I have a spreadsheet with different products, listing units and retail value sold like the example below
Product Units Value
A 10 100
B 15 80
C 30 560
I'd like to compare the Average Selling Price with the Median Selling price, so I am looking for a quick formula to accurately calculate the median.
The median function requires the entire series, so for Product A above I would need 10 instances of 10 etc. How can I calculate the Median quickly considering the condensed form of my data?
Without writing your own VBA function to do this there are a couple of approaches that can be taken.
The first expands the data from its compressed frequency count format to generate the full set of observations. This can be done manually or formulaically. On the assumption the latter is required, it can be achieved using a few columns.
All the blue cells are formulae.
Column Eis simply the cumulative of column B and F is an adjusted version of this. Column H is just the values 1 to 55, the total number of observations given by cell L2. Column I uses the MATCH() with its final argument as 1 to match each observation in H against the adjusted cumulative in F. Column J uses the INDEX() function to generate the value of the observation. (Observations 1-10 have value 100, 11-25 have value 80 and 26-55 have value 560 in this example). The MEDIAN() function is used in cell M2 with column J as its argument.
This approach can be refined to take account of varying numbers of products and data points through the use of the OFFSET function to control the range arguments of the MATCH(), INDEX() and MEDIAN functions. And, of course, adjacent cells in columns I and J could be combined using a single formula - I've shown them separately for ease of explanation.
The second approach involves sorting the data by value (so in this case the data rows would become Product B in row 2, product A in row 3 and product C left as-is in row 4). It is then a case of identifying the middle observation number (if the number of observations is odd) or the middle pair of observation numbers (if the number of observations is even) and then determining the value(s) corresponding to this/these middle observation(s). In this approach the adjusted cumulative in column F is still used but rather than explicitly calculating the values in column I and J for every observation it can now be restricted to just the middle observation(s).
I think there is no way around compromises. Either using big amounts of helper cells or having the table sorted by the values.
Helper cells:
Formula in F4:AS6:
=IF(COLUMN()<COLUMN($F$4)+$B4,$C4,"end")
Formula in D2:
=MEDIAN(F4:AS6)
Sorted:
Formula in F4 downwards:
=SUM($B$3:B3)+1
Formula in D2:
=SUM(LOOKUP(INT(SUM(B4:B6)/2+{0.5,1}),F4:F6,C4:C6))/2
Related
Imagine you have spreadsheet with data in a fixed # of contiguous rows.. let's say row 1 through row 20
Now let's say you have 3 columns of interest.
A, B and C
Column A is a label column.. the data in there are just string labels.. let's say types of canned food.. Tuna, Spam, Sardines, etc.
Column B is our number column.. let's say it is prices. e.g. 2 for Tuna, 5 for Spam and 3 for Sardines. These prices can change often very rapidly.. ok so prices are not the best example but let's imagine that prices change rapidly.
Now Column C is where we want to put the formula.
I would like to have a formula in Column C that will pull the labels from Column A, based on their prices in column B and rank them from highest to lowest.. that is C1 would calculate to "Spam", C2 to "Sardines" and C3 to "Tuna"
right now there are 20 rows of data.. but maybe at some other point there might be 30 or 6 or 40, etc.
So can someone help me out with the formula or at least explain what functions I need to use and the general idea involved? thanks
=IF(A2:A200<>"";SORTBY(A2:A200;B2:B200;-1);"")
You can simply use SORT formula. In this case =SORT(A1:B1000,2,-1) where A1:B1000 is range to be sorted, second parameter 2 is column number from range to sort by, 3rd parameter for order (-1 is desceding).
Place formula in C1 and you will get spilled array.
I am trying to create a formula that gives me the average of the last 12 entries in a given dataset depending on the associated vector.
Let's make an example:
I have in column F2,G2,H2 and I2 dates, Company1, Company2 and Company3 respectively. Then from row3 to row 33 I have months dates starting from May 2016.
Date Company1 Company2 Company3
May-16 2,453,845
Jun-16 13,099,823
Jul-16 14,159,037
Aug-16 38,589,050 8,866,101
Sep-16 63,290,285 13,242,522
Oct-16 94,005,364 14,841,793
Nov-16 123,774,792 7,903,600 41,489,883
Dec-16 93,355,037 12,449,604 69,117,105
Jan-17 47,869,982 13,830,712 83,913,764
Feb-17 77,109,905 10,361,555 68,176,643
The goal is to create a formula that, when I drag it down, correctly calculates the average of the last 12 values for a given company.
So for example i would have, say in table "B2:C5":
Company1 76,856,345
Company2 11,120,859
Company3 65,674,349
And, if a new Company4 is added to the list, then I just have to drag it down the formula, to calculate the average of the last 12 months for Company4.
