Using Mockito I got in trouble with the following:
Mockito.when(restOperationMock.exchange(
Mockito.anyString(),
Mockito.any(HttpMethod.class),
Mockito.any(HttpEntity.class),
Mockito.eq(CustomerResponse.class),
**Mockito.anyMap()**)).
thenReturn(re);
The problem was the method wasn't intercepted because I was using Mockito.any(Map.class) instead of Mockito.anyMap() and I was passing as a parameter a HashMap. What are the differences between Mockito.any(Map.class) and Mockito.anyMap()?
There is only one small difference between any(Map.class) and anyMap(): Starting with Mockito 2.0, Mockito will treat the any(Map.class) call to mean isA(Map.class) rather than ignoring the parameter entirely. (See the comment from Mockito contributor Brice on this SO answer.) Because restOperationMock.exchange takes an Object vararg, you may need anyMap to catch a case where a non-Map object is being passed, or no object at all is passed.
(I'd previously put that as a "dummy value" to return, Mockito can return an empty Map for calls to anyMap(), but can only return a null for calls to any(Map.class). If restOperationMock.exchange delegates to a real implementation during stubbing, such as if it were a spy or unmockable method (final method, method on a final class, etc), then that dummy value may be used in real code. However, that's only true for any(); anyMap() and any(Map.class) both give Mockito enough information to return a dummy Map implementation, where any() has its generics erased and only knows enough to return null.)
Related
It seems that, when I use thenReturn like this:
when(abc.call()).thenReturn(a).thenReturn(b),
I expect:
verify(abc, times(2)).call()
instead, the method seems only get called once, I am a little confused(my test work as expected, the mock seems return the value I expected), but for the invocation times, I don't know if I am getting the wrong result, or it's a expected behavior of the Mockito?
when() is mocking the abc.call() method which has to produce a certain return type. If the method is called once, it will return the value also once, so the stubbing for method invocation is done only once hence the verify only recognizes one call.
You need to customize your function so that the stub(abc.call()) gets called more than once.
You can follow this thread for implementing multiple stubs
From the documentation:
A spy is always based on a real object. Hence you must provide a class type rather than an interface type, along with any constructor arguments for the type. If no constructor arguments are provided, the type’s default constructor will be used.
Method calls on a spy are automatically delegated to the real object. Likewise, values returned from the real object’s methods are passed back to the caller via the spy.
Also:
When stubbing a method on a spy, the real method no longer gets called:
subscriber.receive(_) >> "ok"
Instead of calling SubscriberImpl.receive, the receive method will now simply return "ok".
If a spy is just an interface layer between a real object and the caller, why not just use the real object? What does using a spy offer that using the real object or a Mock do not?
It seems to be in this void between a Mock and a real object to me.
Spies can be used in different scenarios. However, it is good if you can implement your tests without resorting to spies.
(Think twice before using this feature. It might be better to change the design of the code under specification.)
They can be used to verify that a method was called without mocking the method itself
You can stub out calls that you don't want to happen
You can use partial mocks to test the object itself
// this is now the object under specification, not a collaborator
def persister = Spy(MessagePersister) {
// stub a call on the same object
isPersistable(_) >> true
}
when:
persister.receive("msg")
then:
// demand a call on the same object
1 * persister.persist("msg")
Example and quote are from the docs # http://spockframework.org/spock/docs/1.1/all_in_one.html#Spies
In my practice I prefer to use a real objects as much as possible. In case when only one method is to be mocked I still use a real object but with overridden needed method:
MyDomainClass myRealObjectWithMockedMethod = new MyDomainClass() {
#Override
Object doSomething() {
return "hard coded or mocked result";
}
}
// test what you need
myRealObjectWithMockedMethod.action();
Note, this way works only of overridden method is not final. Otherwise Spy will help to define a behavior of this method.
A spy offers the possibility to use the original object but also mock out one method. For example you have a class where you want to test the implementation of the toString() method. But this calls an long running method which needs some external access like a database. In this case you use a spy and let your long running method return some test string and then use the toString from the original object.
Or like the spock example the method subscriber.receive maybe needs a server which sends out asynchronous messages. To write an test for subscriber not relying on the server or to handle asynchronous complexity you let the spy return ok and can easily test your methods which will rely on a server ok.
