I have two strings, i want to extract the number in the middle "2200" i am using the formula
=VALUE(MID(C3,SEARCH("_",C3)+11,4))
C3 is where the string is. this formula working on "string 2" and give me the value i am looking for "2200" but doesn't work for "String 1" i get #VALUE!. if i change the formula
=VALUE(MID(C3,SEARCH("_",C3)+10,4))
it works for "String 1" but doesn't work for "String 2" How can i have same formula work in both situations?
String 1: ABC_1A1B_33C_2200_4AB_ABC4_4800
String 2: ABC_10A1B_33C_2200_4AB_ABC4_4800
thx,
This should work as long as the example 2200 is always 4 digits long:
=LEFT(REPLACE(D7,1,FIND("#",SUBSTITUTE(D7,"_","#",3)),""),4)
If the value you wish to extract is always in the fourth position, then you can try:
=INDEX(TRIM(MID(SUBSTITUTE(C3,"_",REPT(" ",99)),seq_99,99)),4,1)
where seq_99 is a Named Formula that refers to:
=IF(ROW(INDEX(Sheet1!$1:$65535,1,1):INDEX(Sheet1!$1:$65535,255,1))=1,1,(ROW(INDEX(Sheet1!$1:$65535,1,1):INDEX(Sheet1!$1:$65535,255,1))-1)*99)
seq_99 will return an array: {1,99,198,297,...,25146}
This does not care as to the length, only that it is the forth block:
=TRIM(MID(SUBSTITUTE(A1,"_",REPT(" ", 999)),3*999,999))
Note
The above returns a text string that looks like a number. If a number is what is wanted then replace the TRIM with --
=--MID(SUBSTITUTE(A1,"_",REPT(" ", 999)),3*999,999)
This solution is based on the static position of the number being between the third and fourth underscore character.
=--TRIM(MID(SUBSTITUTE(SUBSTITUTE(A2, "_", REPT(" ", LEN(A2)), 4), "_", REPT(" ", LEN(A2)), 3), LEN(A2), LEN(A2)))
Note the double-unary (aka double-minus or --) that converts text-that-looks-like-a-number to a true number.
Related
I'm trying to use a left(find) function to split a name from an account number.
EX: John Smith G123456 -> G123456
Is there a way for excel to detect a string that starts with a specific letter and ends with any digit?
My current implementation has the full string copy pasted from firefox into A1, and then A2 has the following formula:
=LEFT(A1,FIND("G",A1)-1)
This works just fine until I have a name that has G in it.
Thank you!
Assuming you just want the last word of the input, which would always be the account number, you may try this formula:
=TRIM(RIGHT(SUBSTITUTE(A1, " ", REPT(" ", 100)), 100))
To isolate the name, you could try removing space followed by the account (the latter which we found using the above formula):
=SUBSTITUTE(A1, " " & TRIM(RIGHT(SUBSTITUTE(A1, " ", REPT(" ", 100)), 100)), "")
If the Account number is always 1 letter 6 digits (7 characters)
you could use
=MID(A1,LEN(A1)-6,7) to get the account number
and then =LEFT(A1,LEN(A1)-8) for the Name
I am attempting to extract two digits from the right side of a string.
The input string can end with digits or text. For example:Hitch Rack - 4-Bike and Mountain-100 Silver, 38.
My end goal is to pull the last two digits if they exist into another cell. If the initial string doesn't end with the digits, I want to output a " ".
Currently, my brain is telling me this, where [#Product] is the input cell string value:
=IF(ISNUMBER(RIGHT([#Product],2)),RIGHT([#Product],2)," ")
Using the two input examples above I should get: " " (space) and 38 as the outputs respectively.
Try typing *1 after the right() formula:
=IF(NOT(ISERROR(RIGHT([#Product],2)*1)),RIGHT([#Product],2)*1," ")
If you use left/right/mid in excel, it returns the output as a string (e.g. "38") which is text, not a number. Multiplying by 1 makes it a number, if the return values are letters you get an error.
One more method pasted below -
=IFERROR(IF(NUMBERVALUE(RIGHT(H8,2)),RIGHT(H8,2)," ")," ")
I am trying to extract a string from a cell and I am running into some trouble. In this example I am looking to extract the string ARM52CVA from
A18031600473 ( FLORENCE - ARM52CVA )
Ive tried this formula and it doesnt seem to work for me
=RIGHT(C3,SEARCH("-",C3))
You would have come closer with either of:
=RIGHT(C3,LEN(C3)- SEARCH("-",C3))
=MID(C3,FIND("-",C3)+2,99)
but they would have left the ending.
