I have a code that looks like this:
has_venv_in_path() {
unsetopt nomatch 2>/dev/null
local path_to_search
path_to_search=$1
echo "searching in $path_to_search"
if [[ ${path_to_search} = "/" ]]; then
echo "no"
fi
ls ${path_to_search}/*/bin/activate > /dev/null 2> /dev/null
if [ "$?" = '0' ]; then
echo "yes"
else
has_venv_in_path $(dirname "$path_to_search")
fi
}
has_venv_in_path function is written by me and it works if the path provided to it doesn't contain tilde like /home/user/foo. If ~/foo is provided that is going into infinite recursion.
So I found how to expand tilde, but I have very little knowledge of bash, so I can't properly use it in my function.
Can anyone help with that?
Suppose we have following folder structure.
/code/foo/bar/baz
/code/foo/venv/bin/activate
if we cd into /code/foo/bar/baz, it should activate venv.
if we cd into /code/foo, it should activate venv
if we cd out of /code/foo/*, it should deactivate venv.
Given that the actual goal here is to look for a virtualenv root somewhere above the currently specified directory...
find_venv_above() {
local dir=${1:-$PWD}
while [[ $dir = /*/* ]]; do
[[ -e "$dir/bin/activate" ]] && {
printf '%s\n' "$dir"
return 0
}
dir=${dir%/*}
done
return 1
}
...used as:
if venv_root=$(find_venv_above); then
echo "Currently in a virtualenv rooted at $venv_root"
fi
Alternately, if you want to find a virtualenv below the current location:
find_venv() {
for option in "${1:-$PWD}"/*/bin/activate; do
[[ -x "$option" ]] && {
printf '%s\n' "${option%/bin/activate}"
return 0
}
done
return 1
}
Usage is similar. That said, if you wanted to recurse multiple levels rather than only one, I'd strongly suggest using find.
Related
I have a function I wrote in bash that copies files.
It was written so it would be less painful for us to turn our batch scripts that use xcopy to bash scripts. This is because the copy commands in Linux work a little bit different.
The function does several things:
It creates a path to the target directory if it doesn't exist yet.
It uses cp to copy files
it uses cp -r to copy directories.
it uses rsync -arv --exclude-from=<FILE> to copy all the files and folders in a gives directory except the files/folders listed in FILE
The problem is, that when I try to copy files with * it gives me an error:
cp: cannot stat 'some dir with * in it': No such file or directory.
I found out that I can instead write something like that: cp "<dir>/"*".<extension>" "<targetDir>" and the command itself works. But when I try to pass that to my function, it gets 3 arguments instead of 2.
How can I use the cp command in my function while being able to pass a path with wildcard in it? meaning the argument will have double quotes in the beginning of the path and in the end of them, for example: Copy "<somePath>/*.zip" "<targetDir>"
function Copy {
echo "number of args is: $#"
LastStringInPath=$(basename "$2")
if [[ "$LastStringInPath" != *.* ]]; then
mkdir -p "$2"
else
newDir=$(dirname "$2")
mkdir -p "newDir"
fi
if [ "$#" == "2" ]; then
echo "Copying $1 to $2"
if [[ -d $1 ]]; then
cp -r "$1" "$2"
else
cp "$1" "$2"
fi
if [ $? -ne 0 ]; then
echo "Error $? while trying to copy $1 to $2"
exit 1
fi
else
rsync -arv --exclude-from="$3" "$1" "$2"
if [ $? -ne 0 ]; then
echo "Error $? while trying to copy $1 to $2"
exit 1
fi
fi
}
Okay, so I couldn't solve this with the suggestions I was given. What was happening is either the * was expanding before it was sent to function or it wouldn't expand at all inside the function. I tried different methods and eventually I decided to rewrite the function so it would instead support multiple arguments.
