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Asked this question earlier, hopefully I can craft it better.
I have 5 columns each, that could have dates entered. If the date is less than 14 days, the status column shows "current" if false it shows "overdue". But I need to add: if any date is entered into the 5th column the status column will show "complete"
Right now this is what I'm envisioning...
but what you're after and your current setup is very unclear...
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I'm trying to count the columns that have the same name. I need a formula to apply it to all data.
For example, I am trying to count the amount of cloumns with ID=11 and write them in row "N".
Is there a simple formula for this?
Try using COUNTIF:
=COUNTIF(A3:A25, 11)
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The input lets say is 1/10/2019 which is 2nd week Thursday. Can we have an excel formula which will output 2/14/2019
Use:
=DATE(YEAR(TODAY()),MONTH(TODAY())+1,2+7*(INT(DAY(TODAY())/7)+1))-WEEKDAY(DATE(YEAR(TODAY()),MONTH(TODAY())-1,8-WEEKDAY(TODAY())))
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How to count the number of authors in a column? I need the count on
I'm assuming that you have 10 authors in a column A.
The first record in A2 and last in A11. Then You can get the count in A12 by using this formula
=COUNTA(A2:A11)
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Need help on make excel number format to a list of numbers.
For example:
1-3
to become below on different rows.
1
2
3
If anyone could help
A solution with a formula only:
We assume that A1=1-3. Fill the following formula into A2 and copy it down.
=IF(A1<>"",IF(ISNUMBER(A1),IF(A1+1<=VALUE(RIGHT(A$1,LEN(A$1)-FIND("-",A$1))),A1+1,""),VALUE(LEFT(A$1,FIND("-",A$1)-1))),"")
The result will be
1
2
3
This works for any numbers devided by -.
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I have a excel cells with username.id.I want to delete usernames and I just want ID's to be displayed in cells.
EG: sunny.123 should be transformed to 123
Try this formula:
=RIGHT(A1,LEN(A1)-SEARCH(".",A1))*1
This assumes that your IDs are always using the schema String.Number
If this is not always the case, this formula handles a few more situation:
=IF(ISERROR(SEARCH(".",A1)),IF(ISNUMBER(A1),A1,"Pattern does not match User.Id!"),RIGHT(A1,LEN(A1)-SEARCH(".",A1))*1)