I have one data field on the report, the data sample like following:
"75,80,80,80,92"
"75,80,80,80,93"
"75"
"75,80"
I created another expression field to try retrieved only third pair digits if length =14, so I have
=IIf(Len([CRCase.dtcase_Attributes])=14, Substring(Replace([CRCase.dtCase_Attributes],',',''), 4,2),'empty')
when I run the report, I could get "80" for first two rows, but error for bottom two. Is there any way to workaround?
Thanks.
One workaround that I figured out is using padright to make the strings having same length.
But still wondering why first part of boolean expression did not return false for short string.
I have had this same problem. The true portion of IIf is evaluating for all records, regardless of whether or not they meet the condition. It doesn't do anything with the true value for records that don't meet the condition, but it still tries to evaluate it which doesn't make any sense.
It's as Tim mentioned. The full formula is evaluated to parse down the results.
In other words it's using this
1) Evaluate True method
2) Evaluate False method
3) Evaluate comparison
4) Show True/False by comparison.
In your case it's being resulted down to:
IIF(true,{substringvalue},{skipped}) for the first two rows and
IIF(false,ERROR,'empty') for the rest.
Because of the "ERROR" that occurs when trying to evaluate the true portion, the entire formula fails.
Padding is one solution here.
Make sure though to account for a null. you can't pad right a null value.
Related
Okay so my question is how do i use IF with 3 arguments while one of the arguments is "Ignore blanks".
If A1 is "Escalation_complaint or "Escalation_request" B1 must show "Escalated".
If A1 is any other text, B1 must show "Solved"
If A1 is blank, B1 must remain empty.
Can someone please help me figure this out?
Your first test must be whether the A1 is empty or not. This must be the first because if you test whether an empty string is contained in another string the answer is always yes. =SEARCH("","Something") returns 1. So, How do you test for an empty cell? I recommend Excel's COUNTA() function but you may prefer testing for "". So, let's say, your first test is this.
=IF(COUNTA(A1), True, False)
Some would say IF(COUNTA(A1)>0, True, False) and that is equivalent. The simple IF(COUNTA(A1) tests for non-zero. Any number other than zero returns True.
So, now you got your basic function. What's supposed to happen if the result is True? What do you want to happen if the result is False? The latter is easy. If the result is False you want a null string returns. So, now your formula looks like this:-
=IF(COUNTA(A1), True, "")
Observe that we simply replaced the False with the desired output. So, what do you want to happen if A1 has something in it, if the first test resulted in True? There are two possibilities. That makes the problem solvable with a single IF. IF A1 has something starting with "Escalation" in it the result should be "escalate", else it should be "solved". So, how do you test for cell content?
=Find("escalation", A1) will not find "Escalation" (with a capital E). Therefore I recommend SEARCH(), which does.
=SEARCH("escalation", A1) should return 1. If it returns 1 your problem is solved because if it returns any other number its not "escalated" but "solved". Unfortunately, there is a third option. It might return an error. In fact it will return an error every time the word isn't found. That gives you a 3-way possibility (1, bigger than 1, or Error) which can't be solved with a single IF. So, I suggest to avoid the error.
=Find("escalation", A1 & "escalation") will find the word "escalation" every time. But it will find it in first position only if the conditions for "Escalate" is met. Therefore the formula for the True condition in the basic formula must be this:-
IF(SEARCH("escalation", A1 & "escalation") = 1, "Escalated", "Solved")
That's it. Assemble the second IF into the first and you're done.
So, using two if(), and minimising the testing you need :
=IF(left(A1,3)="Esc","Escalated",IF(A1="","","Solved"))
Edit: Based on a comment to another answer, if testing for "esc" only could lead to problems then how about:
=IF(left(A1,5)="Escal","Escalated",IF(A1="","","Solved"))
Which will avoid words like "escaped" or "escargot"...
