I have 1 column with about 60 cells with values or different length. Each (or at least most) of the values have a numeric characters in the value. I want to split the columns cells into more columns which I normally would do with the 'tekst to columns' function of excel.
But this function does not have an advanced option of splitting the value at the first numeric character. splitting based on spaces, comma etc. is possible but this does not help me.
Is there any way to divide the cells into 2 columns at the first number in the cell value?
I have looked at numerous other questions but none of them (or other internet fora) have helped me to split the value at the first number of the cell value.
Thanks #quantum285 for the answer. This routine works if the string contains one number. I changed the teststring to firstpart323secondpart.
then part1 returns 'firstpart32' and part2 return secondpart.
I tried to understand what happens in this code, please correct me if I'm wrong:
First, the lenght of the string is determined.
Secondly, for each position in this string is checked if it is numeric or not. But this check is dan from right to left? So in case of firstpart323secondpart: the length is 22.
then isnumeric() checks for every position from 1 to 22 if it is numeric and stops when it finds a number?
If so, part 1 is the the tekst before the value i, where i is the first position from right to left in the string where a number is found.
and part 2 is then the string on the right from this same position.
However, I am looking for a routine which find the first position from left to right (or the last position from right to left) where a number is, ...
So I changed the routine now, simply adjusting the for i = 1 to line:
Sub test()
For j = 4 To Cells(Rows.Count, 4).End(xlUp).Row
For i = Len(Cells(j, 4)) To 1 Step -1
If IsNumeric(Mid(Cells(j, 4), i, 1)) Then
Cells(j, 5) = Left(Cells(j, 4), i - 1)
Cells(j, 6) = (Right(Cells(j, 4), Len(Cells(j, 4)) - i + 1))
End If
Next i
Next j
End Sub
this almost perfectly works (except for a few cells which have multiple number combinations in the value (like: soup 10g 20boxes). But as these are only a few, I can adjust them by hand.
Thanks!
Sub test()
testString = "firstpart3secondpart"
For i = 1 To Len(testString)
If IsNumeric(Mid(testString, i, 1)) Then
part1 = Left(testString, i - 1)
part2 = (Right(testString, Len(testString) - i))
End If
Next i
MsgBox (part1)
MsgBox (part2)
End Sub
Use something like this within your loop.
Related
I am trying to go through an array and any element with a value I want to print in a list going down. However, I am having problems with identifying blank cells. Right now it recognizes every cell as not be empty. I am also including a screenshot of the data to help. (Some of the columns are hidden in the screen shot)
I have tried:
Evaluate("isblank(" & Cells(i, 8).Address & ")")
IsEmpty(list(i, 1))
IsNull(list(i, 1))
None of the options above work and this is what I currently have
Dim list As Variant
Dim i As Integer
Dim Y As String
Dim X As Integer
Y = "A"
X = 2
list = Range("H12:H158").Value
For i = 1 To 147
If Not IsEmpty(list(i, 1)) Then
Cells(X, Y) = list(i, 1)
X = X + 1
End If
Next i
Any advice is greatly appreciated
I have just tried out your macro and as a result, in the column "A", starting from row 2, I have the values:
HRT-2-11
HRT-2-13
HRT-2-14
HRT-2-15
HRT-2-17
HRT-2-18
This, I believe, is what you are looking for, isn't it? I believe that there has been a value in the cells which appear blank, but now there should be some invisible character (like a space or something). I'd advise you to check the value of such an "empty" cell and go on from there (the "immediate" window is perfect for investigations like this).
Len() never missed a char.
If Len(list(i, 1))>0 Then
....
I want to do an INDEX-MATCH-like lookup between two documents, except my MATCH's index array doesn't stay in one column.
In Vague-English: I want a value from a known column that matches another value that may be found in any column.
Refer to the image below. Let's call everything to the left of the bold vertical line on column H doc1, and the right side will be doc2.