If your data is exactly as you show it, with all of the data and spaces as shown, then try:
=INDEX(TRIM(MID(SUBSTITUTE(C3," ",REPT(" ",99)),{1,99,198,297,396},99)),5)
If there is more variability, you'll need to show more data.
Try,
=REPLACE(REPLACE(A1, 1, FIND("- ", A1)+1, ""), FIND(" ", REPLACE(A1, 1, FIND("- ", A1)+1, "")), LEN(A1), "")
The methods above are far more reliable but if the white space is consistent you can also use
=MID(A1,FIND("-",A1,1)+2,(FIND(")",A1,1)-3-FIND("-",A1,1)+1))
I have dummy emails that are too long. I want to shorten them but I don't want to delete the first parenthesis.
"est#scelerisque.ca"
"fermentum#fringillacursus.edu"
"adipiscing#arcuVivamussit.com"
"vitae.aliquet#Sed.edu"
"magna.tellus#Nullamnisl.com"
"placerat.eget#purusNullam.org"
Is it possible for me to delete for example the first 3 letters after the (") and the next 3 letters after # and stop at the dot?
As i ask this, it sounds really complicated. I may just use the same email for all users since it's just dummy data :/
If you have one email in each cell, you can create an excel formula which will
convert email values for you.
Delete 3 letters after ":
=CHAR(34) & MID(A1, 5, LEN(A1))
(Using result of previous formula in B1):
Skip 3 letters after #:
=MID(B1, 1, FIND("#", B1)) & (MID(B1, FIND("#", B1)+4, LEN(B1)))
(Using result of previous formula in C1):
Stop at the dot (also keep " at the end):
=MID(C1, 1, FIND(".",C1)-1 ) & CHAR(34)
I have a set of data that shown below on excel.
R/V(208,0,32) YR/V(255,156,0) Y/V(255,217,0)
R/S(184,28,16) YR/S(216,128,0) Y/S(209,171,0)
R/B(255,88,80) YR/B(255,168,40) Y/B(255,216,40)
And I want to separate the data in each cell look like this.
R/V 208 0 32
R/S 184 28 16
R/B 255 88 80
what is the function in excel that I can use for this case.
Thank you in advance.
kennytm doesn't provide an example so here's how you do substrings:
=MID(text, start_num, char_num)
Let's say cell A1 is Hello.
=MID(A1, 2, 3)
Would return
ell
Because it says to start at character 2, e, and to return 3 characters.
In Excel, the substring function is called MID function, and indexOf is called FIND for case-sensitive location and SEARCH function for non-case-sensitive location. For the first portion of your text parsing the LEFT function may also be useful.
See all the text functions here: Text Functions (reference).
Full worksheet function reference lists available at:
Excel functions (by category)
Excel functions (alphabetical)
Another way you can do this is by using the substitute function. Substitute "(", ")" and "," with spaces.
e.g.
=SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(A1, "(", " "), ")", " "), ",", " ")
I believe we can start from basic to achieve desired result.
For example, I had a situation to extract data after "/". The given excel field had a value of 2rko6xyda14gdl7/VEERABABU%20MATCHA%20IN131621.jpg . I simply wanted to extract the text from "I5" cell after slash symbol. So firstly I want to find where "/" symbol is (FIND("/",I5). This gives me the position of "/". Then I should know the length of text, which i can get by LEN(I5).so total length minus the position of "/" . which is LEN(I5)-(FIND("/",I5)) . This will first find the "/" position and then get me the total text that needs to be extracted.
The RIGHT function is RIGHT(I5,12) will simply extract all the values of last 12 digits starting from right most character. So I will replace the above function "LEN(I5)-(FIND("/",I5))" for 12 number in the RIGHT function to get me dynamically the number of characters I need to extract in any given cell and my solution is presented as given below
The approach was
=RIGHT(I5,LEN(I5)-(FIND("/",I5))) will give me out as VEERABABU%20MATCHA%20IN131621.jpg . I think I am clear.
Update on 11/30/2022
With new excel functions, you can use the following in cell C1 for the input in A1:
=TEXTJOIN(" ",,TEXTSPLIT(A1,{"(",",",")"}))
Here is the output:
What about using Replace all?
Just replace All on bracket to space.
And comma to space. And I think you can achieve it.