With the following data:
A B
1 CUMULATIVE PERCENTAGE OF ITEMS PRODUCED PER MONTH ("COMPLETION_TABLE")
2 Type Month 1 Month 2
3 KITTENS 0 10
4 FISH 0 20
5 BANANAS 2 5
6 APPLES 0 0
7 PEARS 0 5
8 KITTENS 0 5
9
10
11 PRICES TABLE ("PRICES_TABLE")
12 Type Value
13 APPLES 1000
14 BANANAS 5000
15 PEARS 3000
16 FISH 4000
17 KITTENS 2000
I'm attempting to use the SUMPRODUCT function to calculate the percentage change in each month and use that value as a multiple of the prices table to provide a total price per month across all types that have been produced.
I can calculate the movement as:
=SUMPRODUCT((COMPLETION_TABLE[Month 2]-COMPLETION_TABLE[Month 1]))
... but I then need to calculate the portion of the individual movement values against the price for that type and sum the resulting products together. I have been using various INDEX / MATCH combinations without much luck.
As an example: BANANAS which should =(5-2)*5000.
Written as expanded arrays I would like to do
({10;20;5;0;5;5}-{0;0;2;0;0;0})*{2000;4000;5000;1000;3000;2000}.
Use of SUMPRODUCT implies you want a single figure result. You can use SUMIF as a "pseudo lookup" within SUMPRODUCT to get the prices, e.g.
=SUMPRODUCT(C3:C8-B3:B8,SUMIF(A13:A17,A3:A8,B13:B17))
That would get you a result of 140,000 for your example
From your question I understand the result you want is an array. This is what you get with this formula:
=INDEX($B$13:$B$17,MATCH($A3:$A8,$A$13:$A$17,0))*($C3:$C8-$B3:$B8)
entered as an array formula using Ctrl Shift Enter.
I am sure there is something simpler. I am assuming that the Type in the Price Table are unique:
{=(SUM((A13=$A$3:$A$8)*$C$3:$C$8)-SUM((A13=$A$3:$A$8)*$B$3:$B$8))*SUM((A13=$A$13:$A$17)*$B$13:$B$17)
Related
End-goal: A column with the subtotals of groups (defined in the below table as all foods listed above Zucchini, incl Zucchini).
Current attempt: create a column to define groups using COUNTIF('count all 'zucchini' thus far'). Then use SUMIF to get the total cost for the current group.
Problem: I don't know how to do this without the COUNTIF column (since SUMIF needs range C:C to be resolved first). I'd like to have it in a single formula. I looked into array formulas but not sure if/how to apply that here.
FOOD COST COUNTIF(A2:A$2;"Zucchini") SUMIF(C:C;C2;B:B)
Apple 3 0 12
Pecan 7 0 12
Zucchini 2 0 12
Apple 4 1 23
Olive 8 1 23
Pecan 6 1 23
Zucchini 5 1 23
Apple 4 2 16
Olive 9 2 16
Zucchini 3 2 16
Any ideas on how to solve either the current problem or the end-goal problem? Thanks!
Put this in C2 and copy down:
=IF(A2="Zucchini",SUM($B$1:B2)-SUM($C$1:C1),"")
It basically sums everything to the row and subtracts what is already accounted for.
I'm trying to use Excle's SUMIF to calculate totals of Col1 to Col5 for dates that are similar.
My formula is as follows =SUMIF($A2:$A7,A10,$B2:$F7), but this only gives me the total of a single column.
How can I get the Totals of all the columns based on the date like I've shown in my results.
Date Col 1 Col 2 Col 3 Col 4 Col 5
1/5/2017 1 2 2
1/5/2017 5 3 1
1/5/2017 9 5 5
2/5/2017 10 5 3
2/5/2017 20 10 3
2/5/2017 6 8 1 5
Desired Results
1/5/2017 15 7 7 3 1
2/5/2017 30 11 11 11 8
use below formula in cell B11
=SUMIF($A$2:$A$7,$A11,B$2:B$7)
Per the example you provided, One solution is to use SUMPRODUCT
Multiplies corresponding components in the given arrays, and returns the sum of those products
Microsoft Docs give a thorough example, but per SO etiquette, here is an example in case of link-rot: [FYI, I used absolute reference for easier filling across, arbitrary how you get it done though]
Forumlas shown:
Formula is kind of hard to see without clicking on image:
=SUMPRODUCT(($B$3:$B$8=$B$11)*C3:C8)
This basically breaks down like this, it searches the B:B column for a match, and it will naturally return a true or false for the match, or 0/1 counterparts, and multiplys that by the number found in the column to the right (C3:C8), so it will either be 1 * # = # or 0 * # = 0
I want to implement a simple lookup that uses the classes below and the corresponding grade.
