I have 1000 .mp4 files in a folder in linux and the name of those files are like this:
filename_mywebsite.com_.mp4
I need to rename all files with one command
so how i can change
_mywebsite.com_ to _mywebsite2.com_
in all files
so all my files will be
filename_mywebsite2.com_.mp4
Try renaming it as:
rename 's/.com_/2.com_/' filename_mywebsite.com_.mp4
run below rename command in local directory.
rename 's/mywebsite/mywebsite2/' *.mp4
A piece of code to rename all the files with the same prefix and appends incremental value
declare -i x=1
for f in $(find -type f); do
mv -v $f ${f%/*}/change_me_$x ;
x=$x+1;
done
Related
So, i have a given directory, and that directory contains other subdirectories, and every subdirectory can contain a file. I have to change all the files names, so that it will end in ".txt" .
**You can do something like this using bash : and go over all your directories with it **
for f in *.their_current_end;
do
mv -- "$f" "${f%.their_current_end}.txt"
done
another solution would be using : rename in Linux
rename [OPTIONS] perlexpr files
where the rename will rename all the files mentioned like the regex supplied in the perlexpr parameter.
example :
rename 's/.html/.php/' \*.html
I have the following structure:
FolderA
Sub1
Sub2
filexx.csv
filexx.doc
FolderB
Sub1
Sub2
fileyy.csv
fileyy.doc
I want to write a script that will move the .csv files into the folder sub1 for each parent directory (Folder A, Folder B and so on) giving me the following structure:
FolderA
Sub1
filexx.csv
Sub2
filexx.doc
FolderB
Sub1
fileyy.csv
Sub2
fileyy.doc
This is what I have till now but I get the error mv: cannot stat *.csv: No such file or directory
for f in */*/*.csv; do
mv -v "$f" */*/Sub1;
done
for f in */*/*.doc; do
mv -v "$f" */*/Sub2;
done
I am new to bash scripting so please forgive me if I have made a very obvious mistake. I know I can do this in Python as well but it will be lengthier which is why I would like a solution using linux commands.
find . -name "*.csv" -type f -execdir mv '{}' Sub1/ \;
Using find, search for all files with the extension .csv and then when we find them, execute a move command from within the directory containing the files, moving the files to directory Sub1
find . -name "*.doc" -type f -execdir mv '{}' Sub2/ \;
Follow the same principle for files with the extension .doc but this time, move the files to Sub2.
I believe you are getting this error because no file matched your wildcard. When it happens, the for loop will give $f the value of the wildcard itself. You are basically trying to move the file *.csv which does not exist.
To prevent this behavior, you can add shopt -s nullglob at the top of your script. When using this, if no file is found, your script won't enter the loop.
My advise is, make sure you run your script from the correct location when using wildcards like this. But maybe what you meant to do by writing */*/*.csv is to recursively match all the csv files. If that's what you intended to do, this is not the right way to do it.
To recursively match all csv/doc/etc files using native bash you can add shopt -s globstar to the top of your script and use **/*.csv as wildcard
#!/bin/bash
shopt -s globstar nullglob
for f in **/*.csv; do
mv "$f" Destination/ # Note that $f is surrounded by "" to handle whitespaces in filenames
done
You could also use the find (1) utility to achieve that. But if you're planning to do more processing on the files than just moving them, a for loop might be cleaner as you won't have to inline everything in the same command.
Side note : "Linux commands" as you say are actually not Linux commands, they are part of the GNU utilities (https://www.gnu.org/gnu/linux-and-gnu.en.html)
If csv files you want to move are in the top directories (from the point of view of the current directory), but not in the subdirectories of them, then simply:
#!/bin/bash
for dir in */; do
mv -v "$dir"*.csv "${dir}Sub1/"
mv -v "$dir"*.doc "${dir}Sub2/"
done
If the files in all subdirectories are wanted to be moved similarly, then:
shopt -s globstar
for file in **/*.csv; do
mv -v "$file" "${file%/*}/Sub1/"
done
for file in **/*.doc; do
mv -v "$file" "${file%/*}/Sub2/"
done
Note that, the directories Sub1 and Sub2 are relative to the directory where csv and doc files reside.
