I want to remove the \n (line break) from a string with python
from bs4 import BeautifulSoup
"""
<div class="thecontent" itemprop="description"><p>Kidney stone are painful and often recurring issue that can last for weeks at a time. They are affecting around 10% of the population mostly men between ages 30 and 40. </p>\n
<h4><strong>7. Get Your Fiber</strong></h4>\n
<p>Many vegetable protein sources also have the benefit of being great sources of insoluble fiber – another effective remedy for halting the growth of existing kidney stones and preventing the formation of new ones. </p>\n
<p>While many fruits and vegetables are excellent sources of fiber, be aware that they may also contain high...</p>
</div>
"""
def get_article(html):
soup = BeautifulSoup(html, "html.parser")
e = soup.find('div', class_='thecontent').replace('\n', ' ')
print(e)
I get this error:
e = soup.find('div', class_='thecontent').replace('\n', ' ')
TypeError: 'NoneType' object is not callable
Same things with strip method
or you can put the string into a column of a dataframe, and use a simple for loop regular expression.
don't forget to put extra backslash like this: \\n, because otherwise it wouldn't work.
df['textInColumn'] = store your string here
def replaceNN(text):
res = []
for sub in text:
res.append(sub.replace("\\n", ""))
text = res
return text
df['textInColumn'] = replaceNN(df['textInColumn'])
Related
I'm trying to create a metadata scraper to enrich my e-book collection, but am experiencing some problems. I want to create a dict (or whatever gets the job done) to store the index (only while testing), the path and the series name. This is the code I've written so far:
from bs4 import BeautifulSoup
def get_opf_path():
opffile=variables.items
pathdict={'index':[],'path':[],'series':[]}
safe=[]
x=0
for f in opffile:
x+=1
pathdict['path']=f
pathdict['index']=x
with open(f, 'r') as fi:
soup=BeautifulSoup(fi, 'lxml')
for meta in soup.find_all('meta'):
if meta.get('name')=='calibre:series':
pathdict['series']=meta.get('content')
safe.append(pathdict)
print(pathdict)
print(safe)
this code is able to go through all the opf files and get the series, index and path, I'm sure of this, since the console output is this:
However, when I try to store the pathdict to the safe, no matter where I put the safe.append(pathdict) the output is either:
or
or
What do I have to do, so that the safe=[] has the data shown in image 1?
I have tried everything I could think of, but nothing worked.
Any help is appreciated.
I believe this is the correct way:
from bs4 import BeautifulSoup
def get_opf_path():
opffile = variables.items
pathdict = {'index':[], 'path':[], 'series':[]}
safe = []
x = 0
for f in opffile:
x += 1
pathdict['path'] = f
pathdict['index'] = x
with open(f, 'r') as fi:
soup = BeautifulSoup(fi, 'lxml')
for meta in soup.find_all('meta'):
if meta.get('name') == 'calibre:series':
pathdict['series'] = meta.get('content')
print(pathdict)
safe.append(pathdict.copy())
print(safe)
For two main reasons:
When you do:
pathdict['series'] = meta.get('content')
you are overwriting the last value in pathdict['series'] so I believe this is where you should save.
You also need to make a copy of it, if you don´t it will change also in the list. When you store the dict you really are storing a reeference to it (in this case, a reference to the variable pathdict.
Note
If you want to print the elements of the list in separated lines you can do something like this:
print(*save, sep="\n")
I want to get the count of any phrase appearing in a URL, say https://en.wikipedia.org/wiki/India.
import requests
from bs4 import BeautifulSoup
url = 'https://en.wikipedia.org/wiki/India'
r = requests.get(url)
soup = BeautifulSoup(r.text,'lxml')
Now, I want to get the count of the phrase India is a in the soup. How to go about this?
Please suggest.
This can be done in one of two ways.
First, the common denominator:
texts = soup.find_all(text=True)
cleaned = ["".join(t.strip()) for t in texts]
counter=0
Now, if you want to use regex:
import re
regex = re.compile(r'\bIndia is a\b')
for c in cleaned:
if regex.match(c) is not None:
counter+=1
I, personally, don't like using regex except as last resort, so I would go the longer way
phrase = 'India is a'
for c in cleaned:
if phrase==c or phrase+' ' in c:
counter+=1
In both cases, print(counter) outputs 6.
Note that, intentionally, these do not count the 3 situations where the phrase is part of a larger phrase (such as India is also); it counts only the exact phrase or the phrase followed by a space.
I tried below and the same worked fine:
import re
import requests
url = 'https://en.wikipedia.org/wiki/India'
response = requests.get(url)
response_text = response.text
keyword = 'India is a'
match = re.findall("%s" % keyword, response_text)
count = (len(match))
count
Output is 9.
This code will look into <head>, <body> and elsewhere.
I am trying to print out different things from a Norwegian weather site with beautifulsoup.
I manage to print out everything i want except one thing witch mentions how the weather will be the next hour.
