I am trying to get values from other column, based on some logic, crossed logic, but I didn't get any result with the only thing I know: IF or VLOOKUP.
The table is in this way:
So basically there are groups divided by blank row, and in column D I want to add the value from column B, but according with other letter that the one from the row ( C is from Credit, D is from Debtor). So in first D5 I have C on the same row in A5, so I need to take value from D, which is 2, according to B6.
So sorry if this question is too easy or stupid, but I don't know much about excel formulas, other that the basic one.
I'd say the fastest way with formula takes two columns. The first one (let's say column C) will use this formula to define the blocks:
=IF(A5="",C4+1,IFERROR(C4+0,0))
It's meant for cell C5.
The second column will give back the actual result:
=SUMIFS(B:B,A:A,IF(A5="C","D",IF(A5="D","C","")),C:C,C5)
It's meant for cell D5.
Place them accordingly and drag them down to cover your list.
Then again: if you are looking just for the number and not for its sum (and therefore assuming all numbers are equal for each letter in each block), just use this one in cell D5 instead of the previous one:
=SUMIFS(B:B,A:A,IF(A5="C","D",IF(A5="D","C","")),C:C,C5)/COUNTIFS(A:A,IF(A5="C","D",IF(A5="D","C","")),C:C,C5)
Now if you were to use only IF and VLOOKUP functions, a possible solution could be this one:
A
B
C
D
E
F
G
Block index
0
What to search
What is
Value
Result
C
1
=IF(A5="",C4+1,C4)
=IF(A5="",C4+1,C4)&SE(A5="C","D",SE(A5="D","C",""))
=C5&A5
=B5
=IF(VLOOKUP(D5,E:F,2,FALSO)=0,"",VLOOKUP(D5,E:F,2,FALSO))
D
2
=IF(A6="",C5+1,C5)
=IF(A6="",C5+1,C5)&SE(A6="C","D",SE(A6="D","C",""))
=C6&A6
=B6
=IF(VLOOKUP(D6,E:F,2,FALSO)=0,"",VLOOKUP(D6,E:F,2,FALSO))
D
2
=IF(A7="",C6+1,C6)
=IF(A7="",C6+1,C6)&SE(A7="C","D",SE(A7="D","C",""))
=C7&A7
=B7
=IF(VLOOKUP(D7,E:F,2,FALSO)=0,"",VLOOKUP(D7,E:F,2,FALSO))
=IF(A8="",C7+1,C7)
=IF(A8="",C7+1,C7)&SE(A8="C","D",SE(A8="D","C",""))
=C8&A8
=B8
=IF(VLOOKUP(D8,E:F,2,FALSO)=0,"",VLOOKUP(D8,E:F,2,FALSO))
D
3
=IF(A9="",C8+1,C8)
=IF(A9="",C8+1,C8)&SE(A9="C","D",SE(A9="D","C",""))
=C9&A9
=B9
=IF(VLOOKUP(D9,E:F,2,FALSO)=0,"",VLOOKUP(D9,E:F,2,FALSO))
C
4
=IF(A10="",C9+1,C9)
=IF(A10="",C9+1,C9)&SE(A10="C","D",SE(A10="D","C",""))
=C10&A10
=B10
=IF(VLOOKUP(D10,E:F,2,FALSO)=0,"",VLOOKUP(D10,E:F,2,FALSO))
=IF(A11="",C10+1,C10)
=IF(A11="",C10+1,C10)&SE(A11="C","D",SE(A11="D","C",""))
=C11&A11
=B11
=IF(VLOOKUP(D11,E:F,2,FALSO)=0,"",VLOOKUP(D11,E:F,2,FALSO))
D
2
=IF(A12="",C11+1,C11)
=IF(A12="",C11+1,C11)&SE(A12="C","D",SE(A12="D","C",""))
=C12&A12
=B12
=IF(VLOOKUP(D12,E:F,2,FALSO)=0,"",VLOOKUP(D12,E:F,2,FALSO))
C
5
=IF(A13="",C12+1,C12)
=IF(A13="",C12+1,C12)&SE(A13="C","D",SE(A13="D","C",""))
=C13&A13
=B13
=IF(VLOOKUP(D13,E:F,2,FALSO)=0,"",VLOOKUP(D13,E:F,2,FALSO))
C
5
=IF(A14="",C13+1,C13)
=IF(A14="",C13+1,C13)&SE(A14="C","D",SE(A14="D","C",""))
=C14&A14
=B14
=IF(VLOOKUP(D14,E:F,2,FALSO)=0,"",VLOOKUP(D14,E:F,2,FALSO))
Given an Excel table of shape
Col. A Col B Col. C Col. D Col. E
x 2 x 2 3
x 3 y 7
y 7 z -5
x 2
z -5
I want to return the first unique hit in Column B for argument "x" in Column D,
the second unique hit in Column B for argument "x" in Column E and so forth.