If you know that the text will always be Escalation_complaint or Escalation_request, you can do this with a nested IF query. =IF in Excel takes three parameters: what to verify, result if true, and result if false. You can have another IF statement in the what to do if it returns false section. We can also do an OR() statement to verify both Escalation_complaint and Escalation_request. The result looks like this:
=IF(OR(A1="Escalation_complaint",A1="Escalation_request"),"Escalated",IF(A1="","","Solved"))
The order here is important because you want the "for all other cases" to be in the final IF statement.
If you have a situation where you could also have "Request_escalation" or "complaint_escalation", you should make a more general solution that uses SEARCH or FIND which would allow you to do a more general lookup that allows for more values without having to hardcode them. Here is an example that makes it possible to find the word Escalation anywhere in the cell:
=IF(IFERROR(SEARCH("escalation",A1,1),0)>0, "Escalated", IF(A1="","","Solved"))
Excel have maximum 30 arguments in a formula.
= if (A1=1, "True",if(B1>2,"True", "false"))
Understand this pattern. easy way.
If you no longer understand this, or if your problem has not been resolved, attach a file or screenshot that relates to your problem.
I have a dictionary containing lots of words - I want the user to be able to input a list of substrings, and then a filtered list will be updated, containing only words that contain those substrings and nothing else. Any words that contain extra characters the user didn't specify, should not appear. Cell F3 will use a FILTER function to create the list. As in the mock-up below:
What I need is a formula that would generate the TRUE or FALSE flags from the yellow section (B3:B9), but I'm not sure how to go about this.
I'm sure this could be solved by VBA or Regex using Google Sheets, but I want to know if there's a way to do this by formula, as I don't want this to require a button press or script execution, and my spreadsheet can't be hosted on Google sheets due to its size. Any ideas?
You can also use a combination of ISNUMBER and SUMPRODUCT:
=ISNUMBER(SUMPRODUCT(MATCH(MID(A3,ROW(INDEX(A:A,1,1):INDEX(A:A,LEN(A3),1)),1),$D$3:$D$5,0)))
Adjusted formula:
=ISNUMBER(SUMPRODUCT(MATCH(MID(A3,ROW(A$1:INDEX(A:A,LEN(A3))),1),$D$3:$D$5,0)))
The result:
The test being ran below is subtracting each instance of your dictionary from the length of original string. If the result is 0, this returns TRUE. If not, this returns FALSE. This is not case sensitive - a & A will be treated equally here.
=NOT(LEN(A1)-(LEN(A1)-LEN(SUBSTITUTE(UPPER(A1),D1,"")))-(LEN(A1)-LEN(SUBSTITUTE(UPPER(A1),D2,"")))-(LEN(A1)-LEN(SUBSTITUTE(UPPER(A1),D3,""))))
The equation works fine although I don't know if it is an optimal solution for you, but posting as answer in case it is for somebody else. The issue with this approach is the equation gets longer and longer for each character you add to your dictionary. Depending on the size of dictionary and strings to test against, this can get sloppy and calc heavy really quick.
Have you considered a UDF in VBA?
Is there any reason in an Excel spreadsheet the expression OR(TRUE,#N/A) returns #N/A ?
How can we make it work the way we learned at school ie. OR(TRUE, whatever) should equal TRUE ?
so that we can evaluate a logical expression correctly even if not all parameters are known at the time of running, if those unknown are not really required.
Thank you
PS.
i use #N/A where the input is not known yet, it is not meant to be
an error. For instance
"=OR(turnover>1000000,leadtime>90,AND(turnover>500000,leadtime>30),AND(turnover>200000,leadtime>60))"
indicates an item needs special attention either because its
turnover is high or because its lead time is long but i don't
always have inputs for both. Sometimes one of two should suffice.
N/A is used when not known because i haven't found anything better than that. Tried "Unknown" string and AND(TRUE,"Unknown")
returns TRUE, which is not what it should be
i have many expressions which are more complicated than just
OR(x1,x2) so instead of trapping every parameter for error i have
written an udf OOR where OOR(TRUE,whatever even if error) = TRUE.
