I need to be able to change the prompt on running an executable of a c file to get a custom prompt
E.g:
$ abc
abc>
Here the user can give the commands acceptable to the program.
I saw this happen for programs like MySQL and was wondering if it is possible to do this.
You can use gnu readline for custom prompt
#include <readline/readline.h>
#include <readline/history.h>
while (1)
{
command = readline ("$abc");
command = readline ("abc>");
//validate your command name
system(command);
add_history (command); ///add command in history
}
you can include the readline library in your program to make it have a modern command line interface.
Or you can simply build a loop get each line from input and get the tokens from that line of input to execute commands, and there printout your abc> prompt.
Related
My Python 3.7.1 script generates a fasta file called
pRNA.sites.fasta
Within the same script, I call following system command:
cmd = "weblogo -A DNA < pRNA.sites.fasta > OUT.eps"
os.system(cmd)
print(cmd) #for debugging
I am getting the following error message and debugging message on the command line.
Error: Please provide a multiple sequence alignment
weblogo -A DNA < pRNA.sites.fasta > OUT.eps
"OUT.eps" file is generated but it's emtpy. On the other hand, if I run the following 'weblogo' command from the command line, It works just find. I get proper OUT.eps file.
$ weblogo -A DNA<pRNA.sites.fasta>OUT.eps
I am guessing my syntax for os.system call is wrong. Can you tell me what is wrong with it? Thanks.
Never mind. It turned out to be that I was not closing my file, "pRNA.sites.fasta" before I make system call that uses this file.
When type a unterminated command in a mongo shell, it will return three dots indicating need more input to complete this command like below:
> db.test.find(
... {
...
I am using nodejs child_process.spawn to create a mongo shell process and listen on its output. I can get the standard and error output from the mongo shell but I can't get the ... output. Below is my nodejs code:
const shell = spawn('mongo', params);
shell
.stdout
.on('data', (data) => {
winston.debug('get output ' + data);
});
shell
.stderr
.on('data', (data) => {
const output = data + '';
winston.error('get error output ', data);
});
I run below code to send command on the shell:
shell.stdin.write('db.test.find(');
I wander why I can't get the ... output on above method. Is it a special output?
EDIT1
I tried to use node-pty and pty.js. They can get the ... output but they mix the input and output data together. It is not possible to separate them.
I also tried to use stdbuf and unbuffer to disable buffer but it still doesn't work.
It seems that nodejs child_process doesn't work well with interactive command.
Your code doesn't include anything that writes to the stdin of your child process so I would be surprised if you got the ellipsis that indicates incomplete command when in fact you don't send any command at all - incomplete or otherwise.
That having been said, many command line utilities behave differently when they discover a real terminal connected to their stdin/stdout. E.g. git log will page the results when you run it directly but not when you pipe the results to some other command like git log | cat so this may also be the case here.
This can also have to do with the buffering - if your stream is line-buffered then you won't see any line that is not ended with a newline right away.
The real question is: do you see the > prompt? Do you send any command to the mongo shell?
Scritping interactive CLI tools can be tricky. E.g. see what I had to do to test a very simple interactive program here:
https://github.com/rsp/rsp-pjc-c01/blob/master/test-z05.sh#L8-L16
I had to create two named pipes, make sure that stdin, stderr and stdout are not buffered, and then use some other tricks to make it work. It is a shell script but it's just to show you an example.
I have been experimenting with Haskell. I am trying to write a web crawler and I need to use external curl binary (due to some proxy settings, curl needs to have some special arguments which seem to be impossible/hard to set inside the haskell code, so i rather just pass it as a command line option. but that is another story...)
In the code at the bottom, if I change the marked line with curl instead of curl --help the output renders properly and gives:
"curl: try 'curl --help' or 'curl --manual' for more information
"
otherwise the string is empty - as the `curl --help' response is multiline.
I suspect that in haskell the buffer is cleared with every new line. (same goes for other simple shell commands like ls versus ls -l etc.)
How do I fix it?
The code:
import System.Process
import System.IO
main = do
let sp = (proc "curl --help"[]){std_out=CreatePipe} -- *** THIS LINE ***
(_,Just out_h,_,_)<- createProcess sp
out <-hGetContents out_h
print out
proc takes as a first argument the name of the executable, not a shell command. That, is when you use proc "foo bar" you are not referring to a foo executable, but to an executable named exactly foo bar, with the space in its file name.
This is a useful feature in practice, because sometimes you do have spaces in there (e.g. on Windows you might have c:\Program Files\Foo\Foo.exe). Using a shell command you would have to escape spaces in your command string. Worse, a few other characters need to be escaped as well, and it's cumbersome to check what exactly those are. proc sidesteps the issue by not using the shell at all but passing the string as it is to the OS.
