I am attempting to read in values from a tab delimited text file and store them into ArrayLists. The issue is that some values such as ethnicity and gang may contain multiple strings separated by a single space. Is there a way to make it so that I may read in all strings until the next tab? Thank you in advance.
while (file.hasNext()) // creates while loop using scanner, in that will
// store values in arraylist until it runs out
// of values
{
// stores values from tab delimited file in specified variable each
// time the while loop is run
serial = file.next();
last = file.next();
middle = file.next();
first = file.next();
soc = file.next();
birth = file.next();
ethnicity = file.next();
height = file.next();
weight = file.next();
gang = file.next();
reason = file.next();
dateIn = file.next();
dateOut = file.next();
parole = file.next();
cell = file.next();
// stores values from variables above in the defined array list
serialList.add(i, serial);
lastList.add(i, last);
middleList.add(i, middle);
firstList.add(i, first);
socList.add(i, soc);
birthList.add(i, birth);
ethnicityList.add(i, ethnicity);
heightList.add(i, height);
weightList.add(i, weight);
gangList.add(i, gang);
reasonList.add(i, reason);
dateInList.add(i, dateIn);
dateOutList.add(i, dateOut);
paroleList.add(i, parole);
cellList.add(i, cell);
i++; // increases value each time loop runs
}
Assuming your file is also line-separated. You should read the file line by line.
fis = new FileInputStream("the_file_name");
br = new BufferedReader(new InputStreamReader(fis, Charset.forName("UTF-8")));
while ((line = br.readLine()) != null) {
values = line.split("\t");
serial = values[0];
last = values[1];
...
}
If you want to get an array of all the space-separated values, call values[6].split(" ");
The next method has the option of taking a string as an argument. The String is a pattern you want to get so you want something like the following
String s = file.next("[\\S ]+");
Which says grab me anything that is a group of non white space or a space.
Related
My project need is to make part of a string bold leaving any OR and AND like the below example.
TOWING PACK 11 OR TOWING PACK 13 AND TOWING PACK 14 OR TOWING PACK 15
I tried to follow the reverse approach.
I tried to make the entire cell BOLD // This works
Then using RichTextString make "OR" and "AND" to normal Italics. //The issue - After the first "OR" all the rest of the string is formatted to normal format.
Output I am getting:
TOWING PACK 11 OR TOWING PACK 13 AND TOWING PACK 14 OR TOWING PACK 15
I am using poi 5.2.3 and below is the code sample. Can anyone point out what is wrong here.
CreationHelper creationHelper = workbook.getCreationHelper();
XSSFFont fontBold = workbook.createFont();
fontBold.setBold(true);
XSSFFont fontItalic = workbook.createFont();
fontItalic.setItalic(true);
fontItalic.setBold(false);
XSSFCellStyle boldstyle = workbook.createCellStyle();
boldstyle.setFont(fontBold);
int startrow = 2;
Iterator<Row> boldrowIterator = spreadsheet.iterator();
while (boldrowIterator.hasNext()) {
Row boldrow = boldrowIterator.next();
if (boldrow.getRowNum()==startrow) {
out.println(boldrow.getCell(9));
Cell boldcell = boldrow.getCell(9);
boldcell.setCellStyle(boldstyle);
startrow = startrow+1;
String Featuredescription = boldrow.getCell(9).getStringCellValue();
if (Featuredescription.contains("OR")) {
RichTextString richTextString = creationHelper.createRichTextString(Featuredescription);
String word = " OR ";
int startIndex = Featuredescription.indexOf(word);
int endIndex = startIndex + word.length();
out.println("Featuredescription: " + Featuredescription + startIndex + endIndex);
richTextString.applyFont(startIndex, endIndex, fontItalic);
boldcell.setCellValue(richTextString);
}
} }
EDIT
XSSFCellStyle linstyle = workbook.createCellStyle();
Font linfont = workbook.createFont();
linfont.setColor(IndexedColors.ORANGE.getIndex());
linstyle.setFont(linfont);
Iterator<Row> linrowIterator = spreadsheet.iterator();
while (linrowIterator.hasNext())
{
Row linrow = linrowIterator.next();
Iterator <Cell> lincellIterator = linrow.cellIterator();
if (linrow.getRowNum()==linrowcount) {
if (linrow.getCell(13).getStringCellValue().contains("LIN")) {
while (lincellIterator.hasNext())
{
Cell lincell = lincellIterator.next();
lincell.setCellStyle(linstyle);
} } linrowcount = linrowcount+1; }
}
I would recommend using a simple regular expression to find all the occurrences of AND and OR (note the spaces included in these strings). Doing this lets you easily determine the location of each occurrence within the overall string (the indexes of where each word starts and ends). You can use this to set everything to bold (like you are already doing) and then set each OR and AND to normal.
