I have a time diary spreadsheet that was given to me to record times taken for staff to complete different activities. Column A is the start time, column B is the finish time, where column C is the difference, using the formula B3-A3.
In row 3, this gives me answer of 0:01. Is there a way to convert this to "1" using a formula?
i.e. 0:0X becomes X
or, 0:YX becomes YX?
Thanks
MINUTE() will convert the time to time in minutes.
Related
I am using a spreadsheet to record the intervals between certain medical events. Each event's timestamp is recorded in one column, so the interval between each event is the difference between consecutive cells (and the time since the last event uses now()).
First problem: I want to display the interval in days, hours and minutes. None of the built-in formats will do this, they report the days remaining after discarding complete months. So I am using this expression:
TEXT(TRUNC(C2-C1),"0") & " days " & TEXT(MOD(C2-C1,1),"hh "" hrs "" mm ""mins""")
which (e.g.) shows "46 days 13 hrs 44 mins". I was hoping there was a way to format a date/time value to show this rather than making the cell a string value, but I haven't been able to find one.
Second problem: I want to display the average value of all completed intervals in the same format. Because I can't average the string values produced by the previous expression I need to average the numeric equivalent (which I'd prefer not to have visible in the sheet) and then convert it to a string as for a single interval.
I can probably do this with a similar approach (if I don't run out of characters to enter the formula) but it seems to me that there must be a better way.
Ideally there is a solution which will work in Excel 2010. Has anyone solved a similar problem before and can give me some pointers?
Thanks, T
Edit: Some data to show what I am working with (I hope the image is readable). Here's a few lines from the sheet.
The formula for H2 etc. is
=IF(G2="c",NOW()-C2,"")
I5 is calculated as the difference between C5 and Cprev (where prev is chosen so that D5 and Dprev are both set). Obvious extension of this for J and K.
M2, M3 and M4 are respectively
=AVERAGEIF(K5:(INDIRECT("K"&(ROWS(K:K)))),"<>0")
=AVERAGEIF(J5:(INDIRECT("J"&(ROWS(J:J)))),"<>0")
=AVERAGEIF(I5:(INDIRECT("I"&(ROWS(I:I)))),"<>0")
Now, I can use a custom format for the values in H, I and J, and for M3 and M4, because these values will never exceed a few days. But values in K and M2 will be somewhere around 100 so I can't just format the raw value.
With custom formatting applied:
Here K6 and M2 say "27 days.." not "87 days..". That's what I'd like to fix nicely, hopefully without populating additional cells or writing a 3gl function to do it.
Date_Times in Excel are stored as days (with the decimal part representing parts of a day).
If the date matters, rather than just a number of days, then day zero is 1899/12/31.
Your first thought was right - do with formatting, not by turning a number into a string.
Entering date into A and time into B, with C=A+B is a good start, so that you can E.g. subtract one point in time from another without having to do anything about straddling midnight, month-ends etc, calculate averages etc.
Consolidating the comments already here: per https://support.microsoft.com/en-us/office/format-numbers-as-dates-or-times-418bd3fe-0577-47c8-8caa-b4d30c528309 you cannot get d for days above 31 (and it won't accept a format 0 hh:mm:ss )
I suggest that you do all your calculations using just numbers to get to say column M, and in N2 put =M2 etc, so you have the same values twice.
Then for formatting, use Format Cells | Number | Custom.
In column M put 0 "days".
In column N put hh "hours" mm "minutes".
Hi,
I have this table with me, each record represents one file. My objective is to calculate out the duration for the file to complete.
I stuck at some files are completed within the same day, while some files might complete only after 1 or 2 or 3 days.
Are there any formulas to calculate it out?
Thanks.
You are better off with a single date and time column then use something like the below. Otherwise combine the date and time yourself first
=(TIMEVALUE(B2)-TIMEVALUE(C2)+(TIMEVALUE(B2)<TIMEVALUE(C2)))*24
I think I found a way to achieve that. Solution
First I would apologize for my unclear question. The weekdays are text format, the weekend doesn't count, and the durations are confirmed within one week period.
I actually did the below steps and achieved to my objective.
Convert all the weekdays to numbers, refer to column J and K.
Column L is the variance between column J and K. L=K-J
Then the duration M column put this formula will do.
=IF(L2=0,MOD(I2-G2,1)*24,IF(AND(L2=1,I2>=G2),MOD(I2-G2,1)*24+L2*24,IF(AND(L2=2,I2>=G2),MOD(I2-G2,1)*24+L2*24,IF(AND(L2=3,I2>=G2),MOD(I2-G2,1)*24+L2*24,MOD(I2-G2,1)*24+(L2-1)*24))))
In assessing how many agents can be added to certain times of day without exceeding the number of seats in the call center, I'm trying to discern how many agents are scheduled for each half hour interval on each day of the week.
Using the =SUMPRODUCT(((A$2:A$1000<=D2)+(B$2:B$1000>D2)+(A$2:A$1000>B$2:B$1000)=2)+0) formula I've been able to identify how many total agents work for each interval, however this doesn't take the day of week into account.