Until now, I have came up with this formula:
=AVERAGE(LOOKUP(LARGE(IF(ISNUMBER(G:G),ROW(G:G)),ROW(INDIRECT("1:"&MIN(12,COUNT(G:G))))),ROW(G:G),G:G ))
This formula correctly calculates the average of a given column, considering only the last 12 values. The last step would be to come up with a formula that includes all the columns and then calculates the average for the given company.
Thanks!
I recommend that you use a named range to define your data in columns G:I. When a company is added, just modify the named range's specs. I used the name Target. Of course, you can replace it with $G:$I if you feel so inclined but I would rather recommend reducing the number of rows in the range, which is easier to manage when it is named.
Use the formula below to extract the company names from the first row of Target into the first column of your averages table. This is to ensure that the names are spelled identically in both locations.
=INDEX(Target,1,ROW()-2)
The number 2 indicates the number of rows above the row containing the formula. it is copied here from cell M3. There, ROW()-2 creates the number 1, counting sequentially as the formula is copied down.
Now I have the formula below in my cell N3 and copied down.
=SUM(INDEX(Target,0,MATCH($M3,INDEX(Target,1,0),0)))
The formula simply sums up the columns G, H, and I in 3 consecutive rows.
In the final step I inserted the range definition established above, meaning excluding the SUM() function, into your existing formula.
=AVERAGE(LOOKUP(LARGE(IF(ISNUMBER(INDEX(Target,0,MATCH($M3,INDEX(Target,1,0),0))),ROW(INDEX(Target,0,MATCH($M3,INDEX(Target,1,0),0)))),ROW(INDIRECT("1:"&MIN(12,COUNT(INDEX(Target,0,MATCH($M3,INDEX(Target,1,0),0))))))),ROW(INDEX(Target,0,MATCH($M3,INDEX(Target,1,0),0))),INDEX(Target,0,MATCH($M3,INDEX(Target,1,0),0))))
1) I have two tables. 1st table contains data for more then 20,000 rows and 2nd table I already have the following columns details i.e. Region, Item, Number and I just have to get the Total value of the product from the 1st table
2) There are two types of prices in the 1st table . One is Retail Price and Another one is a Wholesale price
3) In each of the regions Rep, Item and Numbers are same in most of the cases, but the Total price is different
4) I am able to get the Total price details in 2nd table through vlookup formula (After concatinating the following columns i.e. Region, Item and Number from both the tables) wherever there is an account number for retail price
5) Currently I am manually updating "Total Price" details in 2nd table for Wholesale price which is taking lot of time.
Is it possible to build a formula to get the wholesale price details in the 2nd table, since there are more then one account number, but the price is same
If the wholesale price is the lowest price for the specific item, then you can find it with the formulas MIN and IF.
Based on your screen shot:
D is the column with the list of items
I5 is the cell with the item name for which you want to find the wholesale price
F is the column with the list of prices
If you enter the following formula in cell K5, it should find the lowest price for pencils
=MIN(IF(D:D=I5,F:F))
On this link, there is an explanation if you want to use multiple criteria.
http://www.contextures.com/excelminmaxfunction.html
try the sumifs function.
It takes multiple arguments and criteria. So it should look something like:
cell value at j5 = sumifs(f3:f23, b3:b23, h5, d3:d23, i5....)
you need to mark off which rows in your first table are wholesale selling. So it should be a column of some kind. Once you do that, let's say in column G, then you add onto the sumifs function...
, g3:g23, L5)
What you're doing is summing up all of the values in column F where h5 (region) matches in b3:b23, i5 (item) match in d3:d23, and where L5 (retail type) match in a new column g2:g23.
This will find all of the values that match that criteria exactly.
Vlookup is useful, but it's harder to scale IMO than the advanced if functions.
SUMIFS is probably the better way to go on this one, but as an alternative there is also SUMPRODUCT.
=SUMPRODUCT(($H3=$B$3:$B$20004)*($I3=$D$3:$D$20004)*($J3=$E$3:$E$20004)*($F$3:$F$20004))
The * acts as an AND statement in a logical check, and each of the ($H3=$B$3:$B$20004) is a logical check. When the row is true it will evaluate to 1. When it is false it will evaluate to 0. in the end you wind up with a list of prices or 0s that get summed. The end result is the sum of everything that matches your criteria.
The danger of using this formula is that it can get labour intensive as it is performing array calculations without being an array formula.
For example, I need to create a merit list of few student based on total marks (column C), then higher marks in math (column B) -
A B C D
-------------------------
Student1 80 220 1
Student2 88 180 3
Student3 90 180 2
Expected merit position is given in column D.
I can use RANK function but I can only do that for one column (total number). If total number of multiple student is equal, I could not find any solution of this.
You can try this one in D1
=COUNTIF($C$1:$C$99,">"&C1)+1+SUMPRODUCT(--($C$1:$C$99=C1),--($B$1:$B$99>B1))
and then copy/fill down.
let me know if this helps.
