i get this wierd bug.
i have this code, which compares the password in the config file with the given argument:
if(label.equalsIgnoreCase("login")){
if(getConfig().getString("players."+p.getName()+".password") == args[0]){
p.sendMessage("OK!");
} else {
p.sendMessage("NOT OK!");
}
but no matter what, it ouputs "NOT OK!", what am i doing wrong?
ive tried to debug it, to send a message with the given argument and what it sees in the config file.
they were both the same!
You should try
String configValue = config.getString("players."+p.getName()+".password");
if(configValue != null && configValue.equals(args[0]) { // maybe you just need to change the index of args[], depending on if your command looks like /xy <password> or /xy z <password>
p.sendMessage("OK!");
} else {
p.sendMessage("NOT OK!");
}
Related
I'm trying to get my slowmode command working. Basically when I type >sm 2s it replies with "Please follow this example: ;sm 5" <-- this reply should just send if args are null.
if(args[1] == null) {
return message.channel.send("Please follow this example: ;sm 5")
}if (args[1] !== null) {
message.channel.setRateLimitPerUser(args[0])
message.channel.send(`Slowmode is now ${args[0]}s`)
}}
module.exports.config = {
name: "sm",
aliases: []
}```
In JavaScript and most other languages, you could refer to ! in functions as not.
For example, let's take message.member.hasPermission(). If we add ! at the start, giving us:
if (!message.member.hasPermission('ADMINISTRATOR') return
We're basically telling the client, if the message member does **not** have the administrator permission, return the command.
Now, let's take your if statement, saying if (!args[1] == null) {, you're basically telling the client if not args[1] equals to null do this:, which let's face it makes totally no sense.
When we want to compare a variable with a certain value, we would want to tell the client if args[1] is **not** equal to null, do this. Hence why you should fix you if statement into saying:
if (args[1] !== null) {
Sorry for the pretty long answer, felt like giving a little lesson to someone :p
I have a JSON file of 2 discord client IDs `{
{
"premium": [
"a random string of numbers that is a client id",
"a random string of numbers that is a client id"
]
}
I have tried to access these client IDs to do things in the program using a for loop + if statement:
for(i in premium.premium){
if(premium.premium[i] === msg.author.id){
//do some stuff
}else{
//do some stuff
When the program is ran, it runs the for loop and goes to the else first and runs the code in there (not supposed to happen), then runs the code in the if twice. But there are only 2 client IDs and the for loop has ran 3 times, and the first time it runs it goes instantly to the else even though the person who sent the message has their client ID in the JSON file.
How can I fix this? Any help is greatly appreciated.
You may want to add a return statement within your for loop. Otherwise, the loop will continue running until a condition has been met, or it has nothing else to loop over. See the documentation on for loops here.
For example, here it is without return statements:
const json = {
"premium": [
"aaa-1",
"bbb-1"
]
}
for (i in json.premium) {
if (json.premium[i] === "aaa-1") {
console.log("this is aaa-1!!!!")
} else {
console.log("this is not what you're looking for-1...")
}
}
And here it is with return statements:
const json = {
"premium": [
"aaa-2",
"bbb-2"
]
}
function loopOverJson() {
for (i in json.premium) {
if (json.premium[i] === "aaa-2") {
console.log("this is aaa-2!!!!")
return
} else {
console.log("this is not what you're looking for-2...")
return
}
}
}
loopOverJson()
Note: without wrapping the above in a function, the console will show: "Syntax Error: Illegal return statement."
for(i in premium.premium){
if(premium.premium[i] === msg.author.id){
//do some stuff
} else{
//do some stuff
}
}
1) It will loop through all your premium.premium entries. If there are 3 entries it will execute three times. You could use a break statement if you want to exit the loop once a match is found.
2) You should check the type of your msg.author.id. Since you are using the strict comparison operator === it will evaluate to false if your msg.author.id is an integer since you are comparing to a string (based on your provided json).
