I'm a student and I'm very new to bash, so any help is greatly appreciated!
I'm trying to rename a batch of files that look like this: local_date_1415+6556_0001.txt and local_date_1415+6556_0002.txt.
Example file name: uuw_07052006_1415+6556_0001.txt
I need the "1415+6556" section of each filename to have a 2M in front of it, like "2M1415+6556". About half the files in the folder already have the 2M, so I can't just search for the string and replace.
Is there a way to rename the batch of files using "_" as a delimiter so I could replace all the third sections entirely with the correct string?
I have the rename command on my machine, I'm just not sure how to use it here.
Using your version of rename:
rename _ % *_????+*.txt # replace the first underscore with a percent
rename _ _2M *_????+*.txt # add 2M after the second underscore
rename % _ *_2M????+*.txt # return the first underscore back
Only works if your filenames don't contain %. If they do, pick a different character.
You can also write the loop yourself:
#! /bin/bash
for f in *_????+*.txt ; do
before=${f%[0-9][0-9][0-9][0-9]+*}
after=${f#*_[0-9][0-9][0-9][0-9][0-9][0-9][0-9][0-9]}
mv "$f" "$before"2M"$after"
done
Related
I am trying to rename all files located in a directory (recursively) with a specific meta data field appended to the end of the png file name.
the meta data field name is "aesthetic_score" with a value range from 1.0-9.0
when I type:
exiftool -Aesthetic_score -G1 -s testn.png
the result is:
[PNG] Aesthetic_score : 7.0
This is how I would like to append the png files recursively within a directory.
Note i would like to swap out the word aesthetic with the word chad in the append, and not all files will have this data field:
input file:
filename001.png (metadata aesthetic_score:7.0)
output:
filename001-chad-score-70.png
I tried to use Digikam and JExifToolGui-2.01, without success.
I am trying to perform this task in the cmd line, although other solutions are welcome. Thank you for your help.
So, this might work for you, I can't really test it; note that you would need to get rid of the echo before the mv for it to actually do something (rename rather than just show what it would do).
while read name
do
newname=$(exiftool -G1 -s "$name"|awk '$2~/FileName/{name=$4}; $2~/Aesthetic_score/{basename=gensub(/^(.+)\....$/,"\\1","1",name);ext=gensub(/^.*\.(...)$/,"\\1","1",name);gsub(/\./,"",$4);print basename"."$4"."ext}')
echo mv "$name" "$newname"
done <<<$( find -iname \*.png )
Basically the find at the very end finds all the pngs.
The while loop takes every name find throws it, and passes each file through exiftool (using your specs) and parses the output using awk, which then outputs the new name, which gets captured in the shell variable by the same name.
And finally the mv (without the echo) renames the files.
In colab, I have unzip a file, but now there is too much files in the directory according to the colab's setup. Is there a command line to remove the last x files of a directory?
I know I can remove all the files from this repository with rm -rf *, but I just want to remove for instance the last 100 files of the repository.
Try globing or better REGEX.
The most easy way is with globing you use the star * and some differentiation example: rm *.txt # will delete all files that end with .txt or rm document*.local # will delete all files which start with document and end with .local
The better wey is searching files by attribut and executing command on the result but is a bit complex to explain so check this out.
https://www.cyberciti.biz/faq/linux-unix-how-to-find-and-remove-files/
Using a shell array and parameter expansion:
all_files=(*)
printf '%s\n' "${all_files[#]: -100}" | nl
#rm "${all_files[#]: -100}"
Uncomment the last line if it looks like the correct list of files to delete.
The space between the colon and the minus sign is required to disambiguate from another form of parameter expansion.
Ref: 3.5.3 Shell Parameter Expansion
I have a directory containing files following the following naming convention:
Label_0000_AA.gz
Label_0001_BB.gz
Label_0002_CC.gz
...
All I want to do is to rename these files so that the _#### number pattern is removed, resulting in:
Label_AA.gz
Label_BB.gz
Label_CC.gz
...
but only up to a certain number. E.g.: I may have 10000 files but might only want to remove the pattern in the first 3000. Would this be possible using something like bash?
If you don't have prename or rename -
(assuming the names are consistent)
for f in Label_[0-9][0-9][0-9][0-9]_[A-Z][A-Z].gz
do mv "$f" "${f//_[0-9][0-9][0-9][0-9]/}"
done
To just do a certain range -
for n in {0000..2999}
do for f in Label_${n}_??.gz
do mv $f ${f//_$n/}
done
done
You're sure there are not collisions?
If you can name the pattern you want to change/remove in a regex you can use the command prename:
prename 's/_[0-3][[:digit:]]{3}_/_/g' Label_*.gz
This regex would only remove numbers 0000-3999.
Using the flag -n does a "dry-run" and shows what it would do.
Edit: Thanks #KamilCuk to remind me about two renames. I made it clear and changed the name to prename.
