Suppose we have 2 files
First.txt
123
456
And Second.txt
789;123
123;def
482;xaq
What i need is to find the lines in the second file only containing entries of the first file in first column (token 1, delim ; ).
This is what i need:
Output.txt
123;def
Of course,
findstr /g:first.txt second.txt
will output both lines:
789;123
123;def
Any idea how i can mix findstr and for /f to get the needed output?
Thank you!
If all of the elements in the first column are of the same length, then the simple answer would be
findstr /b /g:first.txt second.txt
Note however that if first.txt contains a line 12 then this would match 123;abc and 129;pqr in the second file.
You can take advantage of the super-limited regex capabilities of findstr and compare each line of first.txt to only the very beginning of each line of second.txt.
#echo off
for /F %%A in (first.txt) do findstr /R /C:"^%%A;" second.txt
The /R flag means that the search string should be treated as a regular expression. The ^ in the search string means that %%A comes at the very beginning of the line. The ; is a literal semicolon that will prevent the 123 line from picking up 1234;abcd in second.txt.
Without executing a separate findstr for each value and to avoid the problem with partial matches at the start of the line, you can try with
#echo off
setlocal enableextensions disabledelayedexpansion
( cmd /q /c"(for /f "delims=" %%a in (first.txt) do echo(%%a;)"
) | findstr /g:/ /l /b second.txt
What it does is read first.txt and echo each line with the delimiter. This output is retrieved by the findstr using /g:/ to use the standard input as the source for the elements to match, that will be considered as literals (/l) at the start of the line (/b) in the second.txt file
Is the general form for CSV. Note in batch %A becomes %%A.
for /f "delims=," %A in (csv.txt) do findstr /c:"%A" file2.txt
Here's the output
C:\Users\User>for /f "delims=," %A in (csv.txt) do findstr /c:"%A" csv1.txt
C:\Users\User>findstr /c:"55" csv1.txt
55,61,hi there, Good
C:\Users\User>findstr /c:"60" csv1.txt
54,60,hi there, Bad
C:\Users\User>findstr /c:"Bad" csv1.txt
54,63,hi there, Bad
54,60,hi there, Bad
C:\Users\User>findstr /c:"55" csv1.txt
55,61,hi there, Good
Contents of two files.
55,60
60,60
Bad,60
55,60
and
55,61,hi there, Good
54,62,hi there, Good
54,63,hi there, Bad
54,60,hi there, Bad
Related
So far I have this:
#ECHO OFF
dir *.txt /c /b /on > content.txt
Which gives output:
file1.txt
file2.txt
file3.txt
But I need it like this, separated with semicolon on each line:
file1.txt;
file2.txt;
file3.txt;
I assume I probably need to write for loop and add string ";" somewhere, but I don't know where or how to do this. Or is there a way to just set a specific delimiter?
Edit:
My usecase changed, I thought it would be better if there are files in subfolders listed as well, but "/" should be replaced with space " ".
Example output:
file1.txt;
file2.txt;
subfolder1 file1.txt;
subfolder2 file1.txt;
Note that I do not want the full parent path, only subfolders.
Quick single line batch-file answer:
#(For /F Tokens^=*^ Delims^=^ EOL^= %%G In ('Dir "*.txt" /A:-D /B /O:N 2^>NUL') Do #Echo %%G;) 1>"content.log"
…and in cmd:
(For /F Tokens^=*^ Delims^=^ EOL^= %G In ('Dir "*.txt" /A:-D /B /O:N 2^>NUL') Do #Echo %G;) 1>"content.log"
I have decided to output to a .log file, so that the listing doesn't include itself.
Please use the built-in help to learn how each command works.
When you read the help information, please be aware that a 'simple' for loop will not pick up all files, it will ignore all hidden files for instance. Also despite any first impressions you may have from testing, the order of files returned, depends upon both the file system and type. The dir command is the most efficient way of ensuring that sort order.
[EDIT /]
Here is a batch-file solution, (as that's what you posted as an answer), for your New and completely different question.
