I have three pieces of information: quantity, weight per piece and a limit. What I need is for the weight per piece to multiple without passing the limit and the quantity.
I made a code, but the thing is the data of quantity varies and the code used is very long.
=ROUND(IFS((F13*G13)<H13,F13*G13,((F13-1)*G13)<H13,((F13-1)*G13),
((F13-2)*G13)<H13,,((F13-3)*G13)<H13,,((F13-4)*G13)<H13,,((F13-5)*G13)<H13,,
((F13-6)*G13)<H13,(F13-6)*G13,((F13-7)*G13)<H13,(F13-7)*G13,
((F13-8)*G13)<H13,(F13-8)*G13,((F13-9)*G13)<H13,(F13-9)*G13,
((F13-10)*G13)<H13,(F13-10)*G13,((F13-11)*G13)<H13, (F13-11)*G13,
((F13-12)*G13)<H13,(F13-12)*G13,((F13-13)*G13)<H13,(F13-13)*G13,
((F13-14)*G13)<H13,(F13-14)*G13,((F13-15)*G13)<H13,(F13-15)*G13,
((F13-16)*G13)<H13, (F13-16)*G13,((F13-17)*G13)<H13,(F13-17)*G13,
((F13-18)*G13)<H13,(F13-18)*G13),-2)+200
Here is the input and expected result, if no condition matches returns #N/A.
I don't know if the +200 at the end of the formula is supposed to be included in the limit or not so just adjust the formula accordingly
=ROUND(IF(G13*F13+200>=H13,H13,F13*G13+200),-2)
Multiply the quantity and the weight and add 200.
If the result is equal to or greater than the limit, set the result to the limit.
Otherwise use the results of the quantity * weight + 200
And then round it according to your initial formula
This is what your IFS() looks like:
IFS(((F13-0)*G13)<H13,(F13-0)*G13,
((F13-1)*G13)<H13,(F13-1)*G13,
((F13-2)*G13)<H13,,
((F13-3)*G13)<H13,,
((F13-4)*G13)<H13,,
((F13-5)*G13)<H13,,
((F13-6)*G13)<H13,(F13-6)*G13,
((F13-7)*G13)<H13,(F13-7)*G13,
((F13-8)*G13)<H13,(F13-8)*G13,
((F13-9)*G13)<H13,(F13-9)*G13,
((F13-10)*G13)<H13,(F13-10)*G13,
((F13-11)*G13)<H13,(F13-11)*G13,
((F13-12)*G13)<H13,(F13-12)*G13,
((F13-13)*G13)<H13,(F13-13)*G13,
((F13-14)*G13)<H13,(F13-14)*G13,
((F13-15)*G13)<H13,(F13-15)*G13,
((F13-16)*G13)<H13,(F13-16)*G13,
((F13-17)*G13)<H13,(F13-17)*G13,
((F13-18)*G13)<H13,(F13-18)*G13)
I see three issues:
the cases for 2 up to 5 are missing. Are you sure this is correct?
it looks like (for a general 'x'):
IF ((F13-x)*G13)<H13 THEN (F13-x)*G13, you can calculate the resulting value quite easily, isn't it?
why do you stop at 18?
You can simplify it as follows:
=LET(A, A2, B, B2, C, C2, seq, SEQUENCE(19,,0),
out, IF((seq > 1) * (seq < 6), 0, (A - seq)*B),
ROUND(#FILTER(out, (A - seq)*B < C, NA()), -2) + 200)
and extend it down, or use the array version as follow in cell D2:
=LET(A, A2:A3, B, B2:B3, C, C2:C3, seq, SEQUENCE(19,,0),
MAP(A,B,C, LAMBDA(x,y,z, LET(out, IF((seq > 1) * (seq < 6), 0, (x - seq)*y),
ROUND(#FILTER(out, (x - seq)*y < z, NA()), -2) + 200))))
Here is the output:
The implicit intersection operator (#) ensures to get the first element of FILTER result, which is equivalent to get the first condition that matches. If no condition matches, then it returns NA(). The name out, has the result in the same order it should be tested via IFS. Using SEQUENCE allows to simplify the process.
I have a big function with lots of branches of IFS; each branch uses different references of the worksheet:
MYFUN = LAMBDA(i,
IFS(
i = 1, // a formula uses Row 1 for instance,
i = 2, // a formula uses Row 2 for instance,
... ...
)
Then, I realize that if I write =MYFUN(2) at Cell C1, a circle reference error is raised, even though during runtime =MYFUN(2) does not use values in Row 1.
I try to reproduce the problem with a small code. I define a function as follows:
TRY = LAMBDA(i,
IFS(
i = 1, Sheet1!$B$2,
i = 2, Sheet1!$D$2,
TRUE, "haha"
)
);
Then, writing =TRY(2) at Cell B2 returns well the value of D2 without the error of circle references, which is good.
Now, I add a SUM function as follows:
TRY = LAMBDA(i,
IFS(
i = 1, SUM(Sheet1!$B$2),
i = 2, Sheet1!$D$2,
TRUE, "haha"
)
);
Now, writing =TRY(2) at Cell B2 raises a circle reference error, even though SUM(Sheet1!$B$2) does not need to be executed.
Does anyone know why the behaviour is like that?
How could I restructure the code like in MYFUN to avoid false circle reference errors?
