Php script as daemon - linux

Question

I am new to php daemons. I am using the below script to fire Daemon.php script. But i am getting error while executing this below bash script via shell
The error is,
exit: 0RETVAL=0: numeric argument required
Please help me resolve this error
#!/bin/bash
#
# /etc/init.d/Daemon
#
# Starts the at daemon
#
# chkconfig: 345 95 5
# description: Runs the demonstration daemon.
# processname: Daemon
# Source function library.
#. /etc/init.d/functions
#startup values
log=/var/log/Daemon.log
#verify that the executable exists
test -x /home/godlikemouse/Daemon.php || exit 0RETVAL=0
#
# Set prog, proc and bin variables.
#
prog="Daemon"
proc=/var/lock/subsys/Daemon
bin=/home/godlikemouse/Daemon.php
start() {
# Check if Daemon is already running
if [ ! -f $proc ]; then
echo -n $"Starting $prog: "
daemon $bin --log=$log
RETVAL=$?
[ $RETVAL -eq 0 ] && touch $proc
echo
fi
return $RETVAL
}
stop() {
echo -n $"Stopping $prog: "
killproc $bin
RETVAL=$?
[ $RETVAL -eq 0 ] && rm -f $proc
echo
return $RETVAL
}
restart() {
stop
start
}
reload() {
restart
}
status_at() {
status $bin
}
case "$1" in
start)
start
;;
stop)
stop
;;
reload|restart)
restart
;;
condrestart)
if [ -f $proc ]; then
restart
fi
;;
status)
status_at
;;
*)
echo $"Usage: $0 {start|stop|restart|condrestart|status}"
exit 1
esac
exit $?
exit $RETVAL

Answer 1

This line produces the error:
test -x /home/godlikemouse/Daemon.php || exit 0RETVAL=0
If you want to set the the value of RETVAL to 0 you first need to remove the 0 as you can not have variables that start with a number.
Then you remove the value set from the second statement so it will exit in case Daemon.php does not exist.
test -x /home/godlikemouse/Daemon.php || exit
You can also remove the 2 empty echo statements inside the start and stop functions as the do nothing.
There are also errors in the case statement. You need to quote the case options and can remove the last exit block as the exit $? will trigger the exit before.
case "$1" in
"start")
start
;;
"stop")
stop
;;
"reload"|"restart")
restart
;;
"condrestart")
if [ -f $proc ]; then
restart
fi
;;
"status")
status_at
;;

Answer 2

There is several syntax and logic errors in this script presented. To highlight several:
echo $"Usage (should be just echo "Usage ..." since the string in ".." is not a variable
Double exit statements, the second one for $RETVAL is never ran.
exit 0RETVAL is not the same as exit $RETVAL, and one should just be using exit 1 instead to denote an error, exit 0 means the script ran correctly
$prog is defined but never used
test -x is to check for executable bit enabled in the given path. test -f is safer when testing for a file, test -d safer for testing directories, and test -L is safer when testing symlinks. Combine the test -f and test -x to ensure there is no race conditions or worst. (example: (test -f /home/godlikemouse/Daemon.php && test -x /home/godlikemouse/Daemon.php) || exit 1))
Further details on creating sysv init scripts can be read at http://refspecs.linuxbase.org/LSB_3.0.0/LSB-generic/LSB-generic/iniscrptact.html and bash scripting can be read at http://www.tldp.org/LDP/abs/html/index.html. It is strongly encouraged to learn both before writing system control programs such as init scripts.