/2015 0705 0823
3 1/1/2015 0706 0815
4 1/1/2015 0723 0759
1 1/1/2015 0802 0845
With more than three rigs on the road after 0723 it would grant me a total of one but then at 0802 rig 1 goes back out again meaning my total would increase by 2 and so on and so on. I dont have the slightest clue as to how to program this. I have three years of data i need to crunch through and something like this would help me greatly. Any help whatsoever is appreciated. Thanks in advance and lets see what you all come up with!
First, you might want to convert the times to Excel date-times (assuming you already applied Format as Table to your data, so all new formulas get populated for all rows automatically):
if the values are already Excel times, use:
=$B2 + C2
if you have integers like "703" (formatted as "0703"), use:
=$B2 + INT(C2/100)/24 + MOD(C2, 100)/24/60
or if you have values-as-text:
=$B2 + LEFT(C2, 2)/24 + RIGHT(C2, 2)/24/60
Don't forget to format the new columns using Custom Number format d.m. hh:ss or m/d hh:ss.
The next step is to count all ongoing deployments that end only after the current deployment started, i.e. use following formula as illustrated on screenshot:
=COUNTIFS(F$2:F2, ">" & E2)
Please make sure that the formula e.g. in row 13 looks like =COUNTIFS(F$2:F13, ">" & E13) to check that you are on the right track. Also none of the values can be 5 or more if you only have 4 rigs, otherwise you have an error in your data.
And to count number of times when all 4 rigs were in use, the formula looks like this:
=COUNTIFS($G$2:$G$13, 4)
In case you also want to sum the time while none rigs were available, add 2 more columns in your table. Column H in my illustration needs following array formula (entered by Ctrl+Shift+Enter):
=IF(G2=4, MIN(IF(F$2:F2 > E2, F$2:F2)), "")
And a normal formula in column I:
=IF(G2=4, H2-E2, "")
Don't forget to format numbers accordingly.
And do a simple sum: =SUM($I$2:$I$13).
I need to calculate the working hours elapsed between two dates and times, for example:
Holiday taken between 01/09/2014 and 05/09/2014
5 working days # 8 hours per day.
I need the result to show me how many working hours that would be. For example:
ANNUAL ENTITLEMENT: 89.9 Hours
DATE FROM DATE TO RETURN TO WORK HOURS REQUIRED HOURS REMAINING DATE
01/09/2014 05/09/2014 06/09/2014 40 49.90
I have no idea if this is even possible!
I am assuming these are given cells. if you type in the date to a cell you can click on a new cell and put uptop by the fx this
for example. In C1 you can type this into the fx. Make sure you put the equal sign.
=B1-A1
This is what is the dates in the cells
A1 = 1/9/2014
B1 = 5/9/2014
This will give you 120 which is the total days inbetween.
You will want to get the number of weeks so you can divide by 7.
You will multiply weeks by number of days worked which is 5
Then you want the weeks times 8 hours you can do this in C1
=(B1 - A1)/7 * 5 * 8
which gives you 685.7143
you need to also take into account weekends which a simple subtraction will not do. Firstly find the total number of days:
TOTAL_NUMBER_DAYS = B1-A1 + 1
then calculate how many weekends:
TOTAL_WEEKENDS = WEEKNUM(B1) - WEEKNUM(A1)
finally take the total days and subtract weekends:
NET_TOTAL_DAYS = TOTAL_NUMBER_DAYS - (TOTAL_WEEKENDS * 2)
TOTAL_HOURS = NET_TOTAL_DAYS * 8
I solved this recently and had a working solution initially in Excel 2013. Slightly adapted to work in 2007 (lack of 'Days()' function). We use it for reporting on support tickets (length of time between opening and closing a ticket).
Inputs are "Workday start", "Workday end" from which "Hours worked" and "Hours not worked" are calulated.
Hours worked =HOUR(WorkEnd-WorkStart)+(MINUTE(WorkEnd)+MINUTE(WorkStart))/60
Hours not worked = 24 - Hours worked
Further inputs are a table ("Data") with first two columns "Open" and "Close", which are dateserial cells.
Next column is standard numeric value "Gross hours" =(Data[[#This Row],[Close]]-Data[[#This Row],[Open]])*24
Next column is standard numeric value "Net workdays" =NETWORKDAYS(Data[[#This Row],[Open]],Data[[#This Row],[Close]])
Next column is standard numeric value "Net days" =MAX(1,DAY(Data[[#This Row],[Close]])-DAY(Data[[#This Row],[Open]]))
Next column is standard numeric value "Gross workhours" =IF(Data[[#This Row],[Gross hours]]>0,Data[[#This Row],[Gross hours]]-24*(Data[[#This Row],[Net days]]-Data[[#This Row],[Net workdays]]),0)
Last column is standard numeric value "Total work hours" =IF(Data[[#This Row],[Gross workhours]]<24,Data[[#This Row],[Gross workhours]],Data[[#This Row],[Gross workhours]]-(HoursNotWorked*Data[[#This Row],[Net workdays]]+HoursWorked))
This solution makes it trivial to adjust start and end work times, as well as accounting for any holidays (via a small change to the NETWORKDAYS() function to utilise the optional parameter).