For the executable arguments, proc takes a separate argument list. E.g.
proc "c:\\Program Files\\Foo\\Foo.exe" ["hello world!%$"]
Note that the arguments need no escaping as well.
If you want to pass arguments to curl you have to pass that it in the list:
sp = (proc "/usr/bin/curl" ["--help"]) {std_out=CreatePipe}
Then you will get the complete output in the entire string.
I'm trying to customize the ssh command in ubuntu using the ~/.bash_aliases file, basically I want to use the command 'zssh |$value|' to do: ssh root#name|$valuegoeshere|.hostname.org, I have tried to use this code:
function zssh{ssh root#name$1.hostname.org}
However I got the following error:
bash: /home/amirs/.bash_aliases: line 1: syntax error near unexpected
token root#name$1.hostname.org}' bash: /home/amirs/.bash_aliases:
line 1:function zssh{ssh root#name$1.hostname.org}'
Any suggestions on how to configure the following function?
The correct way to define a function is:
zssh () {
ssh root#name$1.hostname.org
}
The function keyword is optional and a bash extension, so there's no need to use it. You need whitespace around the { character, and there has to be a command delimiter (either newline or ;) before }.
How and who determines what executes when a Bash-like script is executed as a binary without a shebang?
I guess that running a normal script with shebang is handled with binfmt_script Linux module, which checks a shebang, parses command line and runs designated script interpreter.
But what happens when someone runs a script without a shebang? I've tested the direct execv approach and found out that there's no kernel magic in there - i.e. a file like that:
$ cat target-script
echo Hello
echo "bash: $BASH_VERSION"
echo "zsh: $ZSH_VERSION"
Running compiled C program that does just an execv call yields:
$ cat test-runner.c
void main() {
if (execv("./target-script", 0) == -1)
perror();
}
$ ./test-runner
./target-script: Exec format error
However, if I do the same thing from another shell script, it runs the target script using the same shell interpreter as the original one:
$ cat test-runner.bash
#!/bin/bash
./target-script
$ ./test-runner.bash
Hello
bash: 4.1.0(1)-release
zsh:
If I do the same trick with other shells (for example, Debian's default sh - /bin/dash), it also works:
$ cat test-runner.dash
#!/bin/dash
./target-script
$ ./test-runner.dash
Hello
bash:
zsh:
Mysteriously, it doesn't quite work as expected with zsh and doesn't follow the general scheme. Looks like zsh executed /bin/sh on such files after all:
greycat#burrow-debian ~/z/test-runner $ cat test-runner.zsh
#!/bin/zsh
echo ZSH_VERSION=$ZSH_VERSION
./target-script
greycat#burrow-debian ~/z/test-runner $ ./test-runner.zsh
ZSH_VERSION=4.3.10
Hello
bash:
zsh:
Note that ZSH_VERSION in parent script worked, while ZSH_VERSION in child didn't!
How does a shell (Bash, dash) determines what gets executed when there's no shebang? I've tried to dig up that place in Bash/dash sources, but, alas, looks like I'm kind of lost in there. Can anyone shed some light on the magic that determines whether the target file without shebang should be executed as script or as a binary in Bash/dash? Or may be there is some sort of interaction with kernel / libc and then I'd welcome explanations on how does it work in Linux and FreeBSD kernels / libcs?
Since this happens in dash and dash is simpler, I looked there first.
Seems like exec.c is the place to look, and the relevant functionis are tryexec, which is called from shellexec which is called whenever the shell things a command needs to be executed. And (a simplified version of) the tryexec function is as follows:
STATIC void
tryexec(char *cmd, char **argv, char **envp)
{
char *const path_bshell = _PATH_BSHELL;
repeat:
execve(cmd, argv, envp);
if (cmd != path_bshell && errno == ENOEXEC) {
*argv-- = cmd;
*argv = cmd = path_bshell;
goto repeat;
}
}
So, it simply always replaces the command to execute with the path to itself (_PATH_BSHELL defaults to "/bin/sh") if ENOEXEC occurs. There's really no magic here.
I find that FreeBSD exhibits identical behavior in bash and in its own sh.
The way bash handles this is similar but much more complicated. If you want to look in to it further I recommend reading bash's execute_command.c and looking specifically at execute_shell_script and then shell_execve. The comments are quite descriptive.
(Looks like Sorpigal has covered it but I've already typed this up and it may be of interest.)
According to Section 3.16 of the Unix FAQ, the shell first looks at the magic number (first two bytes of the file). Some numbers indicate a binary executable; #! indicates that the rest of the line should be interpreted as a shebang. Otherwise, the shell tries to run it as a shell script.
Additionally, it seems that csh looks at the first byte, and if it's #, it'll try to run it as a csh script.