#(For /F Tokens^=*^ Delims^=^ EOL^= %%G In ('Dir "*.txt" /A:-D /B /O:N /S 2^>NUL') Do #(Set "FileName=%%~dpG" & SetLocal EnableDelayedExpansion & Set "Filename=!FileName:~,-1!" & For %%H In ("!FileName:%__CD__%=!") Do #EndLocal & Echo %%~H %%~nxG;)) 1>"content.log"
In future, when you have existing answers to your asked question, do not change that question when not only the main command is different, but the intended result format too.
a Simple for loop will do:
#(for %%i in (*.txt) do #echo %%i;)>"content.txt"
That will however also echo the content of contents.txt to itself if it exists, so you can exclude it.
#(for %%i in (*.txt) do #if /i not "%%~i" == "content.txt" #echo %%i;)>"content.txt"
if the plan is to iterate through subdirs as well, run for /R
I found a partial solution to list subfolders, excluding parent path. It is not perfect (for loop is not accurate as mentioned in above comments, neither I am happy with pushd command), but works. I left "space" in place of \ because thats how I need it.
#echo off
setlocal enabledelayedexpansion
pushd "c:\users\documents\"
(
for /r %%a in (*.txt) do (
set x=%%a
set x=!x:%cd%=!;
echo !x:\= !
)
)>filelist.log
popd
Code explanation:
First I remove the parent path with set x=!x:%cd%=!; (exclamation marks replace the %, see enabledelayedexpansion help) and then remove the slashes when echoing.
I've searched a long time and didn't find something useful for my problem. It may sound simple, I would be very happy if somebody could help me:
I want to write a batch script, which proves every string in a textfile whether it contains a specific substring. If this is the case, the whole string, which contains this substring, should be printed out.
The strings, I'm looking for, are surrounded by double quotes.
My code just works for all lines of my textfile, but I need it for all strings.
Thx in advance!
#echo off
setlocal enableextensions enabledelayedexpansion
for /f "delims=" %%A in ('findstr "somesubstring" "textfile.txt"') do (
echo %%A
)
Perhaps is this what you want?
#echo off
setlocal enabledelayedexpansion
set "substring=somesubstring"
for /f "delims=" %%A in ('findstr "%substring%" "textfile.txt"') do (
for %%B in (%%A) do (
set "string=%%~B"
if "!string:%substring%=!" neq "!string!" echo %%B
)
)
This Bath file may fail if the characters outside the "strings" (not enclosed in quotes) are special Batch characters.
I would first use a tool to isolate each string on a single line. Then you can use FINDSTR to return only quoted lines that contain the substring
The trickiest part is isolating the quoted strings. My REPL.BAT regex search and replace utility is a good option. It is a hybrid JScript/batch script that will run natively on any modern Windows machine from XP onward.
type "textfile.txt" | repl (\q.*?\q) \r\n$1\r\n x | findstr /x ^"\".*substring.*\"^"
If you want to see your strings without enclosing quotes, then:
for /f delims^=^ eol^= %%A in (
'type "textfile.txt" ^| repl (\q.*?\q) \r\n$1\r\n x ^| findstr /x ^"\".*substring.*\"^"'
) do echo %%~A
I have a txt file that contains about 500 values, one per line. I need to check to see of any of those 500 values appear in any of 6 csv files each containing 100k lines. I can search for one value in those 6 csv files using
for /f "delims==" %%f in ('dir /s /b "P:\*.txt"') do FIND /N "[SEARCHSTRING]" "%~1%%f" >> "C:\found.txt"
but how do I do multiple searches automatically via command-line or batch file (CaSe SenSiTIve)?
#ECHO OFF
SETLOCAL
SET "sourcedir=c:\sourcedir"
SET "destdir=C:\destdir"
for /f "delims=" %%a in ('dir /s /b "%sourcedir%\*.csv"') do (
FINDSTR /N /g:"yourtextfilecontaining500linestomatch.txt" "%%~fa") > "%destdir%\%%~nafound.txt"
GOTO :EOF
What you are asking is rather unclear. I used c:\sourcedir as the location of the .csv files and c:\destdir as the location for the reports. Replacing
FINDSTR /N /g:"yourtextfilecontaining500linestomatch.txt" "%%~fa") > "%destdir%\%%~nafound.txt with your original (with the double > would accumulate the lines into a single file - if that's what you want. As it stands, a new file will be created with name the same as your .csv+found.txt
An easy way is to use a batch script. You can loop through each of the files one by one. If you want to do them all at once you need to thread your program.
for /L %%A in (1,1,6) do (
Your code goes here
)
That batch script will loop six times. I am not really sure how you specify the file but if you loop through each file it will work.
