404 when accessing new route - node.js

I'm trying to add a new route (/profile) to my NodeJS Express web application. I've modified my app.js file like this:
var routes = require('./routes/index');
var profile = require('./routes/profile');
app.use('/', routes);
app.use('/profile', profile);
The '/' index path works fine, my issue is with '/profile'. Whenever I try to access it, I get a 404. This is profile.js:
var express = require('express');
var router = express.Router();
router.get('/profile', function(req, res) {
var username = req.session.username;
if(username) {
res.render('profile');
} else {
res.redirect('/login');
}
});
module.exports = router;
I don't understand what I'm doing wrong because in the example express application that is generated, '/users' works fine. I basically copied that format, but it's throwing a 404. Any ideas?

In my profile.js, I had to change my GET request path to this:
router.get('/', function(req, res) {
//code
});
Otherwise, the router would be looking for /profile/profile. When I change it to /, it's just looking for the root of `/profile', or at least that's how I understand it.

To understand what you are doing wrong you should know that Node.js uses middleware functions to route your requests. To simplify you can think about it as a chain of functions.
Middleware is like a plumbing pipe, requests start at the first middleware you define and work their way “down” the middleware stack processing for each path they match.
So with the following statement you added a middleware function to handle any request starting with the root path /profile, and it is a common pattern in Node to use the use method to define the root paths.
app.use('/profile', profile);
The use method is doing part of the routing in your scenario and the statement above will match any route starting with that path, including /profile/all or /profile/12 or even /profile/go/deeper/inside.
However, you want to narrow down that routing to something more specific, so that is why you pass a router middleware function (profile in your case) to match more specific routes instead of all routes starting with /profile.
The profile middleware function is actually the next step in the chain of functions to execute, and it will start from the root path specified in the use statement, which is the reason why you need to start again with / and not with /profile. If you wanted to match a profile by ID you would do:
router.get('/:id', ...)
Which would be concatenated with the base URL (from the /use statement) and would match a request like /profile/2 or /profile/abc.

Related

How do I access URL parameter after i've routed my express app to another file?

My main express server is called app.js in Node.js.
app.use("/login", require(./routes/login));
app.use("/:id", require("./routes/users"));
When I try to access the URL parameter, it returns undefined.
I tried logging req.params:
const express = require('express');
const router = express.Router();
router.get('/dashboard', (req, res) => {
res.send(`Current Ornament Status and Data for ${req.params}`);
});
module.exports = router;
It gives me an empty array.
I suppose that it the parameter is inaccessible in another file after routing. Could you suggest a workaround?
I think you're missing some fundamental bits about express.js routing for this to make sense.
The requires line means it is loading another piece of code. So you need to show us that too.
The :id thing requires a longer explanation.
Let's say I want the server to process the URL /finduser/23
Where 23 can vary, could be just about any number. I am NOT going to write 99 different versions of router.get, right?
router.get("/finduser/1",...
router.get("/finduser/2",...
router.get("/finduser/3",...
No, what we do is turn that into a parameter
router.get("/finduser/:id",...
Then whatever number we pass turns into req.params.id, assume router passes req,res
EX: If we pass URL /finderuser/15, then req.params.id = 15
If you just pass /finduser then req.params.id gets NOTHING.
Full details are available here
http://expressjs.com/en/guide/routing.html#route-parameters
Your example:
router.get('/dashboard', (req, res)
Doesn't have ANY parameters. so req.params.id has nothing.

ExpressJS Applying middleware only to routes in router

I have app where I have public routes and authorized routes. Public routes should go through auth as well, but if auth fails, it doesn't matter.
So I have two routers:
var publicRoutes = express.Router();
var secretRoutes = express.Router();
publicRoutes
.use(auth)
.use(ignoreAuthError);
publicRoutes.get('/public', function(req, res){
res.status(200).send({message: "public"});
});
secretRoutes
.use(auth)
.use(handleAuthError);
secretRoutes.get('/secret', function(req, res){
res.status(200).send({message: "secret"});
});
...
app.use(publicRoutes);
app.use(secretRoutes);
Now everything works fine, but if I change the order of app.use public routes throw auth error. Also I cannot get any 404, 500 etc errors, because they all go through auth errors.
So obviously what is happening is that Router.use() is being applied to all routes with the same root - in this case "/"
Therefore I think if I would use just auth middleware on all routes and then add other middlewares directly to routes it should work fine. But it kind of brakes the point of having multiple Routers for me.
I would expect that if I use Router.use() the middleware will apply only if that particular router matches any routes it has set up, instead of changing behavior of other router.
Do I understand this correctly? Is there any way to handle this without actually having to add middleware to every single route?
Had the same issue, solved thanks to #Explosion Pills comment.
Bad:
app.use(secretRoutes); // router.use calls won't be scoped to "/secret"
app.use(publicRoutes); // public routes will be impacted
Good:
app.use("/secret", secretRoutes); // router.use calls will be scoped to "/secret"
app.use("/public", publicRoutes); // public routes won't be impacted