My code assumes your test text is in cell A1 - and that is the only cell I test. You can add back your looping logic to handle more cells.
You will also need:
import java.util.regex.Matcher;
import java.util.regex.Pattern;
I have added comments to the code to explain specific lines:
FileInputStream file = new FileInputStream(new File("C:/temp/poi/rich_formatting_in.xlsx"));
Workbook wb = new XSSFWorkbook(file);
Sheet sheet = wb.getSheet("Sheet1");
CreationHelper creationHelper = wb.getCreationHelper();
Row row = sheet.getRow(0);
Cell cell = row.getCell(0);
String content = cell.getStringCellValue();
Font bold = wb.createFont();
bold.setBold(true);
Font normal = wb.createFont();
normal.setBold(false);
//normal.setItalic(true); // uncomment, if you need italics, as well.
RichTextString richStr = creationHelper.createRichTextString(content);
richStr.applyFont(bold); // set everything to bold
String regex = "( AND | OR )"; // note the spaces in the strings
Pattern pattern = Pattern.compile(regex, Pattern.MULTILINE);
Matcher matcher = pattern.matcher(content);
while (matcher.find()) {
// process each found group (one group for each AND and OR):
for (int i = 1; i <= matcher.groupCount(); i++) {
// matcher.start(i) finds where the start of the match is
// matcher.end(i) finds the position of the end of the match
// we can use these start and end positions to set that text to normal:
richStr.applyFont(matcher.start(i), matcher.end(i), normal);
}
}
// write the final string to the spreadsheet:
cell.setCellValue(richStr);
// write the spreadsheet to a file so we can see the results:
try (FileOutputStream out = new FileOutputStream(new File("C:/temp/poi/rich_formatting_out.xlsx"))) {
wb.write(out);
}
The results are:
The regex ( AND | OR ) is very basic - it assumes every occurrence of the words AND and OR surrounded by spaces are what need to be adjusted.
I would like to know if there will be a way to transform a csv to the JSON format suitable for the Tabulator library?
The idea would be to have a format as seen on excel :
- the first cell on the top left, empty
- columns A, B, C... AA, AB... according to the number of cells on the longest row
- the line number automatically on the first cell of each line)
I had the idea of doing it directly with loops, but it takes a lot of time I find. I don't see any other way.
Thank you for the help.
Check the following function, I hope this is what you are looking for...
let csvfile = 'title1,title2,title3,title4\n1,2,3,4\n11,22,33,44' //YOUR CSV FILE
let capLetters = 'ABCDEFGHIJKLMNOPQRSTUVWXYZ' // ALPHABET SET
let finalJson = [];
let headers;
let line =[];
convertCSV2JSON(csvfile)
function convertCSV2JSON(csv) {
line = csv.split("\n"); //PARSE ALL AVAILABLE LINES INTO ARRAY
result = [];
headers = line[0].split(","); //PARSE ALL AVAILABLE STRING NAMES INTO ARRAY AND KEEP ONLY THE FIRST ONE (HEADER)
line.slice(1).forEach(function(item,i){ //RUN EACH ITEM EXCLUDING COLUMN NAMES
var obj = {};
if(line[i] === null || line[i] === undefined) {
}else{
var entries = line[i+1].split(","); // SEPARATE FOUND ENTRIES EXCLUDING COLUMN NAMES (i+1)
for(var j = 0; j < entries.length; j++) { // PARSE ENTRIES
obj[convert2Letters(j)] = entries[j]; // ASSIGN A LETTER AS COLUMN NAME
}
}
finalJson.push(obj);
})
console.log(finalJson);
}
function convert2Letters(iteration) {
let readyLetter = ''
while (iteration >= 0) {
readyLetter += capLetters[iteration % 26]
iteration = Math.floor(iteration / 26) - 1
}
return readyLetter
}
The fuzzy part was at foreach() function, because you cannot initiate index at your preference... slice() did the trick!
