Q1. Wanted to know how do you read the contents of a file to a variable at boot time in grub.cfg?
Q2. Could that be extended to read an .ini type file where you can read the values for various name entries?
[section]
nothisone=whatever
thisone=this is what I want to get
TIA!!
In order to do exactly what you are asking for, you would probably need to write your own GRUB module.
However, you should be able to achieve what you're after either using the configfile command, or with some clever application of the environment block feature.
Use "source" command to include another config file but unlike "configfile" which will change context.
Source is like an online macro while configfile likes a function - environment changes in configfile will not be preserved but source is expanding whatever in the source file and put in the main block, environment variable can be changed in this way.
https://www.gnu.org/software/grub/manual/grub/grub.html#source
https://www.gnu.org/software/grub/manual/grub/grub.html#configfile
Related
I wanted to create a job where I need to consider the latest file available as input file.
File format is as below: FILE1.TEST.TYYMMDD
is there any way to identify latest file based on date present in file name via JCL.
P.S. GDG versions are not created in existing process . Only PS file is created.
Thank you
I wanted to create a job where I need to consider the latest file available as input file. File [name] format is as below: FILE1.TEST.TYYMMDD is there any way to identify latest file based on date present in file name via JCL.
No.
You indicate that GDGs are not created in the existing process. GDGs would be the best way to accomplish your goal. Absent GDGs, you must write code.
You could accomplish your goal by writing (C, clist, COBOL, PL/I, Rexx) code using the LMDINIT and LMDLIST ISPF services. Then you would execute your code by running ISPF in batch. Many mainframe shops have a cataloged procedure to execute ISPF in batch.
Agree with #cschneid that there is not a platform way to handle this. However, I want to point out that GDGs are the platform way of managing PS files for access in a relative form.
Your comment
GDG versions are not created in existing process . Only PS file is
created.
That statement didn't make sense to me. GDGs are not a file type like physical sequential (PS) or partitioned (PO). It's a convention to allow relative reference to files created over time which sounds like what you want. I've only seen the use of GDGs for PS files.
Putting the date in the file name can have its uses but to z/OS its only part of the filename and not meta information that it operates on (like G0000v00's in GDGs.
I use an sh script to start an application in the background after setting several environment variables. I use temporary variables to start binaries from different places using LD_LIBRARY_PATH and temporary variables. Problem is that the application loads one *.so file from a hardcoded path which I cannot change. Currently I solve this problem manually by replacing the hardcoded file location with a symbolic link.
Can you tell me if there is a clean solution to solve this from the sh script? Basically what I want is that a certain file location is switched with a different binary only for open calls from the application the script starts, for all other processes it should stay the same.
Regards.
Example methods to replace open("/the/original") with open("/some/other"):
One simple method is modifying a pathname within an executable.
First copy the original executable to something like "modified" and run
a utility like bvi (similar to vim).
Consider 2 cases from comparing the length of the new vs. original pathnames:
when (new-length <= original-length), overwrite the original pathname in place
when (new-length > original-length), create a short symlink that references
the new longer pathname like the example below, then overwrite the original pathname
with the short symlink pathname,
ln -s /full/path/some/new/file /shorter
For both cases, remember to include a trailing NULL byte.
After saving changes with bvi, test the newly copied+altered executable.
Once "modified" is working to plan, could also rename for convenience:
mv xyz xyz.orig
mv modified xyz
Another method can serve a transparency requirement.
Create a dynamic library (eg custom.so) with a wrapper routine for
open() which conditionally replaces the pathname and calls the real
libc open(). Run the unmodified original executable (xyz) with another
environment variable, eg:
LD_PRELOAD=/path/to/custom.so xyz
There are some tradeoffs with versatility and modest complexity;
the original xyz is left unchanged and can always be run with/without LD_PRELOAD;
some might consider added overhead from a wrapper as undesirable;
doesn't work with statically-linked or set-uid executables.
Many articles provide instructions for creating a preload library, re-using
an original symbol like open() (frequent example is malloc()), call dlsym() once to find the regular libc open(), saving the result as a function pointer, and calling libc open() indirectly.
I need to load XXXX named dat file everyday in Oracle database. But thing is, I need to read simila file with timestamp like: XXXX20191120.dat
Is it possible to create such a configuration in .ctl that INFILE '/blaa/blaa/blaa/XXXXX20191120.dat' part is possible to different in each day ? If so, please example.
If this has to be done with separate shell script, please example.
Thank you all
If you need to use a different filename each time, don't put it in the ctl file, use the command line parameter DATA e.g.
data=/bla/bla/xxxxx20191121.dat
look at the doc, I gave the 12.1 ref as you did not specify which version you're using.