Doc2 has a column "Find This", which will be the INDEX's array. It is compared with "ID1" from doc1 (Note that the values in "Find This" will not be in the same order as column ID1, but it's easier to undertsand this way).
The "[Result]" column in doc2 will be the value from doc1's "Want This" column from the row that matches "FIND THIS" ...However, sometimes the value from "FIND THIS" is not in the "ID1" column, and is instead in "ID2","ID3", etc.
So, I'm trying to generate Col K from Col J. This would be like pressing Ctrl+F and searching for a value in Col J, then taking the value from Col D in that row and copying it to Col K.
I made identical values from a column the same color in the other doc to make it easier to visualize where they are coming from.
Note also that in column F of doc1, the same value from doc2's "Find This" can be found after some other text.
Also note that the column headers are only there as examples, the ID columns are not actually numbered.
I would simply hard-code the correct column to search from, but I'm not in control of doc1, and I'm worried that future versions may have new "ID" columns, with other's being removed.
I'd prefer this to be a solution in the form of a formula, but VB will do.
To generate column K based on given values of column J then you could use the following:
=INDEX(doc1!$D$2:$D$14,SUMPRODUCT((doc1!$B$2:$H$14=J2)*ROW(doc1!$B$2:$H$14))-1)
Copy that formula down as far as you need to go.
It basically only returns the row of the where a matching column J is found. we then find that row in the index of your D range to get your value in K.
Proof of concept:
UPDATE:
If you are working with non unique entities n column J. That is the value on its own can be found in multiple rows and columns. Consider using the following to return the Last row where there J value is found:
=INDEX(doc1!$D$2:$D$14,AGGREGATE(14,6,(doc1!$B$2:$H$14=J2)*ROW(doc1!$B$2:$H$14),1)-1)
UPDATE 2:
And to return the first row where what you are looking in column J is found use:
=INDEX($D$2:$D$14,AGGREGATE(15,6,1/($B$2:$H$14=J2)*ROW($B$2:$H$14)-1,1))
Thanks to Scott Craner for the hint on the minimum formula.
To determine if you have UNIQUE data from column J in your range B2:H14 you can enter this array formula. In order to enter an array formula you need to press CTRL+SHFT+ENTER at the same time and not just ENTER. You will know you have done it right when you see {} around your formula in the formula bar. You cannot at the {} manually.
=IF(MAX(COUNTIF($B$2:$H$14,J2:J14))>1,"DUPLICATES","UNIQUE")
UPDATE 3
AGGREGATE - A relatively new function to me but goes back to Excel 2010. Aggregate is 19 functions rolled into 1. It would be nice if they all worked the same way but they do not. I think it is functions numbered 14 and up that will perform the same way an array formula or a CSE formula if you prefer. The nice thing is you do not need to use CSE when entering or editing them. SUMPRODUCT is another example of a regular formula that performs array formula calculations.
The meat of this explanation I believe is what is happening inside of the AGGREGATE brackets. If you click on the link you will get an idea of what the first two arguments are. The first defines which function you are using, and the second tell AGGREGATE how to deal with Errors, hidden rows, and some other nested functions. That is the relatively easy part. What I believe you want to know is what is happening with this:
(doc1!$B$2:$H$14=J2)*ROW(doc1!$B$2:$H$14)
For illustrative purpose lets reduce this formula to something a little smaller in scale that does the same thing. I'll avoid starting in A1 as that can make life a little easier when counting since it the 1st row and first column. So by placing the example range outside of it you can see some more special considerations potentially.