Moreover convert2Letters() function takes an array of letters and on each iteration finds the modulus of 26 letters, removing by one shows you the next combination...
Example:
If you have 30 columns it will give 30 % 26 = 4
4 corresponds to capLetters[4] which is 'E'
calculate next: iteration = Math.floor(iteration / 26) - 1 which means on every 26 increment (0,26,52,78...) it will give (-1,0,1,2...) corresponding. So a 30 columns iteration will have 0 as result which corresponds to capLetters[0] = 'A'
Resulting: 30 columns will give letters 'EA'
In Flutter, after a Paragraph or TextPainter has laid out it's text, you can get the Rects for the lines (or runs within a line) by calling getBoxesForSelection. If you draw the actual boxes they look something like this:
How do I programmatically get the text within each TextBox?
I wish there were a better way, but this is the only way I have found so far:
// The TextPaint has already been laid out
// select everything
TextSelection selection = TextSelection(baseOffset: 0, extentOffset: textSpan.text.length);
// get a list of TextBoxes (Rects)
List<TextBox> boxes = _textPainter.getBoxesForSelection(selection);
// Loop through each text box
List<String> lineTexts = [];
int start = 0;
int end;
int index = -1;
for (TextBox box in boxes) {
index += 1;
// Uncomment this if you want to only get the whole line of text
// (sometimes a single line may have multiple TextBoxes)
// if (box.left != 0.0)
// continue;
if (index == 0)
continue;
// Go one logical pixel within the box and get the position
// of the character in the string.
end = _textPainter.getPositionForOffset(Offset(box.left + 1, box.top + 1)).offset;
// add the substring to the list of lines
final line = rawText.substring(start, end);
lineTexts.add(line);
start = end;
}
// get the last substring
final extra = rawText.substring(start);
lineTexts.add(extra);
Notes:
To be more rebust, this should check the TextPosition affinity.
This doesn't handle right-to-left text yet.
Update:
If you are getting the text of the whole line, you can use LineMetrics (from TextPainter.computeLineMetrics()) now instead of TextBox. The process would be similar.
i'm having trouble reading in a text file which contains 9 sets of three integer values separated by commas. This is what i have done so far, but how would i be able to read through the data going down row one to get a max value?
very stuck with a program the data text file looks like
21,7,11
20,10,12
17,7,18
these represent temperature, height and carbon%
i have read in the file as so
{
string s;
System.IO.StreamReader inputFile = new System.IO.StreamReader(DataFile);
s = inputFile.ReadLine();
int noDataLines = int.Parse(s);
double[,] data = new double[noDataLines, 3];
string[] ss;
is this right if the data is stored in the debug folder as a .txt file?
from here how would i go about getting a max temp(ie only reading the first vertical column of data)?
