I need to prepare test data having around 10K lines with many blank lines, same has to be removed. Earlier I was using editplus (Text editor) and could able to solve very easily by using Find (Find text: "\n\n" Regular expression) and Replace (empty) option.
Here in this project I am using Sakura editor and tried the below option to remove blank lines but its not working.
Need to remove line 6 and 7.
Find text
\n\n
\r\n\r\n
[\r\n]+[\r\n]
More information about using of regular expression in sakura editor
Click here
PS: I have some restriction in my current project to download and install any other software/tools.
Any help is appreciated.
Finally found solution. Like to share with others.
In sakura editor, we can remove the empty lines by using find and replace option.
Find ^\r\n 【Option:Regular expression】 and replace
Explanation
^ Beginning of the line
\r carriage-return character
\n newline (line feed) character
Related
How can I replace or delete words in VIM anything after
m/PH
Is so hard to use CTRL-v to delete them because I have tons of similar name from last point
My word structure in vim:
To answer your follow-up question
Is there any way Mr. To that without inside VIM ? ,. My file name is paragraph
if your file is named paragraph, the following sed command will do:
$ sed -i 's/\(m\/PH\).*/\1/' paragraph
If you mean the lines after the first occurence of m/PH then I would start a search from the first line to the first occurence and delete from this line on
:1;/m\/PH/,$ d
If you want to delete all characters in each line after m/PH then find this string, preserve it and "forget" anything else behind it
:%s/\(m\/PH\).*$/\1.
I want to use textpad on a .csv file to remove all lines of text that include the following phrase
"Norwegian Cruise Line"
So it does a search and replace on the following and deletes the whole line and repeats through the document:
"V186552004127",18,**"Norwegian Cruise Line"**,655,9751509,"Norwegian Bliss","Superior","Bahamas & Florida",12/04/2020 00:00:00,"Caribbean","Ocean","Scenery","Adventure","History",9,"New York",0,"New York",1,0,,7,0," ",8.00,19/04/2020 00:00:00,"NYK","New York","USA, NY","Disembark",0,0,"",0,0,0,0
Thanks in advance
You can use the following steps:
Open the Find Dialog with F5
Enter your search term and klick Mark All. This will bookmark all lines containing your serached term.
From the Edit menu or the context menu select Delete|Bookmarked Lines
I'm not sure about textpad, but you can use something like visual studio code or sublime which supports multi line cursors. Then, for example, in visual studio code just highlight the phrase you want and hit ctrl+F2 or right click and hit change all occurrences. From there you can hit ctrl+shift+k to delete the lines.
Using regular expressions in Textpad:
Search:
.*"Norwegian Cruise Line".*\r
Replace With:
(empty)
Replace All
This will search zero o more characters before target text followed by zero or more characters and a newline. Will erase all lines containing "Norwegian Cruise Line" (including quotes).
I have a *.qif file (text file) in which I would like to remove all lines from the second line (not including the header) to a line which contains the characters 'D1/7/2015'. In vim I have tried block selecting from the second line and searching up to a the characters but it doesn't work. What I have tried so far:
Move the cursor to second line then:
v/D1/7/2015
v/D1//7//2015
v/D1///7///2015
None of these seem to work.
You can escape slashes with backslashes:
v/D1\/7\/2015
or tell Vim to parse your pattern with "verymagic" syntax:
v/\vD1/7/2015
See :help \v.
Not exactly what I wanted but it works. I used /D1.7.2015 to get to the line then started visual selection up to the beginning of the file with vgg after which I moved one line down with the cursor then pressed d.
You can delete directly without using the visual selection from the second line to the line containing 'D1/7/2015' by executing the command below:
:2,/D1\/7\/2015/ d
I am having a text file
Example:
793643450715275|Andriod Game Hacker
470734673064253|Andriod Firmရာ
382409221961101|Andriod Solution
709215912481252|AndriodوIOS
248027618719895|Exchange App Andriod Reviews
212241765574268|andrioders
I want to remove all alphabet characters
Example Like :
793643450715275
470734673064253
382409221961101
709215912481252
248027618719895
212241765574268
Anybody tell me how can I do this .I have also try notepad++ but not able to do this
Suggest Me.
In Notepad++, please try Find what :
\D+
Replace with :
\r
in Regular expression Search Mode, Replace All.
In Word:
Find what:
|*^13
Replace with:
^p
check Use wildcards and Replace All.
In Excel:
=LEFT(A1,FIND("|",A1)-1)
or if number format preferred:
=1*LEFT(A1,FIND("|",A1)-1)
and in both cases copy down to suit.
Or Text to Columns with pipe as the delimiter and delete what is not required.
I need to use find new lines (\n) in a .txt file and replace them with a backspace (\b). Using this in the Find and Replace feature of Notepad++ successfully finds the new lines, (\n), but replaces them with the characters "\b" instead of applying a backspace. How can this be done correctly?
\r\n should work.
replace them with empty field and you will get your backspace(\b) equivalent
A simple way would be Ctrl + J or Edit->Line Operations->Join Lines
I was also trying to replace \n with backspace, but the above solutions seems neat. Maybe it helps someone.
(I tried the \r\n solution and it seems both works the same way :) )
In notepad++,
Go to Edit menu, line operations and then click on "Remove Empty Lines"
You get what you are trying with regular expression.
Removing empty lines
Use regular expressions, in Find what:, enter \r\n and in Replace with: leave that blank.