Optimal to lookup and display column/row names from a table of binary data - excel

Question

Job Coach ConsumerName Monthly General Goals
Anna Joe 0 0 0
Sam John 0 0 0
Veron Jane 0 0 0
Bill Jack 1 1 1
Anna Jill 1 1 1
Jim 0 0 0
Bill Jiang 1 1 1
Jolly 0 1 1
Sam Jiant 0 0 0
Jap 0 1 1
Joule 1 1 1
Aardvark 0 1 0
Drake Darding 0 0 0
Hello, as you can see above I have two columns of strings; one column is "job coach" the other is "consumer name". There are three columns of 1's and 0's; monthly, general, and goals.
I'm trying to find the specific pattern of 1's and 0's in each of the rows, and to report it. For instance, the data says:
Consumer Jolly still has a a monthly which needs to be completed;
Consumer Aardvark still has a monthly which needs to be completed;
Consumer Aardvark still has a monthly and a goals which needs to be completed.
Lookup doesn't really work, because it only will return the first instance of the corresponding variable and not additionally instances.
I've tried a index function like this:
{=INDEX($C$2:$E$14,SMALL(IF($C$2:$C$14=0,ROW($C$2:$C$14)),ROW(1:1)),3)}
But that only would look up for a single column at a time, which makes the report rather cumbersome. I'm open to doing a loop in excel without formulas, however its not a simple looping formula, because I'm trying to look at each cell and to output the specific column name.
Any thoughts on how to best do it?

Answer 1

It's not exactly clear what the condition you want to check is, but if you want to check for a specific given pattern and return the customer name you can use this adjusted formula:
=INDEX($B$2:$B$14,SMALL(IF($C$2:$C$14&$D$2:$D$14&$E$2:$E$14="010",ROW($C$2:$C$14)-1),ROW(1:1)),1)
In your formula you checked only the first binary column and returned the last. You also had a mistake of returning the row number and not the index in the list which is row-1 in your case.
So notice:
The INDEX returns values from column B.
The IF checks a pattern of C&D&E equals a pattern like 010 which can be changed or set to a reference.
Then return the ROW()-1 in case your list starts at row 2, to return the index in the data and not the actual row.