GET a website url when routing - node.js

Sorry, my vocabulary is very limited, any help clarifying this question is deeply appreciated.
I'm building a server using Nodejs and Express, it has a route like /new/:url. I access the value passed on the url by using req.params.url. This works well for simple strings, like chocolate, however, if I pass a website url, like http://www.google.com, then it won't be routed to /new/:url.
Question: how can I pass a website url and access it with Node/Express?
Edit: I am trying to use the GET method, and apparently a way to solve this problem is through Wildcards/Regex.
Thank you very much for helping!

Use Post method.
Set header "Content-Type" : "application/json"
Set body { "urlblahblah~" : "https://www.google.com" }
Then parse It as JSON in server-side

you can use Javascripts encodeURIComponent, so when you passing to your server on client, you will allsways encode the url, so you can pass it as regular parameter. or as mentioned by Hulk if posting is an options you can pass it as body param as well...
var url = encodeURIComponent("http://some.url/asdasa?asdas=12312")
will result in :
"http%3A%2F%2Fsome.url%2Fasdasa%3Fasdas%3D12312"
which is safe for passing as param

The solution that worked for me was Regex. Instead of routing as /new/:url, I used:
/new/:url(*)
So that if http://www.google.com is given as a parameter:
req.params.url = "http://www.google.com"

Related

Azure Logic App: how to make a x-www-form-encoded?

I'm trying to make a request with Content-Type x-www-form-urlencoded that works perfectly in postman but does not work in Azure Logic App I receive a Bad Request response for missing parameters, like I'd not send enything.
I'm using the Http action.
The body value is param1=value1&param2=value2, but I tried other formats.
HTTP Method: POST
URI : https://xxx/oauth2/token
In Headers section, add the below content-type:
Content-Type: application/x-www-form-urlencoded
And in the Body, add:
grant_type=xxx&client_id=xxx&resource=xxx&client_secret=xxx
Try out the below solution . Its working for me .
concat(
'grant_type=',encodeUriComponent('authorization_code'),
'&client_id=',encodeUriComponent('xxx'),
'&client_secret=',encodeUriComponent('xxx'),
'&redirect_uri=',encodeUriComponent('xxx'),
'&scope=',encodeUriComponent('xxx'),
'&code=',encodeUriComponent(triggerOutputs()['relativePathParameters']['code'])).
Here code is dynamic parameter coming from the previous flow's query parameter.
NOTE : **Do not forget to specify in header as Content-Type ->>>> application/x-www-form-urlencoded**
Answering this one, as I needed to make a call like this myself, today.
As Assaf mentions above, the request indeed has to be urlEncoded and a lot of times you want to compose the actual message payload.
Also, make sure to add the Content-Type header in the HTTP action with value application/x-www-form-urlencoded
therefore, you can use the following code to combine variables that get urlEncoded:
concat('token=', **encodeUriComponent**(body('ApplicationToken')?['value']),'&user=', **encodeUriComponent**(body('UserToken')?['value']),'&title=Stock+Order+Status+Changed&message=to+do')
When using the concat function (in composing), the curly braces are not needed.
First of all the body needs to be:
{ param1=value1&param2=value2 }
(i.e. surround with {})
That said, value1 and value2 should be url encoded. If they are a simple string (e..g a_b) then this would be find as is but if it is for exmaple https://a.b it should be converted to https%3A%2F%2Fa.b
The easiest way I found to do this is to use https://www.urlencoder.org/ to convert it. convert each param separately and put the converted value instead of the original one.
Here is the screenshot from the solution that works for me, I hope it will be helpful. This is example with Microsoft Graph API but will work with any other scenario:

Cannot GET (Passed url as parameter)