Use implicit casting: if (premium.premium[i] == msg.author.id)
Use explicit casting: if (premium.premium[i] === String(msg.author.id))
The really fun and easy way to solve problems like this is to use the built-in Array methods like map, reduce or filter. Then you don't have to worry about your iterator values.
eg.
const doSomethingAuthorRelated = (el) => console.log(el, 'whoohoo!');
const authors = premiums
.filter((el) => el === msg.author.id)
.map(doSomethingAuthorRelated);
As John Lonowski points out in the comment link, using for ... in for JavaScript arrays is not reliable, because its designed to iterate over Object properties, so you can't be really sure what its iterating on, unless you've clearly defined the data and are working in an environment where you know no other library has mucked with the Array object.
Hi everyone,
I am trying to test C programs that use an user input... Like a learning app. So the avaliator(teacher) can write tests and I compile the code with a help of a docker and get back the result of the program that I send. After that I verify if one of the case tests fails..
for that I have two strings, like this:
result = "input_compiled1540323505983: /home/compiler/input/input.c:9: main: Assertion `B==2' failed. timeout: the monitored command dumped core Aborted "
and an array with case tests that is like:
caseTests = [" assert(A==3); // A must have the value of 3;", " assert(B==2); // B must have the value of 2; ", " assert(strcmp(Fulano, "Fulano")==0); //Fulano must be equal to Fulano]
I need to send back from my server something like this:
{ console: [true, true, true ] }
Where each true is the corresponding test for every test in the array of tests
So, I need to test if one string contains the part of another string... and for now I did like this:
criandoConsole = function(arrayErros, arrayResult){
var consol = arrayErros.map( function( elem ) {
var local = elem.match(/\((.*)\)/);
if(arrayResult.indexOf(local) > -1 ) {
return false;
}
else return true;
});
return consol;
}
I am wondering if there are any more efective way of doing that. I am using a nodejs as server. Does anyone know a better way?!
ps: Just do like result.contains(caseTests[0]) did not work..
I know this is changing the problem, but can you simplify the error array to only include the search terms? For example,
result = "input_compiled1540323505983: /home/compiler/input/input.c:9: main: Assertion `B==2' failed. timeout: the monitored command dumped core Aborted ";
//simplify the search patterns
caseTests = [
"A==3",
"B==2",
"strcmp(Fulano, \"Fulano\")==0"
]
criandoConsole = function(arrayErros, arrayResult){
var consol = arrayErros.map( function( elem ) {
if (arrayResult.indexOf(elem) != -1)
return false; //assert failed?
else
return true; //success?
});
return consol;
}
console.log(criandoConsole(caseTests,result));
I have written this code
$ips = preg_split("/,/", $_SERVER["HTTP_X_FORWARDED_FOR"]);
$ip = $ips[0];
if ($key === $ip && $val === env('SERVER_ADDR')) {
$addr = env($ip);
if ($addr !== null) {
$val = $addr;
}
}
But I am getting following error:
<b>Notice</b>: Undefined index: HTTP_X_FORWARDED_FOR
Just dont use array keys without knowing for sure they always exist..
basic PHP one o' one
if (!empty($_SERVER["HTTP_X_FORWARDED_FOR"])) {
// now only try to access this key
}
The alternative in Cake is to use wrapper methods that are designed to automatically check on the existence internally. Then you can just read the value directly. In your case env() checks on those server vars:
$result = env('HTTP_X_FORWARDED_FOR');
I am using auth module of kohana. I did register and login and its working fine. But when i do Auth::instance()->get_user()->id i get NULL
While login i do it with Auth::instance()->login($validator['email'], $validator['password']) and then redirect user to home page.
But when in one of the controller i do Auth::instance()->get_user()->id i get NULL
What would be the cause. Is that i have to first set something???
Try Auth::instance()->get_user()->pk().
pk() is for primary key.
Works in KO3.
My Mistake
In the _login function of modules/auth/classes/kohana/auth/orm.php
In that i was doing the following
$user = ORM::factory('user');
$user->where('email', ' = ', $email)
->and_where('password', ' = ', $password)
->find();
// TODO remember to be done
if ($user !== null) {
$this->complete_login($user);
return true;
} else {
return false;
}
In above i was checking $user is null or not but if the email and password not match the user instance will be created with NULL values for all the columns.
So now i am checking $user->id !== NULL and it is working fine.
Try this:
if ($user->loaded()) {
$this->complete_login($user);
return true;
} else {
return false;
}
See ORM::__call() if you want to know what happends (since ORM::loaded() does not exist)