I am trying to print a file in remote server through CUPS command , User needs to know the status of job status. How to get a response from that. Here is my code :
#!/usr/bin/perl
my $response = system("lpr -P laserJet123 -o raw -T test_womargin abc.txt");
print $response;
$? returns the response status of system command.
system("lpr -P laserJet123 -o raw -T test_womargin abc.txt");
if ($? == -1) {
print "failed to execute: $!\n";
}
elsif ($? & 127) {
printf "Job failed with signal %d, %s coredump\n",
($? & 127), ($? & 128) ? 'with' : 'without';
}
else {
printf "Job exited with value %d\n", $? >> 8;
}
Related
When i am passing value of a variable declared in jenkins Groovy script its value is not retained in for loop which is running on a remote server. Strange thing is i am able to access the same value outside the for loop.
Here is the sample code i am trying to use
#!/usr/bin/env groovy
def config
def COMMANDS_TO_CHECK='curl grep hello awk tr mkdir bc'
pipeline {
agent {
label "master"
}
stages {
stage ('Validation of commands') {
steps {
script {
sh """
#!/bin/bash
/usr/bin/sshpass -p passwrd ssh user#host << EOF
hostname
echo $COMMANDS_TO_CHECK ---> This is printed
for CURRENT_COMMAND in \$COMMANDS_TO_CHECK
do
echo ${CURRENT_COMMAND} ---> Why This is not printed?
echo \${CURRENT_COMMAND} ----> Why This is not printed?
done
hostname
EOF
exit
"""
}
}
}
}
}
Output
[workspace#3] Running shell script
+ /usr/bin/sshpass -p passwrd ssh user#host
Pseudo-terminal will not be allocated because stdin is not a terminal.
illinsduck01
curl grep hello awk tr mkdir bc
illinsduck01
+ exit
You can wrap sh in """ ... """ as below
#!/usr/bin/env groovy
def config
pipeline {
agent {
label "master"
}
stages {
stage ('Validation of commands') {
steps {
script {
sh """#!/bin/sh
/usr/bin/sshpass -p password ssh username#hostname << EOF
COMMANDS_TO_CHECK="curl grep hello awk tr mkdir bc"
hostname
echo \$COMMANDS_TO_CHECK
for CURRENT_COMMAND in \$COMMANDS_TO_CHECK
do
echo \$CURRENT_COMMAND
which \$CURRENT_COMMAND
status=\$?
if [ \${status} -eq 0 ]
then
echo \${CURRENT_COMMAND} command is OK
else
echo "Failed to find the \${CURRENT_COMMAND} command"
fi
done
hostname
EOF
exit
"""
}
}
}
}
}
This the code I,m trying to execute:
#!/bin/bash
set -e -a
err_report() {
echo "Error on line $1"
}
trap 'err_report $LINENO' ERR
IFS=$'\n'
value=($(cat builds.txt))
prevBuild=${value[0]}
prevBuildDir=$prevBuild
currentBuild=${value[1]}
currentBuildDir=$currentBuild
splitPrevBuild=(${prevBuild//./$'\n'})
splitcurrentBuild=(${currentBuild//./$'\n'})
prevBuildSR=${splitPrevBuild[2]}
prevBuildHF=${splitPrevBuild[3]}
prevBuildNum=${splitPrevBuild[4]}
currentBuildSR=${splitcurrentBuild[2]}
currentBuildHF=${splitcurrentBuild[3]}
currentBuildNum=${splitcurrentBuild[4]}
function change {
cd ~/InstallationFiles/${currentBuildSR}/${currentBuildDir}/${currentBuild}extracted
}
change
pwd
ssh -T atao52#kvs-in-hsglap17.in.kronos.com <<-EOF
$(typeset -f)
change
pwd
echo hi
exit
EOF
How to access the variables as currently, it says
cd: /home/atao52/InstallationFiles///extracted: No such file or directory
I want to create a script that automates a installation on multiple linux hosts.
I login to the hosts using ssh keys and inside the login I want to do a sudo, I am trying to use expect, which I have on the stations but I don't have on the server which runs the script.
How do I do this, this is my try, but no luck with it:
#!/bin/bash
ssh user#station04 <<EOF
expect -d -c "
send \"sudo ls\"
expect {
\"password:\" { send '1234'; exp_continue }
\"$user#\"{
send "exit\r"
}
default {exit 1}
}"
EOF
exit
The result:
send: sending "sudo ls" to { exp0 }
expect: does "" (spawn_id exp0) match glob pattern "password:"? no
expect: read eof
expect: set expect_out(spawn_id) "exp0"
expect: set expect_out(buffer) ""
argv[0] = expect argv[1] = -d argv[2] = -c argv[3] =
send "sudo ls\r"
expect {
"password:" { send '1234'; exp_continue }
"#"{
send exitr
}
default {exit 1}
}
set argc 0
set argv0 "expect"
set argv ""
A.K
What about this? <- just make sure of the expected prompts.
