I'm trying to find the manual function on how Excel converts am/pm time (text) values into numeric decimals (using the Format menu > Number while selecting my 12 hour time column).
For example, how does 12:30:00 PM turn into 0.52083?
Thank you.
Date and time can be handled in many ways. The time representation you are observing in Excel is based on 1 day = 24 hours = 1.0. So 12:00 pm should be exactly 0.5, while 12:30:00 pm would be a bit (30/(24*60) = 1/48 = 0.0208333) above.
Btw. 12/24 hour is just a region specific presentation issue. Internally this doesn't affect the actual date and time values.
Related
I have END_Date data like 43830.99931. When I paste it in the excel and format the cell to Date. It convert it to 12/31/2019 11:59:00 PM. I want same functionality in T-SQL. How can I achieve same result using T-SQL?
Excel (by default) uses the 1900 date system. This simply means that the date 1 Jan 1900 has a true numeric value of 1, 2 Jan 1900 has a value of 2 etc. These values are called "serial values" in Excel and it is these serial values that allows us to use dates in calculations.
The code to convert:
DECLARE #SerialDate FLOAT;
SET #SerialDate = 43830.99931;
SELECT CAST(#SerialDate - 2 AS DATETIME);
returning back the date time value of:
2019-12-31 23:59:00.383
You may have noticed the -2 in the cast. That's because Excel, due to issues with 29th Feb 1900 and the inclusiveness of the start/end dates. (1900-01-01 is day 1 not day 0, and 1900 was not a leap year but excel calculates it wrongly) we have to subtract 2. Details on that issue can be found here.
I am trying to do a time subtraction in excel of 30 minutes and I am running into a speed bump. So the table I have are as follows.
Table "Schedule"
Column 1 is day of the week (Mon-Sun) (formated as general, as this is plain text)
Column 2 is start time of the shift (formated as h:mm AM/PM)
Column 3 is end time of the shift (formated as h:mm AM/PM)
Column 4 is duration of the shift (start to end) (formated by formula (TEXT(col3-col2,"h:mm")) )
Column 5 is paid hours (if the total hours is over 6.5 then subtract 0.5 hours for an unpaid lunch) (formula IF(col5>"6:30",col5-"0:30",D5) )
The issue is any time allotment over 10 hours start to end (where column 4, the duration hits 10 hours) no lunch is subtracted at all.
So...
Start 9:00 AM, End 6:59 PM, Hours Total 9:59, Hours Paid 9:29
But...
Start 9:00 AM, End 7:00 PM, Hours Total 10:00, Hours Paid 10:00
and that should obviously not happen. I can't find anything on google so I figured the excel gurus here may have some advice.
Thanks!
If your time columns are stores using excel's dedicated time format, this should be straightforward. Mixed data types are likely your problem.
First, be sure your time columns (columns 2 and 3) are set using the time function, i.e.,
=time(hours,minutes,seconds)
Then, you should be able to add and subtract easily.
Column 4: = column 3 - column 2
... then subtract 30 minutes also using the time() function:
Column 5: = if(column 4 > time(6,30,0),column 4 -time(0,30,0),column 4)
Excel stores time values from 0 to 1. So 24 hours=1, 12 hours=.5 etc. That means 6.5 hours=0.270833333 and .5 hours=0.020833333. As a result you can just do a simple if statement.
=IF(D2>0.270833333,D2-0.020833333,D2)
To turn it into a time format, is to just use excel's time formating options.
I have a column with date and time for start (IN) and end (OUT) and I want to calculate the difference in days.
Date: IN Time: IN Date: OUT Time: OUT
24/07/2018 12:15:00 26/07/2018 06:11:00
I combine them into date time IN and OUT by using:
E1=TEXT(A2,"dd/mm/yy ")&TEXT(B2,"hh:mm:ss")
F1=TEXT(C2,"dd/mm/yy ")&TEXT(D2,"hh:mm:ss")
But I am unable to find any working code for the difference in number of hours.
TEXT will convert your dates and times into text (strangely enough).
Adding the date and time will return a date/time value so you could use:
=SUM(C2:D2)-SUM(A2:B2) to return 1.74722222
(edit: if you then give the cell a custom number format of d:h:mm it will display 1:17:56 or 1 day, 17 hours, 56 minutes).
(EDIT AGAIN: Sorry, only just seen you want it in hours. Give the cell a custom number format of [hh]:mm. The square brackets tells it to count over 24 hours. This will return 41:56).
or
=DATEDIF(SUM(A2:B2),SUM(C2:D2),"d") to return 2.
or if you just want days from the dates you could just use
=C2-A2 to return 2.
Dates and times in Excel are just numbers - no need to complicate things by turning them to text.
= (F1 - E1) * 24
Rather easly :)
I have a list of times:
8:30PM
8:15PM
7:20PM
How can I convert these to decimal hours in Powerpivot (DAX)?
for example:
8.5
8.25
7.33
Use this formula DecimalNumber = Sheet1[DATE]*24, or simply multiply your time with 24. 8:30PM can never evaluate to 8:30 since it is PM, so it's actually 20:50. If you want it to be 8:50 instead, then subtract 12 from formula.
I have tried every which way to format cells to subtract the result from time for instance the formula in the cell = 11(this is 11 minutes) I want to take that result minus 8:00:00 to give me 7:49:00 but it doesn't work the result is ####### no matter how big I make the cell. And if I format the cells with the formula to custom [m]:ss then the value changes.
Sample of the Worksheet:
I want Y2 = X3-W3 in a time format.
So, if A1=11
Then in some other cell, (B1 in this example): =TIME(,A1,)
Then subtract from the cell with 8:00:00. (If it's C1...:)
=C1-B1
That will give you the time you want.
Info: The main thing is that you have to tell Excel that your cell with the "11" in it, is minutes. By using the =TIME(,A1,) you will get the value of: 12:11 am. (If you keep it in Date format.) 12:11 am could also be viewed as: 0 Hours, 11 minutes, 0 seconds. And now that it knows, you should be able to subtract.
Try this:
=TIME(HOUR(X3),MINUTE(X3)-W3,SECOND(X3))
The ######### is because you have a negative time. Becuase Excel reads time as decimals of 24 hours, 8:00:00 is .3333 and if you subtract 11 from that you get -10.6666 and date/time can not be negative.