The expansion of the wild card happens before it sent to my function, and the copy function does all the actions it was doing before while supporting more than one file/dir to copy.
function Copy {
argumentsArray=( "$#" )
#Check if last argument has the word exclude, in this case we must use rsync command
if [[ ${argumentsArray[$#-1],,} == exclude:* ]]; then
mkdir -p "$2"
#get file name from the argument
excludeFile=${3#*:}
rsync -arv --exclude-from="$excludeFile" "$1" "$2"
if [ $? -ne 0 ]; then
echo "Error while to copy $1 to $2"
exit 1
fi
else
mkdir -p "${argumentsArray[$#-1]}"
if [[ -d $1 ]]; then
cp -r "${argumentsArray[#]}"
if [ $? -ne 0 ]; then
exit 1
fi
else
cp "${argumentsArray[#]}"
if [ $? -ne 0 ]; then
exit 1
fi
fi
fi
}
Below is my script to check root path integrity, to ensure there is no vulnerability in PATH variable.
#! /bin/bash
if [ ""`echo $PATH | /bin/grep :: `"" != """" ]; then
echo "Empty Directory in PATH (::)"
fi
if [ ""`echo $PATH | /bin/grep :$`"" != """" ]; then echo ""Trailing : in PATH""
fi
p=`echo $PATH | /bin/sed -e 's/::/:/' -e 's/:$//' -e 's/:/ /g'`
set -- $p
while [ ""$1"" != """" ]; do
if [ ""$1"" = ""."" ]; then
echo ""PATH contains ."" shift
continue
fi
if [ -d $1 ]; then
dirperm=`/bin/ls -ldH $1 | /bin/cut -f1 -d"" ""`
if [ `echo $dirperm | /bin/cut -c6 ` != ""-"" ]; then
echo ""Group Write permission set on directory $1""
fi
if [ `echo $dirperm | /bin/cut -c9 ` != ""-"" ]; then
echo ""Other Write permission set on directory $1""
fi
dirown=`ls -ldH $1 | awk '{print $3}'`
if [ ""$dirown"" != ""root"" ] ; then
echo $1 is not owned by root
fi
else
echo $1 is not a directory
fi
shift
done
The script works fine for me, and shows all vulnerable paths defined in the PATH variable. I want to also automate the process of correctly setting the PATH variable based on the above result. Any quick method to do that.
For example, on my Linux box, the script gives output as:
/usr/bin/X11 is not a directory
/root/bin is not a directory
whereas my PATH variable have these defined,and so I want to have a delete mechanism, to remove them from PATH variable of root. lot of lengthy ideas coming in mind. But searching for a quick and "not so complex" method please.
No offense but your code is completely broken. Your using quotes in a… creative way, yet in a completely wrong way. Your code is unfortunately subject to pathname expansions and word splitting. And it's really a shame to have an insecure code to “secure” your PATH.
One strategy is to (safely!) split your PATH variable into an array, and scan each entry. Splitting is done like so:
IFS=: read -r -d '' -a path_ary < <(printf '%s:\0' "$PATH")
See my mock which and How to split a string on a delimiter answers.
With this command you'll have a nice array path_ary that contains each fields of PATH.
You can then check whether there's an empty field, or a . field or a relative path in there:
for ((i=0;i<${#path_ary[#]};++i)); do
if [[ ${path_ary[i]} = ?(.) ]]; then
printf 'Warning: the entry %d contains the current dir\n' "$i"
elif [[ ${path_ary[i]} != /* ]]; then
printf 'Warning: the entry %s is not an absolute path\n' "$i"
fi
done
You can add more elif's, e.g., to check whether the entry is not a valid directory:
elif [[ ! -d ${path_ary[i]} ]]; then
printf 'Warning: the entry %s is not a directory\n' "$i"
Now, to check for the permission and ownership, unfortunately, there are no pure Bash ways nor portable ways of proceeding. But parsing ls is very likely not a good idea. stat can work, but is known to have different behaviors on different platforms. So you'll have to experiment with what works for you. Here's an example that works with GNU stat on Linux:
read perms owner_id < <(/usr/bin/stat -Lc '%a %u' -- "${path_ary[i]}")
You'll want to check that owner_id is 0 (note that it's okay to have a dir path that is not owned by root; for example, I have /home/gniourf/bin and that's fine!). perms is in octal and you can easily check for g+w or o+w with bit tests:
elif [[ $owner_id != 0 ]]; then
printf 'Warning: the entry %s is not owned by root\n' "$i"
elif ((0022&8#$perms)); then
printf 'Warning: the entry %s has group or other write permission\n' "$i"
Note the use of 8#$perms to force Bash to understand perms as an octal number.