I am using the latest version of pyRevit, v45.
I'm writing some info in temporary files with
myTempFile = script.get_instance_data_file("id")
This creates a file named pyRevit_2018_xxxx_id.tmp in which I store useful info. If I'm not mistaken, the "xxxx" part is changing every time I reload Revit. Now, I need to get access to this information from another pyRevit script.
How can I retrieve the name of the temp file I need to read? In other words, how do I access "myTempFile" from within the second script, which has no idea of the name of "myTempFile"?
I guess I can share somehow that variable between my script, but what's the proper way to do this? I know this must be a very basic programming question, but I'm indeed not a programmer ;)
Thanks a lot,
Arnaud.
Ok, I realise now that my variables in the 1st script cease to exist after its execution.
So for now I wrote the file name in another file, of which I know the name.. That works.
But if there's a cleaner way to do this, I'd be glad to learn ;)
Arnaud
pyrevit.script module provides 4 different methods for creating temporary files based on their use case:
get_instance_data_file:
for data files marked with Revit instance pid. This means that scripts running on another instance will not see this temp file.
http://pyrevit.readthedocs.io/en/latest/pyrevit/script.html#pyrevit.script.get_instance_data_file
get_universal_data_file:
for temp files accessible to all Revit instances and versions
http://pyrevit.readthedocs.io/en/latest/pyrevit/script.html#pyrevit.script.get_universal_data_file
get_data_file:
Base method to get a standard temp file for current revit version
http://pyrevit.readthedocs.io/en/latest/pyrevit/script.html#pyrevit.script.get_data_file
get_document_data_file:
temp file marked with active document (so scripts working on another document will not see this)
http://pyrevit.readthedocs.io/en/latest/pyrevit/script.html#pyrevit.script.get_document_data_file
Each method uses a pattern to create the temp file name. So as long as the call to the method is the same of different scripts, the method generates the same file name.
Example:
Script 1:
from pyrevit import script
tfile = script.get_data_file('mydata')
Script 2:
from pyrevit import script
tempfile = script.get_data_file('mydata')
In this example tempfile = tfile since the file id is the same.
There is documentation on each so make sure you take a look at those and pick the flavor that serves your purpose.
I know puppet modules always have a files directory and I know where it's supposed to be and I have used the source => syntax effectively from my own, handwritten modules but now I need to learn how to deploy files using Hiera.
I'm starting with the saz-sudo module and I've read the docs but I can't see anything about where to put the sudoers file; the one I want to distribute.
I'm not sure whether I need to set up a site-wide files dir in /etc/puppetlabs/puppet and then make subdirs in there for every module or what. And does Hiera know to look in /etc/puppetlabs/puppet/files/sudo if I say, source => "puppet:///files/etc/sudoers" ? Do I need to add a pathname in /etc/hiera.yaml? Add a line - files ?
Thanks for any clues.
My cursory view of the puppet module, given their example of using hiera:
sudo::configs:
'web':
'source' : 'puppet:///files/etc/sudoers.d/web'
'admins':
'content' : "%admins ALL=(ALL) NOPASSWD: ALL"
'priority' : 10
'joe':
'priority' : 60
'source' : 'puppet:///files/etc/sudoers.d/users/joe'
Suggest it assumes you have a "files" puppet module. So under you puppet modules section:
mkdir -p files/files/etc/sudoers.d/
Drop your files in there.
Explanation:
The url 'puppet:///files/etc/sudoers.d/users/joe' is broken down thus:
puppet: protocol
///: Three slashes indicate the source of the file is in a module.
files: name of the module
etc/sudoers.d/users/joe: full path to the file within the module's "files" directory.
You don't.
The idea of a module (Hiera backed or not) is to lift the need to manage the whole sudoers file from you. Instead, you can manage each single entry in the sudoers file.
I recommend reviewing the documentation carefully. You should definitely not have a file { "/etc/sudoers": } resource in your manifest.
Hiera doesn't have to do anything with Files.
Hiera is like a Variables Database, and servers you based on the hierarchy you have.
the files inside puppet, are usually accessed in methods like source => but also these files are using some basic structure.
In most cases when you call an file or template.
A template can serve your needs to automatically build an sudoers based on that.
There are also modules that supports modifying sudoers too.
It is up to you what to do.
In this case, saz stores the location of the file in hiera, but the real location can be a file inside your puppet (like a module file or something similar).
Which is completely unrelated.
Read about puppet file server
If you have questions, just ask.
V