I currently have my spreadsheet setup this way:
K is the start time of the shift, L is the end time of the shift, M to S pulls data from another sheet that shows a 1 if the agent works on that day of the week and 0 if they do not, and then U has all the time intervals listed out. In the example, it's cut off but the columns continue down as needed. U goes to 49 and I've just been using a range from 2 to 500 for the others as we currently do not have that many shifts and I'm leaving space for the moment.
After some Googling, I tried =SUMPRODUCT(--(M2:M500="1"),(((K$2:K$1000<=U2)+(L$2:L$1000>U2)+(K$2:K$1000>L$2:L$1000)=2)+0)) but it only returns #VALUE! so I'm not sure what I'm doing wrong.
Any suggestions of how I can make this work? Please let me know if more information would be useful. Thanks.
=sumproduct(($K$2:$K$1000<=U2)*($L$2:$L$1000>=U2))
That will count the number of occurrences where the start time is less than or equal to the time in U2 AND the end time is greater than or equal to U2. It will check time from row 2 to row 1000. Any time one condition is checked and its true the comparison will result in value of TRUE and FALSE when its not true. The * act like an AND condition while at the same time converts TRUE and FALSE values to 1 and 0. So both conditions have to be true for a value of 1 to result. Sumproduct then totals up all the 1 and 0 to get you a count.
In order to consider the days of the week, you will need one thing to be true. Your headers in M1:S1 will need to be unique (which I believe they are). You will need to either repeat them in adjacent columns to M or in say V1 you have a cell that can change to the header of the day of the week you are interested in. I would assume the former so you can see each day at the same time.
In order to do this you want to add more conditions and pay attention to you reference locks $.
In V2 you could use the following formula and copy down and to the right as needed:
=sumproduct(($K$2:$K$1000<=$U2)*($L$2:$L$1000>=$U2)*(M$2:M$1000))
UPDATE #1
ISSUE 1 Time ranges ending the following day (after midnight)
It is based on the assumption that the ending time is later than the start time. When a shift starts at 22:00 and end at 6:30 as an example, our mind says that the 0630 is later than 22:00 because it is the following day. Excel however has no clue that 0630 is the following day and without extra information assumes it to be the same day. In excel date is stored as an integer and time is stored as a decimal. When you only supply the time during entry it uses 0 for the date.
In excel the date is the number of days since 1900/01/00. So one way to deal with your time out is to add a day to it. This way excel will know your out time is after your in time when the hour is actually earlier in the day.
See your sample data below.
Using your sample data, I did a straight copy of the value in L and placed it in M (=L3 and copy down). I then changed the cell display format from time to general. This allows you to see how excel sees the time. Note how all the time is less than 1.
In column N I added 1 to the value when the out time was less than the in time to indicate that it was the following day and we had not actually invented time travel. I also used the trick of a math operation will convert a TRUE/FALSE result to 1 or 0 to shorten the equation. I used =M3+(L3<K3) and copied down. You will notice in the green bands that the values are now greater than 1.
In the next column I just copied the values from N over using =N3 copied down, and then I applied just a time display format for the cell. Because it is only time format, the date is ignored and visually your time in column O looks the same as column L. The big difference is excel now knows that it is the following day.
you can quickly fix your out times by using the following formula in a blank column and then copying the results and pasting them back over the source column using paste special values.
=M2+(L2<K2)
The next part is for your time check. When looking at the 12:00 time you need to look at 1200 of the current day incase a shift started at 12:00 and you need to look at the 1200 period of the following day. In order to do that we need to modify the the original formula as follows:
=sumproduct(($K$2:$K$1000<=$U2)*($L$2:$L$1000>=$U2)*(M$2:M$1000)+($K$2:$K$1000<=$U2+1)*($L$2:$L$1000>=$U2+1)*(M$2:M$1000))
Note that the + in the middle of (M$2:M$1000) + ($K$2:$K$1000<=$U2+1)? This + acts like an OR function.
Issue 2 Time In/Out 15 minute increments, range 30 minute increments
You may be able to achieve this with the ROUNDDOWN Function or MROUND. I would combine this with the TIME function. Basically you want to have any quarter hour start time be treated as 15 minutes sooner.
=ROUNDDOWN(E3/TIME(0,30,0),0)*TIME(0,30,0)
Where E3 is your time to be converted
So your formula may wind up looking something like:
=sumproduct((ROUNDDOWN($K$2:$K$1000/TIME(0,30,0),0)*TIME(0,30,0)<=$U2)*($L$2:$L$1000>=$U2)*(M$2:M$1000)+((ROUNDDOWN($K$2:$K$1000/TIME(0,30,0),0)*TIME(0,30,0)<=$U2+1)*($L$2:$L$1000>=$U2+1)*(M$2:M$1000))
similar option could be used for the leaving time and rounding it up to the next 30 minute interval. In which case just use the ROUNDUP function. Though I am not sure it is required.
