The following ssh command does not return to terminal. It hangs though the execution is completed. The execution hangs after echo hi command.
ssh user#testserver "echo hello;source .profile;source .bash_profile;/apps/myapp/deploytools/ciInstallAndRun.sh; echo hi"
Output
hello
<outoutfrom remote script"
hi
ciInstallAndRun.sh
echo 'starting'
cd /apps/myapp/current
./tctl kill
cd /apps/myapp
mv myapp_v1.0 "myapp_v1.0_`date '+%Y%m%d%H%M'`"
unzip -o /apps/myapp/myappdist-bin.zip
java -classpath .:/apps/myapp/deploytools/cleanup.jar se.telenor.project.cleanup.Cleanup /apps/myapp myapp_v1.0_ 3
cd /apps/myapp/myapp_v1.0
echo 'Done with deploy'
chmod -R 775 *
echo 'Done'
./tctl start test
Source OS: Redhat
Dest Os: Solaris 10 8/07
Any idea to fix this.
Any idea to fix this.
Your installation script has spawned a child process.
Add a ps -f or ptree $$ command before echo hi. You'll see a child process or multiple child processes spawned by your install script.
To stop the SSH command from hanging, you need to detach such child process(es) from your terminal's input/output. You can sedirect your script's output to a file - both stdout and stderr with > /some/output/file 2>&1, and also redirect its input with < /dev/null.
Or you can use the nohup command.
You haven't provided an MCVE, as others have noted, but this is likely the problem command in you install script, since your question implies that you see the expected output from your install script:
./tctl start test
You probably would do better to replace it with something like:
./tctl start test </dev/null >/some/log/file/path.log 2>&1
Related
I am trying to use daemon on Ubuntu, but I am not sure how to use it even after reading the man page.
I have the following testing script foo.sh
#!/bin/bash
while true; do
echo 'hi' >> ~/hihihi
sleep 10
done
Then I tried this command but nothing happened:
daemon --name="foo" -b ~/daemon.out -l ~/daemon.err -v -- foo.sh
The file hihihi was not updated, and I found this in the errlog:
20161221 12:12:36 foo: client (pid 176193) exited with 1 status
How could I use the daemon command properly?
AFAIK, most daemon or deamonize programs change the current dir to root as part of the daemonization process. That means that you must give the full path of the command:
daemon --name="foo" -b ~/daemon.out -l ~/daemon.err -v -- /path/to/foo.sh
If it still did not work, you could try to specify a shell:
daemon --name="foo" -b ~/daemon.out -l ~/daemon.err -v -- /bin/bash -c /path/to/foo.sh
It is not necessary to use daemon command in bash. You can daemonize your script manually. For example:
#!/bin/bash
# At first you have to redirect stdout and stderr to /dev/null
exec >/dev/null
exec 2>/dev/null
# Fork and go to background
(
while true; do
echo 'hi' >> ~/hihihi
sleep 10
done
)&
# Parent process finished but child still working
When I run the script command it loses all the aliases from the existing shell which is not desired for people using lots of aliases. So, I am trying to see if I can automatically source the .profile again to see if it works without the user have to do it.
Here below is the code:
#!/bin/bash -l
rm aliaspipe
mkfifo aliaspipe
bash -c "sleep 1;echo 'source ~/.bash_profile' > aliaspipe ;echo 'alias' > aliaspipe ;echo 'exec 0<&-' > aliaspipe"&
echo "starting script for recording"
script < aliaspipe
Basically I am creating a named pipe and the making the pipe as stdin to the script program, trying to run the source command and then close the stdin from pipe to the terminal stdin so that I can continue with the script.
But when I execute, the script is exiting after I execute "exec 0<&-",
bash-3.2$ exec 0<&-
bash-3.2$ exit
Script done, output file is typescript
Not sure why the exit is called and script is terminated. If I can make the script move the stdin from pipe to terminal then it should be fine.
You can get script to execute a bash login shell by telling it to do so explicitly.
# Gnu script (most Linux distros)
script -c "bash -l"
# BSD script (also Mac OS X)
script typescript bash -l
That will cause your .bash_profile to be sourced.
By the way, redirections are not stacks. When you write exec 0<&-, you're closing standard input, and when bash's standard input is closed, it exits.
In a very simplified scenario, I have a script that looks like this:
mv test _test
sleep 10
echo $1
mv _test test
and if I execute it with:
ssh localhost "test.sh foo"
the test file will have an underscore in the name as long as the script is running, and when the script is finished, it will send foo back. The script SHOULD keep running, even if you terminate the ssh command by pressing ctrl+c or if you lose connection the the server, but it doesn't (the file is not renamed back to "test"). So, I tried the following:
nohup ssh localhost "test.sh foo"
and it makes ssh immune to ctrl+c but flaky connection to the server still causes trouble. After some debugging, it turns out that the script WILL actually reach the end IF THERE IS NO ECHO IN IT. And when you think about it, it makes sense - when the connection is dropped, there is no more stdout (ssh socket) to echo to, so it will fail, silently.
