I created a number guessing game, that is the code:
#Guess the number game
import random
guesses = 6
number = random.randint(0, 100)
win = False
while guesses > 0:
guess = int(input("Guess: "))
guesses -= 1
if guess > number:
print("Your guess is too high", guesses, "remaining")
elif guess < number:
print("Your guess is too low", guesses, "remaining")
elif guess - number < 6:
print("You are very close")
else:
print("Congrats, you guessed")
win = True
guesses = 0
if win == False:
print("Sorry, you didn't guess the number", number)
However, I want it so that if the user inputs a number which is bigger by 5 or lower by 5 than the random number(number variable), to print "You are close".
how about this:
import random
guesses = 6
number = random.randint(0, 100)
win = False
while guesses > 0:
guess = int(input("Guess: "))
guesses -= 1
if guess == number:
win = True
guesses = 0
elif abs(guess - number) < 6:
print("You are very close")
elif guess > number:
print("Your guess is too high", guesses, "remaining")
elif guess < number:
print("Your guess is too low", guesses, "remaining")
if win == False:
print("Sorry, you didn't guess the number", number)
else:
print("Congrats, you guessed correct")
you need to check early if the number is close (before the guess > number checks); and abs is there to accept a difference in both directions
your guess - number < 6 will never be reached; one of the 2 conditions above will already have been met; and without the abs this condition will be true even for very small guesses.
and maybe it would be better to loop over the guesses with a for loop and break if the solution has been found.
Related
Could you, please, help me to understand how should I use try/except block and count tries at the same time.
Here is the code without try/except block (it seems it's working fine):
import random
number = random.randint(1, 10)
tries = 3
name = input('Hi! What is your name?\n')
answer = input(f'{name}, let\'s play a game! Yes or No?\n')
if answer == 'Yes':
print(f'But be aware: you have only {tries} tries!\nReady?')
chat = input('')
print('Ok, guess a number from 1 to 10!')
while tries != 0:
choice = int(input('Your choice: '))
tries -= 1
if choice > number:
print('My number is less!')
elif choice < number:
print('My number is higher!')
else:
print('Wow! You won!')
break
print(f'You have {tries} tries left.')
if tries == 0 and choice != number:
print(f'Sorry, {name}, you lost... It was {number}. Try next time. Good luck!')
else:
print('No problem! Let\'s make it another time...')
This one is with try/except block.. Not sure where should I place 'choice' variable and where count 'tries', it keeps looping and looping:
import random
number = random.randint(1, 10)
tries = 3
name = input('Hi! What is your name?\n')
answer = input(f'{name}, let\'s play a game! Yes or No?\n')
if answer == 'Yes':
print(f'But be aware: you have only {tries} tries!\nReady?')
chat = input('')
print('Ok, guess a number from 1 to 10!')
while True:
try:
choice = int(input('Your choice: '))
if 0 < choice < 11:
while tries != 0:
tries -= 1
if choice > number:
print(f'My number is less!')
elif choice < number:
print(f'My number is higher!')
else:
print('Wow! You won!')
break
print(f'You have {tries} tries left.')
if tries == 0 and choice != number:
print(f'Sorry, {name}, you lost... It was {number}. Try next time. Good luck!')
else:
print(f'Hey {name}, I said, print a number from 1 to 10!')
except ValueError:
print('Please, enter a number!')
else:
print('No problem! Let\'s make it another time...')
Thanks!
I'm trying to get a guessing game with the user input as an answer and if the user type exit the game will show the amount of time the player tried but the program won't run because it can only take either interger or string type.
import random
while True:
number = random.randint(1,9)
guess = int(input('guess the number: '))
time = 0
time += 1
if guess == number:
print('you guessed correct')
elif guess < number:
print('your guessed is lower than the actual number')
elif guess > number:
print('your guessed is higher than the actual number')
elif guess == 'exit':
print(time)
break
something like this
import random
time = 0
number = random.randint(1,9)
while True:
guess = input('guess the number: ')
time += 1
if guess == "exit":
print(time)
break
elif int(guess) < number:
print('your guessed is lower than the actual number')
elif int(guess) > number:
print('your guessed is higher than the actual number')
elif int(guess) == number:
print('you guessed correct')
print(time)
break
note that time and number have to be initializate outside the while loop, because if not, we would get different random numbers for each iteration, and also time would be initializate to 0 each time.
You can test the input as a string first before converting it to an integer:
while True:
response = input('guess the number: ')
if response == 'exit':
break
guess = int(response)
# the rest of your code testing guess as a number
import random
replay = 1
while replay == 1:
replay = replay - 1
target = random.randint(1, 100)
guess = int(input("Guess the number 1-100: "))
count = 0
score = 0
while count == 0:
score = score + 1
if guess < target:
print ("The number is higher. Try again.")
guess = int(input("Guess the number 1-100: "))
elif guess > target:
print ("The number is lower. Try again.")
guess = int(input("Guess the number 1-100: "))
elif guess == target:
print ("You guessed Correctly!")
print ("Your score was:", score)
again = str(input("Play again? (yes or no)"))
if again == "yes" or "YES":
replay = replay + 1
elif again == "no" or "NO":
break
This is my code, except it doesn't do what I want it to do. After you guess the correct number, it doesn't see to properly loop through the game again when you say yes or no. It just goes through the final if statement again.
