How long is the gap in .mp3 fileformat and is it at the beginning, end or both?
I've tried to google it for an hour and still no answer.
Related
I could really use your help!
A night shift for me begins at 1930 till 2230.
I already have a formula which tells me how long my shift is, but I am looking for a formula to split the time into Day & Night.
For Example:
I had work from 1800 till 2359. or I had work from 0300 till 0700.
I already have a formula which tells me that I have worked for 0559 and 0400 Hours. But I am unable to get it to split into how much of it is Day and how much of it is Night.
I have been scrolling the web, but no luck!
hoping someone can help me out.
Thanks,
Jagdeep
I have a csv file that shows the time stamp like this:
I need to manipulate this csv in python so I'll end up with a 'Time Elapsed' column with millisecond resolution.
Keep in mind this time stamp goes longer than an hour so in Excel the time elapsed column just goes back to zero. I don't want that to happen.
I'm sure I'm not the first person with this issue but before you start flaming me, I have been looking for a few days and I can't find a solution.
That tells me I must be asking the wrong questions. I am new to Pandas/Python and I'm still not familiar with the lingo.
Here is the csv file I am using.
SampleCSV.csv
Before
After
Thanks in advance.
I have a sheet for tracking my hours at work. We also have a time period between the hours of 07:30 & 18:00 where we can accrue 'flex time'. I want to know from my in and out times, how many hours:minutes I have made in flex.
Please can someone help with the calculation?
The standard way of doing these is to use the overlap formula for two intervals
=max(0,min(end1,end2)-max(start1,start2))
So in your case it would be
=MAX(0,MIN(C2,TIMEVALUE("18:00"))-MAX(B2,TIMEVALUE("7:30")))
If some of your time cells contain strings instead of numbers you would need to check for these. One way of doing it is
=IFERROR(MAX(0,MIN(C2+0,TIMEVALUE("18:00"))-MAX(B2+0,TIMEVALUE("7:30"))),0)
If you ever did a night shift including midnight the formula would need further modification.
Fixed my formula to get correct answers. Bit odd but works now!
=C4+IF(A4-TIME(7,30,0)<0,A4-TIME(7,30,0),0)-IF(B4-TIME(18,0,0)>0,B4-TIME(18,0,0),0)
We take the total time then
if our time starts earlier than flex time starts, we ADD the difference between our start time and flex time, which of course will be a negative number
if our end time ends later than flex time ends, we SUBTRACT the difference between our end time and flex time
I need to compute the number of days between two dates using NodaTime, and to do it in a timezone.
The end time is date based with an implied time of midnight at the end of the day. This date is in a timezone.
The start time is the current time, but I am passing it into the function so that the function is testable.
I tried using Period, which seems like the obvious answer, but Period is too granular on one end (when we are on the end day) and not granular enough when we are more than 1 month away.
So if Now is July 9, 5:45pm in America/Toronto and the End Time is Sept 1, 00:00:00, then I would like to be able to calculate 54 days. (assuming I counted the number of days on my calendar correctly. :) )
I figured I would have to handle the sub day problem myself, but it surprised me when I had to figure out how to handle the greater than a month problem.
Is there an obvious way to get the number of days between two times from NodaTime? I have it down to three lines of code using .Net's DateTime and TimezoneInfo classes, but I want to move to NodaTime for all the reasons specified on the site.
Thanks
I should have read the Arithmetic section of the docs more closely before posting.
You can specify which unit you want the math result to be in with a 3rd parameter. Here is what I needed:
Period timeLeft = Period.Between(nowInTz.LocalDateTime, endDate, PeriodUnits.Days);
this is from the docs:
http://nodatime.org/unstable/userguide/arithmetic.html
Hope this helps somebody else in the future.
What is the most efficient way to print out time as HH:MM:SS?
I have it set up where my time is x seconds. Then I calculate the hours, minutes, and left over seconds associated with the x seconds.
Then when I want to print it out as a string onto a figure, I do:
sprintf('Time: %d:%d:%d', hours, minutes, seconds);
Unfortunately, this looks ugly as if I have hours or minutes equal to 0, I get something like 0:0:23.
I suppose I can change the hours, minutes, seconds to a string before doing the sprintf. Is there a more efficient MATLAB way though? Thanks!
The best option for date formatting is datestr, for example:
datestr(now, 'HH:MM:SS')
When it comes to sprintf, then have a look at the formatting parameters. You'll get a better result with zero-padding:
sprintf('Time: %02d:%02d:%02d', hours, minutes, seconds)