The formula I'm currently using in cell D1 for this is
{=IFERROR(INDEX($B$1:$B$5,MATCH(0,COUNTIF($C1:C1,$B$1:$B$5)+($A$1:$A$5<>$C1),0)),"")}
which is working.
The problem I'm having is that since this is an array formula and since I'm analyzing a decent amount of data computation time for my sheet is too high.
Is there an alternative for this functionality avoiding an array formula?
Thanks!
Haven't got time to test this properly, but if you have Excel 365 you can use a single formula per row and it may be faster:
=TRANSPOSE(UNIQUE(FILTER(B1:B10,A1:A10=C1)))
in D1.
EDIT
To pull the formula down, you need static references as OP has pointed out. Probably should check for empty cells in column C as well, so formula becomes:
=IF(C1="","",TRANSPOSE(UNIQUE(FILTER(B$1:B$10,A$1:A$10=C1))))
I have simple problem, but I've not be able to get an answer from searching. I require a column to calculate the number of the nth occurrence of a value. It's best explained in this picture
I require a method to calculate column B.
I'd be very grateful for any help.
Are you looking to merely provide a count of the distinct entries of column A in column B? Or merely add a formula to come up with the table in your link?
If the latter, then the formula to write in cell B2 is:
=COUNTIF(A$2:A2,A2)
then copy/paste it down column B. Note - if your data is both a Date and Time, but the cell is formatted to only display a date, you may not get the results you want. You'd need to interject a new column with a "floor" calculation to round the date/time value to a date (Excel date times are decimal, with integer part dictating the date, and remaining 0.0 -> 1.0 dictating the time of day)
If you just want to derive a table of the counts of distinct entries in column A, then a pivot table will do this for you - simple add a pivot table to cover the data in column A, then select column A into the rows category, and then also drag it into the values category, ensuring the field is set to "Count of". You should then have a table with the distinct entries in your data set in one column, and the count of their occurrences in the other column.
You can use the COUNTIF worksheet function, with a relative address.
Eg. In cell B2, enter this formula:
=COUNTIF(A$2:A2,A2)
And then fill-down.
Use the following formula to generate the required series:
=COUNTIF($A$1:A1,A1) and strech(copy) it in all the cells
This will generate result like this:
A 1 COUNTIF($A$1:A1,A1)
A 2 COUNTIF($A$1:A2,A2)
C 1 COUNTIF($A$1:A3,A3)
C 2 COUNTIF($A$1:A4,A4)
B 1 COUNTIF($A$1:A5,A5)
B 2 COUNTIF($A$1:A6,A6)
A 3 COUNTIF($A$1:A7,A7)
C 3 COUNTIF($A$1:A8,A8)
D 1 COUNTIF($A$1:A9,A9)
D 2 COUNTIF($A$1:A10,A10)
D 3 COUNTIF($A$1:A11,A11)
D 4 COUNTIF($A$1:A12,A12)
Column A Has Text & Columns B, C & D contain numbers.
For Ex.)
A... …B C D
John 4 6 2
Dave 4 6 4
Mike 4 5 1
Bill 2 5 9
I would like a cell to return the name in column A that has the Largest Number in Column B. And if there are similar numbers, go to the next column and determine which is highest, and if that is tied go to the next column and so on.
Any help would be appreciated.
