Not using VBA but just simple excel, can anyone help me find a solution to this problem? Would greatly appreciate it!
I have a list of Names in Sheet 1 like below
-
A
1
sp_abc_Rick
2
sp_abc_Jabba_the
3
sp_abc_Dany
4
sp_random_Rick
5
sp_random_Jabba_the
6
sp_random_Dany
7
sp_constant
8
sp_ripley_art_Dany
9
sp_ripley_art_Jabba_the
10
sp_wakeup
I have a list of Mapping Table in Sheet 2 like below
-
A
B
1
Rick
Morty
2
Jabba_the
Hutt
3
Dany
Dragon
I wish to have a result in Sheet 1, in column B, like below
-
A
B
1
sp_abc_Rick
sp_abc_Morty
2
sp_abc_Jabba_the
sp_abc_Hutt
3
sp_abc_Dany
sp_abc_Dragon
4
sp_random_Rick
sp_random_Morty
5
sp_random_Jabba_the
sp_random_Hutt
6
sp_random_Dany
sp_random_Dragon
7
sp_constant
sp_constant
8
sp_ripley_art_Dany
sp_ripley_art_Dragon
9
sp_ripley_art_Jabba_the
sp_ripley_art_Hutt
10
sp_wakeup
sp_wakeup
To give you a context of the number of rows. Sheet 1 will be bigger with more than 1000 rows. Sheet 2 (Mapping Table) is constant set of rows. Currently it is about 100 rows.
You can use a formula like shown below using LOOKUP(), SEARCH() with SUBSTITUTE()
• Formula used in cell B1
=IFERROR(SUBSTITUTE(A1,LOOKUP(9^9,SEARCH($D$1:$D$3,A1),$D$1:$D$3),
LOOKUP(9^9,SEARCH($D$1:$D$3,A1),$E$1:$E$3)),A1)
There you go. There may have other better solution. This is what I got.
All in column B.
=IFERROR(CONCAT(MID(A1,1,MATCH(1,(CODE(MID(A1,ROW($Z$1:$Z$255),1))<90)*(CODE(MID(A1,ROW($Z$1:$Z$255),1))>=65),FALSE)-1),INDIRECT(CONCAT("sheet2!b", MATCH(MID(A1, MATCH(1,(CODE(MID(A1,ROW($Z$1:$Z$255),1))<90)*(CODE(MID(A1,ROW($Z$1:$Z$255),1))>=65),FALSE), LEN(A1)), Sheet2!$A$1:Sheet2!$A$300, 0)))),A1)
Break down is as follow;
Let's start put things from Column C onward.
Column C, to find the index of the first capital letter from the text.
ref: http://dailydoseofexcel.com/archives/2007/02/21/find-position-of-first-capital-letter-in-a-string/
=MATCH(1,(CODE(MID(A1,ROW($Z$1:$Z$255),1))<90)*(CODE(MID(A1,ROW($Z$1:$Z$255),1))>=65),FALSE)
Column D, cut the name part by using upper case letter index from column C, sp_abc_Jabba_the -> Jabba_the
=MID(A1, C1, LEN(A1))
Column E, search row number from Sheet2 by matching Column D's name with Sheet 2's Column A, this will get matching row number from Sheet2.
=MATCH(D1, Sheet2!$A$1:Sheet2!$A$300, 0)
Column F, get Sheet2's Column B value by the row number from Column E.
=INDIRECT(CONCAT("sheet2!b", E1))
Column G,
Cut "sp_abc_" from "sp_abc_Rick"
Concat "sp_abc_" with Column F's "Morty".
If there is any error, use Column A value as default.
. <- this dot is intentional. please ignore.
=IFERROR(CONCAT(MID(A1,1,C1-1),F1),A1)
Try:
Formula in B1:
=BYROW(A1:A10,LAMBDA(a,LET(b,TEXTBEFORE(a&"|","_"&A12:A14&"|",-1),IFERROR(CONCAT(IF(b&"_"&A12:A14=a,b&"_"&B12:B14,"")),a))))
The concatenation with a "|" would assert we only replace values when at the exact end of the input. Just in case there would be a stray (for example) 'Rick' somewhere before the end.
I need to produce a formula, that can generate a list that follow to the below conditions,
Each letter can only appear in the same column again once the every letter in the list has been used.
If letter is in row 1 column 2 it can't be in row 2 column 1.
The same letter can't be in both columns at the same time.
Example,
List: A,B,C,D
Result,
Column 1 Column2
Row 1 A C
Row 2 B D
C A
D B
A C
Put your list in column A
then put this in the first cell, copy over one and down as far as desired:
=INDEX($A:$A,MOD((ROW(1:1)-1)+(COLUMN(A:A)-1)*2,COUNTA($A:$A))+1)
***1 2 3***
a 2 3
b 3 4
c 4 3
d 5 2
so I know to get the highest value I do
=INDEX(column1, MATCH(MAX(column3), column3, 0))
... which would give me 'b'
now I want to get the second highest value based on the column 3 but because there are two cells with 3 (which is the second highest value) I want to use the one that has the lowest value in column 2 based on those two rows. Is this possible?
Use a 'helper' column that adds column C + (column B ÷ 10) and use a modification of your original formula on that column.
The standard formula in F5 is,
=INDEX(A$2:A$5, MATCH(AGGREGATE(14, 6, D$2:D$5, ROW(1:1)), D$2:D$5, 0))
Fill down as necessary.
I am creating a spreadsheet for my personal use. I need to count the number of times one column's values are equal to an adjacent column's.
Is there any way to do this in Excel without having to modify the formula every time a new row is added?
If you have column A and B now, add column C:
Column A Column B Column C
1 2 =countif(B:B, A1)
2 2
3 1
Then just copy the first value in column C, select the entire column C and paste :)
You will get:
Column C
1
2
0
I am trying to compare two columns in excel, A and B. Column A contains a complete list of customer numbers. Column B contains an incomplete list of the same customer numbers. So if a customer number is in A, but not in B then output that number to column C.
I'd use the MATCH function in combination with ISNA.
If I have the following table
A B C
1 4
2 3
3 1
4 7
5 2 5
6 6
7
I put in column 'A' the full customer list, and in column B is a random ordered partial list. I then put the function in C1 (and the rest of column C):
=IF(ISNA(MATCH(A1,B:B,0)),A1, "")
Now I see the values '5' and '6' only in column C, because those are the only two numbers that don't appear in column B.
In Cel C1 =IF(ISERROR(VLOOKUP(A1,$B$1:$B$10,1,FALSE)),A1,"")
Adjust for row counts and fill down against column A.
I think you're looking for something like this:
=IF(ISERROR(MATCH(A1,B1,0)),A1,"")
Propegate that formula along your new column and it'll reprint the populated Column A when Column B is a no match.
Reference URL: http://support.microsoft.com/kb/213367
(I believe I read the original question wrong, and am going on the assumption that column A and B are already sorted where the values will line up.)