Now, to remove them, you can unset path_ary[i] when one of these tests is triggered, and then put all the remaining back in PATH:
else
# In the else statement, the corresponding entry is good
unset_it=false
fi
if $unset_it; then
printf 'Unsetting entry %s: %s\n' "$i" "${path_ary[i]}"
unset path_ary[i]
fi
of course, you'll have unset_it=true as the first instruction of the loop.
And to put everything back into PATH:
IFS=: eval 'PATH="${path_ary[*]}"'
I know that some will cry out loud that eval is evil, but this is a canonical (and safe!) way to join array elements in Bash (observe the single quotes).
Finally, the corresponding function could look like:
clean_path() {
local path_ary perms owner_id unset_it
IFS=: read -r -d '' -a path_ary < <(printf '%s:\0' "$PATH")
for ((i=0;i<${#path_ary[#]};++i)); do
unset_it=true
read perms owner_id < <(/usr/bin/stat -Lc '%a %u' -- "${path_ary[i]}" 2>/dev/null)
if [[ ${path_ary[i]} = ?(.) ]]; then
printf 'Warning: the entry %d contains the current dir\n' "$i"
elif [[ ${path_ary[i]} != /* ]]; then
printf 'Warning: the entry %s is not an absolute path\n' "$i"
elif [[ ! -d ${path_ary[i]} ]]; then
printf 'Warning: the entry %s is not a directory\n' "$i"
elif [[ $owner_id != 0 ]]; then
printf 'Warning: the entry %s is not owned by root\n' "$i"
elif ((0022 & 8#$perms)); then
printf 'Warning: the entry %s has group or other write permission\n' "$i"
else
# In the else statement, the corresponding entry is good
unset_it=false
fi
if $unset_it; then
printf 'Unsetting entry %s: %s\n' "$i" "${path_ary[i]}"
unset path_ary[i]
fi
done
IFS=: eval 'PATH="${path_ary[*]}"'
}
This design, with if/elif/.../else/fi is good for this simple task but can get awkward to use for more involved tests. For example, observe that we had to call stat early before the tests so that the information is available later in the tests, before we even checked that we're dealing with a directory.
The design may be changed by using a kind of spaghetti awfulness as follows:
for ((oneblock=1;oneblock--;)); do
# This block is only executed once
# You can exit this block with break at any moment
done
It's usually much better to use a function instead of this, and return from the function. But because in the following I'm also going to check for multiple entries, I'll need to have a lookup table (associative array), and it's weird to have an independent function that uses an associative array that's defined somewhere else…
clean_path() {
local path_ary perms owner_id unset_it oneblock
local -A lookup
IFS=: read -r -d '' -a path_ary < <(printf '%s:\0' "$PATH")
for ((i=0;i<${#path_ary[#]};++i)); do
unset_it=true
for ((oneblock=1;oneblock--;)); do
if [[ ${path_ary[i]} = ?(.) ]]; then
printf 'Warning: the entry %d contains the current dir\n' "$i"
break
elif [[ ${path_ary[i]} != /* ]]; then
printf 'Warning: the entry %s is not an absolute path\n' "$i"
break
elif [[ ! -d ${path_ary[i]} ]]; then
printf 'Warning: the entry %s is not a directory\n' "$i"
break
elif [[ ${lookup[${path_ary[i]}]} ]]; then
printf 'Warning: the entry %s appears multiple times\n' "$i"
break
fi
# Here I'm sure I'm dealing with a directory
read perms owner_id < <(/usr/bin/stat -Lc '%a %u' -- "${path_ary[i]}")
if [[ $owner_id != 0 ]]; then
printf 'Warning: the entry %s is not owned by root\n' "$i"
break
elif ((0022 & 8#$perms)); then
printf 'Warning: the entry %s has group or other write permission\n' "$i"
break
fi
# All tests passed, will keep it
lookup[${path_ary[i]}]=1
unset_it=false
done
if $unset_it; then
printf 'Unsetting entry %s: %s\n' "$i" "${path_ary[i]}"
unset path_ary[i]
fi
done
IFS=: eval 'PATH="${path_ary[*]}"'
}
All this is really safe regarding spaces and glob characters and newlines inside PATH; the only thing I don't really like is the use of the external (and non-portable) stat command.
