l = []
print("We will need some information first.")
t_first_name = input("User First Name: ").lower()
while len(t_first_name) == 0 or t_first_name == ' ':
t_first_name = input("User First Name: ").lower()
while len(t_last_name) == 0 or t_last_name == ' ':
t_last_name = input("User Surname: ").lower()
f_n_up = t_first_name.upper()
l_n_up = t_last_name.upper()
f_n_title = t_first_name.title()
l_n_title = t_last_name.title()
l.append(t_first_name) # Lowercase
l.append(t_last_name)
l.append(f_n_up) # Uppercase
l.append(l_n_up)
l.append(f_n_title) # The first letter is uppercase
l.append(l_n_title)
f = open("p_list.txt", "a")
for x in l:
print(x)
if len(x) >= 5:
f.write(x)
print("test")
It will show the print lines and it create the file, but when i open it, i don't find any words in it.
It will ask for the user name and then make a list about him, adding it to a list l and then make a loop inside it and write the string in the file.
You should either call f.close() or f.flush() for the data to be actually written to the file.
Another (and better) solution is to use with to handle the file opening and closing for you:
with open('p_list.txt', 'a') as f:
for x in l:
print(x)
if len(x) >= 5:
f.write(x)
print("test")
Related
my last homework assignment is writing a script that finds the 5 most common email addresses in a text file (linked on hastebin below). I've found a way to find the single most common email address, but how can I expand this output to the top 5? Any help would be greatly appreciated.
while True:
try:
filename = input("Enter a file name: ")
fhand = open(filename, 'r')
email_addresses = {}
for line in fhand:
if line.startswith("From "):
email = line.split()[1]
email_addresses[email] = email_addresses.get(email, 0) + 1
max_address = None
max_emails = 0
for k in email_addresses:
if email_addresses[k] > max_emails:
max_address = k
max_emails = email_addresses[k]
print(max_address, max_emails)
print(email_addresses, email)
ans = input('Do you want to try another file?: (y/n): ')
ans = ans.lower()
if ans == 'y':
continue
if ans == 'n':
print('Thanks for playing!')
break
else:
continue
except:
print('File name',fname,'does not exist.')
continue
And the text file: https://hastebin.com/egixurubak.makefile
A quick idea:
Find the single most common email address in email_addresses, remove it from the dict, store it in a list, find the next single most common email address....
For a class I have to create a simple spell checking program that takes two files as inputs, one containing correctly spelled words and one containing a paragraph with a few misspelled words. I thought I had it figured out but I am getting an error I have never seen before. When the program finishes it gives the error:
<function check_words at 0x7f99ba6c60d0>
I have never seen this nor do I know what it means, any help in getting this program working would be appreciated. Program code is below:
import os
def main():
while True:
dpath = input("Please enter the path to your dictionary:")
fpath = input("Please enter the path to the file to spell check:")
d = os.path.isfile(dpath)
f = os.path.isfile(fpath)
if d == True and f == True:
check_words(dpath, fpath)
break
print("The following words were misspelled:")
print(check_words)
def linecheck(word, dlist):
if word in dlist:
return None
else:
return word
def check_words(dictionary, file_to_check):
d = dictionary
f = file_to_check
dlist = {}
wrong = []
with open(d, 'r') as c:
for line in c:
(key) = line.strip()
dlist[key] = ''
with open(f, 'r') as i:
for line in i:
line = line.strip()
fun = linecheck(line, dlist)
if fun is not None:
wrong.append(fun)
return wrong
if __name__ == '__main__':
main()
It's not an error, it's doing exactly what you are telling it to.
This line:
print(check_words)
You are telling it to print a function. The output you are seeing is just Python printing the name of the function and it's address: "printing the function".
