I am new to this website so apologies if I have formatted my code wrong. I am having some trouble with my program; I want to have Player One able to re-enter their number if their first entry was greater than ten. My program seems to end after the first if statement.
Is there any particular statement I could use to get this job done?
Thanks.
#Program that gives Player2 five guesses to guess Player1's number.
import time
Number_To_Guess = int(input('Player One Enter Your Chosen Number: '))
if Number_To_Guess > 10:
print('Your Number Must Be Less Than 10')
elif Number_To_Guess < 10:
Player_Two_Guess = int(input('Player Two Guess The Number: '))
time.sleep(3)
Program that gives Player2 five guesses to guess Player1's number.
This will work until user got right guess:
import time
Number_To_Guess = int(input('Player One Enter Your Chosen Number: '))
if Number_To_Guess > 10:
print('Your Number Must Be Less Than 10')
elif Number_To_Guess < 10:
Player_Two_Guess = 0
TotalGuesses = 0
while Player_Two_Guess != Number_To_Guess and TotalGuesses < 5:
TotalGuesses += 1
Player_Two_Guess = int(input('Player Two Guess The Number: '))
time.sleep(3)
But i would reduce the sleep time :D
Added a counter to reduce the number of guesses to 5.
An infinite loop will do the work:
while True:
Number_To_Guess = int(input('Player One Enter Your Chosen Number: '))
if Number_To_Guess > 10:
print('Your Number Must Be Less Than 10')
else:
break
Player_Two_Guess = int(input('Player Two Guess The Number: '))
Related
Could you, please, help me to understand how should I use try/except block and count tries at the same time.
Here is the code without try/except block (it seems it's working fine):
import random
number = random.randint(1, 10)
tries = 3
name = input('Hi! What is your name?\n')
answer = input(f'{name}, let\'s play a game! Yes or No?\n')
if answer == 'Yes':
print(f'But be aware: you have only {tries} tries!\nReady?')
chat = input('')
print('Ok, guess a number from 1 to 10!')
while tries != 0:
choice = int(input('Your choice: '))
tries -= 1
if choice > number:
print('My number is less!')
elif choice < number:
print('My number is higher!')
else:
print('Wow! You won!')
break
print(f'You have {tries} tries left.')
if tries == 0 and choice != number:
print(f'Sorry, {name}, you lost... It was {number}. Try next time. Good luck!')
else:
print('No problem! Let\'s make it another time...')
This one is with try/except block.. Not sure where should I place 'choice' variable and where count 'tries', it keeps looping and looping:
import random
number = random.randint(1, 10)
tries = 3
name = input('Hi! What is your name?\n')
answer = input(f'{name}, let\'s play a game! Yes or No?\n')
if answer == 'Yes':
print(f'But be aware: you have only {tries} tries!\nReady?')
chat = input('')
print('Ok, guess a number from 1 to 10!')
while True:
try:
choice = int(input('Your choice: '))
if 0 < choice < 11:
while tries != 0:
tries -= 1
if choice > number:
print(f'My number is less!')
elif choice < number:
print(f'My number is higher!')
else:
print('Wow! You won!')
break
print(f'You have {tries} tries left.')
if tries == 0 and choice != number:
print(f'Sorry, {name}, you lost... It was {number}. Try next time. Good luck!')
else:
print(f'Hey {name}, I said, print a number from 1 to 10!')
except ValueError:
print('Please, enter a number!')
else:
print('No problem! Let\'s make it another time...')
Thanks!
I'm trying to get a guessing game with the user input as an answer and if the user type exit the game will show the amount of time the player tried but the program won't run because it can only take either interger or string type.
import random
while True:
number = random.randint(1,9)
guess = int(input('guess the number: '))
time = 0
time += 1
if guess == number:
print('you guessed correct')
elif guess < number:
print('your guessed is lower than the actual number')
elif guess > number:
print('your guessed is higher than the actual number')
elif guess == 'exit':
print(time)
break
something like this
import random
time = 0
number = random.randint(1,9)
while True:
guess = input('guess the number: ')
time += 1
if guess == "exit":
print(time)
break
elif int(guess) < number:
print('your guessed is lower than the actual number')
elif int(guess) > number:
print('your guessed is higher than the actual number')
elif int(guess) == number:
print('you guessed correct')
print(time)
break
note that time and number have to be initializate outside the while loop, because if not, we would get different random numbers for each iteration, and also time would be initializate to 0 each time.
