I want to trim a row in excel which contains the following values:
row a row b
texas/dallas 5
texas/austin 10
california/sf 5
california/la 20
to
row a row b
texas 5
texas 10
california 5
california 20
It sounds like what you want to do is get the value of everything to the left of the / symbol in a particular field. To do that, you can use the following formula:
=LEFT(A1,FIND("/",A1)-1)
where A1 is the cell you want to change.
Here's how it works:
Find("/", A1) finds the first instance of the "/" in the text in A1 and returns it's position.
Then Left(A1, <#>) takes all the characters to the left of position calculated by the previous expression.
Related
I want to know if I can use a macro in Excel to separate data in a single column into different colums according to number of characters. For example, what I have is this in column A
A
AB
ABC
1A
564
8
What I need is this, in colums A, B and C
A AB ABC
8 1A 564
Thanks.
Use the following formula in a new column B next to Column A:
=IFERROR(INDEX($A$1:$A$6,SMALL(IF(LEN($A$1:$A$6)=1,ROW($A$1:$A$6),99999),ROW()),1),"")
Array Formula press Ctrl+Shift+Enter at the same time
and drag it down, it will write the Values of B whose Length is 1, and when it gives empty it means no more Values with Length 1
Small will find the Cell which length is 1 (Row()=1, 1st cell which length=1, Row()=2, 2nd cell which length =1 ...)
If will return all the rows for the corresponding condition
Index will return the Cell
Iferror return empty "" if no more match
For the second column write 2 instead of 1 in LEN($A$1:$A$6)=2
=IFERROR(INDEX($A$1:$A$6,SMALL(IF(LEN($A$1:$A$6)=2,ROW($A$1:$A$6),99999),ROW()),1),"")
For the third column write 3 in LEN($A$1:$A$6)=3
=IFERROR(INDEX($A$1:$A$6,SMALL(IF(LEN($A$1:$A$6)=3,ROW($A$1:$A$6),99999),ROW()),1),"")
I am looking to format some data. To make it more easy I use an example with simple numbers.
Sheet 1 ('S1'):
A1 10
A2 14
A3 23
A4 12
A5 64
A6 32
.... etc
It is a long list(vertical) of 600 values
Now I want in Sheet 2('S2'):
To show it as:
S1!A1 S1!A2 S1!A3 S1!A4 S1!A5 S1!A6
S1!A7 S1!A8 S1!A9 S1!A10 S1!A11 S1!A12
S1!A13 S1!A14 S1!A15 S1!A16 S1!A17 S1!A18
References to the cells in the other sheet.
I have tried to transpose them but I cannot find a modifier to set an amount of columns used. i.e. I would get 1 row with all my data. I want only the first 6 in row, next 6 in next row, next 6... etc.
Thanks for any help/feedback given.
Put this in the upper left cell desired:
=INDEX(Sheet1!$A:$A,(ROW(1:1)-1)*6+COLUMN(A:A))
Then copy/drag over 6 columns and down till you finish the list
Sheet1
I have 3 columns of data. Col A contains Names, Col B contains a client ID, Col C contains a date.
I'm trying to figure out how to write a formula that will find the top 2 and top 3 instances of a specific Name in Col A and client ID in Col B and return the value in Col C.
Trying to avoid using VBA, but not sure if this is doable.
So for example data looks like this and I would want to return that Sam dealt with Client ABC the 2nd time around on 12/16.
Sam ABC 12/3
Adam XYZ 12/5
John DEF 12/9
Sam ABC 12/16
Adam HIJ 12/18
Assuming
your headers are in A1:C1
your data starts from A3 (yes, not A2)
You enter the name in G2 & Client ID in G3 & you want the list of
dates starting from G5
Enter these formula/values:
A2: =G2
B2: =G3
C2: =0
G5:
=IFERROR(INDEX(($A$2:$A$500=$G$2)*($B$2:$B$500=$G$3)*($C$2:C$500),MATCH(0,COUNTIF($G$4:G4,($A$2:$A$500=$G$2)*($B$2:$B$500=$G$3)*($C$2:C$500)),0)),"End")
(Formula in G5 is an array formula; confirm this with Ctrl+Shift+Enter)
Drag the formula in G5 down until you see 'End'
Value in cell G5 will always be 0 or '1/0' based on your formatting.
The list of dates corresponding to the name & client ID combination will start from G6.
Let me see if I understood your need. Correct me if I'm wrong.
You want to be able to inform a Name and a Client ID and have Excel tell you the last 3 occurrences of that combination?
By "top 2 and top 3 instances of a specific name" I'm assuming you mean the top 2 and 3 dates found for that specific name and ID.
