How to select log levels to the output of a bash script - linux

Question

In the script i have written, the output is sent to a log file mySysMonitor.log. I want the user of this script to be able to choose what log levels(debug or info) to be sent to the log file. How do i do this. Take the script below as an example.
#!/bin/bash
processKD(){
printf "\nCURRENT PROCESSES \r"
ps -eo user,pid,pcpu,pmem,start | sort -rk 3,4 | head -n 11
echo "TOTAL NUMBER OF RUNNING PROCESSES: $(ps aux | wc -l)"
}
loggedInKD(){
printf "\nUSERS CURRENTLY LOGGED IN\r"
echo "Number of users logged in: $(w | head -n 1 | cut -d"," -f 3)"
who
}
processKd >> mySysMonitor.log
loggedInKd >> mySysMonitor.log

Answer 1

you can use something like this;
#!/bin/bash
processKD(){
printf "\nCURRENT PROCESSES \r"
ps -eo user,pid,pcpu,pmem,start | sort -rk 3,4 | head -n 11
echo "TOTAL NUMBER OF RUNNING PROCESSES: $(ps aux | wc -l)"
}
loggedInKD(){
printf "\nUSERS CURRENTLY LOGGED IN\r"
echo "Number of users logged in: $(w | head -n 1 | cut -d"," -f 3)"
who
}
LOG_LEVEL="info"
#LOG_LEVEL=$1 #with parameter ./script info
#LOG_LEVEL="debug"
if [ "$LOG_LEVEL" == "info" ]; then
loggedInKd >> mySysMonitor.log
fi
if [ "$LOG_LEVEL" == "debug" ]; then
processKd >> mySysMonitor.log
loggedInKd >> mySysMonitor.log
fi