Ubuntu14.04LTS desktop app launcher for node? - Desktop Entry - node.js

This is not a duplicated question. The link suggested is for Shell Script, and I can launch node app via shell script doing normaly just 'node app', but for .desktop file, it does not work. So the answer linked never solve my problem, and what is the point to try to close the question suggesting to use an unsatisfied answer.
I simply try to exec node app from the current directory where .desktop file exists.
I do as follows, but for unknown reason, it does not work.
Surely, when I do node app on the directory, the node app launches as expected.
Any idea? Thanks.
[Desktop Entry]
Version=1.0
Name=JS Bin
Comment=JS Bin Offline REPL
Exec=node '"$(dirname "$1")"/app'
Icon=/home/ken/Google Drive/js-bin/code.png
Terminal=false
Type=Application
Categories=Utility;Application;
Exec=node '/home/ken/Google Drive/js-bin/app.js'
would be the same result.
Just in case, I don't have to re-login to make this work, correct?

SOLVED:
for node.js program, we should be careful for the path.
I have to do like
var app1 = proc.spawn(atom, [__dirname + '/app1.js']);
using __dirname properly, otherwise, PATH context problem occurs especially using shell script.
thanks.

Related

Dotnet Core - Get the application's launch path

Question - Is there a better/right way to get the application's launch path?
Setup -
I have a console application that runs in a Linux Debian docker image. I am building the application using the --runtime linux-x64 command line switch and have all the runtime identifiers set appropriately. I was expecting the application to behave the same whether launching it by calling dotnet MyApplication.dll or ./MyApplication but they are not.
Culprit Code -
I have deployed files in a folder below the application directory that I reference so I do the following to get what I consider my launch path. I have read various articles saying this is the correct way to get what I want, and it works depending on how I launch it.
using var processModule = Process.GetCurrentProcess().MainModule;
var basePath = Path.GetDirectoryName(processModule?.FileName);
When launching this using the comand dotnet MyApplication.dll the above codes path is /usr/share/dotnet
When launching this using the command ./MyApplication.dll the path is then /app
I understand why using dotnet would be different as it is the process that is running my code, but again it was unexpected.
Any help here to what I should use given the current environment would be appreciated. Ultimately I need the path where the console application started from as gathered by the application when it starts up.
Thanks for your help.
This code should work:
public static IConfiguration LoadConfiguration()
{
var assemblyDirectory = Path.GetDirectoryName(Assembly.GetExecutingAssembly().Location);
.....
}

how to run windows service automatically using nodejs application? [duplicate]

Can any node.js experts tell me how I might configure node JS to autostart a server when my machine boots?
I'm on Windows
This isn't something to configure in node.js at all, this is purely OS responsibility (Windows in your case). The most reliable way to achieve this is through a Windows Service.
There's this super easy module that installs a node script as a windows service, it's called node-windows (npm, github, documentation). I've used before and worked like a charm.
var Service = require('node-windows').Service;
// Create a new service object
var svc = new Service({
name:'Hello World',
description: 'The nodejs.org example web server.',
script: 'C:\\path\\to\\helloworld.js'
});
// Listen for the "install" event, which indicates the
// process is available as a service.
svc.on('install',function(){
svc.start();
});
svc.install();
p.s.
I found the thing so useful that I built an even easier to use wrapper around it (npm, github).
Installing it:
npm install -g qckwinsvc
Installing your service:
> qckwinsvc
prompt: Service name: [name for your service]
prompt: Service description: [description for it]
prompt: Node script path: [path of your node script]
Service installed
Uninstalling your service:
> qckwinsvc --uninstall
prompt: Service name: [name of your service]
prompt: Node script path: [path of your node script]
Service stopped
Service uninstalled
If you are using Linux, macOS or Windows pm2 is your friend. It's a process manager that handle clusters very well.
You install it:
npm install -g pm2
Start a cluster of, for example, 3 processes:
pm2 start app.js -i 3
And make pm2 starts them at boot:
pm2 startup
It has an API, an even a monitor interface:
Go to github and read the instructions. It's easy to use and very handy. Best thing ever since forever.
If I'm not wrong, you can start your application using command line and thus also using a batch file. In that case it is not a very hard task to start it with Windows login.
You just create a batch file with the following content:
node C:\myapp.js
and save it with .bat extention. Here myapp.js is your app, which in this example is located in C: drive (spcify the path).
Now you can just throw the batch file in your startup folder which is located at C:\Users\%username%\AppData\Roaming\Microsoft\Windows\Start Menu\Programs\Startup
Just open it using %appdata% in run dailog box and locate to >Roaming>Microsoft>Windows>Start Menu>Programs>Startup
The batch file will be executed at login time and start your node application from cmd.
This can easily be done manually with the Windows Task Scheduler.
First, install forever.
Then, create a batch file that contains the following:
cd C:\path\to\project\root
call C:\Users\Username\AppData\Roaming\npm\forever.cmd start server.js
exit 0
Lastly, create a scheduled task that runs when you log on. This task should call the batch file.
I would recommend installing your node.js app as a Windows service, and then set the service to run at startup. That should make it a bit easier to control the startup action by using the Windows Services snapin rather than having to add or remove batch files in the Startup folder.
Another service-related question in Stackoverflow provided a couple of (apprently) really good options. Check out How to install node.js as a Windows Service. node-windows looks really promising to me. As an aside, I used similar tools for Java apps that needed to run as services. It made my life a whole lot easier. Hope this helps.
you should try this
npm forever
https://www.npmjs.com/package/forever
Use pm2 to start and run your nodejs processes on windows.
Be sure to read this github discussion of how to set up task scheduler to start pm2: https://github.com/Unitech/pm2/issues/1079
Here is another solution I wrote in C# to auto startup native node server or pm2 server on Windows.
I know there are multiple ways to achieve this as per solutions shared above. I haven't tried all of them but some third party services lack clarity around what are all tasks being run in the background. I have achieved this through a powershell script similar to the one mentioned as windows batch file. I have scheduled it using Windows Tasks Scheduler to run every minute. This has been quite efficient and transparent so far. The advantage I have here is that I am checking the process explicitly before starting it again. This wouldn't cause much overhead to the CPU on the server. Also you don't have to explicitly place the file into the startup folders.
function CheckNodeService ()
{
$node = Get-Process node -ErrorAction SilentlyContinue
if($node)
{
echo 'Node Running'
}
else
{
echo 'Node not Running'
Start-Process "C:\Program Files\nodejs\node.exe" -ArgumentList "app.js" -WorkingDirectory "E:\MyApplication"
echo 'Node started'
}
}
CheckNodeService
Simply use this, install, run and save current process list
https://www.npmjs.com/package/pm2-windows-startup
By my exp., after restart server, need to logon, in order to trigger the auto startup.
Need to create a batch file inside project folder.
Write this code in batch file
#echo off
start npm start
save batch file with myprojectname.bat
Go to run command and press window + R
Enter this command :- shell:common startup
Press ok then folder will be open.
Folder path like as C:\ProgramData\Microsoft\Windows\Start Menu\Programs\StartUp
You will be paste your myprojectname.bat file.
You can check also. Need to system restart.
Copied directly from this answer:
You could write a script in any language you want to automate this (even using nodejs) and then just install a shortcut to that script in the user's %appdata%\Microsoft\Windows\Start Menu\Programs\Startup folder

