ntfsundelete sh shell script failure - linux

I am trying to write a script to undelete a lot of files from a windows partition. I was able to pull the inode numbers for all of the files and their names by using the scan function of ntfsundelete.
I then took this huge list and made a file like this:
#!/bin/sh
ntfsundelete /dev/sda2 -u -i 50365 -o file1.doc -d .
ntfsundelete /dev/sda2 -u -i 58234 -o file1.doc -d .
I did chmod +x script.sh and ran it sh ./script.sh
I get the error "Couldn't create output file: No such file or directory".
If I run those commands individually, it works, but if I run the script, it fails. I have 1200+ files.

Related

How to replace backup file with timestamp in its name without producing duplicates in Linux Bash (shell script)

#!/usr/bin/env bash
# usage: wttr [location], e.g. wttr Berlin, wttr New\ York
# Standard location if no parameters were passed
location=''
language=''
time=`date`
# Expand terminal display
if [ -z "$language" ]; then
language=${LANG%_*}
fi
curl \
-H -x "Accept-Language: ${language}" \
-x wttr.in/"${1:-${location}}" |
head -n 7 |
tee /home/of/weather.txt |
tee -a /home/of/weather.log |
tee /home/of/BACKUP/weather_"$time".txt
#cp weather.txt /home/of/BACKUP
#mv -f /home/of/BACKUP/weather.txt /home/of/BACKUP/weather_"$time".txt
I'm very new to Linux Bash and Shell scripting and can't figure out the following.
I have a problem with the shell script above.
It works fine so far (curling ASCII data from website and writing it to weather.txt and .log).
It is also in set in crontab to run every 5 minutes.
Now I need to make a backup of weather.txt under /home/of/, in /home/of/BACKUP with the filename weather_<timestamp>.txt.
I tried to delete (rm weather*.txt) the old timestamped files in /home/of/BACKUP and then copy and rename the file everytime the cronjob is running.
I tried piping cp and mv and so on but somehow I end up with producing many duplicates as due to the timestamp the filenames are different or nothing at all when I try to delete the content of the folder first.
All I need is ONE backup file of weather.txt as weather_<timestamp>.txt which gets updated every 5 minutes with the actual timestamp bit I can't figure it out.
If I understand your question at all, then simply
rm -f /home/of/BACKUP/weather_*.txt
cp /home/of/weather.txt /home/of/BACKUP/weather_"$time".txt
cp lets you rename the file you are copying to; it doesn't make sense to separately cp and then mv.
For convenience, you might want to cd /home/of so you don't have to spell out the full paths, or put them in a variable.
dir=/home/of
rm -f "$dir"/BACKUP/weather_*.txt
cp "$dir"/weather.txt "$dir"/BACKUP/weather_"$time".txt
If you are running out of the cron of the user named of then your current working directory will be /home/of (though if you need to be able to run the script manually from anywhere, that cannot be guaranteed).
Obviously, make sure the wildcard doesn't match any files you actually want to keep.
As an aside, you can simplify the tee commands slightly. If this should only update the files and not print anything to the terminal, you could even go with
curl \
-H -x "Accept-Language: ${language}" \
-x wttr.in/"${1:-${location}}" |
head -n 7 |
tee /home/of/weather.txt \
>>/home/of/weather.log
I took out the tee to the backup file since you are deleting it immediately after anyway. You could alternatively empty the backup directory first, but then you will have no backups if the curl fails.
If you want to keep printing to the terminal, too, probably run the script with redirection to /dev/null in the cron job to avoid having your email inbox fill up with unread copies of the output.

I'm not able to execute HandBrakeCLI sh script through php program

I have a sh file named test.sh
SRC=/var/www/html/plms/video/
DEST=/var/www/html/plms/mp4files/
DEST_EXT=mp4
HANDBRAKE_CLI=HandBrakeCLI
for FILE in `ls $SRC`
do
filename=$(basename $FILE)
extension=${filename##*.}
filename=${filename%.*}
$HANDBRAKE_CLI -i $SRC/$FILE -o $DEST/$filename.$DEST_EXT -e x264 -q 22 -r 12 -B 64 -X 480 -O
done
This gets run on command prompt and gives me output.
But when i try to execute it I dont get any output .Here output is .mp4 file from wmv file
testvideo.php
$output = shell_exec('sh test.sh');
Where I am doing wrong?
If i write any other command in test.sh then its get executed.So have issue with HANDBRAKE_CLI only.