I'd recommend you get a good book on Bash shell scripting. It looks like you learned Bash from looking at 30 year old system shell scripts and by hacking away. This isn't a terrible thing. In fact, it shows initiative and great logic skills. Unfortunately, it leads you down to some really bad code.
If statements
In the original Bourne shell the [ was a command. In fact, /bin/[ was a hard link to /bin/test. The test command was a way to test certain aspects of a file. For example test -e $file would return a 0 if the $file was executable and a 1 if it wasn't.
The if merely took the command after it, and would run the then clause if that command returned an exit code of zero, or the else clause (if it exists) if the exit code wasn't zero.
These two are the same:
if test -e $file
then
echo "$file is executable"
fi
if [ -e $file ]
then
echo "$file is executable"
fi
The important idea is that [ is merely a system command. You don't need these with the if:
if grep -q "foo" $file
then
echo "Found 'foo' in $file"
fi
Note that I am simply running grep and if grep is successful, I'm echoing my statement. No [ ... ] are necessary.
A shortcut to the if is to use the list operators && and ||. For example:
grep -q "foo" $file && echo "I found 'foo' in $file"
is the same as the above if statement.
Never parse ls
You should never parse the ls command. You should use stat instead. stat gets you all the information in the command, but in an easily parseable form.
[ ... ] vs. [[ ... ]]
As I mentioned earlier, in the original Bourne shell, [ was a system command. In Kornshell, it was an internal command, and Bash carried it over too.
The problem with [ ... ] is that the shell would first interpolate the command before the test was performed. Thus, it was vulnerable to all sorts of shell issues. The Kornshell introduced [[ ... ]] as an alternative to the [ ... ] and Bash uses it too.
The [[ ... ]] allows Kornshell and Bash to evaluate the arguments before the shell interpolates the command. For example:
foo="this is a test"
bar="test this is"
[ $foo = $bar ] && echo "'$foo' and '$bar' are equal."
[[ $foo = $bar ]] && echo "'$foo' and '$bar' are equal."
In the [ ... ] test, the shell interpolates first which means that it becomes [ this is a test = test this is ] and that's not valid. In [[ ... ]] the arguments are evaluated first, thus the shell understands it's a test between $foo and $bar. Then, the values of $foo and $bar are interpolated. That works.
For loops and $IFS
There's a shell variable called $IFS that sets how read and for loops parse their arguments. Normally, it's set to space/tab/NL, but you can modify this. Since each PATH argument is separated by :, you can set IFS=:", and use a for loop to parse your $PATH.
The <<< Redirection
The <<< allows you to take a shell variable and pass it as STDIN to the command. These both more or less do the same thing:
statement="This contains the word 'foo'"
echo "$statement" | sed 's/foo/bar/'
statement="This contains the word 'foo'"
sed 's/foo/bar/'<<<$statement
Mathematics in the Shell
Using ((...)) allows you to use math and one of the math function is masking. I use masks to determine whether certain bits are set in the permission.
For example, if my directory permission is 0755 and I and it against 0022, I can see if user read and write permissions are set. Note the leading zeros. That's important, so that these are interpreted as octal values.