So put your current batch script where I said "Your code goes here"
for /f "delims==" %%f in ('dir /s /b "P:\*.txt"') do FIND /N "[SEARCHSTRING]" "%~1%%f" >> "C:\found.txt"
But you need to edit it to point to the file that you want to search. If your files are 1.txt, 2.txt 3.txt then all you need to do is set your file name to the current loop iteration number.
I've been using variants of this shell function for years:
ematch () {
for f in $(find . -type f | grep -v '~' | grep -v \.svn\/) ; do
egrep "$1" "$f" /dev/null 2> /dev/null
done
}
-> ematch "(string1|string2|string3)"
Feel free to adapt to your needs and post your mods here.
I have a ChatRoom batch file and it creates a text file were all the user inputs go into like this:
Echo %User Input% >> C:\ChatterBox\Chat.txt
I have this so far:
For /F "Delims=" %%A In (C:\ChatterBox\Chat.txt) Do (
Set Chat=%%A
)
Echo %Chat%
That didn't work and it only gave me the first line of the text file, do you know how I can echo every line in this way?
Echo %Chat%
And have the output look like this?
"Line one"
"Line two"
"Line three"
"Line four"
You're echoing the line after the loop ends, so you only get the last line printed (not the first). In order to use the lines within the loop, you must enable delayed variable expansion -- otherwise the variables get expanded when the loop is started rather than every iteration. Once you've enabled it, you use !var! instead of %var% to get the delayed expansion.
Here's how to do it:
setlocal enabledelayedexpansion
For /F "Delims=" %%A In (Chat.txt) Do (
Set Chat=%%A
Echo !Chat!
)
Use this command:
for /f "delims=" %%i in (chat.txt) do echo %%i
this will show you all lines in the chat.txt file
hope it helps!
You could also put all lines in a single variable that can be used outside of the loop:
set Chat=
set NL=^
::The above two blank lines are needed
setlocal enabledelayedexpansion
for /f "delims=" %%a in (chat.txt) do (
set Chat=!Chat!!NL!%%a
)
Echo %Chat%
And that should serve you well. It is important to note that instead of going through all the trouble to print every line just use: type chat.txt.
Mona.
This will display the lines:
type "C:\ChatterBox\Chat.txt"
We have 2 Unicode files. One of them contains lines that are missing in another file. Like so:
1.
2. bbbbbbbbbbbbbbbbb
3.
4. ddddddddddddddddddddd
5. eeeeeeeeeeeeeeeeeeeeeeee
1. aaaaaaaaaaaaaa
2.
3. ccccccccccccccccc
4.
5.
We want to merge them into third file that will contain all lines:
1. aaaaaaaaaaaaaa
2. bbbbbbbbbbbbbbbbb
3. ccccccccccccccccc
4. ddddddddddddddddddddd
5. eeeeeeeeeeeeeeeeeeeeeeee
Notes:
a,b,c,d,e - can be any text.
line numbers are just for illustration purposes, they are not present in actual files.
I created this question with "batch-file" tag, but I am open to any suggestions about how to achieve this. Of course better not to involve something like C++
Assuming that no line starts with a colon,
first we read each line from two files into two arrays, including blank lines - there is a special hack for this, since normal for skips blank lines.
And then just concatenate elements with from both arrays with identical index, and output into results.txt :
setlocal EnableDelayedExpansion
set i=0
for /f "tokens=1* delims=:" %%A in ('type "file1.txt" ^| findstr /n "^"') do (
set /A i+=1
set arr1[!i!]=%%B
)
set i=0
for /f "tokens=1* delims=:" %%A in ('type "file2.txt" ^| findstr /n "^"') do (
set /A i+=1
set arr2[!i!]=%%B
)
for /L %%i in (1,1,%i%) do echo.!arr1[%%i]!!arr2[%%i]!>> result.txt