Clearr cmd after sending text - text

I've found this small script. And my question is, how can I clear cmd (cls) after every line?
So when the first line is done, it clears cmd and the next line shows up.
Can anyone help? :)
#echo off
:: Ghost typer
setlocal enableextensions enabledelayedexpansion
set lines=6
set "line1=Twinkle twinkle little star"
set "line2=How I wonder what you are"
set "line3=Up above the world so high"
set "line4=Like a diamond in the sky"
set "line5=Twinkle twinkle little star"
set "line6=How I wonder what you are"
for /f %%a in ('"prompt $H&for %%b in (1) do rem"') do set "BS=%%a"
for /L %%a in (1,1,%lines%) do set num=0&set "line=!line%%a!"&call :type
pause>nul
goto :EOF
:type
set "letter=!line:~%num%,1!"
set "delay=%random%%random%%random%%random%%random%%random%%random%"
set "delay=%delay:~-6%"
if not "%letter%"=="" set /p "=a%bs%%letter%" <nul
:: adjust the 3 in the line below: higher is faster typing speed
for /L %%b in (1,10,%delay%) do rem
if "%letter%"=="" echo.&goto :EOF
set /a num+=1
goto :type
Thanks!

put your cls there, where typing a new line starts (just before the call :type):
for /L %%a in (1,1,%lines%) do set num=0&set "line=!line%%a!"&cls&call :type
^---- here

Related

How can I have multiple string colors in this batch file? [duplicate]

This question already has answers here:
Batch Color per line
(11 answers)
Closed 5 years ago.
I have this script and I can't manage to get multiple string colors.
this is the script:
:Sentence 1
#echo off
setlocal enableextensions enabledelayedexpansion
set lines=1
set "line1=This Line in Blue, please" && set LineCount=26
for /f %%a in ('"prompt $H&for %%b in (1) do rem"') do set "BS=%%a"
for /L %%a in (1,1,%lines%) do set num=0&set "line=!line%%a!"&call :type1
pause>nul
goto :EOF
:type1
set /a LineCount-=1
if %LineCount% == 0 ping localhost /n 2 >nul && goto Sentence2
set "letter=!line:~%num%,1!"
set "delay=%random%%random%%random%%random%%random%%random%%random%"
set "delay=%delay:~-6%"
if not "%letter%"=="" set /p "=a%bs%%letter%" <nul
for /L %%b in (1,40,%delay%) do rem
if "%letter%"=="" echo.&goto :EOF
set /a num+=1
goto type1
:Sentence2
#echo off
setlocal enableextensions enabledelayedexpansion
echo.
set lines=1
set "line1=This Line in Red, please" && set LineCount=25
for /f %%a in ('"prompt $H&for %%b in (1) do rem"') do set "BS=%%a"
for /L %%a in (1,1,%lines%) do set num=0&set "line=!line%%a!"&call :type2
pause>nul
goto :EOF
:type2
set /a LineCount-=1
if %LineCount% == 0 ping localhost /n 2 >nul && goto end
set "letter=!line:~%num%,1!"
set "delay=%random%%random%%random%%random%%random%%random%%random%"
set "delay=%delay:~-6%"
if not "%letter%"=="" set /p "=a%bs%%letter%" <nul
for /L %%b in (1,40,%delay%) do rem
if "%letter%"=="" echo.&goto :EOF
set /a num+=1
goto type2
end
echo.
pause
exit
Now I would like to get these two string in a different color:
-This Line in Blue, please
-This Line in Red, please
I tried FINDSTR /L and COLOR /n but I can't manage to get it right..... I know that batch doesn't really support multiple colors in a single command window, but it's possible with external files.
Could anyone help me out?
~Czgb
Probably msr.exe's side function can help you to add foreground and background colors to your script's running, see following screenshot. More usages and examples can see the git docs like: msr on Windows or vivid demo.
In fact, msr.exe/msr.gcc* is a cross platform exe about 1.6MB in my open project for file/text processing.