Can routes in express not take a full URL as a parameter?
For example,
router.get("/new/:url", <some function>);
gives me the Cannot GET error when the :url is https://www.google.com
You can't get full URL like this format.This type of format is used to take parameters send by client
router.get("/new/:url", <some function>);
//you can get url as params
req.params.url//Use your URL
You should encode url parameter before sending. Your example encoded would be Http%3A%2F%2Fwww.google.com. On server side you can decode parameter to get value from before.
I think you are not much aware about ExpressJS routing because your url https://www.google.com have // which is used route separation.
In you case, we know that ExpressJS support regex route. I think following regex will work for you
app.get("/new/:protocol(http:|https:|ftp:)?/?/:url", <some function>);
In above case, you have bunded with limited protocol http, https and ftp. You may add more protocol by using | separator( or condition) and even you don't know what would be protocol then you like following
app.get("/new/:protocol?/?/:url", <some function>);
In above both route, ? means option that routes works file for
/new/www.google.com
/new/https://www.google.com
and in your function, you may append protocol in url like
function newUrl(req, res) {
if(req.params.protocol)
req.params.url = req.params.protocol + '//' + req.params.url;
console.log(req.params.url);
}

Get params using ExpressJS

I'd like to get a specific param using ExpressJS with "#" instead of "?" in the url...
My URL :
http://localhost:3000/#access_token=LMkdfkdmsklmfdkslklmdskfmsda
I'd like to get "access_token" and "req.params.access_token" doesn't work...
Anthony
Short answer: you can't.
Longer answer: fragment identifiers (that's the part after the #) are supposed to be evaluated on the client and are not supposed to be sent to server. Your express app has no way of knowing them.
You could try to convert them to query parameters or path variables (i.e. by handling fragment identifier change in javascript) to make them visible server-side.

Node.js : Express app.get with multiple query parameters

I want to query the yelp api, and have the following route:
app.get("/yelp/term/:term/location/:location", yelp.listPlaces)
When I make a GET request to
http://localhost:3000/yelp?term=food&location=austin,
I get the error
Cannot GET /yelp?term=food&location=austin
What am I doing wrong?
Have you tried calling it like this?
http://localhost:30000/yelp/term/food/location/austin
The URL you need to call usually looks pretty much like the route, you could also change it to:
/yelp/:location/:term
To make it a little prettier:
http://localhost:30000/yelp/austin/food
In the requested url http://localhost:3000/yelp?term=food&location=austin
base url/address is localhost:3000
route used for matching is /yelp
querystring url-encoded data is ?term=food&location=austin i.e. data is everything after ?
Query strings are not considered when peforming these matches, for example "GET /" would match the following route, as would "GET /?name=tobi".
So you should either :
use app.get("/yelp") and extract the term and location from req.query like req.query.term
use app.get("/yelp/term/:term/location/:location") but modify the url accordingly as luto described.
I want to add to #luto's answer. There is no need to define query string parameters in the route. For instance the route /a will handle the request for /a?q=value.
The url parameters is a shortcut to define all the matches for a pattern of route so the route /a/:b will match
/a/b
/a/c
/a/anything
it wont match
/a/b/something or /a
Express 4.18.1 update:
using app.get("/yelp/term/:term/location/:location"), your query string can be yelp/term/food/location/austin
So your request url will look like this:
http://localhost:3000/yelp/term/food/location/austin

ExpressJS Route Parameter with Slash

Im using ExpressJS. I want pass url as parameter.
app.get('/s/:url', function(req, res) {
console.log(req.params.url);
});
/s/sg.com //sg.com
/s/www.sg.com //www.sg.com
/s/http://sg.com //http://sg.com
/s/http://sg.com/folder //http://sg.com/folder
How to correct the route such that everything afterr /s/ will be considered as paramenter including slashes.
Thanks
Uh, if you want to stick a URL inside of another URL, you need to URLencode it. If you want to stick one in their raw and suffer the consequences, just use app.get('/s/*'... and then manually parse out the url with req.url.slice(3). But hear me know and believe me later, URL Encoding is the right way to do this via the encodeURIComponent that is built in to JavaScript and works in both the browser and node.js.

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