Why won't it go through the entire program again?
Your code will always be evaluated to true
if again == "yes" or "YES":
Change it to:
if again.lower() == "yes":
Or
if again in ("YES", "yes", "y",..)
When it is true, you need to break from you second loop:
if again.lower() == "yes":
replay = replay + 1
break
When it is false, don't break but exit the program using:
exit()
Since replay is only used to exit your code, you don't need it if you use exit().
Code would then be:
import random
while True:
target = random.randint(1, 100)
guess = int(input("Guess the number 1-100: "))
score = 0
while True:
score = score + 1
if guess < target:
print ("The number is higher. Try again.")
guess = int(input("Guess the number 1-100: "))
elif guess > target:
print ("The number is lower. Try again.")
guess = int(input("Guess the number 1-100: "))
elif guess == target:
print ("You guessed Correctly!")
print ("Your score was:", score)
again = str(input("Play again? (yes or no)"))
if again.lower() == "yes":
break
elif again.lower() == "no":
exit()
I created a simple number guessing game, but every time I don't type in a number the system crashes. Can someone please help!
import random
randNum = random.randint(1, 100)
guesses = 0
for i in range(1, 8):
guesses = guesses + 1
print("hi human guess a number 1-100! \n")
guess = input()
guess = int(guess)
if guess > randNum:
print("your guess is too high")
elif guess < randNum:
print("your guess is too low")
elif guess == randNum:
print("duuude you're a genius \n")
print("you needed " + str(guesses) + " guesses")
I took a quick look at your code and one thing which stands out is that on Line 10, you cast the input to an int without checking if the input is indeed an int.
The system crashes because Python cannot typecast characters to integers when you type cast them. You should explicitly write a condition to check for characters i.e. if the input string is anything except numbers, your code should print something like "Try Again" or "Invalid Input".
import random
randNum = random.randint(1, 100)
guesses = 0
for i in range(1, 8):
guesses = guesses + 1
print("hi human guess a number 1-100! \n")
guess = input()
if guess.isdigit():
if int(guess) > randNum:
print("your guess is too high \n")
elif int(guess) < randNum:
print("your guess is too low \n")
elif int(guess) == randNum:
print("duuude you're a genius \n")
print("you needed " + str(guesses) + " guesses")
else:
print("Invalid Input! Try a number. \n")
Try this code. I hope it helps. And from next time try to upload code instead of images. ;-)
import random
def game():
computer = random.randint(1, 10)
# print(computer)
user = int(input("Please guess a number between 1-10: "))
count = 0
while count < 5:
if computer > user:
count += 1
print("You guessed too low!")
print("You have used " + str(count) + "/5 guesses")
user = int(input("Please guess a number another number!: "))
elif computer < user:
count += 1
print("You guessed too high!")
print("You have used " + str(count) + "/5 guesses")
user = int(input("Please guess a number another number: "))
else:
print("YOU WON!!")
again = input("Would you like to play again?")
if again in["n", "No", "N", "no"]:
break
elif again in["y", "Yes", "Y", "yes"]:
pass
game()
if count == 5:
print("Bummer, nice try...the number was actually " + str(computer) + "!")
again = input("Would you like to play again?")
if again in["n", "No", "N", "no"]:
break
elif again in["y", "Yes", "Y", "yes"]:
pass
game()
else:
print("I'm sorry that's an invalid entry! Restart the game to try again!")
game()
I am a real newbie to Python, I am taking it for GCSE at my school and I have been given an assignment to complete. I completed all of the requirements for this simple code but am not sure how to repeat it. Could someone please show me a simple way of repeating the code?
Thanks
import random
Random = random.randint(1,100)
Guess = int(input("Please guess a number between 1 and 100: "))
counter = 1
while Guess != Random:
if Guess > Random:
print("Too high")
Guess = int(input("Please guess the number: "))
else:
print("Too low")
Guess = int(input("Please guess the number: "))
counter += 1
print("Well Done:")
print("You took:",counter, "Guesses")
Easiest way of doing it would be to put it in a while True loop with a conditional break:
import random
while True:
Random = random.randint(1,100)
Guess = int(input("Please guess a number between 1 and 100: "))
counter = 1
while Guess != Random:
if Guess > Random:
print("Too high")
Guess = int(input("Please guess the number: "))
else:
print("Too low")
Guess = int(input("Please guess the number: "))
counter += 1
print("Well Done:")
print("You took:",counter, "Guesses")
choice = input("Would you like to continue? y/n")
if choice == "n":
break
Note, randint(1,100) will return a number from 1-99 inclusive, and you are actually asking the user for a guess 2-99 inclusive the way you have phrased it.