I am writing a web application that supports multiple languages. What I am doing is passing strings to a translator class and it will perform the translation. Now I need to add some long text in my templates and I would like to have it on multiple lines for readability.
- var longText = 'Some really long text ... ';
// ...
p #{i18n.tr(longText)}
I would like to do something like
- var longText = 'Some text ' +
- 'some other text'
// ...
p #{i18n.tr(longText)}
Unfortunatly jade does not like that.
Is it possible to have strings on multiple lines in jade?
According to this forum, it is undocumented but ending a line in a backslash allows a string to continue onto the next line.
https://github.com/jadejs/jade/issues/1447
Related
I'm building a command parser and I've successfully managed to split strings into separate words and get it all working, but the one thing I'm a bit stumped at is how to remove all punctuation from the string. Users will input characters like , . ! ? often, but with those characters there, it doesn't recognize the word, so any punctuation will need to be removed.
So far I've tested this:
func process_command(_input: String) -> String:
var words:Array = _input.replace("?", "").to_lower().split(" ", false)
It works fine and successfully removes question marks, but I want it to remove all punctuation. Hoping this will be a simple thing to solve! I'm new to Godot so still learning how a lot of the stuff works in it.
You could remove an unwantes character by putting them in an array and then do what you already are doing:
var str_result = input
var unwanted_chars = [".",",",":","?" ] #and so on
for c in unwanted_chars:
str_result = str_result.replace(c,"")
I am not sure what you want to achieve in the long run, but parsing strings can be easier with the use of regular expressions. So if you want to search strings for apecific patterns you should look into this:
regex
Given some input, which I'll just write here as example:
var input := "Hello, It's me!!"
We want to get a modified version where we have filtered the characters:
var output := ""
We need to know what we will filter. For example:
var deny_list := [",", "!"]
We could have a list of things we accept instead, you would just flip a conditional later on.
And then we can iterate over the string, for each character decide if we want to keep it, and if so add it to the output:
for position in input.length():
var current_character := input[position]
if not deny_list.has(current_character):
output += current_character
Spaces are useful to indent urls, sql queries to make it more readable.
Is there a way to remove characters from a const string at compile time in golang ?
ex: (runtime version)
const url = `https://example.com/path?
attr1=test
&attr2=test
`
// this is the code to be replaced
urlTrim := strings.Replace(
strings.Replace(url, "\n", "", -1)
)
Constant expressions cannot contain function calls (except a few built-in functions). So what you want cannot be done using a raw string literal.
If your goal with using multiple lines is just for readability, simply use multiple literals and concatenate them:
const url = "https://example.com/path?" +
"attr1=test" +
"&attr2=test"
Try it on the Go Playground.
See related question: Initialize const variable
I am wondering is there any way to replace this type of value in string
https://farm5.staticflickr.com/4796/39790122335_bdc207b259_o.jpg https://farm5.staticflickr.com/4776/39790122225_c8e96339fa.jpg
What i want is that replace the right side of URL and just show the left side there is little space between them.
You can do that in many different ways, using many different languages.
For example, this is how you can do it with JavaScript
var str = 'https://farm5.staticflickr.com/4796/39790122335_bdc207b259_o.jpg https://farm5.staticflickr.com/4776/39790122225_c8e96339fa.jpg'
str = str.split(' ')
str = str[0]
it can be easily done using the split function.
First assign the url to a Variable
Python
theurl = 'https://farm5.staticflickr.com/4796/39790122335_bdc207b259_o.jpg https://farm5.staticflickr.com/4776/39790122225_c8e96339fa.jpg'
each_url = theurl.split()
now your new variable each url is a list of objects containing all the URLS
i.e each_url = ['https://farm5.staticflickr.com/4796/39790122335_bdc207b259_o.jpg ', 'https://farm5.staticflickr.com/4776/39790122225_c8e96339fa.jpg']
the Split function works in pretty different Programming Languages
though in some like Javascript you might have to specify split as split(' ')
showing you are splitting by spaces
I am currently attempting to parse data that is sent from an outside source serially. An example is as such:
DATA|0|4|7x5|1|25|174-24|7x5|1|17|TERW|7x5|1|9|08MN|7x5|1|1|_
This data can come in many different lengths, but the first few pieces are all the same. Each "piece" originally comes in with CRLF after, so I've replaced them with string.gsub(input,"\r\n","|") so that is why my input looks the way it does.
The part I would like to parse is:
4|7x5|1|25|174-24|7x5|1|17|TERW|7x5|1|9|08MN|7x5|1|1|_
The "4" tells me that there will be four lines total to create this file. I'm using this as a means to set the amount of passes in the loop.
