Echo Serial Strings with Arduino - string

Question

EDIT 2: I got the solution. Anytime someone wants the code I'd be happy to provide. Peace.
Topic:
I'm trying an experiment of echoing strings that I receive in my arduino.
So this is the code so far:
byte byteRead = 0;
bool readable = LOW;
char fullString[50];
int index = 0;
void setup() {
Serial.begin(9600);
}
void loop() {
// State 1
if (Serial.available()) {
readable = HIGH; // flag to enter in the next state when there's nothing else to read
byteRead = Serial.read();
fullString[index] = (char)byteRead;
index++;
}
// State 2
if (readable == HIGH && !Serial.available()){
fullString[index] = '\0'; // '\0' to terminate the string
Serial.println(fullString);
// resets variables
index = 0;
readable = LOW;
}
/**
* Somehow a delay prevents characters of the string from having
* a line printed between them.
* Anyways, when the string is too long, a line is printed between
* the first and second characters
*/
delay(5);
}
Somehow this delay in the end prevents the characters of the string from having a line printed between them, like this:
H
e
l
l
o
Nonetheless, when the string is too long, a line is printed between the first and second characters.
Do you know a better way of doing this?
EDIT: Next time I'd appreciate answers from someone who actually KNOWS programming. Not just condescending idiots.

Answer 1

that's my String Echo
#define MAX_BUFFER_SIZE 0xFF
char buffer[MAX_BUFFER_SIZE];
void setup() {
Serial.begin(115200);
buffer[0] = '\0';
}
void loop() {
while (Serial.available() > 0) {
char incomingByte;
size_t i = 0;
do {
incomingByte = Serial.read();
buffer[i++] = incomingByte;
} while (incomingByte != '\0' && i < MAX_BUFFER_SIZE);
if(i > 0){
delay(1000); /// delay for the echo
Serial.write(buffer, i);
}
}
}

Answer 2

You want to echo the string read, so just echo the input.
void setup() {
Serial.begin(9600);
}
void loop() {
int c = Serial.read();
if (c >= 0) Serial.write(c);
}