I'm currently performing analysis on some data. Basically, sorting different product by certain variables, all this in different time frames (product flow every 30 minutes).
My date and time column looks like this: 2.01701E+11 (201701262230).
How do I refer to it?
Thank you.
Thank you for the prompt answer, but I still don't quite get how to use it. I've tried but failed.
Basically imagine I have a column with products (A, B, C, D) and next to them a column with daytimevalues that start at 13 o'clock on a certain day (201701241300) and end at 11PM the same day (201701242300). The range changes each 30 minutes.
I am trying to count all product A on the 24th of January at 13:00, and then at 13:30 and so forth:
the formula would go something like this:
=COUNTIFS(Data[Product_type], "A", Data[day_hour], ??????????)
=DATEVALUE(TEXT(A1,"0000-00-00 00\:00")) this fromula will get you the date.
=TIMEVALUE(TEXT(A1,"0000-00-00 00\:00")) this formula will give you the time.
A1 is the cell containing the input value
In the Image the column C and D contains the above mentioned formula...
=COUNTIFS($A$2:$A$10,F3,$C$2:$C$10,$G$1,$D$2:$D$10,(">=13:00:00"),$D$2:$D$10,("<14:00:00"))
you can use the above formula in cell G3 to get desired output...similarly you can use it to get other values as well.
enter image description here
You can see the situation here. Basically I have the dates under that form. I need to count the countries by occurence in time, every have hour in a given day.
I'm trying to perform an AVERAGEIFS formula on some data, but there are 2 possible results and as far as I can tell AVERAGEIFS doesn't deal with that situation.
I basically want to have an ELSE inside it.
At the moment I have 2 ranges of data:
The first column only contains values 'M-T' and 'F' (Mon-Thurs and Fri).
The second column contains a time.
The times on the rows with an 'F' value in column 1 are an hour behind the rest.
I want to take an average of all the times, adjusting for the hour delay on Fridays.
So for example I want it to take an average of all the times, but subtract 1 hour from the values which are in a row with an 'F' value in it.
The way I've been doing it so far is by having 2 separate results for each day, then averaging them again for a final one:
=AVERAGEIFS(G3:G172, B3:B172, "M-T")
=AVERAGEIFS(G3:G172, B3:B172, "F")
I want to combine this into just one result.
The closest I can get is the following:
=AVERAGE(IF(B3:B172="M-T",G3:G172,((G3:G172)-1/24)))
But this doesn't produce the correct result.
Any advice?
Try this
=(SUMPRODUCT(G3:G172)-(COUNTIF(B3:B172,"=F")/24))/COUNTIF(B3:B172,"<>""""")
EDIT
Explaining various steps in the formula as per sample data in the snapshot.
SUMPRODUCT(G3:G17) sums up all the value from G3 to G17. It gives a
value of 4.635416667. This after formatting to [h]:mm gives a value
of 111.15
OP desires that Friday time be one hour less. So I have kept one hour less for Friday's in the sample data. Similar SUMPRODUCT on H3:H17 leads to a value of 4.510416667. This after formatting to [h]:mm gives a value
of 108.15. Which is exactly three hours less for three occurrences of Fridays in the sample data.
=COUNTIF(B3:B17,"=F") counts the occurrences of Friday's in the B3:B17 range which are 3 occurrences.Hence 3 hours have to less. These hours are to be represented in terms of 24 hours hence the Function COUNTIF() value is divided by 24. This gives 0.125. Same is the difference of 4.635416667 and 4.510416667 i.e. 0.125
Demonstration column H is for illustrative purposes only. Infact Friday accounted values that is 108.15 in sample data has to be divided by total data points to get the AVERAGE. The occurrences of data points are calculated by =COUNTIF(B3:B17,"<>""""") with a check for empty columns.
Thus 108:15 divided by 15 data points give 7:13 in the answer.
Revised EDIT Based upon suggestions by #Tom Sharpe
#TomSharpe has been kind enough to point the shortcomings in the method proposed by me. COUNTIF(B3:B172,"<>""""") gives too many values and is not advised. Instead of it COUNTA(B3:B172) or COUNT(G3:G172) are preferable. Better Formula to get AVERAGE as per his suggestion gives very accurate results and is revised to:
=AVERAGE(IF(B3:B172="M-T",G3:G172,((G3:G172)-1/24)))
This is an Array Formula. It has to be entered with CSE and further cell to be formatted as time.
If your column of M-T and F is named Day and your column of times is named TIME then:
=SUMPRODUCT(((Day="M-T")*TIME + (Day="F")*(TIME-1/24)))/COUNT(TIME)
One simple solution would be to create a separate column that maps the time column and performs the adjustment there. Then average this new column.
Is that an option?
Ended up just combining the two averageifs. No idea why I didn't just do that from the start:
=((AVERAGEIFS(G$3:G171, $B$3:$B171, "F")-1/24)+AVERAGEIFS(G$3:G171, $B$3:$B171, "M-T"))/2