#!/bin/bash
expect <<'END'
spawn ssh user#station04
expect "password:"
send "$pw\r"
expect "#"
send "sudo ls\r"
END
I suggest you would use public key authentication for the ssh part, then just use something like:
ssh -t username#server-ip -C "echo sudo-password | /usr/bin/sudo -S ls"
You got the usage of expect not quite right - don't send a command; rather spawn the command and send just its input. So, your script becomes:
ssh … <<EOF
expect -d -c "
spawn sudo ls
expect -nocase password: { send 1234\r }
expect eof
"
exit
EOF
i am using a perl script for unzipping a zip file by crontab. The script is working properly if i execute it manually. but whenever i set it in cron the script does not work any more. i have tested cron setting other script files are working from cron only this zip extracting script is not working .
Script is as follows :
#!/usr/bin/perl
use IO::Uncompress::Unzip qw(unzip $UnzipError);
$dir = '/root/perl';
open (han2, "ls -l $dir/*.zip |awk '{print \$9}'|");
#array1 = <han2>;
chomp(#array1);
for ($i=0;$i<=$#array1;$i++) {
$zipfile = $array1[$i];
$u = new IO::Uncompress::Unzip $zipfile
or die "Cannot open $zipfile: $UnzipError";
die "Zipfile has no members"
if ! defined $u->getHeaderInfo;
for ( $status = 1; $status > 0; $status = $u->nextStream) {
$name = $u->getHeaderInfo->{Name};
warn "Processing member $name\n" ;
if ($name =~ /\/$/) {
mkdir $name;
}
else {
unzip $zipfile => $name, Name => $name
or die "unzip failed: $UnzipError\n";
}
}
}
Crontab setting :
34 14 * * * /root/perl/./unzip.pl > /dev/null 2>&1
Please help me to do this task by cronjob
When cron executes your script, the current directoy probably won't /root/perl. Try chdir($dir) after you set $dir, or use full pathnames where required:
$u = new IO::Uncompress::Unzip "$dir/$zipfile"
or die "Cannot open $zipfile: $UnzipError";
mkdir "$dir/$name";
unzip "$dir/$zipfile" => "$dir/$name" ...
Changing to the correct directory is probably easier.
The following bash script doesn't work because command 'expect' always return 0 regardless which exit code of the remote script /tmp/my.sh returns.
any idea to make it work? thanks.
#!/usr/bash
user=root
passwd=123456abcd
host=10.58.33.21
expect -c "
spawn ssh -o StrictHostKeyChecking=no -l $user $host bash -x /tmp/my.sh
expect {
\"assword:\" {send \"$passwd\r\"}
eof {exit $?}
}
"
case "$?" in
0) echo "Password successfully changed on $host by $user" ;;
1) echo "Failure, password unchanged" ;;
2) echo "Failure, new and old passwords are too similar" ;;
3) echo "Failure, password must be longer" ;;
*) echo "Password failed to change on $host" ;;
esac
Edited at 10:23 AM 11/27/2013
Thanks for the comments. Let me emphasis the problem once again,
The main script is supposed to run on linux server A silently, during which it invokes another script my.sh on server B unattended. The question is how to get exit code of my.sh?
That's why I cannot leverage ssl_key approach in my case, which requires at least one time configuration.
#!/usr/bin/expect
set user root
set passwd 123456abcd
set host 10.58.33.21
set result_code 255
# exp_internal 1 to see internal processing
exp_internal 0
spawn ssh -o StrictHostKeyChecking=no -l $user $host bash -x /tmp/my.sh && echo aaa0bbb || echo aaa$?bbb
expect {
"assword:" {send "$passwd\r"; exp_continue}
-re "aaa(.*)bbb" {set result_code $expect_out(1,string)}
eof {}
timeout {set result_code -1}
}
switch $result_code {
0 { puts "Password successfully changed on $host by $user" }
1 { puts "Failure, password unchanged" }
2 { puts "Failure, new and old passwords are too similar" }
3 { puts "Failure, password must be longer" }
-1 { puts "Failure, timeout" }
default { puts "Password failed to change on $host" }
}
exit $result_code