What I want to know is what row each of the items list in Column C occurs in column B
| B | C
3 | DOG | PLATYPUS
4 | CAT | DOG
5 | PLATYPUS |
The full formula for our mini example would be:
{=($B$3:$B$5=C2)*ROW($B$3:$B$5)}
And we are going to look at the following as an array
=INDEX($B$3:$B$5,AGGREGATE(14,6,($B$3:$B$5=C2)*ROW($B$3:$B$5),1)-2)
So the first brackets is going to be a Boolean array as you noted. Every cell that is TRUE will TRUE until its forced into a math calculation. When that happens, True becomes 1 and False becomes 0.I that formula was entered as a CSE formula and place in D2, it would break down as follows:
FALSE X 3
FALSE X 4
TRUE X 5
The 3, 4 and 5 come from ROW() returning the value of the row number that it is dealing with at the time of the array math operation. Little trick, we could have had ROW(1:3). Just need to make sure the size of the array matches! This is not matrix math is just straight across multiplication. And since the Boolean is now experiencing a math operation we are now looking at:
0 X 3 = 0
0 X 4 = 0
1 X 5 = 5
So the array of {0,0,5} gets handed back to the aggregate for more processing. The important thing to note here is that it contains ONLY 0 and the individual row numbers where we had a match. So with the first aggregate formula, formula 14 was chosen which is the LARGE function. And we also told it to ignore errors, which in this particular case does not matter. So after providing the array to the aggregate function, there was a ,1) to finish off the aggregate function. The 1 tells the aggregate function that we want the 1st larges number when the array is sorted from smallest to largest. If that number was 2 it would be the 2nd largest number and so on. So the last row or the only row that something is found on is returned. So in our small example it would be 5.
But wait that 5 was buried inside another function called Index. and in our small example that INDEX formula would be:
=INDEX($B$3:$B$5,AGGREGATE(...)-2)
Well we know that the range is only 3 rows long, so asking for the 5th row, would have excel smacking you up side the head with an error because your index number is out of range. So in comes the header row correction of -1 in the original formula or -2 for the small example and what we really see for the small example is:
=INDEX($B$3:$B$5,5-2)
=INDEX($B$3:$B$5,3)
and here is a weird bit of info, That last one does not become PLATYPUS...it becomes the cell reference to =B5 which pulls PLATYPUS. But that little nuance is a story for another time.
Now in the comments Scott essentially told me to invert for the error to get the first row. And this is important step for the aggregate and it had me running in circles for awhile. So the full equation for the first row option in our mini example is
=INDEX($B$3:$B$5,AGGREGATE(15,6,1/($B$3:$B$5=C2)*ROW($B$3:$B$5),1)-2)
And what Scott Craner was actually suggesting which Skips one math step is:
=INDEX($B$3:$B$5,AGGREGATE(15,6,ROW($B$3:$B$5)/($B$3:$B$5=C2),1)-2)
However since I only realized this after writing this all up the explanation will continue with the first of these two equations
So the important thing to note here is the change from function 14 to function 15 which is SMALL. Think of it a finding the minimum. And this time that 6 plays a huge factor along with the 1/. So our array in the middle this time equates to:
1/FALSE X 3
1/FALSE X 4
1/TRUE X 5
Which then becomes:
1/0 X 3
1/0 X 4
1/1 X 5
Which then has excel slapping you up side the head again because you are trying to divide by 0:
#div/0 X 3
#div/0 X 4
1/1 X 5
But you were smart and you protected yourself from that slap upside the head when you told AGGREGATE to ignore error when you used 6 as the second argument/reference! Therefore what is above becomes:
{5}
Since we are performing a SMALL, and we passed ,1) as the closing part of the AGGREGATE, we have essentially said give me the minimum row number or the 1st smallest number of the resulting array when sorted in ascending order.
The rest plays out the same as it did for the LARGE AGGREGATE method. The pitfall I fell into originally is I did not use the 1/ to force an error. As a result, every time I tried getting the SMALL of the array I was getting 0 from all the false results.
SUMPRODUCT works in a very similar fashion, but only works when your result array in the middle only returns 1 non zero answer. The reason being is the last step of the SUMPRODUCT function is to all the individual elements of the resulting array. So if you only have 1 non zero, you get that non zero number. If you had two rows that matched for instance 12 and 31, then the SUMPRODUCT method would return 43 which is not any of the row numbers you wanted, where as aggregate large would have told you 31 and aggregate small would have told you 12.