Here's your program rewritten using the above:
#! /bin/bash
grep -q "::" <<<"$PATH" && echo "Empty directory in PATH ('::')."
grep -q ":$" <<<$PATH && "PATH has trailing ':'"
#
# Fix Path Issues
#
path=$(sed -e 's/::/:/g' -e 's/:$//'<<<$PATH);
OLDIFS="$IFS"
IFS=":"
for directory in $PATH
do
[[ $directory == "." ]] && echo "Path contains '.'."
[[ ! -d "$directory" ]] && echo "'$directory' isn't a directory in path."
mode=$(stat -L -f %04Lp "$directory") # Differs from system to system
[[ $(stat -L -f %u "$directory") -eq 0 ]] && echo "Directory '$directory' owned by root"
((mode & 0022)) && echo "Group or Other write permission is set on '$directory'."
done
I'm not 100% sure what you want to do or mean about PATH Vulnerabilities. I don't know why you care whether a directory is owned by root, and if an entry in the $PATH is not a directory, it won't affect the $PATH. However, one thing I would test for is to make sure all directories in your $PATH are absolute paths.
[[ $directory != /* ]] && echo "Directory '$directory' is a relative path"
The following could do the whole work and also removes duplicate entries
export PATH="$(perl -e 'print join(q{:}, grep{ -d && !((stat(_))[2]&022) && !$seen{$_}++ } split/:/, $ENV{PATH})')"
I like #kobame's answer but if you don't like the perl-dependency you can do something similar to:
$ cat path.sh
#!/bin/bash
PATH="/root/bin:/tmp/groupwrite:/tmp/otherwrite:/usr/bin:/usr/sbin"
echo "${PATH}"
OIFS=$IFS
IFS=:
for path in ${PATH}; do
[ -d "${path}" ] || continue
paths=( "${paths[#]}" "${path}" )
done
while read -r stat path; do
[ "${stat:5:1}${stat:8:1}" = '--' ] || continue
newpath="${newpath}:${path}"
done < <(stat -c "%A:%n" "${paths[#]}" 2>/dev/null)
IFS=${OIFS}
PATH=${newpath#:}
echo "${PATH}"
$ ./path.sh
/root/bin:/tmp/groupwrite:/tmp/otherwrite:/usr/bin:/usr/sbin
/usr/bin:/usr/sbin
Note that this is not portable due to stat not being portable but it will work on Linux (and Cygwin). For this to work on BSD systems you will have to adapt the format string, other Unices don't ship with stat at all OOTB (Solaris, for example).
It doesn't remove duplicates or directories not owned by root either but that can easily be added. The latter only requires the loop to be adapted slightly so that stat also returns the owner's username:
while read -r stat owner path; do
[ "${owner}${stat:5:1}${stat:8:1}" = 'root--' ] || continue
newpath="${newpath}:${path}"
done < <(stat -c "%A:%U:%n" "${paths[#]}" 2>/dev/null)
I want to recursively loop through all subdirectories within the current directory.
for i in *
this only iterates through all the files in the current directory. How do you make it so that if the file it is looking at is a directory, to enter that directory and recursively look through that directory too and so on and so forth.
EDIT: sorry should have been more specific. i cant use ls -R, as i want to display it in a tree structure with a certain format type. I have heard there are commands which can do this but i have to use a loop. cannot use "find" either...
Here is a function to do what you need. Call it with recp 0 in the current directory.
function recp
{
lvl=$(($1 + 1))
for f in *
do
j=0
while [[ $j -lt $lvl ]]
do
echo -n " "
j=$(($j+1))
done
echo $f
[[ -d $f ]] && ( cd $f && recp $lvl )
done
}
I'm not very good at bash scripting
but the example below goes through all the directories.
You can replace the echo command with whatever you like.
I'm sure the style of this example can be improved.
Also did you consider the command "tree"?
Good luck.
#!/bin/bash
function recursiveList
{
if [ -d $1 ]
then
cd $1
for x in *
do
recursiveList $x
done
cd ..
else
echo $1
fi
}
for i in *
do
recursiveList $i
done
I want to create a bash alias to do the following:
Assume I am at the following path:
/dir1/dir2/dir3/...../dirN
I want to go up to dir3 directly without using cd ... I will just write cdd dir3 and it should go directly to /dir1/dir2/dir3. cdd is my alias name.
