I have hundreds of files in a directory all have the suffix "_aac" in the name. For example: weoi32rijwef_aac.mp4
How can I rename all of these files in a batch process to remove the "_aac" from their filenames?
Much simpler way is
cd /to/that/directory
rename 's/_aac//' *
Something like this?:
for i in *_aac.*
do
mv "$i" "`echo $i | sed -e 's/_aac././'`"
done
Related
I have a folder with lots of files which name has the following structure:
01.artist_name - song_name.mp3
I want to go through all of them and rename them using the regexp:
/^d+\./
so i get only :
artist_name - song_name.mp3
How can i do this in bash?
You can do this in BASH:
for f in [0-9]*.mp3; do
mv "$f" "${f#*.}"
done
Use the Perl rename utility utility. It might be installed on your version of Linux or easy to find.
rename 's/^\d+\.//' -n *.mp3
With the -n flag, it will be a dry run, printing what would be renamed, without actually renaming. If the output looks good, drop the -n flag.
Use 'sed' bash command to do so:
for f in *.mp3;
do
new_name="$(echo $f | sed 's/[^.]*.//')"
mv $f $new_name
done
...in this case, regular expression [^.].* matches everything before first period of a string.
I have a list of for example 100 files with the naming convention
<date>_<Time>_XYZ.xml.abc
<date>_<Time>_XYZ.xml
<date>_<Time>_XYZ.csv
for example
20140730_025373_XYZ.xml
20140730_015233_XYZ.xml.ab
20140730_015233_XYZ.csv
Now I want to write script which will remove anything between two underscores. for example in the above case
remove 015233 and change 20140730_015233_XYZ.xml.ab to 20140730_XYZ.xml.ab
remove 015233 and change 20140730_015233_XYZ.csv to 20140730_XYZ.csv
I have tried number of various options using rename, cut, mv but I am getting varied results, not the one which I expect.
You could use rename command if you want to rename files present inside the current directory,
rename 's/^([^_]*)_[^_]*(_.*)$/$1$2/g' *
You can use sed:
sed 's/\([^_]*\)_.*_\(.*\)/\1_\2/' files.list
You can also use cut command
cut -d'_' -f1,3 filename
for FILE in *; do mv "$FILE" "${FILE/_*_/_}"; done
And more specific is
for FILE in *.xml *.xml.ab *.csv; do mv "$FILE" "${FILE/_*_/_}"; done
Further:
for FILE in *_*_*.xml *_*_*.xml.ab *_*_*.csv; do mv "$FILE" "${FILE/_*_/_}"; done
I have a directory full of sub-directories that look like this:
Track_0000111
Track_0004444
Track_0022222
Track_0333333
Track_5555555
I would like to remove certain directories if they are contained within a list in the file "RemoveFromTop6000_reformatted.txt"
The contents of the text file look like this:
Track_0000111
Track_0022222
Track_0333333
I tried to write a small script to handle this, but it does not seem to work:
#!/bin/bash
for file in cat RemoveFromTop6000_reformatted.txt; do
rm -rfv $file
done
Unfortunately this simply removes the text files, rather than the directories. Any tips?
Thanks!
You forgot backquotes around your call to cat. Without them, rm will simply delete the files cat (which probably doesn't exist, but you might not notice because you're using rm -f) and RemoveFromTop6000_reformatted.txt
Try this:
#!/bin/bash
for file in `cat RemoveFromTop6000_reformatted.txt`; do
rm -rv "$file"
done
or, more simply,
rm -rv `cat $file`
(but this will only work if the directory names don't contain whitespace).
No need to for, for something like this you can do a while read ...; do ... done < file just like this:
#!/bin/bash
while read file
rm -rfv "$file"
done < RemoveFromTop6000_reformatted.txt
you can try below command,
Command:
sed 's/^/"/g' sample.txt | sed 's/$/"/g' | xargs rm -rfv
Description:
Command will remove files as well as directories mentioned in "sample.txt".
NOTE:
In your case,make sure that "RemoveFromTop6000_reformatted.txt"
contains only directories name.
Command will also work if the directories name contains whitespace.
I'm encountering many files with the same content and the same name on some of my servers. I need to quarantine these files for analysis so I can't just remove the duplicates. The OS is Linux (centos and ubuntu).
I enumerate the file names and locations and put them into a text file.
Then I do a for statement to move the files to quarantine.
for file in $(cat bad-stuff.txt); do mv $file /quarantine ;done
The problem is that they have the same file name and I just need to add something unique to the filename to get it to save properly. I'm sure it's something simple but I'm not good with regex. Thanks for the help.
Since you're using Linux, you can take advantage of GNU mv's --backup.
while read -r file
do
mv --backup=numbered "$file" "/quarantine"
done < "bad-stuff.txt"
Here's an example that shows how it works:
$ cat bad-stuff.txt
./c/foo
./d/foo
./a/foo
./b/foo
$ while read -r file; do mv --backup=numbered "$file" "./quarantine"; done < "bad-stuff.txt"
$ ls quarantine/
foo foo.~1~ foo.~2~ foo.~3~
$
I'd use this
for file in $(cat bad-stuff.txt); do mv $file /quarantine/$file.`date -u +%s%N`; done
You'll get everyfile with a timestamp appended (in nanoseconds).
You can create a new file name composed by the directory and the filename. Thus you can add one more argument in your original code:
for ...; do mv $file /quarantine/$(echo $file | sed 's:/:_:g') ; done
Please note that you should replace the _ with a proper character which is special enough.
I have a series of files named like such:
file 1.jpeg
file 2.jpeg
file 3.jpeg
...
file 40.jpeg
I would like remove the space from all of their filenames without having to individually do it. I know its possible using something like: file{1,40}.jpeg or something like that but i can't remember and I don't even know how to search for it.
Thanks!
EDIT: linux
http://www.google.es/search?q=shell+rename+similar+files+in+a+directory
The first result is http://www.debian-administration.org/articles/150
Using the perl rename command [...] we can also, for example, strip spaces from filenames with this:
~$ rename 's/ //' *.jpeg
In other posts I've found this kind of commands that do not require perl:
for f in *; do mv "$f" `echo $f | tr --delete ' '`; done
I've not tried any of them.