Outputting string to a text file from a batch program [duplicate]

I have a file report.txt having comma separated values like (1,2,3,4). I am checking if the file is not blank then assign the 4 variables with values in the file. But the variables are not set. Any help why this is happening?
setlocal enabledelayedexpansion
for /f %%i in ("Report.txt") do set size=%%~zi
if %size% gtr 0 (
for /F "tokens=1-4 delims=," %%A in ("Report.txt") do (
set "var1=%%a"
set "var2=%%b"
set "var3=%%c"
set "var4=%%d"
)
set var
)
echo %var1%
You've enabled delayed expansion, but you aren't using it. In order to use delayed expansion, you need to use !variable! instead of %variable%. Additionally, the variable specified in for loops is case-sensitive, so you either need to set var1 equal to %%A or use %%a as the loop variable.
setlocal enabledelayedexpansion
for /f %%i in ("Report.txt") do set size=%%~zi
if %size% gtr 0 (
for /F "tokens=1-4 delims=," %%a in (Report.txt) do (
set "var1=%%a"
set "var2=%%b"
set "var3=%%c"
set "var4=%%d"
)
set var
)
echo !var1!
setlocal enabledelayedexpansion
for /f %%i in ("Report.txt") do set size=%%~zi
if %size% gtr 0 (
I changed the code as below and it started working. Thank you guys for your time. Appeciate it.
for /F "tokens=1-4 delims=," %%A in (%cd%\Report.txt) do (
set "var1=%%A"
set "var2=%%B"
set "var3=%%C"
set "var4=%%D"
)
set var
)
echo !var1!

How can I reverse a string in Batch?

I found this solution for reversing strings that worked before, but not any more for some reason:
setlocal enabledelayedexpansion
set num=0
:LOOP
call set tmpa=%%advanced:~%num%,1%%%
set /a num+=1
if not "%tmpa%" equ "" (
set string1=%tmpa%%string1%
goto LOOP
)
My message that I receive is:
The input line is too long.
The syntax of the command is incorrect.
I simply need to reverse the string in the variable %advanced% and output it to %string1%.
If reversing strings can be done in one line, that would be super helpful in the project I am working on. If it can be done without the setlocal enabledelayedexpansion, that would be even more helpful but I doubt it is be possible.
Another way using a BAT/VBS :
#echo off
set "advanced=1234567890"
echo WScript.Echo StrReverse("%advanced%"^) >reverse.vbs
for /f "delims=" %%a in ('cscript //nologo reverse.vbs') do set "$reversed=%%a"
>nul del reverse.vbs
echo reversed string --^> %$reversed%
You said it first worked and later not anymore; I think simply clearing variable string1 will do the trick. Your code should work as is.
Next, you do not need to enable delayed expansion as you are not using it (!! expansion) anyway.
Finally, instead of asking whether tmpa is empty, you could query whether it is defined (but this is a matter of taste though).
set string1=
set num=0
:LOOP
call set tmpa=%%advanced:~%num%,1%%%
set /a num+=1
if defined tmpa (
set string1=%tmpa%%string1%
goto :LOOP
)
In this way it works if you change to set string1=!tmpa!!string1!
#echo off
setlocal enabledelayedexpansion
set "advanced=abcdefghijklmnopqrstuvwxyz!"
set "num=0"
:LOOP
call set "tmpa=%%advanced:~%num%,1%%%"
set /a num+=1
if not "%tmpa%" equ "" (
set "string1=!tmpa!!string1!"
goto LOOP
)
echo !string1!
endlocal
Another way a bit faster:
#echo off
setlocal enabledelayedexpansion
set "advanced=abcdefghijklmnopqrstuvwxyz"
echo %advanced%>"%tmp%\alpha.tmp"
for %%l in ("%tmp%\alpha.tmp") do set /a len=%%~zl
set /a len-=2
set "reverse="
set "char="
for /l %%i in (0,1,%len%) do (
for /f "usebackq" %%a in ("%tmp%\alpha.tmp") do (
set "char=%%a"
set "reverse=!char:~%%i,1!!reverse!"
)
)
del "%tmp%\alpha.tmp"
echo !reverse!
endlocal
To reverse a string or file contents:
REM eg. set string/content to file
set /p="Hello, world!"> test
certutil -encodehex -f test temp 4
REM reverse file contents
set rev=
(for /f "delims=" %i in (temp) do for %j in (%i) do set rev=%j !rev!)
set /p="%rev:~0,-6%">temp
certutil -decodehex temp out.txt
REM view content
more out.txt
Tested in Win 10 CMD

