I have this file named checkinout100.php and need to copy it to another 100 files following the numbered sequence like checkinout101.php, checkinout102.php and so on until 200.
I've been looking to do it with seq but can't figure it out on my own.
Thanks.
NOTE: Has nothing to do with webpages. It's an Asterisk PBX (Yeastar), I need one of those files per extension (link with hotel software).
You can use seq in the following way:
for n in $(seq 101 200) ; do
cp checkinout100.php checkinout$n.php
done
Related
I have two folders each with several files.
Folder 1:
abc_1600_efg.xlsx
abc_1601_efg.xlsx
abc_1602_efg.xlsx
abc_1603_efg.xlsx
Folder 2:
ijk_1600_xyz.xlsx
ijk_1601_xyz.xlsx
ijk_1602_xyz.xlsx
ijk_1603_xyz.xlsx
lmn_1600_tuv.xlsx
lmn_1601_tuv.xlsx
lmn_1602_tuv.xlsx
lmn_1603_tuv.xlsx
Assuming the files in each folder are randomized, anyone have any ideas on how to use python 3.x to copy from file 'abc_1600_efg.xlsx' in folder 1 then have python search for the corresponding file in folder 2 ('ijk_1600_xyz.xlsx'). The number portion of the title is the key that needs to be matched. Then I want to paste the data into the file 'ijk_1600_xyz.xlsx' (folder two has two files with the same number 1600 but I need to find just the 'ijk_1600_xyz' file).
I want to loop this so that this would be done for every file in folder 1 starting at 1600 then 1601 then 1602 etc. I have the copy and paste portion finished I'm just stuck on the search and match portion.
Thank you in advance.
I haven't checked it
but something like:
import re,os
for file1 in os.listdir(folder1):
match=re.match('..._(\d+)_.*'),file1).group(1)
for file2 in os.listdir(folder2):
if ('_'+match+'_' in file2) :
... copy ...
Anyway, you should know how to adapt to these situations.
I have no previous programming experience. I know this question has been asked before or the answer is out there but I, for the life of me, cannot find it. I have searched google for hours trying to figure this out. I am working on a Red Hat Linux computer and it is in bash.
I have a directory of files 0-500 in /directory/.
They are named as such,
/directory/filename_001, /directory/filename_002, and so forth.
After running my analysis for my research, I have a listofnumbers.txt (txt file, with each row being a new number) of the numbers that I am interested in. For example,
015
124
187
345
412
A) Run a command from the list of files the files from the list of numbers? Our code looks like this:
g09slurm filename_001.com filename_001.log
Is there a way to write something like:
find value (row1 of listofnumbers.txt) then g09slurm filename_row1value.com filename_row1value.log
find value (row2 of listofnumbers.txt) then g09slurm filename_row2value.com filename_row2value.log
find value (row3 of listofnumbers.txt) then g09slurm filename_row3value.com filename_row2value.log
etc etc
B) Move the selected files from the list to a new directory, so I can rename them sequentially, then run a sequential number command?
Thanks.
First, read the list of files into an array:
readarray myarray < /path/to/filename.txt
Next, we'll get all the filenames based on those numbers, and move them
cd /path/to/directory
mv -t /path/to/new_directory "${myarray[#]/#/filename_}"
After this... honestly, I got bored. Stack Overflow is about helping people who make a good start at a problem, and you've done zero work toward figuring this out (other than writing "I promise I tried google").
I don't even understand what
Run a command from the list of files the files from the list of numbers
means.
To rename them sequentially (once you've moved them), you'll want to do something based on this code:
for i in $(ls); do
*your stuff here*
done
You should be able to research and figure stuff out. You might have to do some bash tutorials, here's a reasonable starting place
For example I want to download data from:
http://nimbus.cos.uidaho.edu/DATA/OBS/
with the link:
http://nimbus.cos.uidaho.edu/DATA/OBS/pr_1979.nc
to
http://nimbus.cos.uidaho.edu/DATA/OBS/pr_2015.nc
How can I write a script to download all of them? with wget?and how to loop the links from 1979 to 2015?
wget can take file as input which contains URLs per line.
wget -ci url_file
-i : input file
-c : resume functionality
So all you need to do is put the URLs in a file and use that file with wget.
A simple loop like Jeff Puckett II's answer will be sufficient for your particular case, but if you happen to deal with more complex situations (random urls), this method may come in handy.
Probably something like a for loop iterating over a predefined series.
Untested code:
for i in {1979..2015}; do
wget http://nimbus.cos.uidaho.edu/DATA/OBS/pr_$i.nc
done
I have a large directory of files (100+) that I'd like to pass through a program via the terminal.
The files are paired and all follow a naming scheme like such:
TS-8_S53_L001_R1_001.fastq
TS-8_S53_L001_R2_001.fastq
RS-9_S54_L001_R1_001.fastq
RS-9_S54_L001_R2_001.fastq
And the program execution looks like:
Seqprogram -i1 Blah_R1_001.fastq -i2 Blah_R2_001.fastq -o Blah_paired.fastq
All of these files are in one directory.
I'd like to able to run the program on all of the files, using the files paired together in the proper sequence (R1 files are passed through i1, the R1 and R2 files have the same base name) and the output file (-o) is saved under the base name with some identifier attached ("_paired", etc).
I've envisioned on how I'd do this over Python; however, I am trying to get better with BASH.
I'm familiar with how one might call multiple files into a single command; i.e., uncompressing all .gz files in a particular directory
gunzip "*.gz"
But this command has two inputs, and the inputs must be ordered, so the wildcard scheme isn't sufficient.
Thanks
Use a wildcard to get one file of the pair, and then use parameter substitution to get the other corresponding filenames.
for i1 in *_R1_001.fastq; do
i2=${i1/R1_001/R2_001}
paired=${i1/R1_001/paired}
Seqprogram -i1 "$i1" -i2 "$i2" -o "$paired"
done
The easiest way to do this is to match a single one of the three filenames patterned, and to modify it to get the other two.
That is to say:
for r1file in *_R1_*.fastq; do
r2file=${r1file/_R1_/_R2_}
pairfile=${r1file%_R1_*}_paired.fastq
Seqprogram -i1 "$r1file" -i2 "$r2file" -o "$pairfile"
done
I have ~ 60K bibliographic records, which can be identified by system number. These records also hold full-text (individudal text files named by system number).
I have lists of system numbers in bunches of 5K and I need to find a way to copy only the text files from each 5K list.
All text files are stored in a directory (/fulltext) and are named something along these lines:
014776324.txt.
The 5k lists are plain text stored in separated directories (e.g. /5k_list_1, 5k_list_2, ...), where each system number matches to a .txt file.
For example: bibliographic record 014776324 matches to 014776324.txt.
I am struggling to find a way to copy into the 5k_list_* folders only the corresponding text files.
Any idea?
Thanks indeed,
Let's assume we invoke the following script this way:
./the-script.sh fulltext 5k_list_1 5k_list_2 [...]
Or more succinctly:
./the-script.sh fulltext 5k_list_*
Then try using this (totally untested) script:
#!/usr/bin/env bash
set -eu # enable error checking
src_dir=$1 # first argument is where to copy files from
shift 1
for list_dir; do # implicitly consumes remaining args
while read bibliographic record sys_num rest; do
cp "$src_dir/$sys_num.txt" "$list_dir/"
done < "$list_dir/list.txt"
done