This contains the text i want to get:
<span class="nowcast-description" data-reactid="59">har opphold nå, det holder seg tørt den neste timen</span>
And i am trying print it with this:
cond = soup.find(class_='nowcast-description').get_text()
Inspected elements from storm.no/ski
Here is a picture of the some of the elements on the site.
with printing these:
soup = bs4.BeautifulSoup(html, "html.parser")
loc = soup.find(class_='info-text').get_text()
cond = soup.find(class_='nowcast-description').get_text()
temp = soup.find(class_='temperature').get_text()
wind = soup.find(class_='indicator wind').get_text()
also tested with this line:
cond = soup.select("span.nowcast-description")
but that gives me everything except what i want from the line.
Site link: https://www.storm.no/ski
i get:
Ski Akershus, 131 moh.
""
2°
3 m/s
It is retrieved dynamically from a script tag. You can regex out object containing all forecasts and handle with hjson library due to unquoted keys. You need to install hjson then do the following:
import requests, hjson, re
headers = {'User-Agent':'Mozilla/5.0'}
r = requests.get('https://www.storm.no/ski')
p = re.compile(r'window\.__dehydratedState = (.*?);', re.DOTALL)
data = hjson.loads(p.findall(r.text)[0])
print(data['app-container']['current']['forecast']['nowcastDescription'])
You could regex out with library direct as well but using hsjon means you have access to all the other data.
It's because text under nowcast-description is generated dynamically. If you will dump the loaded page:
print(soup.prettify())
You only find only this:
<span class="nowcast-description" data-reactid="59">
</span>
On rough analysis, it seems that the content of this span is loaded from field nowcastDescription which is a part of window.__dehydratedState .
Because the field is a simple json, you can try to extract it from it.
i ues this code
import urllib.request
fp = urllib.request.urlopen("https://english-thai-dictionary.com/dictionary/?sa=all")
mybytes = fp.read()
mystr = mybytes.decode("utf8")
fp.close()
print(mystr)
x = 'alt'
for item in mystr.split():
if (x) in item:
print(item.strip())
I get Thai word from this code but I didn't know how to get Eng word.Thanks
If you want to get words from table you should use parsing library like BeautifulSoup4. Here is an example how you can parse this (I'm using requests to fetch and beautifulsoup here to parse data):
First using dev tools in your browser identify table with content you want to parse. Table with translations has servicesT class attribute which occurs only once in whole document:
import requests
from bs4 import BeautifulSoup
url = 'https://english-thai-dictionary.com/dictionary/?sa=all;ftlang=then'
response = requests.get(url)
soup = BeautifulSoup(response.text, 'lxml')
# Get table with translations
table = soup.find('table', {'class':'servicesT'})
After that you need to get all rows that contain translations for Thai words. If you look up page's source file you will notice that first few <tr rows are headers that contain only headers so we will omit them. After that we wil get all <td> elements from row (in that table there are always 3 <td> elements) and fetch words from them (in this table words are actually nested in and ).
table_rows = table.findAll('tr')
# We will skip first 3 rows beacause those are not
# contain information we need
for tr in table_rows[3:]:
# Finding all <td> elements
row_columns = tr.findAll('td')
if len(row_columns) >= 2:
# Get tag with Thai word
thai_word_tag = row_columns[0].select_one('span > a')
# Get tag with English word
english_word_tag = row_columns[1].find('span')
if thai_word_tag:
thai_word = thai_word_tag.text
if english_word_tag:
english_word = english_word_tag.text
# Printing our fetched words
print((thai_word, english_word))
Of course, this is very basic example of what I managed to parse from page and you should decide for yourself what you want to scrape. I've also noticed that data inside table does not have translations all the time so you should keep that in mind when scraping data. You also can use Requests-HTML library to parse data (it supports pagination which is present in table on page you want to scrape).
I parse a webpage using beautifulsoup:
import requests
from bs4 import BeautifulSoup
page = requests.get("webpage url")
soup = BeautifulSoup(page.content, 'html.parser')
I find the table and print the text
Ear_yield= soup.find(text="Earnings Yield").parent
print(Ear_yield.parent.text)
And then I get the output of a single row in a table
Earnings Yield
0.01
-0.59
-0.33
-1.23
-0.11
I would like this output to be stored in a list so that I can print on xls and operate on the elements (For ex if (Earnings Yield [0] > Earnings Yield [1]).
So I write:
import html2text
text1 = Ear_yield.parent.text
Ear_yield_text = html2text.html2text(pr1)
list_Ear_yield = []
for i in Ear_yield_text :
list_Ear_yield.append(i)
Thinking that my web data has gone into list. I print the fourth item and check:
print(list_Ear_yield[3])
I expect the output as -0.33 but i get
n
That means the list takes in individual characters and not the full word:
Please let me know where I am doing wrong
That is because your Ear_yield_text is a string rather than a list. Assuming that the text have new lines you can do directly this:
list_Ear_yield = Ear_yield_text.split('\n')
Now if you print list_Ear_yield you will be given this result
['Earnings Yield', '0.01', '-0.59', '-0.33', '-1.23', '-0.11']