We can simply use mixture of System.IO File.ReadLines() method and LINQ .ToList() in order to read all text lines to List<string>. At this point we can just iterate through the collection parsing double values from text lines :
List<string> lines = File.ReadLines("filepath").ToList();
List<int[]> values = new List<int[]>();
int[] temp = new int[3];
for (int i = 0; i < lines.Count; i++)
{
string[] strValues = lines[i].Split(',');
for (int i2 = 0; i2 < strValues.Length; i2++)
temp[i2] = Convert.ToInt32(strValues[i2]);
values.Add(temp.ToArray());
}
Or we can use LINQ :
List<string> lines = File.ReadLines("filepath").ToList();
List<int[]> values = new List<int[]>();
int[] temp = new int[3];
for (int i = 0; i < lines.Count; i++)
values.Add(lines[i].Split(',')
.Select(l => Convert.ToInt32(l)).ToArray());
I'm making an air dictionary and I have a(nother) problem. The main app is ready to go and works perfectly but when I tested it I noticed that it could be better. A bit of context: the language (ancient egyptian) I'm translating from does not use punctuation so a phrase canlooklikethis. Add to that the sheer complexity of the glyph system (6000+ glyphs).
Right know my app works like this :
user choose the glyphs composing his/r word.
app transforms those glyphs to alphanumerical values (A1 - D36 - X1A, etc).
the code compares the code (say : A5AD36) to a list of xml values.
if the word is found (A5AD36 = priestess of Bast), the user gets the translation. if not, s/he gets all the possible words corresponding to the two glyphs (A5A & D36).
If the user knows the string is a word, no problem. But if s/he enters a few words, s/he'll have a few more choices than hoped (exemple : query = A1A5AD36 gets A1 - A5A - D36 - A5AD36).
What I would like to do is this:
query = A1A5AD36 //word/phrase to be translated;
varArray = [A1, A5A, D36] //variables containing the value of the glyphs.
Corresponding possible words from the xml : A1, A5A, D36, A5AD36.
Possible phrases: A1 A5A D36 / A1 A5AD36 / A1A5A D36 / A1A5AD36.
Possible phrases with only legal words: A1 A5A D36 / A1 A5AD36.
I'm not I really clear but to things simple, I'd like to get all the possible phrases containing only legal words and filter out the other ones.
(example with english : TOBREAKFAST. Legal = to break fast / to breakfast. Illegal = tobreak fast.
I've managed to get all the possible words, but not the rest. Right now, when I run my app, I have an array containing A1 - A5A - D36 - A5AD36. But I'm stuck going forward.
Does anyone have an idea ? Thank you :)
function fnSearch(e: Event): void {
var val: int = sp.length; //sp is an array filled with variables containing the code for each used glyph.
for (var i: int = 0; i < val; i++) { //repeat for every glyph use.
var X: String = ""; //variable created to compare with xml dictionary
for (var i2: int = 0; i2 < val; i2++) { // if it's the first time, use the first glyph-code, else the one after last used.
if (X == "") {
X = sp[i];
} else {
X = X + sp[i2 + i];
}
xmlresult = myXML.mot.cd; //xmlresult = alphanumerical codes corresponding to words from XMLList already imported
trad = myXML.mot.td; //same with traductions.
for (var i3: int = 0; i3 < xmlresult.length(); i3++) { //check if element X is in dictionary
var codeElement: XML = xmlresult[i3]; //variable to compare with X
var tradElement: XML = trad[i3]; //variable corresponding to codeElement
if (X == codeElement.toString()) { //if codeElement[i3] is legal, add it to array of legal words.
checkArray.push(codeElement); //checkArray is an array filled with legal words.
}
}
}
}
var iT2: int = 500 //iT2 set to unreachable value for next lines.
for (var iT: int = 0; iT < checkArray.length; iT++) { //check if the word searched by user is in the results.
if (checkArray[iT] == query) {
iT2 = iT
}
}
if (iT2 != 500) { //if complete query is found, put it on top of the array so it appears on top of the results.
var oldFirst: String = checkArray[0];
checkArray[0] = checkArray[iT2];
checkArray[iT2] = oldFirst;
}
results.visible = true; //make result list visible
loadingResults.visible = false; //loading screen
fnPossibleResults(null); //update result list.
}
I end up with an array of variables containing the glyph-codes (sp) and another with all the possible legal words (checkArray). What I don't know how to do is mix those two to make legal phrases that way :
If there was only three glyphs, I could probably find a way, but user can enter 60 glyphs max.