I'm trying to subtract 2 timepoints which excel is registering as negative when it shouldn't be. Time 1= 00:40 and Time 2=00:20 . Time 1- Time 2 should equal 00:20 but Excel seems to think this is a negative number. The formula I have is a bit more complex as it involves a Look Up function and I only have this problem on 2 of the lookup values (Other values are 00:45 and 01:00). Any thoughts would be much appreciated!
Thanks
I deleted one of the lookup values and it's registering the correct time now. Might be because one of the words in the lookup vector/value repeated itself (e.g. a in one cell and a b in a cell further down). I'm guessing Excel got confused? Although both result vectors in this case had the same time (00:20) so don't know what's going on there!
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I am working on the capstone project in of the Google Career Certificate in Data Analytics. I am using Microsoft Excel. I have to calculate the ride length based on the start and end ride times. I've inputted the formula =F2(end time)-D2(start time) which returns the ride length. Going through my entire list I have some areas where the start time is like 11pm and the end time is 1am and this is returning ###### because it is a negative number with the regular formula. I've found a modified formula that can kind of do the conversion I am looking for but it is still a bit problematic. The modified formula is =(F2-D2+(F2<D2))*24 and it seems to give an accurate ride length if I reformat the answer to number. The issue is the rest of my data is in time format and the modified ones are in number format. If I convert the number values to time, the ride length values are inaccurate.
It is tricky to make the numeric value change as well due to me using a formula. I can correct them one by one after I save Excel and it no longer stores the numbers as the formula, but there are lots of data points to change and that would be time consuming. I'm hoping to find a more concise way to solve this problem. Maybe with a better formula.
[Snippet of the chart 1
Just like everything in life, there are multiple ways to achieve things. I would have formatted the date and time into a single cell; but. if you're gathering the data from another source, that's understandable.
A simple IF statement here will work. IF the days are one apart, then take '1' day off the starting time, else do your original formula:
=IF(E4-C4=1,F4-(D4-1),F4-D4)
I'm trying to perform an AVERAGEIFS formula on some data, but there are 2 possible results and as far as I can tell AVERAGEIFS doesn't deal with that situation.
I basically want to have an ELSE inside it.
At the moment I have 2 ranges of data:
The first column only contains values 'M-T' and 'F' (Mon-Thurs and Fri).
The second column contains a time.
The times on the rows with an 'F' value in column 1 are an hour behind the rest.
I want to take an average of all the times, adjusting for the hour delay on Fridays.
So for example I want it to take an average of all the times, but subtract 1 hour from the values which are in a row with an 'F' value in it.
The way I've been doing it so far is by having 2 separate results for each day, then averaging them again for a final one:
=AVERAGEIFS(G3:G172, B3:B172, "M-T")
=AVERAGEIFS(G3:G172, B3:B172, "F")
I want to combine this into just one result.
The closest I can get is the following:
=AVERAGE(IF(B3:B172="M-T",G3:G172,((G3:G172)-1/24)))
But this doesn't produce the correct result.
Any advice?
Try this
=(SUMPRODUCT(G3:G172)-(COUNTIF(B3:B172,"=F")/24))/COUNTIF(B3:B172,"<>""""")
EDIT
Explaining various steps in the formula as per sample data in the snapshot.
SUMPRODUCT(G3:G17) sums up all the value from G3 to G17. It gives a
value of 4.635416667. This after formatting to [h]:mm gives a value
of 111.15
OP desires that Friday time be one hour less. So I have kept one hour less for Friday's in the sample data. Similar SUMPRODUCT on H3:H17 leads to a value of 4.510416667. This after formatting to [h]:mm gives a value
of 108.15. Which is exactly three hours less for three occurrences of Fridays in the sample data.
=COUNTIF(B3:B17,"=F") counts the occurrences of Friday's in the B3:B17 range which are 3 occurrences.Hence 3 hours have to less. These hours are to be represented in terms of 24 hours hence the Function COUNTIF() value is divided by 24. This gives 0.125. Same is the difference of 4.635416667 and 4.510416667 i.e. 0.125
Demonstration column H is for illustrative purposes only. Infact Friday accounted values that is 108.15 in sample data has to be divided by total data points to get the AVERAGE. The occurrences of data points are calculated by =COUNTIF(B3:B17,"<>""""") with a check for empty columns.
Thus 108:15 divided by 15 data points give 7:13 in the answer.
Revised EDIT Based upon suggestions by #Tom Sharpe
#TomSharpe has been kind enough to point the shortcomings in the method proposed by me. COUNTIF(B3:B172,"<>""""") gives too many values and is not advised. Instead of it COUNTA(B3:B172) or COUNT(G3:G172) are preferable. Better Formula to get AVERAGE as per his suggestion gives very accurate results and is revised to:
=AVERAGE(IF(B3:B172="M-T",G3:G172,((G3:G172)-1/24)))
This is an Array Formula. It has to be entered with CSE and further cell to be formatted as time.
If your column of M-T and F is named Day and your column of times is named TIME then:
=SUMPRODUCT(((Day="M-T")*TIME + (Day="F")*(TIME-1/24)))/COUNT(TIME)
One simple solution would be to create a separate column that maps the time column and performs the adjustment there. Then average this new column.
Is that an option?