Something like this maybe, starting in K2 and copied down:
=IFERROR(INDEX(D:D,MAX(IFERROR(MATCH(J2,B:B,0),-1),IFERROR(MATCH(J2,E:E,0),-1),IFERROR(MATCH(J2,G:G,0),-1),IFERROR(MATCH(J2,H:H,0),-1))),"")
If you want to keep the positions of the columns for the Match variable, consider creating generic range names for each column you want to check, like "Col1", "Col2", "Col3". Create a few more range names than you think you will need and reference them to =$B:$B, =$E:$E etc. Plug all range names into Match functions inside the Max() statement as above.
When columns are added or removed from the table, adjust the range name definitions to the columns you want to check.
For example, if you set up the formula with five Matches inside the Max(), and the table changes so you only want to check three columns, point three of the range names to the same column. The Max() will only return one result and one lookup, even if the same column is matched several times.
I came up with a vba solution if I understood correctly:
Sub DisplayActiveRange()
Dim sheetToSearch As Worksheet
Set sheetToSearch = Sheet2
Dim sheetToOutput As Worksheet
Set sheetToOutput = Sheet1
Dim search As Range
Dim output As Range
Dim searchCol As String
searchCol = "J"
Dim outputCol As String
outputCol = "K"
Dim valueCol As String
valueCol = "D"
Dim r As Range
Dim currentRow As Integer
currentRow = 1
Dim maxRow As Integer
maxRow = sheetToOutput.UsedRange.Rows.Count
For currentRow = 1 To maxRow
Set search = Range("J" & currentRow)
For Each r In sheetToSearch.UsedRange
If r.Value <> "" Then
If r.Value = search.Value Then
Set output = sheetToOutput.Range(outputCol & currentRow)
output.Value = sheetToSearch.Range(valueCol & currentRow).Value
currentRow = currentRow + 1
Set search = sheetToOutput.Range(searchCol & currentRow)
End If
End If
Next
Next currentRow
End Sub
There might be better ways of doing it, but this will give you what you want. We assume headers in both "source" and "destination" sheets. You will need to adapt the "Const" declarations according to how your sheets are named. Press Control & G in Excel to bring up the VBA window and copy and paste this code into "This Workbook" under the "VBA Project" group, then select "Run" from the menu:
Option Explicit
Private Const sourceSheet = "Source"
Private Const destSheet = "Destination"
Public Sub FindColumns()
Dim rowCount As Long
Dim foundValue As String
Sheets(destSheet).Select
rowCount = 1 'Assume a header row
Do While Range("J" & rowCount + 1).value <> ""
rowCount = rowCount + 1
foundValue = FncFindText(Range("J" & rowCount).value)
Sheets(destSheet).Select
Range("K" & rowCount).value = foundValue
Loop
End Sub
Private Function FncFindText(value As String) As String
Dim rowLoop As Long
Dim colLoop As Integer
Dim found As Boolean
Dim pos As Long
Sheets(sourceSheet).Select
rowLoop = 1
colLoop = 0
Do While Range(alphaCon(colLoop + 1) & rowLoop + 1).value <> "" And found = False
rowLoop = rowLoop + 1
Do While Range(alphaCon(colLoop + 1) & rowLoop).value <> "" And found = False
colLoop = colLoop + 1
pos = InStr(Range(alphaCon(colLoop) & rowLoop).value, value)
If pos > 0 Then
FncFindText = Mid(Range(alphaCon(colLoop) & rowLoop).value, pos, Len(value))
found = True
End If
Loop
colLoop = 0
Loop
End Function
Private Function alphaCon(aNumber As Integer) As String
Dim letterArray As String
Dim iterations As Integer
letterArray = "ABCDEFGHIJKLMNOPQRSTUVWXYZ"
If aNumber <= 26 Then
alphaCon = (Mid$(letterArray, aNumber, 1))
Else
If aNumber Mod 26 = 0 Then
iterations = Int(aNumber / 26)
alphaCon = (Mid$(letterArray, iterations - 1, 1)) & (Mid$(letterArray, 26, 1))
Else
'we deliberately round down using 'Int' as anything with decimal places is not a full iteration.