Just wondering if Microsoft has a better approach i don't know
You can wrap the logicals in an IFERROR that returns FALSE:
=IF(OR(IFERROR(A1=1,FALSE),IFERROR(B1=1,FALSE)),TRUE,FALSE)
You cannot compare to an error without throwing an error. Use ISERROR or ISNA on the cell to see if it contains an error.
=IF(OR(A1=TRUE,ISERROR(A1)), <something if true>, <something if false>)
In the above, you don't need to say A1 = TRUE, simply A1 will return true or false.
I have an Excel file I'm working with. There is a column that contains numbers and text, sometimes it's just one or the other. I'm trying to write a function that scans the left most part of the cell to see if it starts with a number. I thought I had it but apparently not. This is what I had:
=IF(ISNUMBER(LEFT(E8,1)), "True", "False")
This continues to throw me a "false" result even though that particular cell, E8, begins with a "3". What am I missing here?
Try this out:
=IF(ISNUMBER(VALUE(LEFT(E8,1))),"True","False")
Using the IF statement is redundant. The most simple and effective way to achieve your desired result is:
=ISNUMBER(--LEFT(E8,1))
It will automatically return TRUE or FALSE
Note that you can achieve what you require with just the following:
=NOT(ISERROR(LEFT(E8)*1))
If you do not LEFT(E8) evaluates to LEFT(E8,1) and multiplication by 1 throws an error on anything non-numeric
If you need your output as strings then update as per below:
IF(NOT(ISERROR(LEFT(E8)*1)),"True","False")
EDIT
Using ISNUMBER() is a good alternative to NOT(ISERROR())
=ISNUMBER(LEFT(A1)*1)
=IF(ISNUMBER(LEFT(A1)*1),"True","False")
=IFERROR(IF(VALUE(LEFT(E8,1)),"TRUE","FALSE"),"FALSE")
How do I apply following requirement in Saved Search criteria?
Filter all inventory items
Where min( {memberitem.quantityavailable} / {memberquantity} ) <> custitem_quantity
Note: custitem_quantity is a custom numeric field.
Note2: NetSuite is throwing error when I use min function in filters.
There is more than one issue here.
You have to be careful with custom numerics in Netsuite.
When your inner condition evaluates, it does not have the same type because it is fractional. At some point it has to be rounded and / or truncated internally. The other side of the expression would need to call a floor or ceiling function to remove everthing past the decimal.
Also, the min function evaluates after the <> conditional, which will be dependent upon whether your custom numeric is type compatible to begin with.
In the expression you provided us, it would have to be an exact match (and an exact type), and that is before you consider whether MIN gets to be evaluated.
Look at how the datatypes are cast and what columns you are processing because memberitem.quantityavailable may need a secondary index depending upon your dependencies and where the formula is being called. If this formula is being used over multiple products, it may not be logically consistent.
When I have similar items in inventory that I want to generate stats for I try to process it separately, even if I have to make a second pass.
What are you trying to isolate exactly - - I cannot think of a quantity-related situation where there would be a need to use division in this way - - please refer to the formula Mike Robbins listed above for a properly structured evaluation and see if it achieves the desired result.
If you post the rest of your code, I will help you resolve this.
The entire expression is not valid and will not evaluate due to the conditional shown, the MIN, nor the division. Index the count on the memberquantity if you are looking to sum over values. Otherwise, CountIF will work for quantities. MIN will only finds the lowest value in a given column, so SumIF appears to be what you are after. You can create a second expression which bounds the values you are searching for as a preliminary step.
I am new here, so please elaborate on what you are trying to accomplish so I can earn the bounty.
You may want to take into account null values as well to avoid errors or inconsistent data.
If you're using formula numeric, try this:
Formula(Numeric):
case when min((NVL({memberitem.quantityavailable},0) / NVL({memberquantity},0)) - (NVL{custitem_quantity},0)) then 1 else 0 end
'IS EQUAL TO' 1
I believe you can use the Formula Text or Formula Numeric Search Filter for that.