PS:
I also realize that ROWS(Sheet1!$B$2) at the place of SUM(Sheet1!$B$2) does not raise circle reference error. So what's their semantics?
IFS will try to resolve every criterion then return the one associated with the first TRUE. It does not find the first TRUE then resolve the Criterion associated.
Put 6 in B2 and 3 in D2 then put this in B4
=IFS(2=1,SUM(B2),2=2,D2,TRUE,1=1)
Then with that cell selected evaluate the formula:
We can see that all 6 criteria were resolved, but the 3 was returned.
I have a problem with my nested if condition as an Excel formula. I know it would be easier by using VBA, but I have to do it this way.
This is my formula, but it returns FALSE:
=IF(D:D="SUPER";IF(AND(AA:AA="0";AA:AA="1");"V";IF(AA:AA="3";"R";"O")))
The D:D column has 3 filters, I have to apply the same formula with each filter.
The AA:AA column has the following conditions:
- if 0 and 1 -> V
- if 3 -> R
- if anything else -> O
I don't know why it doesn't work, but I would appreciate any advice!
This will return R, because there is 3 in there
enter image description here
I think this is more a matter of prioritizing logic flow. It seems that at least a single occurrence of SUPER with 3 supersedes the rest. The next priority would be SUPER with 0 and SUPER with 1 (both must occur). If none of those apply, default to O.
=if(countifs(d:d, "super", aa:aa, 3), "R", if(not(and(countifs(d:d, "super", aa:aa, 0), countifs(d:d, "super", aa:aa, 1))), "O", "V"))
'with semi-colons
=if(countifs(d:d; "super"; aa:aa; 3); "R"; if(not(and(countifs(d:d; "super"; aa:aa; 0); countifs(d:d; "super"; aa:aa; 1))); "O"; "V"))
=IF(COUNTIFS(D:D;"super";AA:AA;3)<>0;"R";IF(COUNTIFS(D:D;"super";AA:AA;1)*COUNTIFS(D:D;"super";AA:AA;0)=0;"O";"V"))
The order of the criteria was wrong, also you generally can't refer to entire columns in the way you did. This formula first checks whether there's any cell with the value 3. Then if there isn't it multiplies the count of 1s and 0s to check whether there are both numbers present.
I am having an issue with an excel problem and cannot use vba or add any extra columns. The problem goes along with the format of this image. I could not find anything on google that helped me with this problem and im sorry if it has been asked before.
Example Image
On a separate page in a cell i need to write a function that will check if Info 2 = "z" and Info4 = "x" and if that is true then i need to do the following equation with the numbers in Info1 and Info3: Info1*(1 - Info3)
I will also have to keep a sum of these numbers.
For this example I would want the cell with the formula to equal -34 by doing the following:
3*(1-4)+5*(1-6) = -34
I would want the cell to just display the finished sum
Any help would be greatly appreciated,
Thank you!
You are looking for the mighty powers of SUMPRODUCT
=SUMPRODUCT((B:B="z")*(D:D="x")*(A:A)*(1-C:C))
The first two multipliers will make sure we only evaluate those rows having z for B and x for D. While the latter two are your desired function. Excel will evaluate this for each row and sum up the results.
I am using psuedo values below but this should work:
= [value of cell above] + if(and([info2] = "z" , [info4] = "x"), [info1]*(1-[info3]),0)
so basically starting in the middle, you have a two truth tests,
[info2] = "z", [info4]= "x"
using AND() requires they both pass
and([info2] = "z", [info4]= "x")
if they do pass you want to do your formula:
if(and([info2] = "z" , [info4] = "x"), [info1]*(1-[info3]),FALSE)
but since we want to sum all values for each iterative row we make not passing this test 0:
if(and([info2] = "z" , [info4] = "x"), [info1]*(1-[info3]),0)
Ok so this works for one row, but doesn't sum the numbers from the tests on the previous row:
= [value of cell above or 0 for first row] + if(and([info2] = "z" , [info4] = "x"), [info1]*(1-[info3]),0)
an example written with real excel ranges that you may have to tweak depending on where your values are stored:
Sample picture
I am attempting to translate my existing Matlab code into Numbers (basically Excel). In Matlab, I have the following code:
clear all; clc;
n = 30
x = 1:(n-1)
T = 295;
D = T./(n-x)
E = T/n
for i=1:(n-2)
C(i) = D(i+1) - D(i)
end
hold on
plot(x(1:end-1), C, 'rx')
plot(x, D, 'bx')
I believe everything has been solved by your formulas, there are parts of them that I don't understand otherwise I would try to figure the rest out myself. Attached is the result (Also you might like to know that the formulas you gave work and are recognized in Numbers). Im trying to figure out why (x) begins at 2 as I feel as though it should start at 1?
Also it is clear that the realistic results for the formulas only exist under certain conditions i.e. column E > 0. That being the case, what would be the easiest way to chart data with a filter so that only certain data is charted?
(Using Excel...)
Suppose you put your input values T & n in A1 & B1 respectively.
You could generate x, D & C In columns C,D & E with:
C1: =IF(ROW()<$A$1,ROW(),"")
D1: =IF(LEN(C1)>0,$A$2/($A$1-C1),"")
E1: =IF(LEN(D2)>0,D2-D1,"")
You could then pull all 3 columns down as far as you need to generate the full length of your vectors. If you then want to chart these, simply use these columns as inputs.