I'm running a command to retrieve the location of a logfile using from a .sh bash script
rig=`forever list | grep 'server.*root.*\.log' | awk '{print $8}'`
echoing it prints:
echo $rig
/root/.forever/1cFY.log
But when I try to read the file (which exists) like so:
less $rig
I get:
/root/.forever/1cFY.log: No such file or directory
However if I manually enter the file name without my .sh script it works.
Any ideas?
Looks like you have grep configured to output color. Just drop the grep and use awk:
rig=$(forever list | awk '/server.*root.*\.log/{print $8}')
Related
I have a file testtns.txt which has numbers like below :
123
456
I am then passing the input of the file folder path like "/var/www/batchfiles/files/test.csv" . The test.csv has following records :
1,123,On its way to warehouse,20230131
2,456,On its way to warehouse,20230201
3,777,Pickedup,20230201
4,888,Pickedup,20230202
I have created the script printgrep.bash to read the numbers from the file testtns.txt and then grep the csv files in folder "/var/www/batchfiles/files/". I am running the script using command .\printgrep.bash /var/www/batchfiles/files/* and excepting the output to be in output.txt as follows :
1,123,On its way to warehouse,20230131
2,456,On its way to warehouse,20230201
However when I run the above command, output.txt is empty and doesnt have any results. However if I run the grep command as it is, it does return results as excepted.
Can someone let me know why the grep command not working in the below script printgrep.bash :
#!/bin/bash
cat testtns.txt | while read line
do
grep -i "^ $line" $1 >> output.txt
done
Tried even below grep command but still didnt work :
#!/bin/bash
cat testtns.txt | while read line
do
grep -i "$line" $1 >> output.txt
done
I write down some commands row by row in a file, and I want to execute the commands through grep and pipe;
for example:
1.there is a file a.txt,which content is like below:
echo "hello world"
ls -l
2.then I want execute the first line in my terminal, so I want it like this:
cat a.txt | grep echo | execute the output of previous commands
so that, I can finally execute the command, which is the first line of a.txt.
(can not find any answer of this, so I come here to find some help.)
You can either pipe the command to bash (or any other shell) to execute it:
sed -n 1p a.txt | bash
or you can use eval with command substitution:
eval $(head -n1 a.txt)
BTW, I showed you another two ways how to extract the line from the file.
I am running the following command:
for file in 2017120[1-9]/54100_*.zip; do unzip -c "$file" | grep "3613825" | grep '3418665' ; done
This does a grep job of pulling the data that matches my grep parameters, but I can't figure out how to capture which file the results came from.
I have tried adding grep -H but the result comes back with (standard input).
How can I capture the file name?
When I need to do something like this I just add an echo of the file name to the for loop like this:
for file in 2017120[1-9]/54100_*.zip; do echo $file; unzip -c "$file" | grep "3613825" | grep '3418665' ; done
This prints out the list of files, and the grep line that matches will print immediately after the file that the match is in. like this:
file_1
file_2
file_3
matching line
file_4
file_5
another matching line
file_6
...
Thus I know the matching lines occurred in file_3 and file_5.
I'm trying to parse lines from an error log in BASH and then send a certain part out to a BASH variable to be used later in the script and having issues once I try and pass it to a BASH variable.
What the log file looks like:
1446851818|1446851808.1795|12|NONE|DID|8001234
I need the number in the third set (in this case, the number is 12) of the line
Here's an example of the command I'm running:
tail -n5 /var/log/asterisk/queue_log | grep 'CONNECT' | awk -F '[|]' '{print $3}'
The line of code is trying to accomplish this:
Grab the last lines of the log file
Search for a phrase (in this case connect, I'm using the same command to trigger different items)
Separate the number in the third set of the line out so it can be used elsewhere
If I run the above full command, it runs successfully like so:
tail -n5 /var/log/asterisk/queue_log | grep 'CONNECT' | awk -F '[|]' '{print $3}'
12
Now if I try and assign it to a variable in the same line/command, I'm unable to have it echo back the variable.
My command when assigning to a variable looks like:
tail -n5 /var/log/asterisk/queue_log | grep 'CONNECT' | brand=$(awk -F '[|]' '{print $3}')
(It is being run in the same script as the echo command so the variable should be fine, test script looks like:
#!/bin/bash
tail -n5 /var/log/asterisk/queue_log | grep 'CONNECT' | brand=$(awk -F '[|]' '{print $3}')
echo "$brand";
I'm aware this is most likely not the most efficient/eloquent solution to do this, so if there are other ideas/ways to accomplish this I'm open to them as well (my BASH skills are basic but improving)
You need to capture the output of the entire pipeline, not just the final section of it:
brand=$(tail -n5 /var/log/asterisk/queue_log | grep 'CONNECT' | awk -F '|' '{print $3}')
You may also want to consider what will happen if there is more than one line containing CONNECT in the final five lines of the file (or indeed, if there are none). That's going to cause brand to have multiple (or no) values.
If your intent is to get the third field from the latest line in the file containing CONNECT, awk can pretty much handle the entire thing without needing tail or grep:
brand=$(awk -F '|' '/CONNECT/ {latest = $3} END {print latest}')
I have to write a shell script in linux in which i have to pull the name of the second last folder of the given path. For example:-
/var/www/html/folder1/folder2/folder3
How can i get only the name of second last folder "folder2" using a command?
Note: My shell script is placed at root (/var/www/html)
Using awk:
awk -F/ '{print $(NF-1)}' <<< "/var/www/html/folder1/folder2/folder3"
Alternatively, call basename on the dirname.
basename "$(dirname /var/www/html/folder1/folder2/folder3)"
you can use sed to get it:
export some_path="/var/www/html/folder1/folder2/folder3"
export folder_place2=`echo $some_path | sed -e "s/.*\/\([^/]*\)\/[^/]*/\1/"`
echo $folder_place2