I wrote the following alias, but it doesn't work:
alias cdd='export newDir=$1; export myPath=`pwd | sed "s/\/$newDir\/.*/\/$newDir/"`; cd $myPath'
Simply it should get the current full path, then remove anything after the new destination directory, then cd to this new path
The problem with my command is that $1 doesn't get my input to the command cdd
This is a slightly simpler function that I think achieves what you're trying to do:
cdd() { cd ${PWD/$1*}$1; }
Explanation:
${PWD/$1*}$1 takes the current working directory and strips off everything after the string passed to it (the target directory), then adds that string back. This is then used as an argument for cd. I didn't bother adding any error handling as cdwill take care of that itself.
Example:
[atticus:pgl]:~/tmp/a/b/c/d/e/f $ cdd b
[atticus:pgl]:~/tmp/a/b $
It's a little ugly, but it works.
Here's a function - which you could place in your shell profile - which does what you want; note that in addition to directory names it also supports levels (e.g., cdd 2 to go up 2 levels in the hierarchy); just using cdd will move up to the parent directory.
Also note that matching is case-INsensitive.
The code is taken from "How can I replace a command line argument with tab completion?", where you'll also find a way to add complementary tab-completion for ancestral directory names.
cdd ()
{
local dir='../';
[[ "$1" == '-h' || "$1" == '--help' ]] && {
echo -e "usage:
$FUNCNAME [n]
$FUNCNAME dirname
Moves up N levels in the path to the current working directory, 1 by default.
If DIRNAME is given, it must be the full name of an ancestral directory (case does not matter).
If there are multiple matches, the one *lowest* in the hierarchy is changed to." && return 0
};
if [[ -n "$1" ]]; then
if [[ $1 =~ ^[0-9]+$ ]]; then
local strpath=$( printf "%${1}s" );
dir=${strpath// /$dir};
else
if [[ $1 =~ ^/ ]]; then
dir=$1;
else
local wdLower=$(echo -n "$PWD" | tr '[:upper:]' '[:lower:]');
local tokenLower=$(echo -n "$1" | tr '[:upper:]' '[:lower:]');
local newParentDirLower=${wdLower%/$tokenLower/*};
[[ "$newParentDirLower" == "$wdLower" ]] && {
echo "$FUNCNAME: No ancestral directory named '$1' found." 1>&2;
return 1
};
local targetDirPathLength=$(( ${#newParentDirLower} + 1 + ${#tokenLower} ));
dir=${PWD:0:$targetDirPathLength};
fi;
fi;
fi;
pushd "$dir" > /dev/null
}
I agree with mklement0, this should be a function. But a simpler one.
Add this to your .bashrc:
cdd () {
newDir="${PWD%%$1*}$1"
if [ ! -d "$newDir" ]; then
echo "cdd: $1: No such file or directory" >&2
return 1
fi
cd "${newDir}"
}
Note that if $1 (your search string) appears more than once in the path, this function will prefer the first one. Note also that if $1 is a substring of a path, it will not be found. For example:
[ghoti#pc ~]$ mkdir -p /tmp/foo/bar/baz/foo/one
[ghoti#pc ~]$ cd /tmp/foo/bar/baz/foo/one
[ghoti#pc /tmp/foo/bar/baz/foo/one]$ cdd foo
[ghoti#pc /tmp/foo]$ cd -
/tmp/foo/bar/baz/foo/one
[ghoti#pc /tmp/foo/bar/baz/foo/one]$ cdd fo
cdd: fo: No such file or directory
If you'd like to include the functionality of going up 2 levels by running cdd 2, this might work:
cdd () {
newDir="${PWD%%$1*}$1"
if [ "$1" -gt 0 -a "$1" = "${1%%.*}" -a ! -d "$1" ]; then
newDir=""
for _ in $(seq 1 $1); do
newDir="../${newDir}"
done
cd $newDir
return 0
elif [ ! -d "$newDir" ]; then
echo "cdd: $1: No such file or directory" >&2
return 1
fi
cd "${newDir}"
}
The long if statement verifies that you've supplied an integer that is not itself a directory. We build a new $newDir so that you can cd - to get back to your original location if you want.