We can de-conflict ties.In E1 enter:
=B1 + C1/(10*MAX(C:C))+D1/(100*MAX(D:D))
and copy down. Then in another cell enter:
=INDEX(A:A,MATCH(MAX(E:E),E:E,0))
EDIT#1
This is only good for 3 columns of numbers, but it is very easy to add additional de-confliction terms if necessary:
=B1 + C1/(10*MAX(C:C))+D1/(100*MAX(D:D))+E1/(1000*MAX(E:E))
For an expandable number of rows/columns, use a helper row with the same number of columns as number columns in your data. The formulas below reference the following image (the data are in A1:G7):
B9-->=MAX(B1:B7)
C9 (fill over the remaining columns to G9)-->
=MAX(IF(MMULT(--($B1:B7=$B9:B9),--(ROW(INDIRECT("1:"&COLUMNS($B9:B9)))>0))=COLUMNS($B9:B9),C1:C7))
The following formula will give the answer (shown in A9 above):
=INDEX(A1:A7,MATCH(TRUE,(MMULT(--($B1:G7=$B9:G9),--(ROW(INDIRECT("1:"&COLUMNS($B9:G9)))>0))=COLUMNS($B9:G9)),0))
UPDATE WITH ALTERNATIVE METHOD
Using a helper column instead, again referencing the image below (the data are in A1:G7):
I1 (fill down to I7)-->
=SUM(--(MMULT(SIGN(B1:G1-$B$1:$G$7)*2^(COLUMN(G1)-COLUMN(A1:F1)),--(ROW(INDIRECT("1:"&COLUMNS(B1:G1)))>0))>0))
The following formula will give the answer (shown in J1 above):
=INDEX(A1:A7,MATCH(MAX(I1:I7),I1:I7,))
As a bonus, notice that the helper column corresponds to the order that you would get from sorting the data by each column left-to-right. In other words, you could use the helper column to perform a formula-based multi-column sort on strictly numeric data. For the last image, entering the following array formula into a range with the same dimensions as A1:G7 gives a descending sort on columns B through G:
=IF(A1:A7=A1:A7,INDEX(A1:G7,MATCH(ROW(A7)-ROW(A1:A7),I1:I7,0),))
I have simple problem, but I've not be able to get an answer from searching. I require a column to calculate the number of the nth occurrence of a value. It's best explained in this picture
I require a method to calculate column B.
I'd be very grateful for any help.
Are you looking to merely provide a count of the distinct entries of column A in column B? Or merely add a formula to come up with the table in your link?
If the latter, then the formula to write in cell B2 is:
=COUNTIF(A$2:A2,A2)
then copy/paste it down column B. Note - if your data is both a Date and Time, but the cell is formatted to only display a date, you may not get the results you want. You'd need to interject a new column with a "floor" calculation to round the date/time value to a date (Excel date times are decimal, with integer part dictating the date, and remaining 0.0 -> 1.0 dictating the time of day)
If you just want to derive a table of the counts of distinct entries in column A, then a pivot table will do this for you - simple add a pivot table to cover the data in column A, then select column A into the rows category, and then also drag it into the values category, ensuring the field is set to "Count of". You should then have a table with the distinct entries in your data set in one column, and the count of their occurrences in the other column.
You can use the COUNTIF worksheet function, with a relative address.
Eg. In cell B2, enter this formula:
=COUNTIF(A$2:A2,A2)
And then fill-down.
Use the following formula to generate the required series:
=COUNTIF($A$1:A1,A1) and strech(copy) it in all the cells
This will generate result like this:
A 1 COUNTIF($A$1:A1,A1)
A 2 COUNTIF($A$1:A2,A2)
C 1 COUNTIF($A$1:A3,A3)
C 2 COUNTIF($A$1:A4,A4)
B 1 COUNTIF($A$1:A5,A5)
B 2 COUNTIF($A$1:A6,A6)
A 3 COUNTIF($A$1:A7,A7)
C 3 COUNTIF($A$1:A8,A8)
D 1 COUNTIF($A$1:A9,A9)
D 2 COUNTIF($A$1:A10,A10)
D 3 COUNTIF($A$1:A11,A11)
D 4 COUNTIF($A$1:A12,A12)