I can, of course, echo to a file and then get the file, but I would prefer something smarter, along the lines of test tty && echo $1 (but tty invoked like this always returns false). Any suggestions are greatly appreciated.
The following command does what you want:
ssh -t user#host 'nohup ~/test.sh foo > nohup.out 2>&1 & p1=$!; tail -f ~/nohup.out & wait $p1'
... test.sh is located in the users home directory
Explanation:
1.) "ssh -t user#host " ... pretty clear ... starts remote session
2.) "nohup ~/test.sh foo > nohup.out 2>&1" ... starts the test.sh script with nohup in background
3.) "p1=$!;" ... stores the child pid of the previous command in p1
4.) "tail -f ~/nohup.out &" ... tail nohup.out in background to see the output of test.sh
5.) "wait $p1" ... waits for proccess test.sh (which pid is stored in p1) to finish
The above command works even if you interrupt it with ctrl+c.
you can use ...
ssh -t localhost "test.sh foo"
... to force a tty allocation
As st0ne suggested, tail fails, but does not cause the script to terminate, as opposed to cat and echo. So, there is no need for nohup, redirecting stdout to a temporary file, etc. just plain and simple:
mv test _test
sleep 10
echo $1 | tail
mv _test test
and execute it with:
ssh localhost "test.sh foo"
Here is what I'm entering in Terminal:
curl --silent https://raw.githubusercontent.com/githubUser/repoName/master/installer.sh | bash
The WordPress installing bash script contains a "read password" command that is supposed to wait for users to input their MySQL password. But, for some reason, that doesn't happen when I run it with the "curl githubURL | bash" command. When I download the script via wget and run it via "sh installer.sh", it works fine.
What could be the cause of this? Any help is appreciated!
If you want to run a script on a remote server without saving it locally, you can try this.
#!/bin/bash
RunThis=$(lynx -dump http://127.0.0.1/example.sh)
if [ $? = 0 ] ; then
bash -c "$RunThis"
else
echo "There was a problem downloading the script"
exit 1
fi
In order to test it, I wrote an example.sh:
#!/bin/bash
# File /var/www/example.sh
echo "Example read:"
read line
echo "You typed: $line"
When I run Script.sh, the output looks like this.
$ ./Script.sh
Example read:
Hello World!
You typed: Hello World!
Unless you absolutely trust the remote scripts, I would avoid doing this without examining it before executing.
It wouldn't stop for read:
As when you are piping in a way you are forking a child which has been given input from parent shell.
You cannot give the values back to parent(modify parent's env) from child.
and through out this process you are always in parent process.
I have a basic script that outputs various status messages. e.g.
~$ ./myscript.sh
0 of 100
1 of 100
2 of 100
...
I wanted to wrap this in a parent script, in order to run a sequence of child-scripts and send an email upon overall completion, e.g. topscript.sh
#!/bin/bash
START=$(date +%s)
/usr/local/bin/myscript.sh
/usr/local/bin/otherscript.sh
/usr/local/bin/anotherscript.sh
RET=$?
END=$(date +%s)
echo -e "Subject:Task Complete\nBegan on $START and finished at $END and exited with status $RET.\n" | sendmail -v group#mydomain.com
I'm running this like:
~$ topscript.sh >/var/log/topscript.log 2>&1
However, when I run tail -f /var/log/topscript.log to inspect the log I see nothing, even though running top shows myscript.sh is currently being executed, and therefore, presumably outputting status messages.
Why isn't the stdout/stderr from the child scripts being captured in the parent's log? How do I fix this?
EDIT: I'm also running these on a remote machine, connected via ssh using pseudo-tty allocation, e.g. ssh -t user#host. Could the pseudo-tty be interfering?
I just tried your the following: I have three files t1.sh, t2.sh, and t3.sh all with the following content:
#!/bin/bash
for((i=0;i<10;i++)) ; do
echo $i of 9
sleep 1
done
And a script called myscript.sh with the following content:
#!/bin/bash
./t1.sh
./t2.sh
./t3.sh
echo "All Done"
When I run ./myscript.sh > topscript.log 2>&1 and then in another terminal run tail -f topscript.log I see the lines being output just fine in the log file.
Perhaps the things being run in your subscripts use a large output buffer? I know when I've run python scripts before, it has a pretty big output buffer so you don't see any output for a while. Do you actually see the entire output in the email that gets sent out at the end of topscript.sh? Is it just that while the processes run you're not seeing the output?
try
unbuffer topscript.sh >/var/log/topscript.log 2>&1
Note that unbuffer is not always available as a std binary in old-style Unix platforms and may require a search and installation for a package to support it.
I hope this helps.