I would like to know is the thing in the description possible and how to do it.
I know you can call original method and then do the Answer like this:
when(presenter, "myMethod").doAnswer(<CUSTOMANSWER>)
but I would like to order them differently, first do CUSTOMANSWER and then call the original method.
For followers, it's actually possible to doAnswer and callRealMethod at the same time...
doAnswer(new Answer<Object>() {
public Object answer(InvocationOnMock invocationOnMock) throws Throwable {
invocationOnMock.callRealMethod(); // this one
return null;
}
}).when(subject).method(...);
You won't ever see when(...).doAnswer() in Mockito. Instead, you'll see either of the following, which includes the "call real method" behavior you're describing. As usual with Mockito stubbing, Mockito will select the most recent chain of calls that matches the method call and argument values in the invocation, and do each action in the chain once until the final action (which it will do for all calls afterwards.
// Normal Mockito syntax assuming "myMethod" is accessible. See caveat below.
when(presenter.myMethod()).thenAnswer(customAnswer).thenCallRealMethod();
// ...or...
doAnswer(customAnswer).doCallRealMethod().when(presenter).myMethod();
That said, there's a deficiency in the PowerMockito API that makes this difficult, because after the first doAnswer call all subsequent calls you get a normal Mockito Stubber instance rather than a PowerMockitoStubber instance. The bug 599 was misinterpreted, so for the time being you'll still have to make the cast yourself.
((PowerMockitoStubber) doAnswer(customAnswer).doCallRealMethod())
.when(presenter, "myMethod");
I am trying to mock a call to a protected method of one of my classes:
import com.couchbase.client.java.view.Stale; // an enum
import com.google.common.base.Optional;
public class MyClass {
public List<String> myList(Optional<Integer> arg1, Optional<Stale> arg2) {
...
}
}
The mock shall be accomplished in the following way:
// Providing types for any() does not change anything
Mockito.when(myClass.myList(Mockito.any(), Mockito.any()).thenReturn(new ArrayList());
Whenever the previous line is executed the actual myList() method is called with null values for arg1 and arg2. Why is the method called, at all? After all, I am trying to avoid any executing thereof...
As Brice mentioned, if your myList method is final, then Java skips virtual method dispatch and will call the original object (not your mock).
If you are spying on an actual class, it is expected behavior that when will call the actual object as part of the stub: after all, in the expression when(foo.bar()) Java doesn't know anything special about when and assumes that it cares about the return value) of foo.bar(), not the call itself. (I walk through the stubbing process in the "Implementation details" section of my answer here.)
This syntax is better for spies:
doReturn(new ArrayList()).when(myClass).myList(any(), any());
Because this different when method receives an object, Mockito can prepare the object to do nothing during the stubbing, which avoids any spurious calls to your myList method.
Although Jeff's answer did not show a workaround for my problem it pointed me into the right direction.
After changing the mocking behaviour to doReturn... I suddenly got an error message. This message told me that myClass is not a mock which makes sense since you can only mock (or stub?) methods of mocked or spied objects. So as Jeff's answer indicates and is explained in the documentation of mockito I created a partial mock of MyClass with
MyClass myClass = Mockito.spy(new MyClass());
With this partial mock Jeff's approach to method mocking suddenly worked (mine still does not and should therefore be avoided).
So: Thank you, Jeff!
I have a method which return array of object.
public IConfigurationElement[] getConfigurationElementsFor(String extensionPointId);
I am not sure how can I mock this call using mockito and powermock.
I have tried
mockConfigurationElements = (IConfigurationElement[]) Mockito.anyListOf( IConfigurationElement.class ).toArray();
but this is ending in ClassCastException.
Mocking (stubbing) calls with Mockito is done in a following way (for example):
Mockito.when(mockObject.getConfigurationElementsFor(Mockito.anyString()).thenReturn(new IConfigurationElement[]{})
or
Mockito.doReturn(new IConfigurationElement[]{}).when(mockObject).getConfigurationElementsFor(Mockito.anyString());
Mockito.anyListOf() is a use of a matcher. Matchers are passed instead of real arguments when stubbing meaning that the behavior is to be applied if the method is called with arguments satisfying those matchers.