If so, try this:
Supposing you have your example data table starting at Cell A1 and ending at Cell C6 (including column headers) and that you'll enter the name in F1 and Client ID on F2
A B C
1 Name Client ID Date
2 Sam ABC 12/3
3 Adam XYZ 12/5
4 John DEF 12/9
5 Sam ABC 12/16
6 Adam HIJ 12/18
Type this formula where you want to return the date of the last occurrence:
=IFERROR(LARGE(IF($A$2:$A$6=$F$1,IF($B$2:$B$6=$F$2,$C$2:$C$6)),1),"-")
This should be entered as an Array Formula, so don't forget to press CTRL + SHIFT + ENTER or it'll not work.
To bring the 2nd last occurrence on another cell, just copy and paste the formula and change the number 1 to 2 (as indicated below):
=IFERROR(LARGE(IF($A$2:$A$6=$F$1,IF($B$2:$B$6=$F$2,$C$2:$C$6)),2),"-")
If you typed 'Sam' on F1 and 'ABC' on F2, this formula would return '12/16' as the last occurrence, '12/3' as the 2nd last occurrence and a dash (-) as the 3rd last occurrence, since there isn't one.
Of course, you'll have to adjust the ranges and other cell references accordingly in your real data set.
Hope this helps.
I have a table excel with one column and X rows.
4 various informations
example:
row 1 2 3 4 = informations for 1
row 5 6 7 8 = information for 2
I would like to know how can I do to have these information by row instead of by column?
Example:
paul
madrid
14
victor
canada
23
emilie
paris
18
and I Would like:
paul Victor Emilie
Madrid Canada Paris
14 23 18
If you want change data only once, use Copy/Paste
Switch (transpose) columns and rows
Or if you want use formula
TRANSPOSE function
Or you can use the INDIRECT function instead. It's a bit tricky but it works :
On the same sheet where you have :
Paul
Madrid
23
Victor
Montréal
22
Aude
Copenhague
17
Valérie
Alger
28
Add something like (for example on columns B, C, D) :
1 2 3
4 5 6
7 8 9
10 11 12
etc.
It's easy to do with =X+3 formula and drag down formula.
Then, this matrix represent the position of each element in the list, you now just have to use INDIRECT in this way :
=INDIRECT("A" & B1)
A is the column where are your data
B1 is the position of the first element in the matrix
By draging this formula down and on the right, you will the matrix with the A's elements.
(Using example where source column in G2:G100 and target table in H2:J34.)
Type formula below in first cell of target table (H2):
=OFFSET($G$2;(ROW()-ROW($2:$2))*3+COLUMN()-COLUMN($H:$H);0)
Replacing $G$2 with first cell of source data, $2:$2 with first row of target table and $H:$H with first column of target table (mind the $).
Then just drag formula left and then bottom.
I have a spreadsheet with 2 columns of data, column A and B, and column C where I'm looking for the formula.
row A B C
1 50
2
3
4
5 56 6
6
7
8 46 10
9
10
11 64 18
As you can see, a row either contains a value or not. In column C, I'm looking to calculate the difference between
a) the value in column B and the value in column A's first non-empty cell directly above (so for example, at row 5, I calculate the difference between B5 and A1 56 - 50 = 6) if the value of B is a number and
b) the value in column A and the value in column B's first non-empty cell directly above (row 8, 56 - 46 = 10)
and put nothing if neither column A and B are empty.
I've been struggling with "first non-empty cell" to write an R1C1 formula. Note that I know I can do this in VBA but I'm looking for the R1C1 formula.
Thanks for your help.
Here is an array formula (that you need to validate with Ctrl + Shift + Enter) you can put in C1 and drag and drop till the end of your data:
=IF(OR(A1<>"",B1<>""),INDEX($B$1:B1,MAX(IF($B$1:B1="",0,ROW($B$1:B1))))-INDEX($A$1:A1,MAX(IF($A$1:A1="",0,ROW($A$1:A1)))),"")
Or, in a french version of Excel:
=SI(OU(A1<>"";B1<>"");INDEX($B$1:B1;MAX(SI($B$1:B1="";0;LIGNE($B$1:B1))))-INDEX($A$1:A1;MAX(SI($A$1:A1="";0;LIGNE($A$1:A1))));"")
Note that if you feel interested, you can commit into Stackoverflow in french
Perhaps try this formula in C2 copied down
=IF(B2="",IF(A2="","",LOOKUP(9.99E+307,B$1:B1)-A2),B2-LOOKUP(9.99E+307,A$1:A1))