You can test the input as a string first before converting it to an integer:
while True:
response = input('guess the number: ')
if response == 'exit':
break
guess = int(response)
# the rest of your code testing guess as a number
Hi I'm a beginner Making a Game Where The Program Generates a random Number And The User Needs To Guess The Number. If They Fail 5 Times They Lose. I Need To Count How Many Times The User Can Enter And If It Reaches 5 And Print You Lost And restart.
Something Like This
cnt = 0
if cnt >= 5:
print("You Lost")
pass
You need :
import random
op_number = random.randint(1,20)
# print(op_number)
number = int(input("Guess a number between 1 to 20 : "))
count=0
while True:
if count == 5:
print("You Lose.")
break
count+=1
if op_number == number:
print("You won")
break
else:
print("Incorrect guess. {} attempts left.".format(5-count))
number = int(input("Guess a number between 1 to 20 : "))
So I am making a guess the number game in Python 3
After the whole process, I want my while loop to generate another number so that I can start the game again without running the program again.
Please let me know what I'm doing wrong, and if you could provide me with some insight on how to use the while loop, it'll be much appreciated.
Here's the code :
import random
while True:
number = random.randint(1, 1000)
count = 0
guessed = input("Enter the number you guessed: ")
count += 1
if int(guessed) < number:
print("You guessed too low")
elif int(guessed) > number:
print("You guessed too high")
elif int(guessed) == number:
print(f'You guessed right and it took you {count} guesses to the right number which is {number}')
Not sure if the code you pasted was a typo (on indentation), but I may have accidentally changed your implementation.
Regardless, you should just add another while loop, and a break condition when the user gets it right.
import random
while True:
number = random.randint(1, 1000)
count = 0
while True: # Added, and added another layer of indentation
guessed = input("Enter the number you guessed: ")
count += 1
if int(guessed) < number:
print("You guessed too low")
elif int(guessed) > number:
print("You guessed too high")
elif int(guessed) == number:
print(f'You guessed right and it took you {count} guesses to the right number which is {number}')
break # Added
In doing so, the code will keep looping to guess the correct number until they are correct. And then generate a new number to guess. However this code will never end unless you add another breaking condition (such as setting a flag the while loop will check to break out of the outer loop.
I wrote some quick code that prompts the user if they want to continue playing or not and then loops through and continues the game with a new number if they want to. I also fixed some minor bugs. Your count kept getting reset in the loop so it would always say you found it in 1 try.
import random
def promptUser():
user_continue = input("Do you want to continue playing? y/n")
if (user_continue == 'y'):
number = random.randint(1, 10)
game(0, number)
def game(count, number):
while True:
guessed = input("Enter the number you guessed: ")
count += 1
if int(guessed) < number:
print("You guessed too low")
elif int(guessed) > number:
print("You guessed too high")
elif int(guessed) == number:
print(f'You guessed right and it took you {count} guesses to the right number which is {number}')
promptUser()
break
promptUser()
I have this program:
number = int(input('Contact Number:'))
def validatePhoneNumber(number):
count = 0
while True:
while number > 0:
number = number//10
count = count+1
if (count == 10) :
break
elif (count > 10) :
print('Invalid phone number')
return -1
elif (count < 10):
print('Invalid phone number')
return -1
validatePhoneNumber(number)
it will appear like this:
Contact Number:1234
Invalid phone number
>>>
I want it to continue to loop until a 10 digit number is entered then it will stop.
Contact Number:1234567890
>>>
The condition is that If the number is missing or invalid, return ‐1.
Am I missing something inside the program?
Thanks
What about this:
number = input('Contact Number:') # it's a str now, so we can use len(number)
def validatePhoneNumber(number):
while len(number) != 10:
number = input("Please enter a 10-digit contact number: ")
return number
number = validatePhoneNumber(number)
It's a more pythonic approach and therefore easier to understand and debug. Also as other comments pointed out, leading 0s aren't stripped away now.