Ended up just combining the two averageifs. No idea why I didn't just do that from the start:
=((AVERAGEIFS(G$3:G171, $B$3:$B171, "F")-1/24)+AVERAGEIFS(G$3:G171, $B$3:$B171, "M-T"))/2
I'm having problems trying to do this formula and it just doesn't work. Can anyone help me?
=IF(JH2="13",CEILING(JD2/0.68+13,0.5)-0.01,""),IF(AND(JH2="6.95",(JD2/0.68))<50,CEILING(JD2/0.68+3,0.5)-0.01,CEILING(JD2/0.68+6.95,0.5)-0.01),IF(AND(M2="CA",ISNUMBER(SEARCH(S2,"INCONTINENCE"))),CEILING(JD2/0.68+6.95,0.5)-0.01,""))
Just a FYI it reads,
IF Freight price is 13 THEN to Divide the Cost price by .68 and ADD the 13.
IF Freight price is 6.95 AND the Cost Price Divide .68 is LESS than $50 THEN add $3.00 ELSE ADD 6.95.
IF M2 (which is Unit of Measurement) has CA AND Column S2 (which is the category) contains the word "Incontinence" THEN calculate Cost Price Divide .68 and add 6.95 Regardless.
Everything is rounded up.
But can't get the Damn thing to work.
First some nagging and whining.
Unreadable source code.
Reference to cells without provided values.
Now the answer (at least a part of it, depending on me missing something else).
If you start breaking up the formula, you'll notice that the first AND has the condition of equality first (that's correct) but then you'll see that the second condition only is a division, whereas the inequality comparison with 50 is put outside.
I believe that's your error. But that's based on the assumption that I got the formula correctly.
As a general suggestion for working with complex formulas in Excel, I usually do a single step at a time (putting the sub-results in separate columns to verify that they're correct). When done and confirmed, I can merge them into a single one.
Try this, it is untested:
=IFERROR(CEILING(IF(JH2=13,JD2/0.68+13,IF(AND(JH2=6.95,JD2/0.68<50),JD2/0.68+3,IF(JH2=6.95,JD2/0.68+6.95,IF(AND(M2="CA",ISNUMBER(SEARCH("INCONTINENCE",S2))),JD2/0.68+6.95,"")))),0.5)-0.01,"")
I keep a running avg of kids grades in Excel over a 2 week period. The way i have the code now
AVERAGE(OFFSET('1'!E4,COUNTA('1'!D:D)-29,):OFFSET('1'!E4,COUNTA('1'!D:D),))
it returns an error if i don't have 2 weeks of data. I found a way around this by doing this
=IFERROR(AVERAGE(OFFSET('1'!E4,COUNTA('1'!D:D)-29,):OFFSET('1'!E4,COUNTA('1'!D:D),)),IFERROR(AVERAGE(OFFSET('1'!E4,COUNTA('1'!D:D)-28,):OFFSET('1'!E4,COUNTA('1'!D:D),)),IFERROR(AVERAGE(OFFSET('1'!E4,COUNTA('1'!D:D)-27,....
Im Sure there is a better way to do this any help would be appreciated.
As pointed out in the comments - it's difficult to give a definitive answer without some more knowledge - it's not easy to tell, for instance, where the numeric data starts (E4 or E5)?
Firstly you can simplify your original formula which appears to AVERAGE the last 30 rows of data (not sure how 30 rows equates to 2 weeks of data) - you can do that with just:
=AVERAGE(OFFSET('1'!E4,COUNTA('1'!D:D)-29,0,30))
Now I assume the error comes about when COUNTA('1'!D:D) is < 29 so you can simply add an If function which AVERAGES all the data if that function returns a number < 29, i.e.
=IF(COUNTA('1'!D:D)<29,AVERAGE('1'!E4:E33),AVERAGE(OFFSET('1'!E4,COUNTA('1'!D:D)-29,0,30)))
That formula may need some small adjustments to cater for the specifics of your layout but the general approach is valid
I've got a spreadsheet (Office 2007 version of Excel) full of text entries that are negative time values, example "-0:07" as in an employee took 7 mins less to complete a job than expected. I need to perform mathematical calculations on these entries and am looking for a more elegant formula/method than I've come up with so far.
I know about 1904 date system and * or / by 24 to convert back and forth, the problem is getting a formula that will recognize the text entry as a negative time value.
I've tried value(), *1, which both work on the text fields if the number is positive, but the "-" seems to mess those up. Even paste-special/add fails to recognize these as numbers.
Here's what I came up with that gets the job done, but it's just so ugly to me:
=IF(LEFT(E5,1)="-",((VALUE(RIGHT(E5,LEN(E5)-1)))*-1.0),VALUE(E5))
Obviously my text entry is in cell E5 in this example.
This works, so I'm not desperate for a solution, but for educational purposes (and smaller code) I'd like to know if there's a better way to this. Does anyone have a suggestion for something shorter, easier?
Thanks.
P.S. - an interesting tidbit here, I use Excel at work, but not at home, so I uploaded a sample spreadsheet to Google Docs, and it actually handles the Value() command on those entries properly. Weird, huh?
Thanks again for any suggestions.
Excel doesn't handle time spans in cells. It only deals with time. When you do "00:07" it is then converted to 0.0048611 which is the same as Jan 1st 1900 12.07 am. So if you did 2 minutes minus 7 minutes it would give at best 11.55pm.
The way you do it is the only way.