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I just started to learn linux.
What I wanna do is to write a bash script that prints the file name, the number of lines, and the number of words to stdout, for all files in the directory
for example: Apple.txt 15 155
I don't know how to write a command that can work for all the files in the directory.
Based on your most recent comment, I would say you want something like:
wc -lw ./* | awk '{print $3 "\t" $1 "\t" $2}'
Note that you will get a line in the output (from stderr) for each directory that looks something like:
wc: ./this-is-a-directory: Is a directory
If the message about directories is undesirable, you can suppress stderr messages by adding 2>/dev/null to the wc command, like this:
wc -lw ./* 2>/dev/null | awk '{print $3 "\t" $1 "\t" $2}'
Try this:
wc -lw ./*
It will be in the format of <lines> <words> <filename>.
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How to get from a file exactly what I want in Linux?
I have: 123456789012,refid2141,test1,test2,test3 and I want this: 123456789012 or 123456789012 test3.
$ echo "123456789012,refid2141,test1,test2,test3" | awk -F "," '{print $1}'
123456789012
$ echo "123456789012,refid2141,test1,test2,test3" | awk -F "," '{printf("%s, %s", $1,$5)}'
123456789012, test3
foo.csv:
123456789012,refid2141,test1,test2,test3
import csv
with open("foo.csv", "rt") as fd:
data = list(csv.reader(fd))
print(data[0][0])
For a bash solution:
cat foo.csv | cut -d',' -f1
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Specify a command / command set that displays the number of lines of code in the .c and .h files in the current directory, displaying each file in alphabetical order followed by ":" and the number of lines in the files, and finally the total of the lines of code.
An example that might be displayed would be :
test.c: 202
example.c: 124
example.h: 43
Total: 369
I'd like to find a solution in the shortest form possible. I've experimented many commands like:
find . -name '*.c' -o -name '*.h' | xargs wc -l
== it shows 0 ./path/test.c and the total, but isn't close enough
stat -c "%n:%s" *
== it shows test.c:0, but it shows all file types and doesn't show the number of lines or the total
wc -l *.c *.h | tr ' ' '\:
== it shows 0:test.c and the total, but doesn't search in sub-directories and the order is reversed compared to the problem (filename: number_of_lines).
This one is closer to the answer but I'm out of ideas after searching most commands I saw in similar problems.
This should do it:
wc -l *.c *.h | awk '{print $2 ": " $1}'
Run a subshell in xargs
xargs -n1 sh -c 'printf "%s: %s\n" "$1" "$(wc -l <"$1")"' --
xargs -n1 sh -c 'echo "$1 $(wc -l <"$1")"' --
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I have a text file with the following format.
12345
abcdefg
I need this to be in the same line. So the output should look like this...
12345 abcdefg
How should i proceed ? using sed or awk ?
If you want to join every line[i] and line[i+1] with a space,
you could use paste:
paste -d' ' - - < file
For given input and expected output below one should work
Using xargs
$ cat infile
12345
abcdefg
$ xargs < infile
12345 abcdefg
Using tr
$ tr -s '\n' ' ' <infile ; echo
12345 abcdefg
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There is a line:
00000000000000;000022233333;2;NONE;true;100,100,5,1,28;UNKNOWN
It is necessary to sort 100,100,5,1,28 numbers in descending order.
Example:
00000000000000;000022233333;2;NONE;true;100,100,28,5,1;UNKNOWN
try this;
#!/bin/bash
while read line
do
beforeC=$(echo "$line" | cut -f-5 -d';')
sortcolumn=$(echo "$line" | awk -F ";" '{print $6}' | tr -t , "\n" | sort -r -n | xargs | sed 's/ /,/g')
afterC=$(echo "$line" | cut -f7- -d';')
echo -e $beforeC";"$sortcolumn";"$afterC
done <file
user#host:/tmp/test$ cat file
00000000000000;000022233333;2;NONE;true;100,100,5,1,28;UNKNOWN
00000000000000;000022233333;2;NONE;true;99,100,5,1,28;UNKNOWN
00000000000000;000022233333;2;NONE;true;100,99,5,1,28;UNKNOWN
00000000000000;000022233333;2;NONE;true;100,100,4,1,28;UNKNOWN
00000000000000;000022233333;2;NONE;true;100,100,4,0,28;UNKNOWN
00000000000000;000022233333;2;NONE;true;100,100,4,1,27;UNKNOWN
user#host:/tmp/test$ ./sortAColumn.sh
00000000000000;000022233333;2;NONE;true;100,100,28,5,1;UNKNOWN
00000000000000;000022233333;2;NONE;true;100,99,28,5,1;UNKNOWN
00000000000000;000022233333;2;NONE;true;100,99,28,5,1;UNKNOWN
00000000000000;000022233333;2;NONE;true;100,100,28,4,1;UNKNOWN
00000000000000;000022233333;2;NONE;true;100,100,28,4,0;UNKNOWN
00000000000000;000022233333;2;NONE;true;100,100,27,4,1;UNKNOWN
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So, I have about 60k-70k vCard-Files and want to check (or, at this point, count), which vCards contain a mail address (EMAIL;INTERNET:me#my-domain.com)
I tried to pass the output of find to awk, but I just get awk to work with the files list, not with every files content. How can I get awk to do so? I tried several combinations of find, xargs and awk, but I don't get it to work properly.
Thanks for your help,
Wolle
I'd probably use grep for this.
If you want to extract adresses from the files:
grep -rio "EMAIL;INTERNET:.*#[a-z0-9-]*\.[a-z]*" *
Use cut, sed or awk to remove the leading EMAIL;INTERNET::
... | cut -d: -f2
... | sed "s/.*://"
... | awk -F: '{print $2}'
If you want the names of the files containing a particular address:
grep -ril "EMAIL;INTERNET:me#my-domain\.com" *
If grep can't process that many files at once, drop the -r option and try with find and xargs:
find /start/dir -name "*.vcf" -print0 | xargs -0 -I {} grep -io "..." {}
grep recursive can do this
grep -r 'EMAIL.+#'