Ok so I kinda dropped the ball. I was trying to understand how things work. I had a few html files on my computer that I was trying to rename as txt files. This was strictly a learning exercise. Following the instructions I found here using this code:
for file in *.html
do
mv "$file" "${file%.html}.txt"
done
produced this error:
mv: rename *.html to *.txt: No such file or directory
Long story short I ended up going rogue and renaming the html files, as well as a lot of other non html files as txt files. So now I have files labeled like
my_movie.mp4.txt
my_song.mp3.txt
my_file.txt.txt
This may be a really dumb question but.. Is there a way to check if a file has two extensions and if yes remove the last one? Or any other way to undo this mess?
EDIT
Doing this find . -name "*.*.txt" -exec echo {} \; | cat -b seems to tell me what was changed and where it is located. The cat -b part is not necessary but I like it. This still doesn't fix what I broke though.
I'm not sure if terminal can check for extensions "twice", but you can check for . in every name an if there's more than one occurence of ., then your file has more extensions. Then you can cut the extension off with finding first occurence of . in a string when going backwards... or last one if checking characters in string in a normal way.
I have a faster option for you if you can use python. You can strip the extension with:
for file in list_of_files:
os.rename(file,os.path.splitext(file)[0])
which can give you from your file.txt.txt your file.txt
Example:
You wrote that your command tells you what has changed, so just take those changed files and dump them into a file(path to file per line). Then you can easily run this:
with open('<path to list>') as f:
list_of_files = f.readlines()
for file in list_of_files:
os.rename(file.strip('\n'), os.path.splitext(file.strip('\n'))[0])
If not, then you'd need to get the list from python:
import os
results = []
for root, folder, filenames in os.walk(<your path to folder>):
for filename in filenames:
if filename.endswith('.txt.txt'):
results.append(os.path.join(root, filename))
With this you got a list of files ending with .txt.txt like this <your folder>\\<path_to_file>.
Get a path to your directory used in os.walk() without folder's name(it's already in list) so it'll be like this:
e.g. os.walk('/home/me/directory') -> path='/home/me/' and res is item already in a list, which looks like directory/...
for res in results:
path = '' # set the path here
file = os.path.join(path,r)
os.rename(file, os.path.splitext(file)[0])
Depending on what files you want to find change .txt.txt in if filename.endswith('...') to whatever you like and os.rename() will take file's name without extension which in your case means it strips the additional extension you don't want to have.
I need to rename hundreds of files in Linux to change the unique identifier of each from the command line. For sake of examples, I have a file containing:
old_name1 new_name1
old_name2 new_name2
and need to change the names from new to old IDs. The file names contain the IDs, but have extra characters as well. My plan is therefore to end up with:
abcd_old_name1_1234.txt ==> abcd_new_name1_1234.txt
abcd_old_name2_1234.txt ==> abcd_new_name2_1234.txt
Use of rename is obviously fairly helpful here, but I am struggling to work out how to iterate through the file of the desired name changes and pass this as input into rename?
Edit: To clarify, I am looking to make hundreds of different rename commands, the different changes that need to be made are listed in a text file.
Apologies if this is already answered, I've has a good hunt, but can't find a similar case.
rename 's/^(abcd_)old_name(\d+_1234\.txt)$/$1new_name$2/' *.txt
Should work, depending on whether you have that package installed. Also have a look at qmv (rename-utils)
If you want more options, use e.g.
shopt -s globstart
rename 's/^(abcd_)old_name(\d+_1234\.txt)$/$1new_name$2/' folder/**/*.txt
(finds all txt files in subdirectories of folder), or
find folder -type f -iname '*.txt' -exec rename 's/^(abcd_)old_name(\d+_1234\.txt)$/$1new_name$2/' {} \+
To do then same using GNU find
while read -r old_name new_name; do
rename "s/$old_name/$new_name/" *$old_name*.txt
done < file_with_names
In this way, you read the IDs from file_with_names and rename the files replacing $old_name with $new_name leaving the rest of the filename untouched.
I was about to write a php function to do this for myself, but I came upon a faster method:
ls and copy & paste the directory contents into excel from the terminal window. Perhaps you may need to use on online line break removal or addition tool. Assume that your file names are in column A In excel, use the following formula in another column:
="mv "&A1&" prefix"&A1&"suffix"
or
="mv "&A1&" "&substitute(A1,"jpeg","jpg")&"suffix"
or
="mv olddirectory/"&A1&" newdirectory/"&A1
back in Linux, create a new file with
nano rename.txt and paste in the values from excel. They should look something like this:
mv oldname1.jpg newname1.jpg
mv oldname1.jpg newname2.jpg
then close out of nano and run the following command:
bash rename.txt. Bash just runs every line in the file as if you had typed it.
and you are done! This method gives verbose output on errors, which is handy.