Hi everyone this is saikrishna. I need some help in linux shell scripts. I need to open the different types of files like mp3,mp4,jpg...etc and other extensions are existing in the same folder. I had tried "gnome" code for this but it opens only one file i needed to open all the files one after the other.
is it possible in linux.need help for it
You can list multiple files using ls and then use while to open them one by one:
ls *.mp3 | while read -r file; do xdg-open "$file"; done
see this answer for more details.
Related
I find myself in a situation similar to this question:
Linux: Overwrite all files in folder with specified data?
The answers there work nicely, however, they are for typed-out text. Allow me to provide context.
I have a Linux terminal which the following file structure: (with files & folders irrelevant to the question removed)
root/
empty.svg
svg/
257238.svg
297522.svg
a7yf872.svg
236y27fh.svg
38277.svg
... (~200 other .svg files with arbitrary names)
2903852.svg
The framework I am working with requires those .svg files to exist with those specific filenames, but obviously, it does not care about SVG image they contain. I do not plan on using such files and they take up a hefty amount of space on disk, so I wish to convert them all into empty SVGs, aka the empty.svg file on my root directory, which is a 12x12 transparent SVG file (124 bytes). This way the framework shouldn't error out like it did when I tried simply overwriting the raw data of those SVGs with plaintext using the answer of the question linked at the top of this question. I've tried many methods by trying to be creative with my basic Linux command-line knowledge but no success. How do I accomplish this?
TL;DR: How to recursively overwrite all files in a folder with the raw data of another file from Linux CLI?
Similar to the link, you can use tee command, but instead of echo use cat to copy file contents, where cat is the command to read the contents of the file.
cat empty.svg | tee svg/257238.svg svg/297522.svg <etc>
But if there are a lot of files in svg directory it will be useful to use loop to automate the previous command:
for f in svg/*; do
if [[ "$f" == *.svg ]]; then
cat empty.svg > "$f"
fi
done
Here we use pipes and redirections to connect commands and redirect previous command output.
I am looking to write a script to move files from a directory:
/home/mydir/
To another directory based on tokens in the file name. I have a bunch of files named as such:
red_office_mike_2015_montreal_546968.ext
or
$color_$location_$name_$year_$city_$numbers.extension (files will be various movie files: mov, mp4, mkv, etc.)
I would like the script to move the files to the following location:
/dir/work/$color/$name
Then verify the file has successfully copied, and delete the original file once it has.
I would also love it if the script would create the to directory if it does not already exist.
So in summary, I need a script to move files based on underscore separated tokens, create the to directory if it doesn't already exist, verify the successful copy (maybe with a size check), then delete the original file.
I am working on linux, and would prefer a bash script. The variables I have given are generic, and I will incorporate some other things to the script, I'm just looking for help on building the skeleton.
Thanks in advance for any help!
It's not a bash script, but perl is much better at this kind of thing and is installed on all Linux systems
while(<>) {
chomp;
$file = $_;
($colour, $location, $name, $year, $city, $numbers) = split(/_/,$file);
$dest0 = "/dir/work/$colour";
$dest1 = "$dest0/$name";
mkdir ($dest0) unless (-d $dest0);
mkdir ($dest1) unless (-d $dest1);
rename ($file, "$dest1/$file");
}
The script splits your input file on the underscore character, creates all the directories to the destination and then renames the file to the new filename. Rename takes care of all the copying and deleting for you. In fact it just changes the directory entries without any copying at all.
UPDATE
The above version takes its input from a file containing a list of filenames to process. For an alternative version which processes all files in the current directory, replace the while line with
while(glob("*")) {
I was able to fumble around online and come up with a for loop to do this task. I used cut and it made things simple. Here is what worked for me:
#!/bin/sh
cd "${1:-.}"
for f in *.*; do
color=`echo "$f" | cut -d'_' -f1`
name=`echo "$f" | cut -d'_' -f3`
todir="/dir/work/$color/$name"
mkdir -p "$todir"
mv "$f" "$todir"
done
This worked perfectly and I hope it can help others who might need to create directories based on portions of filenames.
The first line under the shebang made it so that it will either look at the current working directory or a directory you pass it as an argument.
Thanks to those who chimed in on the original post. I'm new with scripting so it take me a while to figure this stuff out. I love this site though, it is super helpful!
I used command zip in linux (RedHat), this is my command:
zip -r /home/username/folder/compress/zip.zip /home/username/folder/compressed/*
Then, i open file zip.zip, i see architecture as path folder compress.
I want to in folder zip only consist list file *.txt
Because i used this command in script crontab hence i can't use command cd to path folder before run command zip
Please help me
I skimmed the zip man page and this is what I have found. There is not an option archive files relative to a different directory. The closest I have found is zip -j which removes the entire path and stores the files directly in the zip rather than sub directories. I do not know what happens in the case of file name conflicts such as if /home/username/folder/compressed/a.txt and /home/username/folder/compressed/subdir/a.txt both exist. If this is not a problem for you, you can use this option, but I am concerned because you did specify the -r option indicating that you expect zip to traverse sub folders.
I also thought of the possibility that your script could somehow call zip with a different working directory, but I took a look at this unix stack exchange page and it looks like their options use cd.
I have to admit I do not understand why you cannot use cd and I am very curious about it. You said something about using crontab, but I have never heard of anything wrong with changing directories in a crontab script.
I used option -j in command zip
zip -jr /home/username/folder/compress/zip.zip /home/username/folder/compressed/*
and i was yet settled this problem, thanks
I need to download all 492 files from a Linux directory which contain a given String within the file. I can't quite manage to find a command which can accomplish this from my searching so far. Could anybody help me out?
Cheers.
Use grep to filter the files with a given string and loop over them to scp like this
for file in $(grep <some-pattern> <directory>); do scp $file <remote>; done;
Just in case if you need to filter out also the files in subdirectories of directory add the -R option to grep
I'm fairly new to Linux (CentOS in this case). I have a folder with about 2000 files in it. I'd like to ideally execute a command at the command prompt that would write out the name of all the files into a single txt file.
If I have to, I could write an actual program to do it too, I was just thinking there might be a way to simply do it from the command prompt.
you can just use
ls > filenames.txt
(usually, start a shell by using "Terminal", or "shell", or "Bash".) You may need to use cd to go to that folder first, or you can ls ~/docs > filenames.txt
If only names of regular files immediately contained within a directory (assume it's ~/dirs) are needed, you can do
find ~/docs -type f -maxdepth 1 > filenames.txt