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I have a text file with the following format.
12345
abcdefg
I need this to be in the same line. So the output should look like this...
12345 abcdefg
How should i proceed ? using sed or awk ?
If you want to join every line[i] and line[i+1] with a space,
you could use paste:
paste -d' ' - - < file
For given input and expected output below one should work
Using xargs
$ cat infile
12345
abcdefg
$ xargs < infile
12345 abcdefg
Using tr
$ tr -s '\n' ' ' <infile ; echo
12345 abcdefg
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How to get from a file exactly what I want in Linux?
I have: 123456789012,refid2141,test1,test2,test3 and I want this: 123456789012 or 123456789012 test3.
$ echo "123456789012,refid2141,test1,test2,test3" | awk -F "," '{print $1}'
123456789012
$ echo "123456789012,refid2141,test1,test2,test3" | awk -F "," '{printf("%s, %s", $1,$5)}'
123456789012, test3
foo.csv:
123456789012,refid2141,test1,test2,test3
import csv
with open("foo.csv", "rt") as fd:
data = list(csv.reader(fd))
print(data[0][0])
For a bash solution:
cat foo.csv | cut -d',' -f1
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Below I shared my console. I want to cut some string from output of some commands.
But there are 17 extra chars which I have no idea where comes from.
Can someone pls explain to me?
$ ls -al | grep total | sed 's/[[:blank:]].*$//' | wc -m
23
$ ns="total"
$ echo $ns | sed 's/[[:blank:]].*$//' | wc -c
6
But there are 17 extra chars which I have no idea where comes from.
Those are ANSI escape codes that grep uses for coloring matching substrings. You probably have an alias (run alias | grep grep to examine) like
alias grep='grep --color=always'
somewhere that causes grep to color matches even if output is not a tty, or something similar.
Try
ls -al | grep --color=never total | sed 's/[[:blank:]].*$//' | wc -m
and you'll get six.
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There is a line:
00000000000000;000022233333;2;NONE;true;100,100,5,1,28;UNKNOWN
It is necessary to sort 100,100,5,1,28 numbers in descending order.
Example:
00000000000000;000022233333;2;NONE;true;100,100,28,5,1;UNKNOWN
try this;
#!/bin/bash
while read line
do
beforeC=$(echo "$line" | cut -f-5 -d';')
sortcolumn=$(echo "$line" | awk -F ";" '{print $6}' | tr -t , "\n" | sort -r -n | xargs | sed 's/ /,/g')
afterC=$(echo "$line" | cut -f7- -d';')
echo -e $beforeC";"$sortcolumn";"$afterC
done <file
user#host:/tmp/test$ cat file
00000000000000;000022233333;2;NONE;true;100,100,5,1,28;UNKNOWN
00000000000000;000022233333;2;NONE;true;99,100,5,1,28;UNKNOWN
00000000000000;000022233333;2;NONE;true;100,99,5,1,28;UNKNOWN
00000000000000;000022233333;2;NONE;true;100,100,4,1,28;UNKNOWN
00000000000000;000022233333;2;NONE;true;100,100,4,0,28;UNKNOWN
00000000000000;000022233333;2;NONE;true;100,100,4,1,27;UNKNOWN
user#host:/tmp/test$ ./sortAColumn.sh
00000000000000;000022233333;2;NONE;true;100,100,28,5,1;UNKNOWN
00000000000000;000022233333;2;NONE;true;100,99,28,5,1;UNKNOWN
00000000000000;000022233333;2;NONE;true;100,99,28,5,1;UNKNOWN
00000000000000;000022233333;2;NONE;true;100,100,28,4,1;UNKNOWN
00000000000000;000022233333;2;NONE;true;100,100,28,4,0;UNKNOWN
00000000000000;000022233333;2;NONE;true;100,100,27,4,1;UNKNOWN
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I just started to learn linux.
What I wanna do is to write a bash script that prints the file name, the number of lines, and the number of words to stdout, for all files in the directory
for example: Apple.txt 15 155
I don't know how to write a command that can work for all the files in the directory.
Based on your most recent comment, I would say you want something like:
wc -lw ./* | awk '{print $3 "\t" $1 "\t" $2}'
Note that you will get a line in the output (from stderr) for each directory that looks something like:
wc: ./this-is-a-directory: Is a directory
If the message about directories is undesirable, you can suppress stderr messages by adding 2>/dev/null to the wc command, like this:
wc -lw ./* 2>/dev/null | awk '{print $3 "\t" $1 "\t" $2}'
Try this:
wc -lw ./*
It will be in the format of <lines> <words> <filename>.
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How can extract only "name" and "available space" from df linux command.
You can use...
df | tail -n +2 | awk '{ print $1, $4 }'
...assuming you don't want the headers too. If you do, remove the tail.
We are piping df's output into tail, where we cut the first line off (the headers), and then pipe that into awk, using it to print the first and fourth columns.
Assuming name and available space are 1st and 4th columns:
df | awk '{print $1, $4}'
the traditional approach would be
df | awk '{printf "%-15s%-8s\n",$1,$5}'