Is there an easy way to find all files where no part of the path of the file is a symbolic link?
Short:
find myRootDir -type f -print
This would answer the question.
Care to not add a slash at end of specified dir ( not myRootDir/ but myRootDir ).
This won't print other than real files in real path.
No symlinked file nor file in symlinked dir.
But...
If you wanna ensure that a specified dir contain a symlink, there is a litte bash function to could do the job:
isPurePath() {
if [ -d "$1" ];then
while [ ! -L "$1" ] && [ ${#1} -gt 0 ] ;do
set -- "${1%/*}"
if [ "${1%/*}" == "$1" ] ;then
[ ! -L "$1" ] && return
set -- ''
fi
done
fi
false
}
if isPurePath /usr/share/texmf/dvips/xcolor ;then echo yes; else echo no;fi
yes
if isPurePath /usr/share/texmf/doc/pgf ;then echo yes; else echo no;fi
no
So you could Find all files where no part of the path of the file is a symbolic link in running this command:
isPurePath myRootDir && find myRootDir -type f -print
So if something is printed, there are no symlink part !
You can use this script : (copy/paste the whole code in a shell)
cat<<'EOF'>sympath
#!/bin/bash
cur="$1"
while [[ $cur ]]; do
cur="${cur%/*}"
if test -L "$cur"; then
echo >&2 "$cur is a symbolic link"
exit 1
fi
done
EOF
${cur%/*} is a bash parameter expansion
EXAMPLE
chmod +x sympath
./sympath /tmp/foo/bar/base
/tmp/foo/bar is a symbolic link
I don't know any easy way, but here's an answer that fully answers your question, using two methods (that are, in fact, essentially the same):
Using an auxiliary script
Create a file called hasnosymlinkinname (or choose a better name --- I've always sucked at choosing names):
#!/bin/bash
name=$1
if [[ "$1" = /* ]]; then
name="$(pwd)/$1"
else
name=$1
fi
IFS=/ read -r -a namearray <<< "$name"
for ((i=0;i<${#namearray[#]}; ++i)); do
IFS=/ read name <<< "${namearray[*]:0:i+1}"
[[ -L "$name" ]] && exit 1
done
exit 0
Then chmod +x hasnosymlinkinname. Then use with find:
find /path/where/stuff/is -exec ./hasnosymlinkinname {} \; -print
The scripts works like this: using IFS trickery, we decompose the filename into each part of the path (separated by the /) and put each part in an array namearray. Then, we loop through the (cumulative) parts of the array (joined with the / thanks to some IFS trickery) and if this part is a symlink (see the -L test), we exit with a non-success return code (1), otherwise, we exit with a success return code (0).
Then find runs this script to all files in /path/where/stuff/is. If the script exits with a success return code, the name of the file is printed out (but instead of -print you could do whatever else you like).
Using a one(!)-liner (if you have a large screen) to impress your grand-mother (or your dog)
find /path/where/stuff/is -exec bash -c 'if [[ "$0" = /* ]]; then name=$0; else name="$(pwd)/$0"; fi; IFS=/ read -r -a namearray <<< "$name"; for ((i=0;i<${#namearray[#]}; ++i)); do IFS=/ read name <<< "${namearray[*]:0:i+1}"; [[ -L "$name" ]] && exit 1; done; exit 0' {} \; -print
Note
This method is 100% safe regarding spaces or funny symbols that could appear in file names. I don't know how you'll use the output of this command, but please make sure that you'll use a good method that will also be safe regarding spaces and funny symbols that could appear in a file name, i.e., don't parse its output with another script unless you use -print0 or similar smart thing.