iterations = Int(aNumber / 26)
alphaCon = (Mid$(letterArray, iterations, 1)) & (Mid$(letterArray, (aNumber - (26 * iterations)), 1))
End If
End If
End Function
Good day everyone,
I am trying to find a smart solution of extracting 8 digits from a cell (unique ID). The problem here occurs that it might look like this:
112, 65478411, sale
746, id65478411, sale 12.50
999, 65478411
999, id65478411
Thats most of the cases, and probably all mentioned, so I basically need to find the 8 digits in the cell and extract them into different cell. Does anyone have any ideas? I though of eliminating the first characted, then check if the cell is starting with the id, eliminate it further but I understood that this is not the smart way..
Thank you for the insights.
Try this formula:
=--TEXT(LOOKUP(10^8,MID(SUBSTITUTE(A1," ","x"),ROW(INDIRECT("1:"&LEN(A1)-7)),8)+0),"00000000")
This will return the 8 digit number in the string.
To return just the text then:
=TEXT(LOOKUP(10^8,MID(SUBSTITUTE(A1," ","x"),ROW(INDIRECT("1:"&LEN(A1)-7)),8)+0),"00000000")
You can also write a UDF to accomplish this task, example below
Public Function GetMy8Digits(cell As Range)
Dim s As String
Dim i As Integer
Dim answer
Dim counter As Integer
'get cell value
s = cell.Value
'set the counter
counter = 0
'loop through the entire string
For i = 1 To Len(s)
'check to see if the character is a numeric one
If IsNumeric(Mid(s, i, 1)) = True Then
'add it to the answer
answer = answer + Mid(s, i, 1)
counter = counter + 1
'check to see if we have reached 8 digits
If counter = 8 Then
GetMy8Digits = answer
Exit Function
End If
Else
'was not numeric so reset counter and answer
counter = 0
answer = ""
End If
Next i
End Function
Here is an alternative:
=RIGHT(TRIM(MID(SUBSTITUTE(A1,",",REPT(" ",LEN(A1))),LEN(A4),LEN(A1))),8)
Replace all commas with spaces repeated the length of the string,
Then take the mid point starting from the length of the original string for the length of the string (ie second word in new string)
Trim out the spaces
take the right 8 chars to trim out any extra chars (like id)
I want to multiply two 100-Digit Numbers In Excel using matrix. The issue in Excel is that after 15-digit, it shows only 0. So, the output also need to be in a Matrix.
1st Number: "9999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999"
2nd Number: "2222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222"
Output: "22222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222217777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777778"
This may be what OP was after. I thought I would try a naive multiplication method to see how long it would take to run. The answer is less than a second for two 100-digit numbers. You have to select the output range (i.e. A3:GR3 for a 200-digit result) and enter the formula containing the input ranges as an array formula using CtrlShiftEnter e.g.
=Multiply(A1:CV1,A2:CV2)
for two 100-digit numbers.
The method is basically just a simulation of school maths long multiplication, except that the intermediate rows are not stored but immediately added to the answer thus saving a lot of space.
The utility of it is obviously not that it is a replacement for the Karatsuba method, but it is a simple verifiable method which could be used for one-off calculations.
Currently limited to multiplication of rows containing more than one cell (so if you wanted to multiply by a single digit number, would have to enter it as e.g. 09).