Class Grade
From to
19 20 1
17 18 1,5
14 15 2
12 13 2,5
10 11 3
7 9 3,5
4 6 4
2 3 4,5
0 1 5
In my example I have the search criterion 14 which should give out the grade 2.
Assuming the matrix to be located in the cells A1:C11 and the search criterion in cell E10, the following function gives me the value of 5, but why? The 3 in the formula refers to column 3, which is the value I want to receive.
=VLOOKUP(E10;A1:C11;3)
Thank you for your useful hints and help!
Try,
=index(c:c; match(e10; a:a; -1))
The default True for approximate lookup in VLOOKUP wants the data sorted in ascending order, not descending. MATCH uses 1 for ascending and -1 for descending.
Your Vlookup is missing the last parameter
=VLOOKUP(E10;A1:C11;3) returns an approximate result.
=VLOOKUP(E10;A1:C11;3;0) returns the exact result of your search.
I have a column "Uni"
E.g.
Person Uni Round 1 Round 2 Total Rank
Leia Notts 5 5 10
Hailey Notts 6 5 11
Bobby Bath 8 1 9
James Liverpool 9 1 10
Then another table:
University Total Score Rank
Notts =sum(vlookup(...))
Bath =sum(vlookup(...))
Currently, my formula returns the 'first' lookup of the keyword - e.g. for notts, it returns '10' - rather than looking up the 10 and the 11 and summing them.
How do I make it lookup and sum both values?
My current formula is =sum(vlookup(S7,B$3:Q$40,15,FALSE)) where S7 is "Notts", range, index column 15 is "total score"
There's about 8-10 of each university.
Vlookup only returns one value, you can't sum over that.
Maybe use instead something like
=SUMIF(B$3:B$40,S7,$P3:$P40)
I'm looking for a way to compare multiple rows with data to each other, trying to find the best possible match. Each number in every column must be an approximately match the other numbers in the same column.
Example:
Customer #1: 1 5 10 9 7 7 8 2 3
Customer #2: 10 5 9 3 5 7 4 3 2
Customer #3: 1 4 10 9 8 7 6 2 2
Customer #4: 9 5 6 7 2 1 10 5 6
In this example customer #1 and #3 is quite similar, and I need to find a way to highlight or sort the rows so I can easily find the best match.
I've tried using conditional formatting to highlight the numbers that are the similar, but that is quite confusing, because the amount of data is quite big.
Any ideas of how I could solve this?
Thanks!
The following formula entered in (say) L1 and pulled down gives the best match with the current row based on the sum of the absolute differences between corresponding cells:-
=MIN(IF(ROW($C$1:$K$4)<>ROW(),(MMULT(ABS($C1:$K1-$C$1:$K$4),TRANSPOSE(COLUMN($C$1:$K$4))^0))))
It is an array formula and must be entered with CtrlShiftEnter.
You can then sort on column L to bring the customers with lowest similarity scores to the top or use conditional formatting to highlight rows with a certain similarity value.
EDIT
If you wanted to penalise large differences in individual columns more heavily than small differences to try and avoid pairs of customers which are fairly similar except for having some columns very different, you could try something like the square of the differences:-
=MIN(IF(ROW($C$1:$K$4)<>ROW(),(MMULT(($C1:$K1-$C$1:$K$4)^2,TRANSPOSE(COLUMN($C$1:$K$4))^0))))
then the scores for your test data would come out as 7,127,7,127.
I'm assuming you want to compare customers 2-4 with customer 1 and that you are comparing only within each column. In this case, you could implement a 'scoring system' using multiple IFs. For example,:
A B C D E
1 Customer 1 1 1 2
2 Customer 2 1 2 2
3 Customer 3 0 1 0
you could use in E2
=if(B2=$B$1,1,0)+if(C2=$C$1,1,0)+if(D2=$D$1,1,0)
This will return a 'score' of 1 when you have a match and a 'score' of 0 when you don't. It then adds up the scores and your highest value will be your best match. Copying down would then give
A B C D E
1 Customer 1 1 1 2
2 Customer 2 1 2 2 2
3 Customer 3 0 1 0 1
so customer 2 is the best match.