Execute commands in specific location and depending on answer of previous command

I am currently working on a Text-to-speech project and I need to write bash script which will, when it is called, execute two commands. If the first command returns the proper answer (if returns an answer at all), the second command will be called and executed.
My question is, how can I write a script, that executes shell commands in a specific certain file system location?
For example, I need to be in the directory /opt/text/example and execute this command:
sudo ./bin/sample_read -I ../languages/ -I ../languages -v dave -T 2 \
-i /opt/text/example.txt -F 22 -O embedded-pro -o out_file.pcm
and then to wait for the answer, then (if it is good) execute the second command.
The second command is
aplay -f S16_LE -r 22050 -c 1 out_file.pcm
This should help:
pushd /path/to/directory
my_var=$(command1)
if [ "$my_var" == "expected_result" ]; then
command2
fi
popd
You basically run command1 and store its output in my_var. Then you compare the content of $my_var with whatever you're expecting.
Also pushd <path>/popd allow you to move to a directory and back.

Executing same command for several files in same repository in linux

I'd like to execute the following command for several files in same repository in linux:
../../../../../openSMILE-2.1.0/SMILExtract -C ../../../../../openSMILE-2.1.0/config/IS13_ComParE.conf -I inputfilename.wav -D outputfilename.csv
there are several files (named 1.wav, 2.wav, 3.wav) in the directory and if I execute
../../../../../openSMILE-2.1.0/SMILExtract -C ../../../../../openSMILE-2.1.0/config/IS13_ComParE.conf -nologfile 1 -noconsoleoutput 1 -I 1.wav -D 1.csv
it outputs 1.csv.
How can I create 1.csv, 2.csv, 3.csv, .. by executing just one single command in linux? (or do I have to make .sh file?)
It's probably cleaner to put the following to a script, but you can type it directly into the bash command line as well:
#! /bin/bash
for file in *.wav ; do
prefix=${file%.wav} # Remove from the right.
../../../../../openSMILE-2.1.0/SMILExtract \
-C ../../../../../openSMILE-2.1.0/config/IS13_ComParE.conf \
-I "$file" -D "$prefix".csv
done

scp multiple files with different names from source and destination

I am trying to scp multiple files from source to destination.The scenario is the source file name is different from the destination file
Here is the SCP Command i am trying to do
scp /u07/retail/Bundle_de.properties rgbu_fc#<fc_host>:/u01/projects/MultiSolutionBundle_de.properties
Basically i do have more than 7 files which i am trying seperate scps to achieve it. So i want to club it to a single scp to transfer all the files
Few of the scp commands i am trying here -
$ scp /u07/retail/Bundle_de.properties rgbu_fc#<fc_host>:/u01/projects/MultiSolutionBundle_de.properties
$ scp /u07/retail/Bundle_as.properties rgbu_fc#<fc_host>:/u01/projects/MultiSolutionBundle_as.properties
$ scp /u07/retail/Bundle_pt.properties rgbu_fc#<fc_host>:/u01/projects/MultiSolutionBundle_pt.properties
$ scp /u07/retail/Bundle_op.properties rgbu_fc#<fc_host>:/u01/projects/MultiSolutionBundle_op.properties
I am looking for a solution by which i can achieve the above 4 files in a single scp command.
Looks like a straightforward loop in any standard POSIX shell:
for i in de as pt op
do scp "/u07/retail/Bundle_$i.properties" "rgbu_fc#<fc_host>:/u01/projects/MultiSolutionBundle_$i.properties"
done
Alternatively, you could give the files new names locally (copy, link, or move), and then transfer them with a wildcard:
dir=$(mktemp -d)
for i in de as pt op
do cp "/u07/retail/Bundle_$i.properties" "$dir/MultiSolutionBundle_$i.properties"
done
scp "$dir"/* "rgbu_fc#<fc_host>:/u01/projects/"
rm -rf "$dir"
With GNU tar, ssh and bash:
tar -C /u07/retail/ -c Bundle_{de,as,pt,op}.properties | ssh user#remote_host tar -C /u01/projects/ --transform 's/.*/MultiSolution\&/' --show-transformed-names -xv
If you want to use globbing (*) with filenames:
cd /u07/retail/ && tar -c Bundle_*.properties | ssh user#remote_host tar -C /u01/projects/ --transform 's/.*/MultiSolution\&/' --show-transformed-names -xv
-C: change to directory
-c: create a new archive
Bundle_{de,as,pt,op}.properties: bash is expanding this to Bundle_de.properties Bundle_as.properties Bundle_pt.properties Bundle_op.properties before executing tar command
--transform 's/.*/MultiSolution\&/': prepend MultiSolution to filenames
--show-transformed-names: show filenames after transformation
-xv: extract files and verbosely list files processed

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