Run NodeJS application without environment variable

I have a node application that I run on a Linux Server (CentOS 6.5) by setting my environment with a bash script
env_nodejs.sh
#!/bin/bash
PATH=$PATH:/opt/nodejs/node-v6.9.4-linux-x64/bin
export PATH
So that I can
# . ./env_nodejs.sh
# node /var/www/html/application/app.js
That all works fine but if I do the following in a separate script
run_app.sh
#!/bin/bash
$COMMAND=/opt/nodejs/node-v6.9.4-linux-x64/bin/node
$SITE=/var/www/html/application/app.js
nohup $COMMAND $SITE > /tmp/nodeapp.log &
This runs the node server and app but with errors that seem to be related to npm
Error: Failed to lookup view "control/users" in views directory "/views"
I have a feeling this is because the environment is not set but is there a way to run it correctly without the environment or to pass additional parameters for the npm location?
It seems like it's trying to find the files in "/views" which is a top level directory in your file system.
If that is the case then it's not PATH but PWD that's in fault here.
Make sure that when you define where to look for the views in your app, instead of saying 'views' or './views' you use path.join(__dirname, 'views') instead.
You first need to require path with: var path = require(path);
Of course this is just my guess as you didn't include any part of your source code that you have problem with.

Start shell script after lightdm is being logged in

I have Debian OS, and I want to start shell script after lightdm is being logged in, how can I do that?
I tried to put
session-setup-script=/path/to/my/script in /etc/lightdm/lightdm.conf
file, but It won't work.
Any advice?
Try invoking your script in an ~/.xsession file.
This file is executed upon X server startup. More info here: https://unix.stackexchange.com/questions/47359/what-is-xsession-for
I was having the same issue and realised that I had set the option at the wrong point in /etc/lightdm/lightdm.conf, a silly mistake.
The seat defaults are documented before the [SeatDefaults] heading and I was placing my setting on the line below the documentation.
so
# session-setup-script = Script to run when starting a user session (runs as root)
session-setup-script=/usr/bin/bla
Looking further down the file I found the heading [SeatDefaults] and below that the setting.
#session-setup-script=
Un-commenting that line and setting the script worked as expected.

Run executable from local storage using Azure Web Role

i'm trying to run a simple executable using an Azure Web Role.
The executable is stored in the Web Role's local storage.
The executable produces a log.txt file once it has been run.
This is the method I am using to run the executable:
public void RunExecutable(string path)
{
Process.Start(path);
}
Where path is localStorage.RootPath + "Application.exe"
The problem I am facing is that when I open the local storage folder the executable is there however there is no log.txt file.
I have tested the executable, it works if I manually run it, it produces the log.txt file.
Can anyone see the problem?
Try setting an explicit WorkingDirectory for the process... I wonder if log.txt is being created, just not where you expect. (Or perhaps the app is trying to create log.txt but failing because of the permissions on the directory it's trying to create it in.)
If you remote desktop into the instance, can't you find the file created at E:\approot\ folder ? As Steve said, using a WorkingDirectory for the process will fix the issue
You can use Environment.GetEnvironmentVariable("RoleRoot") to construct the URL to your application root

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