character manipulation in file cmd

this is file.txt
hello
hai
So i wanna create a program that will read this file. and then replace every ALPHABET with the succeeding one. keeping all numbers and other symbols intact.
so the file.txt would become
ifmmp
ibj
current have tried reading every \n and then reading every character in the line, but echoing them would result in it being in different lines
ie
for /f "delims=" %%i in ('^<%path% findstr /n "^"') do (
set "line=%%i"
setlocal enabledelayedexpansion
set "line=!line:*:=!"
set "num=-1"
:loop
set /a num=num+1
call set "name2=%%line:~%num%,1%%"
if defined name2 (
rem set /a name2+=1 this statement wont work
echo %name2%
goto :loop )
)
but then the output i get is
echo is off
e
l
l
o
any ideas?
The set /a command does only work with numbers, you can try this:
#echo off&setlocal
set "alfa=abcdefghijklmnopqrstuvwxyza"
set "test=hello hai"
set /a num=0
:loop
call set "char=%%test:~%num%,1%%"
if not defined char goto:eof
call set "alf1=%%alfa:*%char%=%%"
if "%char%" neq " " echo %alf1:~0,1%
set /a num+=1
goto:loop
..output is:
i
f
m
m
p
i
b
j
Here is a ROT13 batch file - what you are describing is a ROT1 translation. Maybe this will work for you as it is, or give you ideas and you can modify it.
#echo off
:: by aacini
:: program works as a filter, that is, it read lines from keyboard (stdin) and send output to screen (stdout). "type filetext.txt|rot13.bat" or "rot13.bat < filetext.txt"
:: with d benham update
#echo off
:: simple rot-13 conversion filter program
setlocal disableDelayedExpansion
set lower=abcdefghijklmnopqrstuvwxyz
set upper=ABCDEFGHIJKLMNOPQRSTUVWXYZ
for /l %%a in (0,1,25) do (
set /a "rot13=(%%a+13)%%26"
setlocal enableDelayedExpansion
for %%b in (!rot13!) do for /f "tokens=1-4" %%A in (
"!lower:~%%a,1! !lower:~%%b,1! !upper:~%%a,1! !upper:~%%b,1!"
) do (
endlocal
set "lower%%A=%%B"
set "upper%%C=%%D"
)
)
for /f "delims=" %%a in ('findstr /n "^"') do (
set "line=%%a"
setlocal enableDelayedExpansion
set "line=!line:*:=!"
set output=
if defined line (
set /a len=0
for /l %%b in (12,-1,0) do (
set /a "len|=1<<%%b"
for %%c in (!len!) do if "!line:~%%c,1!" equ "" set /a "len&=~1<<%%b"
)
for /l %%b in (0,1,!len!) do (
set "char=!line:~%%b,1!"
if defined lower!char! for /f delims^=^ eol^= %%c in ("!char!") do (
if "!lower:%%c=%%c!" neq "!lower!" (
set "char=!upper%%c!"
) else set "char=!lower%%c!"
)
set "output=!output!!char!"
)
)
echo(!output!
endlocal
)