Yes, don't do print(check_words), do print(check_words())
Furthermore, change check_words(dpath, fpath) to misspelled_words = check_words(dpath, fpath)
And change print(check_words) to print(misspelled_words)
Final code (with a few modifications):
import os
def main():
while True:
dpath = input("Please enter the path to your dictionary: ")
fpath = input("Please enter the path to the file to spell check: ")
d = os.path.isfile(dpath)
f = os.path.isfile(fpath)
if d == True and f == True:
misspelled_words = check_words(dpath, fpath)
break
print("\nThe following words were misspelled:\n----------")
#print(misspelled_words) #comment out this line if you are using the code below
#optional, if you want a better looking output
for word in misspelled_words: # erase these lines if you don't want to use them
print(word) # erase these lines if you don't want to use them
#------------------------
def linecheck(word, dlist):
if word in dlist:
return None
else:
return word
def check_words(dictionary, file_to_check):
d = dictionary
f = file_to_check
dlist = {}
wrong = []
with open(d, 'r') as c:
for line in c:
(key) = line.strip()
dlist[key] = ''
with open(f, 'r') as i:
for line in i:
line = line.strip()
fun = linecheck(line, dlist)
if fun is not None:
wrong.append(fun)
return wrong
if __name__ == '__main__':
main()
I am a noob in python and i need help.I have made a phonebook where you can add the contacts.But the problem is that when i exit the program the changes to the list are not saved.I want the user to be able to make permanent changes to the list.I have seen posts about a file=open("something",'w') code to do this(I think) but i dont know where to insert this code and i dont really understand what it is.Could someone help me understand what this is about..Here is the full code:
name = ["ranga","hari"]
number = [9895497777,9]
book = {name[0]:number[0],name[1]:number[1]}
def search():
print("Contacts:")
for x in book:
print(x,':',book[x])
while 1:
count = 0
a = 0
ch1 = input("search: ")
try:
ch1 = int(ch1)
except ValueError:
while a < len(name):
result = name[a].find(ch1)
if result == -1:
a = a + 1
else:
print(name[a],number[a])
a = a + 1
count = count + 1
if count == 0:
print("Not available.Try again")
continue
else:
break
ch1 = str(ch1)
while a < len(number):
sumber = str(number[a])
result = sumber.find(ch1)
if result == -1:
a = a + 1
else:
print(name[a],number[a])
a = a + 1
count += 1
if count == 0:
print("Not available.try again")
continue
else:
break
def add():
print("What is the name of the contact you want to add?")
name1 = input()
name.append(name1)
while 1:
print("What is the number of this contact?")
number1 = input()
try:
number1 = int(number1)
except ValueError:
print("Please type a number..")
continue
number.append(number1)
book[name1] = number1
break
def remoe():
print("Reference:")
for x in book:
print(x,':',book[x])
while 1:
print("What is the name of the contact you want to remove?")
name2 = input()
if name2 in book:
increment = name.index(name2)
name.pop(increment)
number.pop(increment)
del book[name2]
break
else:
print("Not available.Please try again")
while 1:
print("Contacts:")
for x in book:
print(x, ':', book[x])
print("\nWhat do you want to do?\n1.Search for a person\n2.edit the phone book\n3.exit")
choice = input()
try:
choice = int(choice)
except ValueError:
print("Type 1,2 or 3")
continue
if choice == 1:
search()
elif choice == 2:
while 1:
print("Do you want to:\n1.Add a contact\n2.Remove a contact\n3.Go back to main menu")
ch2 = input()
if ch2 in['3']:
break
else:
try:
ch2 = int(ch2)
except ValueError:
print("Type 1 or 2..")
if ch2 == 1:
add()
elif ch2 == 2:
remoe()
elif choice == 3:
exit()
else:
print("Type 1,2 or 3")
I appreciate the help.
When you choose to add a contact, it does properly add the name and number to the list. But, that is it.
When you re-run the program, the list gets re-assigned due to the first 2 lines of your code:
name = ["ranga","hari"]
number = [9895497777,9]
So, you won't see the last changes.
This is where you should maintain a file which lives outside the scope of your code, rather than a list.
You can modify your add function like this:
def add():
print("What is the name of the contact you want to add?")
name1 = input()
#name.append(name1)
# Just add the name1 variable's value to the file
with open('contacts_list.txt', 'a+') as f:
f.write(name1 + '\n')
while 1:
print("What is the number of this contact?")
number1 = input()
try:
number1 = int(number1)
except ValueError:
print("Please type a number..")
continue
#number.append(number1)
# Similarly, append the number1 variable's value to file again.
with open('contacts_list.txt', 'w+') as f:
f.write(number1)
#book[name1] = number1
with open('contacts_list.txt', 'r') as f:
print(f.read())
break
Note: You would also need to change the other functions search and remove to read and write from the file. I've just given you a taste of how things are done. You need to modify your code and make it work.
Let me know if it helps.
I took your advice and made a new text file but i still did not know how to do it but after reading ur answers i understood and at last i came to this..
removelist = []
def search():
while 1:
search = str(input("Search: "))
if search not in["exit", "Exit"]:
with open('output.txt', 'r+') as f:
line = f.readline()
while line:
data = line.find(search)
if not data == -1:
print(line.rstrip('\n'))
line = f.readline()
else:
line = f.readline()
else:
break
f.close()
def add():
print("Type the name of the contact:")
name = input()
while 1:
print("Type the number of this contact:")
number = input()
try:
number = int(number)
except ValueError:
print("Please type a number")
continue
number = str(number)
with open('output.txt', 'a+') as f:
f.write('\n' + name +' ' + number)
break
def remoe(): #this is where the problem comes in
while 1:
remove = str(input("Remove: "))
with open('output.txt', 'r+') as f:
line = f.readline()
while line:
if not remove in["Remove", "remove"]:
removelist.clear()
data = line.find(remove)
if not data == -1:
removelist.append(line) #This saves all the lines coming from the search to a
print(removelist) #removelist which can be accessed when you type in remove
line = f.readline() #But the problem is that if there is a \n at the end of the
else: #string then the remove function does not work
line = f.readline()
else:
print(removelist)
with open('output.txt', 'r') as f:
d = f.readlines()
f.close()
with open('output.txt', 'w') as f:
for i in d:
if i not in removelist:
f.write(i)
f.truncate()
f.close()
break
while 1:
with open('output.txt', 'r') as f:
data = f.read()
print("Contacts:")
print(data)
print('''What do you want to do?