Start of numbers
Middle of numbers
End of numbers
Function Multiply(rng1 As Variant, rng2 As Variant)
Dim arr() As Integer
Dim arrLength, r1Length, r2Length, carry, product, digit As Integer
Dim tot, totDigit, totCarry As Integer
Dim v1, v2 As Variant
v1 = rng1
v2 = rng2
r1Length = UBound(v1, 2)
r2Length = UBound(v2, 2)
arrLength = r1Length + r2Length
' Declare 1D array with enough space
ReDim arr(1 To arrLength)
' Loop over digits in first number starting from right
For i = r1Length To 1 Step -1
carry = 0
totCarry = 0
' Loop over digits in second number starting from right
For j = r2Length To 1 Step -1
' Calculate next digit in intermediate values (i.e. one row of long multiplication)
product = v1(1, i) * v2(1, j) + carry
digit = product Mod 10
carry = Int(product / 10)
' Calculate next digit in final values (i.e. totals line of long multiplication)
tot = arr(i + j) + digit + totCarry
arr(i + j) = tot Mod 10
totCarry = Int(tot / 10)
Next j
' Process final carry
arr(i) = carry + totCarry
Next i
' Return as an array
Multiply = arr
End Function
OK it might work like this:-
(1) You need to concatenate your numbers into a string because that's what you need as the input to your function. Native Excel won't do concatenation on arrays so you need a UDF like this one. So B2 contains
=concat(D1:G1)
(2) The output from the function is a string so you need to split it back into separate cells. You could use another UDF or a formula like this one copied across:-
=IF(COLUMNS($C3:C3)>LEN($B$3),"",VALUE(MID($B3,COLUMNS($C3:C3),1)))
So for the simple example it would look like this:-
But I might have got the wrong end of the stick completely.
Place your arrays into A1:A100 and B1:B100, then use three formulas:
1) In C2:C200 enter this as an array formula:
=MMULT(IFERROR(INDEX(A1:A100*TRANSPOSE(B1:B100),(ROW(INDIRECT("1:"&ROWS(A1:A100)*2-1))>0)+TRANSPOSE(ROW(INDIRECT("1:"&ROWS(A1:A100))))-1,MOD(ROW(INDIRECT("1:"&ROWS(A1:A100)*2-1))-TRANSPOSE(ROW(INDIRECT("1:"&ROWS(A1:A100)))),ROWS(A1:A100)*2-1)+1),0),SIGN(A1:A100+1))
2) In D1 enter =C1+INT(D2/10) and fill down to D200.
3) In E1 enter =MOD(D1,10) and fill down to D200.
E1:E200 will contain the answer.
I have some fields that need to be split up into different cells. They are in the following format:
Numbers on Mission 21 0 21
Numbers on Mission 5 1 6
The desired output would be 4 separate cells. The first would contain the words in the string "Numbers on Mission" and the subsequent cells would have each number, which is determined by a space. So for the first example the numbers to extract would be 21, 0, 21. Each would be in its own cell next to the string value. And for the second: 5, 1, 6.
I tried using a split function but wasn't sure how to target the numbers specifically, and to identify the numbers based on the spaces separating them.
Pertinent to your first case (Numbers on Mission), the simple solution could be as shown below:
Sub SplitCells()
Const RowHeader As String = "Numbers on Mission"
Dim ArrNum As Variant
ArrNum = Split(Replace(Range("A1"), RowHeader, ""), " ")
For i = 1 To UBound(ArrNum)
Cells(1, i + 2) = ArrNum(i)
Next
Cells(1, 2) = RowHeader
End Sub
The same logic is applicable to your second case. Hope this may help.
Unless I'm overlooking something, you may not need VBA at all. Have you tried the "Text to Columns" option? If you select the cell(s) with the information you would like to split up, and go to Data -> Text to Columns. There, you can choose "delimited" and choose a space as a delimiter, which will split your data into multiple cells, split by where the space is.
edit: Just realized that will also split up your string. In that case, when you are in 3rd part of the Text to Columns, choose a destaination cell that isn't the cell with your data. (I.E. if your data is in A1, choose B1 as destination, and it'll put the split info there. Then just combine the text columns with something like =B1&" "&C1&" "&D1)
I was able to properly split the values using the following:
If i.Value Like "*on Mission*" Then
x = Split(i, " ")
For y = 0 To UBound(x)
i.Offset(0, y + 1).Value = x(y)
Next y
End If