Lets say i have a folder named Pictures and I want to move or copy all files out of this folder.
However I also want to move and harvest all of the files who are in sub folders so:
Pictures/1.png
Pictures/yolo/2.png
Pictures/yolo/swag/sand/3.png
Pictures/extra/fire/4.png
I want to move or copy all these files to another folder like results so I get:
results/1.png
results/2.png
results/3.png
results/4.png
Only I have no idea in advance what sub folders will be in the Pictures folder.
How can I accomplish this in bash/shell scripts ?
I also appreciate making it file type neutral so any files are harvested from their directories (not only .png like in my example) and I have no idea what the file name will be (I only used 1...4 because i did not have any idea how to name them).
You can do it like this:
find /absolute/path/to/Pictures -type f -name '*.png' -exec mv -i {} /absolute/path/to/results \;
Another option is to use xargs
find /absolute/path/to/Pictures -name '*.png' | xargs -I files mv files /absolute/path/to/results
You can simply copy all files and subdirectories along with their contents using cp's recursive option:
cp -pr <source_path>/* <destination_path>/
But, moving them recursively is a bit tricky, you will need to create tar files of the subdirectories and move them and then untar the tar files in destination path. As this is a complex process, as a workaround, you can copy the files/directories recursively and then delete the files from original path.
cp -pr <source_path>/* <destination_path>/ && rm -rf <source_path>/*
I'm trying write a script in linux. Where I have some csv files in Two different folders(A and B) and then after some processing copy of rejected files are moving to Bad Folder.
SO I want bad files to be deleted from Table A and B which have copied to Bad Folder.
Can you help me to write this script for linux?
Best
lets say name of Bad Folder is 'badFolder' and considering 'A', 'B' and 'badFolder' are in same directory
Steps to delete files from folder A and B:
step 1: change current directory to your 'badFolder'
cd badFolder
step 2: delete identical files
find . -type f -exec rm -f ../A/{} \;
find . -type f -exec rm -f ../B/{} \;
The argument -type f tells to look for files, not directories.
The -exec ... \; argument tells that, once it finds a file in 'badFolder', it should run the command rm -f on its counterpart in the A subdirectory.
Because rm is given with the -f option, it will silently ignore files that don't exist.
Also, it will not prompt before deleting files. This is very handy when deleting a large number of files. However, be sure that you really want to delete the files before running this script.
#!/bin/bash
#Set the working folder in which you want to delete the file
Working_folder=/<Folder>/<path>
cd $Working_folder
#command to delete all files present in folders
rm <filenames seperated by space>
echo "files are deleted"
#if you want to delete all files you can use wild card character
# e.g. command rm *.*
# if you want to delete a particular file say for deleting .csv file you can use command rm *.csv command
Set variables containing the paths of your A, B and BAD directories.
Then you can do something along the lines of
for file in ls ${PATH_TO_BAD}
do
rm ${PATH_TO_A}/$file
rm ${PATH_TO_B}/$file
done
This is iterating over the BAD directory and any file it finds, it deletes from the A and B directories.
I am on a Linux system and I am trying to rename all .jpg files in many subdirectories to sequential filenames, so all the jpeg files in each subdirectory are renamed 0001.jpg, 0002.jpg, etc. I have a 'rename' command that works in a single directory:
rename -n 's/.*/sprintf("%04d",$::iter++ +1).".jpg"/e' *.jpg
I am trying to use it like this:
for i in ls -D; do rename -n 's/.*/sprintf("%04d",$::iter++ +1).".jpg"/e' *.jpg; done
but for output I get this:
*.jpg renamed as 0001.jpg
for each subdirectory. What am I doing wrong?
You need to put the command in backticks (or use the $( ... ) bash syntax) in order
to iterate over its output. Also use the $i variable together with the *.jpg file
name pattern, e.g.
for i in `ls -D`
do
rename -n 's/.*/sprintf("%04d",$::iter++ +1).".jpg"/e' $i/*.jpg
done
however, for this scenario you want to iterate over all the subdirectories, and you are
better of using the find command:
for i in `find . -type d`; do rename ...
It seems to me you've forgot to change a current working directory so it should looks like
for i in *; do
[ -d "$i" ] || continue
pushd "$i"
# rename is here
popd
done