Explanation
Your first criteria sits in column C, and the second criteria sits in Column B.
Basically, first it is counting the number of entries ($C$1:$C$99) that are bigger than the entry itself ($C1). For the first one in the ranking, you will get zero, therefore you need to add 1 to each result (+1).
Until here, you will get duplicate rankings if you have the same value twice. Therefore you need to add another argument to do some extra calculations based on the second criteria:
To resolve the tie situation, you need to sumproduct two array formulas and add the result to the previous argument, the goal is to find the number of entries that are equal to this entry with $C$1:$C$99=C1 and have a bigger value in the second criteria column $B$1:$B$99>B1:
you add -- to convert TRUE and FALSE to 0s and 1s so that you can multiply them:
SUMPRODUCT(--($C$1:$C$99=C1),--($B$1:$B$99>B1))
the first array is to see how many ties you have in the first criteria. And the second array is to find the number of bigger values than the entry itself.
Note you can add as many entries as you like to your columns, but remember to update the ranges in the formula, currently it is set to 99, you can extend it to as many rows as you want.
Sometimes a helper column will provide a quick and calculation-efficient solution. Adding the math marks to the total marks as a decimal should produce a number that will rank according to your criteria. In an unused column to the right, use this formula in row 2,
=C2+B2/1000
Fill down as necessary. You can now use a conventional RANK function on this helper column like =RANK(D2, D$2:D$9) for your ranking ordinals.
Very simple (or, at least, much more simpler that the one provided by the best answer) 'math' solution: do a linear combination with weights.
Do something like
weighted_marks = 10*colC + colB
then sort weighted marks using simple rank function.
It does solve your problem, bulding the ranking you need.
If you don't like to limit the number of rows or the numbers used in the criteria, Jeeped's approach can be extended. You can use the following formulas in cells D2 to L2, assuming that there are three criteria, the first one in column A, the second one in column B, and the third one in column C:
=RANK($A2,$A:$A,1)
=RANK($B2,$B:$B,1)
=D2*2^27+E2
=RANK(F2,F:F,1)
=RANK($C2,$C:$C,1)
=G2*2^27+H2
=RANK(I2,I:I,1)
=J2*2^27-ROW()
=RANK(K2,K:K,0)
The formulas have to be copied down. The result is in column L. Ties are broken using the row number.
If you like to add a fourth criterion, you can do the following after having the formulas above in place:
Add the new criterion between columns C and D.
Insert three new columns between columns I and J.
Copy columns G:I to the new columns J:L.
Copy column G to column M, overwriting its content.
Change the formula in column L to point to the new criterion.
The factor 2^27 used in the formulas balances the precision of 53 bits available in double-precision numbers. This is enough to cover the row limit of current versions of Excel.
I have two columns in a table that are known as S and D, where S is a date, and D is a duration.
E.g.:
'S' Column
January
February
March
April
'D' Column
60
30
45
30
On a separate sheet, imagine that Row 1 contains a sequence of dates (variable, depends on user menu selection).
Row 2 requires the following calculation:
[(x - s1)/d1 + (x-s2)/d2 + ... + (x-sn)/dn] / n
...where "x" is any date along Row 1.
The calculation would only be done when multiple criteria are matched.
My initial attempt involved creating a separate table, but I think this can be done in a one-cell formula in Row 2. I don't think a sum(index(match)) type would work here considering d1, d2, ..., dn are denominators with different values.
Here is an example attempt:
=SUM((SelectedDate-INDEX(Table[StartDates],MATCH(Criteria1&Criteria2,Range1&Range2,0))/INDEX(Table[Durations],MATCH(Criteria1&Criteria2,Range1&Range2,0))))
It may be important to note that I am able to do this in a two-step fashion. First, I create a table that does the calculation on each row. Then, I reference the table. It would be nice if I can eliminate the need of a "calculation table" in favour of an array-type formula.
I took a guess before most of the comments and suggest the following mainly in case it provides ay ideas or is of help in specifying the requirement more closely. This is "two-step" because the average formula is separate from that for each column, so I appreciate may well be not what is required.
Assuming S and D are labelled data in Sheet2 ColumnsA:B.
Assuming Row1 data rows are labelled in ColumnA.
Assuming dates are not strings (eg January is actually Jan 1) and the differences are in days and always positive, etc.
=(B$1-CHOOSE(COLUMN(),Sheet2!$A1,Sheet2!$A2,Sheet2!$A3,Sheet2!$A4))/CHOOSE(COLUMN(),Sheet2!$B1,Sheet2!$B2,Sheet2!$B3,Sheet2!$B4)
in Row2 to suit and if four data columns, in F2 and copied down to suit :
=AVERAGE(B2:E2)