The 7x5 is the font height.
The 1 is the xpos.
The 25 is the ypos.
The variable data (172-24 in this case) is the text at these parameters.
As you can see, it should continue to loop this pattern throughout the input string received. Now the "4" can actually be any variable > 0; with each number equaling a set of four variables to capture.
Here is what I have so far. Please excuse the loop variable, start variable, and print commands. I'm using Linux to run this function to try to troubleshoot.
function loop_input(input)
var = tonumber(string.match(val, "DATA|0|(%d*).*"))
loop = string.match(val, "DATA|0|")
start = string.match(val, loop.."(%d*)|.*")
for obj = 1, var do
for i = 1, 4 do
if i == 1 then
i = "font" -- want the first group to be set to font
elseif i == 2 then
i = "xpos" -- want the second group to be set to xpos
elseif i == 3 then
i = "ypos" -- want the third group to be set to ypos
else
i = "txt" -- want the fourth group to be set to text
end
obj = font..xpos..ypos..txt
--print (i)
end
objects = objects..obj -- concatenate newly created obj variables with each pass
end
end
val = "DATA|0|4|7x5|1|25|174-24|7x5|1|17|TERW|7x5|1|9|08MN|7x5|1|1|_"
print(loop_input(val))
Ideally, I want to create a loop that, depending on the var variable, will plug in the captured variables between the pipe deliminators and then I can use them freely as I wish. When trying to troubleshoot with parenthesis around my four variables (like I have above), I receive the full list of four variables four times in a row. Now I'm having difficulty actually cycling through the input string and actually grabbing them out as the loop moves down the data string. I was thinking that using the pipes as a means to delineate variables from one another would help. Am I wrong? If it doesn't matter and I can keep the [/r/n]+ instead of each "|" then I am definitely all for that.
I've searched around and found some threads that I thought would help but I'm not sure if tables or splitting the inputs would be advisable. Like these threads:
Setting a variable in a for loop (with temporary variable) Lua
How do I make a dynamic variable name in Lua?
Most efficient way to parse a file in Lua
I'm fairly new to programming and trying to teach myself. So please excuse my beginner thread. I have both the "Lua Reference Manual" and "Programming in Lua" books in paperback which is how I've tried to mock my function(s) off of. But I'm having a problem making the connection.
I thank you all for any input or guidance you can offer!
Cheers.
Try this:
val = "DATA|0|4|7x5|1|25|174-24|7x5|1|17|TERW|7x5|1|9|08MN|7x5|1|1|_"
val = val .. "|"
data = val:match("DATA|0|%d+|(.*)$")
for fh,xpos,ypos,text in data:gmatch("(.-)|(.-)|(.-)|(.-)|") do
print(fh,xpos,ypos,text)
end
I'm trying to read a string in a specific format
RealSociedad
this is one example of string and what I want to extract is the name of the team.
I've tried something like this,
houseteam = sscanf(str, '%s');
but it does not work, why?
You can use regexprep like you did in your post above to do this for you. Even though your post says to use sscanf and from the comments in your post, you'd like to see this done using regexprep. You would have to do this using two nested regexprep calls, and you can retrieve the team name (i.e. RealSociedad) like so, given that str is in the format that you have provided:
str = 'RealSociedad';
houseteam = regexprep(regexprep(str, '^<a(.*)">', ''), '</a>$', '')
This looks very intimidating, but let's break this up. First, look at this statement:
regexprep(str, '^<a(.*)">', '')
How regexprep works is you specify the string you want to analyze, the pattern you are searching for, then what you want to replace this pattern with. The pattern we are looking for is:
^<a(.*)">
This says you are looking for patterns where the beginning of the string starts with a a<. After this, the (.*)"> is performing a greedy evaluation. This is saying that we want to find the longest sequence of characters until we reach the characters of ">. As such, what the regular expression will match is the following string:
<ahref="/teams/spain/real-sociedad-de-futbol/2028/">
We then replace this with a blank string. As such, the output of the first regexprep call will be this:
RealSociedad</a>
We want to get rid of the </a> string, and so we would make another regexprep call where we look for the </a> at the end of the string, then replace this with the blank string yet again. The pattern you are looking for is thus:
</a>$
The dollar sign ($) symbolizes that this pattern should appear at the end of the string. If we find such a pattern, we will replace it with the blank string. Therefore, what we get in the end is:
RealSociedad
Found a solution. So, %s stops when it finds a space.
str = regexprep(str, '<', ' <');
str = regexprep(str, '>', '> ');
houseteam = sscanf(str, '%*s %s %*s');
This will create a space between my desired string.