Random line of text using batch

How could one select a random line of text from a text file and set it in a variable to use?
The Batch program below is Eitan's solution slightly modified to run faster:
#echo off
setlocal EnableDelayedExpansion
set INPUT_FILE="test.txt"
:: # Count the number of lines in the text file and generate a random number
for /f "usebackq" %%a in (`find /V /C "" ^< %INPUT_FILE%`) do set lines=%%a
set /a randnum=%RANDOM% * lines / 32768 + 1, skiplines=randnum-1
:: # Extract the line from the file
set skip=
if %skiplines% gtr 0 set skip=skip=%skiplines%
for /f "usebackq %skip% delims=" %%a in (%INPUT_FILE%) do set "randline=%%a" & goto continue
:continue
echo Line #%randnum% is:
echo/!randline!
Like it is already mentioned here in StackOverflow, among others, %RANDOM% expands to a random number between 0 and 32767.
You can use this mechanism to generate a random line number. However, to make it a valid line number you will have to normalize it by the the number of lines in the input text file.
Here's a simple script that shows how to do it:
#echo off
setlocal enabledelayedexpansion
set INPUT_FILE="test.txt"
:: # Count the number of lines in the text file and generate a random number
set lines=0
for /f "usebackq" %%a in (%INPUT_FILE%) do set /a lines+=1
echo %RANDOM% >nul
set /a randnum=%RANDOM% * !lines! / 32768 + 1
:: # Extract the line from the file
set lines=0
for /f "usebackq tokens=*" %%a in (%INPUT_FILE%) do (
set /a lines+=1
if !lines!==!randnum! set randline=%%a
)
echo Line #!randnum! is:
echo.!randline!
Here's yet another approach. It reads the file name from the command line and uses a FOR /L loop to get to the calculated line number:
#ECHO OFF
FOR /F "" %%I IN ('FIND /C /V "" ^<%1') DO SET /A lines=%%I
SET /A skip=%RANDOM%%%lines
<%1 (
FOR /L %%I IN (1,1,%skip%) DO (
SET /P line=
)
SET line=
SET /P line=
)
ECHO(%line%
The FOR /F loop simply gets the number of lines in the file (the method is borrowed from #Aacini's answer).
A rather simplistic formula then calculates the number of lines to skip in the file.
Next, the file is read. The FOR /L loop merely consumes the specified number of lines using a SET /P instruction. Following the loop, one more SET /P command reads the line that is eventually ECHOed.
The above implementation is just to show the basic idea. It is not without issues, but some of them could easily be resolved:
There's no testing whether the parameter is indeed supplied. If it is absent, the script will break. You could add the necessary check at the beginning of the script like this:
IF "%~1"=="" GOTO :EOF
If there's no parameter, this command terminates the script by sending the control to the end of the script (GOTO :EOF).
The file specified might not exist. Again, you could test that at the beginning, just after verifying that the parameter is supplied, to terminate the script if necessary:
IF NOT EXIST %1 GOTO :EOF
If the file is empty, the lines will be 0 and the subsequent expression using it will run into a division by zero error. Therefore, you'll also need to test the resulting line count (and prevent the script from running further if the count is indeed 0). You can do that by adding the following line just after the FOR /F loop:
IF %lines%==0 GOTO :EOF
Like I said, the formula is somewhat simplistic. It doesn't produce a number greater than 32767, which is the limitation of %RANDOM%. That might well be enough for you, but in case it is not, you could extend the range to 230-1 using two %RANDOM% calls like this:
SET /A skip=(%RANDOM%*32768+%RANDOM%)%%lines
So, here's the same script again, amended to address the above mentioned issues:
#ECHO OFF
IF "%~1"=="" GOTO :EOF
IF NOT EXIST %1 GOTO :EOF
FOR /F "" %%I IN ('FIND /C /V "" ^<%1') DO SET /A lines=%%I
IF %lines%==0 GOTO :EOF
SET /A skip=(%RANDOM%*32768+%RANDOM%)%%lines
<%1 (
FOR /L %%I IN (1,1,%skip%) DO (
SET /P line=
)
SET line=
SET /P line=
)
ECHO(%line%
One other note is that, if you like, you can add messages explaining the reason for the premature termination of the script. Basically, wherever you want to add the message, you'll just need to replace the single
GOTO :EOF
with
(ECHO your message & GOTO :EOF)
For instance:
IF NOT EXIST %1 (ECHO Error! File not found & GOTO :EOF)

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