c++ program replace digits in a given number [closed] - linux

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How would you be able to replace digits in a given number using basic c++. Example if the number is 23444 and you want to take the old digit 4 and replace is with a new digit 5 to get a new number 23555.
I have some work done below but when I enter the inputs, it ends up giving me an incorrect result.
cout << "Enter the number: " << endl;
cin >> number;
cout << "Enter the old digit: " << endl;
cin >> oldDigit;
cout << "Enter the newDigit: " << endl;
cin >> newDigit;
newDigit=oldDigit;
cout << Newnum << endl;

Answer 1

You can convert int to char* using itoa() and iterate over it to
check does it contain number. If it does, get 4's position and replace
it with 5.
I know you didnt work with strings, but it can be helpful in your case.
Simple code:
#include <string.h>
#include <iostream>
#include <stdlib.h>
int main(){
int numer;
std::cin>>numer;
char* str;
itoa(numer, str, 10);
for(int i = 0; i < strlen(str); i++){
if(str[i] == '4') str[i]='5';
}
}

Answer 2

If I understand you correctly, you don't just want to simply add 111, you want to treat the number as a string, then change elements in the array. Is that correct?
This may get you on the right track:
Convert an int to ASCII character

Answer 3

if you really want to use only int to do this, here is a working example (base on some of your code)
#include <iostream>
using namespace std;
int replaceDig( int num, int oldDigit, int newDigit)
{
if(num==0)return 0;
int digit = num%10;
if(digit==oldDigit)digit = newDigit;
return replaceDig(num/10,oldDigit,newDigit)*10+digit;
}
int main()
{
int num, newnum, oldDigit, newDigit;
cout << "Enter the number: " << endl;
cin >> num;
cout << "Enter the old digit: " << endl;
cin >> oldDigit;
cout << "Enter the newDigit: " << endl;
cin >> newDigit;
newnum = replaceDig(num, oldDigit, newDigit);
cout << newnum << endl;
return newnum; //do you really want to return this?
}

Answer 4

I have come up with a solution . Don't know if it contains bug or not. Please let me know.
int num = 23444 ,new_num = 0;
int mod;
int exponent = 0;
/**
* Now form the new number
*/
while ( num > 0 ) {
mod = num % 10;
num /= 10;
if ( mod == 4 ) // check whether this is the old digit or not
new_num += 5 * pow( 10 , exp); // replace with new digit
else
new_num += mod * pow(10 , exp); // otherwise no change
exp++;
}
num = new_num;
std::cout << num;

Answer 5

I hope this works for you -
std::string s = std::to_string(23444);
std::replace( s.begin(), s.end(), '4', '5');
int num = std::stoi(s);

Answer 6

int replaceDig( int num, int oldDigit, int newDigit) // replacing the old digits in a number with a new digit
{
int position = numDigits(num);
int remainder = num;
int currentDigit;
while (remainder >0)
{
currentDigit=(num/pow(10,position))%10;
if(currentDigit==oldDigit)
{
num = num - oldDigit*pow(10,position);
num = num + newDigit*pow(10,position);
}
remainder = remainder/10;
position--;
}
}
This is the general idea, I guess. I didn't try to compile it though. And of course, this version isn't really optimized and we could find some more efficient ways of doing it. Oh, and it doesn't work with negative numbers, but this should be quite easy to adapt.