I have a script that I would like to run 60 seconds after initial system reboot and then every 10 minutes after that. I currently need two cron job listings to achieve this:
*/10 * * * * php myscript.php
#reboot /bin/sleep 60; php myscript.php
The first listing will run my cron job immediately after system boot and so I need to have the second listing to account for the on start wait time.
Is there anyway to combine the above two cron listings into one?
Related
I ran a cron job as ec2 user, in AWS server.
I set the cron command, like this
*/5 * * * * ec2-user bash ./dailyMailSend.sh
in crontab -e file.
It was set to run after every 5 minutes. But it runs every minute. Don't know why ?
For Amazon Linux use "0/5" instead of "*/5". This expression means every 5th minute from 0 through 59.
Next, do not specify relative paths in your crontab. Use only absolute paths.
I tried to set up the cron job any minute, I tried 3 different commands.
Any of them is not working.
Below is the error:
Run cron job every minute
The syntax is:
* * * * * /path/to/your/script > output
I have to schedule execution of a .sh file for every 5 hours 30 minutes. is it possible to configure this way in linux crontab.
This should work. Also make sure your shell script should have valid permissions to exeucte.
30 */5 * * * sh yourscript
Suppose, current time is 11:42 and i have setup one cron file to run at every 5 minutes.
Then this file will run at which time 11:47 or 11:45?
So basically i am trying to understand that how the cron timing is work?
Edit : it was ran at 11:45, but i don't know the reason behind it
Cron Configuration :
*/5 * * * * wget -O /dev/null http://XXX/index.php?r=controller/action
As you know, cron will run jobs at a specific time.
A cron job will not use the time it was started, only the configuration matters. This means a cron job set to every 5 minutes (like your */5 * * * *) will only ever run at times ending with 0 or 5 (eg: 12:00, 12:05, 12:10), regardless of the time you run it. This makes sense because we want to schedule a job for a specific time.
If you really need a job to run every 5 minutes, with an offset (eg: 11:42, 11:47, 11:52) you will have to give a list in the configuration.
instead of (*/5 * * * *) you would need to use:
(2,7,12,...,57 * * * *), filling ... with all the other numbers.
I want to set a cron run after an other cron. For example: Cron A finishs at 01:00 PM, cron B will start at 01:01 PM. The problem is I don't know when cron A finishs.
I checked the crontab syntax. It doesn't provide any param for that purpose.
My actual situation is:
# This cron must run first.
? ? * * * /usr/local/bin/php -f /path/select_and_print_to_log_file.php
# two these crons runs at the same time.
0 13 * * * /usr/local/bin/php -f /path/update_user.php
0 13 * * * /usr/local/bin/php -f /path/update_image.php
# This cron runs right after two above cron completes.
? ? * * * /usr/local/bin/php -f /path/select_and_print_to_log_file.php
You can use the batch command inside the first cron to have the second thing being scheduled to run.
Your first job could produce a timestamp when finished.
Then you estimate - for example - that job A needs about 60 to 90 minutes. After 60 minutes, you start job B. Job b looks for the timestamp. If it is present, job B starts, else it waits for a minute and looks again.
After finishing, job B deletes the timestamp, or renames it, maybe from 'todo' to 'done'. You could insert the current date inside the file, to check, whether your estimation is still acceptable, or should be adjusted.
What I do in such cases (commonly a backup scenario where I don't want to thrash the disk by having concurrent backups) is to write a script that cron calls, and in the script have the actual tasks run serially.
Something like:
#!/bin/bash
/usr/local/bin/php -f /path/update_user.php
/usr/local/bin/someOtherTaskToRunSecond
YMMV.