Determining path in Express router routes

I've set up an express app and using the routing middleware to abstract some routes into a separate include.
I reference them using this style in the app.js:
app.use('/foo', my_urls);
This means "/foo/bar" in the browser is handled as if it's "/bar".
The problem though is that in the router.get("/bar"...) section in the included router file, I need to know the value of the preceding (foo) part. I've set up the route that this "foo" could be anything from an array of values.
Is there any way to know the context of the routing middleware, the preceding part of the path that the routes are acting within? In other words, can I do something like (pretend code here):
router.get('/bar', function(req, res, next) {
res.send(req.path[0]) // foo
});
Solved: Thanks for the answer. I can get the value using this:
router.get('/bar', function(req, res, next) {
res.send(req.baseUrl.splice(1)) // foo
});
express has req.path property so you can know the path but is shows path after parent Router's path (if you have one), so to get parent router path you can use req.baseUrl and req.originalUrl to get full url with queryparam.

Node Express auth status

I have multiple routes, split into different files (my app consists of different "modules", which I maintain in separate folders. For each folder, there is an index.js file in which I manage the routes per module, and I require these in the app.js file).
For every route, I will require to check the auth, and pass the loggedIn status to the header of every page:
//Default variables for the ejs template
var options = {
loggedIn: true
};
res.render("home/home", options);
If the logged in status is true, then the user's name will be displayed. If not, the login / signup labels are displayed.
What is the best way to centralise this, so that I don't need to require the auth script in every of these index.js (route) files?
I need to be able to pass the auth status to the view via the options object (see example).
In your auth, module, use a middleware function. That function can check and store res.locals.loggedIn which will be available for any view that will eventually be rendered. Just make sure the app.use call executes prior to your other routes and it will work properly.
app.use(function auth(req, res, next) {
res.locals.loggedIn = true; // compute proper value here
next();
});
From what I understand you need to do this for every request.One common thing is adding this as middleware so that all the request gets this .
For Example :
var http = require('http');
var connect = require('connect');
var app = connect();
app.use(function(req, res) {
res.end('Hello!');
});
http.createServer(app).listen(3000)
Now for every request , Hello is printed . You could extract this as a module and reuse it across projects. Check here for more details

Express-js wildcard routing to cover everything under and including a path

I'm trying to have one route cover everything under /foo including /foo itself. I've tried using /foo* which work for everything except it doesn't match /foo. Observe:
var express = require("express"),
app = express.createServer();
app.get("/foo*", function(req, res, next){
res.write("Foo*\n");
next();
});
app.get("/foo", function(req, res){
res.end("Foo\n");
});
app.get("/foo/bar", function(req, res){
res.end("Foo Bar\n");
});
app.listen(3000);
Outputs:
$ curl localhost:3000/foo
Foo
$ curl localhost:3000/foo/bar
Foo*
Foo Bar
What are my options? The best I've come up with is to route /fo* which of course isn't very optimal as it would match way too much.
I think you will have to have 2 routes. If you look at line 331 of the connect router the * in a path is replaced with .+ so will match 1 or more characters.
https://github.com/senchalabs/connect/blob/master/lib/middleware/router.js
If you have 2 routes that perform the same action you can do the following to keep it DRY.
var express = require("express"),
app = express.createServer();
function fooRoute(req, res, next) {
res.end("Foo Route\n");
}
app.get("/foo*", fooRoute);
app.get("/foo", fooRoute);
app.listen(3000);
The connect router has now been removed (https://github.com/senchalabs/connect/issues/262), the author stating that you should use a framework on top of connect (like Express) for routing.
Express currently treats app.get("/foo*") as app.get(/\/foo(.*)/), removing the need for two separate routes. This is in contrast to the previous answer (referring to the now removed connect router) which stated that "* in a path is replaced with .+".
Update: Express now uses the "path-to-regexp" module (since Express 4.0.0) which maintains the same behavior in the version currently referenced. It's unclear to me whether the latest version of that module keeps the behavior, but for now this answer stands.
It is not necessary to have two routes.
Simply add (/*)? at the end of your path string.
For example, app.get('/hello/world(/*)?' /* ... */)
Here is a fully working example, feel free to copy and paste this into a .js file to run with node, and play with it in a browser (or curl):
const app = require('express')()
// will be able to match all of the following
const test1 = 'http://localhost:3000/hello/world'
const test2 = 'http://localhost:3000/hello/world/'
const test3 = 'http://localhost:3000/hello/world/with/more/stuff'
// but fail at this one
const failTest = 'http://localhost:3000/foo/world'
app.get('/hello/world(/*)?', (req, res) => res.send(`
This will match at example endpoints: <br><br>
<pre>${test1}</pre>
<pre>${test2}</pre>
<pre>${test3}</pre>
<br><br> Will NOT match at: <pre>${failTest}</pre>
`))
app.listen(3000, () => console.log('Check this out in a browser at http://localhost:3000/hello/world!'))
In array you also can use variables passing to req.params:
app.get(["/:foo", "/:foo/:bar"], /* function */);
For those who are learning node/express (just like me): do not use wildcard routing if possible!
I also wanted to implement the routing for GET /users/:id/whatever using wildcard routing. This is how I got here.
More info: https://blog.praveen.science/wildcard-routing-is-an-anti-pattern/

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