I would like to draw a Gaussian curve as a vector graphic in LibreOffice Draw. With the "Curve" functions I was only able to get something parabola-like.
Has anyone got an idea of how to do the Gaussian?
Thank you in advance!
A Gaussian curve is basically a normal distribution aka a bell curve.
This is sort of a hack.
In libre office calc
Add the following data in a column.
1
2
4
5
4
2
1
Then insert->chart->line
From the Dialogue box **Select line AND line only AND smooth line **
You should end up with a chart that looks like this.
In libreoffice calc double click on the chart bell curve then right click on the bell curve LINE
Then from the menu (right click menu) select copy
Open Libreoffice draw and then paste.
You should have something like this.
You can make your own spin.
I hope this helps
Related
I'm using Libreoffice (but I think that this is similar in Excel) and I need to draw a vertical line in correspondence of the green points in this image:
Possibly follow the line style that I used in the legend. How can I do this?
In Excel you can use vertical error bars. If you want to have a line drop vertically to the axis, use the settings with Minus and 100%
I've made a chart with Excel 2010's "Combo" option for chart type so I can plot two data series for the same depth points. The image below shows the default, which is very close to what I want - except I would like to have the axes flipped so that the current X axis, which is depth, is displayed as the Y axis and both primary and secondary current Y axes plot as X axes. In other words, I'd like to rotate the chart area by 90 degrees clockwise. The "Switch Row/Column" doesn't do what I want (or expect) and I'm running out of both ideas and patience. Is there an easy fix? Or a hard fix?
Here's the plot as-is:
And here's a dummy plot of the end goal made by rotating the image around in Paint, in case the picture makes it clearer:
Finally, as was pointed out in the comments, the whole thing looks goofy and might be better plotted as a bar graph with two bars. I tried this as well and came away almost all set - but the gray bars plot from left to right and the blue bars plot from right to left. Seems like it should be as simple as changing the "Plot Series On" option to Primary Axis for both, but this destroys the graph.
I looked around and I think this link has instructions for what you're looking for: https://superuser.com/questions/188064/excel-chart-with-two-x-axes-horizontal-possible
I'm using Excel 2016 and wanted to know how I can make a chart that represents a spectrum from left to right with labels on both sides, and a marker in the middle. Essentially I want to represent the Myers Briggs Type Indicator.
What I've tried so far is to make a horizontal bar chart with a marker, but I can't seem to get labels to the left and right. How might I be able to achieve this?
You just need to add text boxes from drawing tools and put them on top of the chart. Set their backgrounds to transparent by choosing no fill.
I know how to draw a line with scatter plot options where X is the independent and Y the dependent variable.
In the scatter plot of that data I need to add another line: X=2. I have the following data:
But how to draw a line X=1 ?
Maybe you want something like this:
I hear that charting is more different than many other aspects of Excel between versions and that perhaps my version (Excel 2007) is one of the least ‘friendly’ hence some of the reason for “not very easy” but the principle is as #Bill the Lizard has described. In view of some weird behaviour with (my?) Excel 2007 however I recommend being careful about the sequence in which the lines are drawn.
First I suggest getting your chart right for all aspects but the green line. Then add another series with X values of 1 and 1 and Y=2 values of 10 and -2 (or whatever the limits are of your chosen y-axis as displayed). Select and copy that array (four cells) select your chart and Paste Special…, and Add cells as New Series, Columns, Categories (X Values) in First Column, OK.
This should add a vertical line of the same chart type as the existing (ie XY (Scatter) Scatter with Straight Lines and Markers). The colour can be changed, by selecting that series (click on it and Format Data Series…, Line Color etc) and presumably you would want the markers removed. It was these that for me at first refused to disappear to order – but persistence paid off. Click on either of the data points, and under Marker Options choose none for Marker Type. If necessary, repeat for the other data point – and keep repeating if required!
Also, I selected what was showing as Series3 (text) in the legend and deleted that.
Forgot to mention that for anything to do with Excel charts Jon Peltier is the ultimate authority (eg) and that an alternative approach is to use an error bar and a secondary vertical axis.
Most simple thing to do on paper, but somehow near impossible to work out in Excel.
I need to interpolate off a standard curve in Excel.
I have a standard curve and need to find an unknown concentration of a known absorbance.
Just like this;
http://class.fst.ohio-state.edu/fst601/Lectures/spectt/Image161.gif
My lecturer would not give us any more hints than to either use the, linear regression equation (which i think i worked out but couldn't get it to calculate the concentration) or use the point finding/picking option (no idea what this could mean)
If anyone could help me out with this I would really appreciate it, and so would my whole class!
In excel, you can do it two ways:
Method 1: Use a standard interpolation/extrapolation formula. (Bingle)
Method 2: Plot any existing data points that you have as an x-y(scatter) plot. Right-click on the data line in the chart and choose 'Add trendline'. Excel will calculate a best-fit line for your data (using linear regression) and display the line over the top of your existing data. If you right-click on this trendline, you can adjust its settings and display properties of it, including the equation used to draw it. Once you have that equation, you can plug in any value of x and get the corresponding value of y.