1.Search for a contact
2.Edit contacts
3.Exit''')
f.close()
choice = input()
if choice in["1"]:
search()
elif choice in["2"]:
while 1:
print('''What do you wanna do:
1.Add a contact
2.Remove a contact
3.Exit to main menu''')
ch1 = input()
if ch1 in["1"]:
add()
elif ch1 in["2"]:
remoe()
elif ch1 in["3"]:
break
else:
print("Please type 1,2 or 3")
elif choice in[3]:
print("Ok bye")
else:
print("Please type 1,2 or 3")
Now the problem seems to be the remove function..if i try to remove a line with \n at the end of it then it wont work while the opp. seems to work.Any guess what i am doing here?
And thanks for the help Mayank porwal
At the first you should know name = ["ranga","hari"], number = [9895497777,9] that you have defined are in the code and you can not change those value, and after exit() they will reset to default value.
you should use of file (for example .txt file) in this issue:
1. you must create a .txt file in your project (for example Contacts.txt)
2. and write your information in there (for example in first line: Kourosh +98938....)
3. at the first step in your program you must read Contact.txt and load it in a structure like a list or dictionary (for example
>>> with open('workfile') as f:
... read_data = f.read()
>>> f.closed
)
4.now you can edit, add, remove structure.
5.and finally you can write structure in the file, before exit()
for example:
>>> with open('workfile') as f:
... f.write(s)
>>> f.closed
I want to input a series of numbers and end with "stop", the while loop is to check if x is not equal to the 'stop', it continues add up the input number and output the sum for each loop, however the while loop falls into infinity. For example, my input is:
12
35
56
23
56
455
556
344
22
22
stop
#read the input
x = input()
#add up by a loop
T = 0
x_int = int(x)
while x != 'stop':
for i in range(1, 10):
T += x_int
print(i, T)
You need to prompt for the next input in the while loop. As stands, you never prompt for additional data and so you will never see the stop. I added a prompt so that it is more clear.
#add up by a loop
T = 0
while True:
x = input("enter data: ")
if x == 'stop':
break
x_int = int(x)
for i in range(1, 10):
T += x_int
print(i, T)
Several of us are confused about how you want to enter data. If you don't want any prompts and want to read any number of lines from the user (or perhaps piped from another program) you could read stdin directly.
#add up by a loop
import sys
T = 0
for line in sys.stdin:
x = line.strip()
if x == 'stop':
break
x_int = int(x)
T += x_int
print(i, T)
Try this program and see if it works. The problem with your code was there is no need of a for loop. I didn't understand why it was used there in your program, hope you understood.
T = 0
i = 0
while True:
x = input("enter data: ")
if x == 'stop':
break
else:
i =i+1
x_int = int(x)
T += x_int
print(i, T)
I have a problem, when in Hangman game there is a word like happy, it only append 1 'p' in the list...run my code and please tell me what to do?
check my loops.
import random
import time
File=open("Dict.txt",'r')
Data = File.read()
Word = Data.split("\n")
A = random.randint(0,len(Word)-1)
Dict = Word[A]
print(Dict)
Dash = []
print("\n\n\t\t\t","_ "*len(Dict),"\n\n")
i = 0
while i < len(Dict):
letter = str(input("\n\nEnter an alphabet: "))
if letter == "" or letter not in 'abcdefghijklmnopqrstuvwxyz' or len(letter) != 1:
print("\n\n\t\tPlease Enter Some valid thing\n\n")
time.sleep(2)
i = i - 1
if letter in Dict:
Dash.append(letter)
else:
print("This is not in the word")
i = i - 1
for item in Dict:
if item in Dash:
print(item, end = " ")
else:
print("_", end = " ")
i = i + 1
The error is with the "break" on Line 25: once you have filled in one space with the letter "p", the loop breaks and will not fill in the second space with "p".
You need to have a flag variable to remember whether any space has been successfully filled in, like this:
success = False
for c in range(len(Dict)):
if x == Dict[c]:
Dash[c] = x
success = True
if not success:
Lives -= 1
P.S. There's something wrong with the indentation of the code you have posted.